SQL> create table justlike(customerid varchar(19),first_name varchar(40),last_name varchar(100),Address varchar(50),city varchar(30),pincode varchar(10),state varchar(20));
Just use:
desc <table_name>;
This will print the description of your table columns
in your case:
desc justlike;
You can always check the table definition, in case you are using Oracle, by running below query -
SELECT * FROM USER_TAB_COLS
WHERE TABLE_NAME = 'JUSTLIKE';
OR you can write a select on table itself -
SELECT * FROM JUSTLIKE;
I have some SQL scripts; one of them references an object called "names". I can:
select * from names
and it returns results. However, I cannot see a table called "names". Neither can I see a view called "names". I can't find a custom type called "names".
If I look for one of the columns that is returned by the query select * from names using:
select * from sys.all_tab_columns where column_name like '%MyColumn%'
it finds a table called LSNAMES, but that has no rows.
Any ideas how I can find this "table"?
I'd start the research with understanding what type of object this is:
SELECT owner, object_name, object_type
FROM all_objects
WHERE object_name = 'NAMES'
Once you have a type, you could query some more information from all_<type>s
Look for:
A materialized view called NAMES
SELECT * FROM ALL_MVIEWS WHERE MVIEW_NAME = 'NAMES';
A synonym called NAMES
SELECT * FROM ALL_SYNONYMS WHERE SYNONYM_NAME = 'NAMES';
SQL Developer shows the creation and last DDL time for a public synonym in a table:
CREATED 15-AUG-09
LAST_DDL_TIME 15-AUG-09
OWNER PUBLIC
SYNONYM_NAME ISEMPTY
TABLE_OWNER MDSYS
TABLE_NAME OGC_ISEMPTY
DB_LINK (null)
How can I get the same information via a SQL query?
select * from all_synonyms where synonym_name = 'ISEMPTY'
does not get the created/last ddl dates.
More generally, is there a good way to see the queries that sql developer uses to display the data it displays (when you do not have access to a profiler)?
Thanks
You need the ALL_OBJECTS system view:
select *
from all_objects
where owner = 'OWNER_NAME'
and object_name = 'ISEMPTY'
and object_type = 'SYNONYM'
I know how to get all columns in oracle.
select * from all_tab_columns
but how can I get all columns from SYNONYMSas well?
Is this possible to do in oracle?
Isn't that a bit redundant? If you can see the table a synonym points to, then selecting from all_tab_columns gets you what you want.
You can get any synonyms for tables you can see thusly:
SELECT atc.*, s.synonym_name
FROM all_tab_columns atc LEFT JOIN all_synonyms s
ON (atc.owner = s.table_owner AND atc.table_name = s.table_name)
ORDER BY atc.owner, atc.table_name;
I want to find the foreign keys of a table but there may be more than one user / schema with a table with the same name. How can I find the one that the currently logged user is seeing? Is there a function that gives its owner? What if there are public synonyms?
You can query the ALL_OBJECTS view:
select owner
, object_name
, object_type
from ALL_OBJECTS
where object_name = 'FOO'
To find synonyms:
select *
from ALL_SYNONYMS
where synonym_name = 'FOO'
Just to clarify, if a user user's SQL statement references an object name with no schema qualification (e.g. 'FOO'), Oracle FIRST checks the user's schema for an object of that name (including synonyms in that user's schema). If Oracle can't resolve the reference from the user's schema, Oracle then checks for a public synonym.
If you are looking specifically for constraints on a particular table_name:
select c.*
from all_constraints c
where c.table_name = 'FOO'
union all
select cs.*
from all_constraints cs
join all_synonyms s
on (s.table_name = cs.table_name
and s.table_owner = cs.owner
and s.synonym_name = 'FOO'
)
HTH
-- addendum:
If your user is granted access to the DBA_ views (e.g. if your user has been granted SELECT_CATALOG_ROLE), you can substitute 'DBA_' in place of 'ALL_' in the preceding SQL examples. The ALL_x views only show objects which you have been granted privileges. The DBA_x views will show all database objects, whether you have privileges on them or not.
I found this question as the top result while Googling how to find the owner of a table in Oracle, so I thought that I would contribute a table specific answer for others' convenience.
To find the owner of a specific table in an Oracle DB, use the following query:
select owner from ALL_TABLES where TABLE_NAME ='<MY-TABLE-NAME>';
Interesting question - I don't think there's any Oracle function that does this (almost like a "which" command in Unix), but you can get the resolution order for the name by:
select * from
(
select object_name objname, object_type, 'my object' details, 1 resolveOrder
from user_objects
where object_type not like 'SYNONYM'
union all
select synonym_name obj , 'my synonym', table_owner||'.'||table_name, 2 resolveOrder
from user_synonyms
union all
select synonym_name obj , 'public synonym', table_owner||'.'||table_name, 3 resolveOrder
from all_synonyms where owner = 'PUBLIC'
)
where objname like upper('&objOfInterest')
Oracle views like ALL_TABLES and ALL_CONSTRAINTS have an owner column, which you can use to restrict your query. There are also variants of these tables beginning with USER instead of ALL, which only list objects which can be accessed by the current user.
One of these views should help to solve your problem. They always worked fine for me for similar problems.
To find the name of the current user within an Oracle session, use the USER function.
Note that the owner of the constraint, the owner of the table containing the foreign key, and the owner of the referenced table may all be different. It sounds like it’s the table owner you’re interested in, in which case this should be close to what you want:
select Constraint_Name
from All_Constraints
where Table_Name = 'WHICHEVER_TABLE'
and Constraint_Type = 'R' and Owner = User;
It is like #entpnerd said, but I suggest you to use upper() clause:
select *
from ALL_TABLES
where upper(TABLE_NAME) = upper('<table_name>')