I am writing a simple script that takes a user input number and outputs whether the number was less than, equal to or greater than 100. I am using tcsh and I keep getting an error at set myNum -i = $< on line 6 that states syntax error near unexpected token 'newline'. I have tried multiple different indents and small changes, but nothing is working.
#!/bin/tcsh
set myNum -i = 0
echo "Please enter a number: "
set myNum -i = $<
if ($myNum > 100) then
echo "You put in a number bigger than 100."
else if ($myNum == 100) then
echo "You put in 100."
else
echo "You put in a number less than 100."
endif
I copied your code exactly and tested it. I didn't get the same error. Instead I got
set: Variable name must begin with a letter.
This error was caused by the -i option to set.
After removing the -i options from set, the script works fine for me:
Related
I have a shell script with a function and when I call the function I am getting a bad number error. In my function I am getting a filename from the database and returning it. The return gives the 'bad number' error. Details below:
call to GET_MYFILE() :
GET_MYFILE $jobid
--$job id has the correct number in it
GET_MYFILE()
{
echo "job id input parameter is : " $1
curfile=`sqlplus -s /#username<< EOF
set feed off heading off verify off serveroutput off
select my_file_name
from my_table_name
where jobid=$1;
exit;
EOF`
echo "curfile is : " $curfile
return $curfile
}
-- echo "curfile is : " $curfile - displays correct filename
--return $curfile gives bad number error.
In the Korn Shell syntax, the return statement syntax offers only two variants:
return (and in this case, the returned number is the exit code of the most recently executed command in the function).
return n (where n is a number between 0 and 255)
In either case, the caller can access the numeric value returned via the $? pseudovariable in an assignment or conditional statement.
If you try to return a filename then you should expect "bad number", because a filename string cannot usually be interpreted as a number.
Given the following code, BASH's output is unexpected for me and I'm looking for possible solutions (I've tried changing the way I'm quoting but that doesn't seem to affect anything to produce the desired result):
Testing File:
#!/bin/bash
. FindMissingSettings.function
Settings[0]="FirstSetting"
Settings[1]="SecondSetting"
Settings[2]="ThirdSetting"
ThisFile="ThisFile"
find_missing_settings "${Settings[#]}" "$ThisFile"
The included FindMissingSettings.function:
#!/bin/bash
find_missing_settings () {
Settings=("$#")
File=$2
for Setting in "${Settings[#]}"; do
echo "$Setting"
echo "1"
done
echo "$File"
echo "2"
}
I expected the output from this script and the included function to be:
FirstSetting
1
SecondSetting
1
ThirdSetting
1
ThisFile
2
However this was the result I received:
FirstSetting
1
SecondSetting
1
ThirdSetting
1
ThisFile
1
SecondSetting
2
Why is this and what can I do to provide the desired result? Thank you!
In your find_missing_settings function, in your variable Setting, you have all the given inputs (FirstSetting, Second Setting, ThirdSetting, ThisFile). That's why it print it all with during the loop.
Then it print the 2nd setting in the list, so SecondSetting
To fix this, you can put ThisFile as first parameter of the function:
find_missing_settings "$ThisFile" "${Settings[#]}"
And change in the find_missing_settings function how you get the inputs:
Settings=("${#:2}")
File=$1
The :2 ask to get the inputs starting from the 2nd one only, and you put the first one (ThisFile) in the variable File
As I'm new to Unix, can someone help why I get this error?
Error: 0403-057 Syntax error at line 1 : `(' is not expected
Unix server used: AIX servname 1 6 00F635064C00
Script used (to send email alert if day before yesterday source files didn't arrive):
#!/usr/bin/ksh
count=$(sqlplus $PROD_DB #select count(*) from file_audit where (file_name like '%abc%' or file_name like '%dce%') and substr(file_name,17,8)=to_char(to_date(sysdate-2,'DD/MM/YY'), 'yyyymmdd') > asa_file_count.log)
daybefore=`TZ=aaa48 date +%d-%m-%Y`
if [[ $count -lt 20 ]]
then
echo "Alert - Source files are yet to be received for date: $daybefore" | mail -s "Alert : Source data files missing" s#g.com
fi
Parentheses are special to the shell. Your SQL script contains parentheses you don't want the shell to process. However, the shell processes all non-quoted parentheses. Therefore, you can use quotes to prevent the parentheses in your SQL from being interpreted by the shell:
count=$(sqlplus $PROD_DB "#select count(*) from file_audit where (file_name like '%abc%' or file_name like '%dce%') and substr(file_name,17,8)=to_char(to_date(sysdate-2,'DD/MM/YY'), 'yyyymmdd')" > asa_file_count.log)
# ^ and similarly, a closing quote at the end, just before ">asa_file..." .
Now, there is a second issue: you have
count=$(sqlplus ... > asa_file_count.log)
However, I think this means count will always be empty, since the count will go into asa_file_count.log and will not be available to be captured with $(). I believe removing the >asa_file_count.log will probably do what you want:
count=$(sqlplus "$PROD_DB" "<your query>")
(I also put double-quotes around $PROD_DB just in case PROD_DB's value contains any spaces.)
This is my script:
#!/bin/bash
JOB_NUM=4
function checkJobNumber() {
if (( $JOB_NUM < 1 || $JOB_NUM > 16 )); then
echo "pass"
fi
}
...
checkJobNumber
...
When I try to launch the script I get the message:
./script.sh line 49: ((: < 1 || > 16 : syntax error: operand expected (error token is "< 1 || > 16 ")
(Please notice the spaces in the error message)
I really don't understand what the problem is. If I do the evaluation manually at the command line, it works.
Also, I tried different evaluations like if [[ "$JOB_NUM" -lt 1 -o "$JOB_NUM" gt 16 ]];... still no success.
UPDATE: As suggested I made few more attempts in the rest of the code outside the function call, and I found the problem.
My variables declaration was actually indented this way:
JOB_NUM= 4
THREAD_NUM= 8
.....
VERY_LONG_VAR_NAME= 3
and apparently this hoses the evaulation. BAH! It always worked for me before, so why doesn’t it now?
If I delete the white spaces, the evaluation works:
JOB_NUM=4
THREAD_NUM=8
....
VERY_LONG_VAR_NAME=3
OK I officially hate bash . . . sigh :(
this will work fine
#!/bin/bash
JOB_NUM=7
function checkJobNumber() {
if [ $JOB_NUM -lt 0 ] || [ $JOB_NUM -gt 16 ] ; then
echo "true"
else
echo "false"
fi
}
checkJobNumber
And if you want to check variable during tests you can write in your bash :
set -u
this will generate a message like "JOB_NUM: unbound variable" if variable is not well set
i have a script & it goes as below,
instant_client="/root/ora_client/instantclient_11_2"
output=`$instant_client/sqlplus -s HRUSER/HRUSER#TOMLWF <<EOF
set heading off
set feedback off
set lines 10000
set pagesize 10000
select count (1) from onboardingcandidates o, candidatedetails c where o.candidateid=c.candidateid and o.JOININGSTATUS='0091' and to_date(o.joiningdate)=to_date(sysdate+5);
EOF
exit
`
query=(`$instant_client/sqlplus -s HRUSER/HRUSER#TOMLWF <<EOF
set heading off
set feedback off
set lines 10000
set pagesize 10000
select o.candidateid from onboardingcandidates o, candidatedetails c where o.candidateid=c.candidateid and o.JOININGSTATUS='0091' and to_date(o.joiningdate)=to_date(sysdate+5);
EOF`)
i=0
echo "Throwing individual arrays:"
while [ $i -lt $output ]
do
a=${query[$i]}
echo Candidate[$i]=$a
i=$(($i+1))
done
OUTPUT:
Throwing individual arrays:
Candidate[0]=cand1
Candidate[1]=cand2
Candidate[2]=cand3
Candidate[3]=cand62
REQUIRED OUTPUT
Everything is working fine.
All i need is, i need 1 output at a time.
i.e. if i run the above script then the output should be controlled.
It should throw 1 output at a time on the prompt.
Is this possible ??
IF YOU NEED ANYTHING MORE THEN PLZ ASK. I HOPE I AM CLEAR WITH MY DOUBT
So you're running two queries, one to get the count of the number of results, the second to get the results.
If you want to only have one query, you can iterate through the count of the number of results. as the variable query is an array, you can use:
${#query[*]}
as the number of result rows, then use:
while [ $i -lt ${#query[*]} ]
as the loop condition.
If you want to display one result at a time, and require an enter between them, then you can add a read after the echo.
If you want to display a specific return row, then, assuming that the routine is called as-is, then the row number to display is passed in as the first parameter $1, then you can use:
a=${query[$1]}
echo Candidate[$1]=$a
if you just want to display the result at that line, without the Candidate[] text, then you can just echo:
echo ${query[$1]}
If I have understood your question correctly, before your echo statement to print the output,put this line:
read dummy
This will prompt you to enter some key, when entered, will show the next line output.