I have some SQL scripts; one of them references an object called "names". I can:
select * from names
and it returns results. However, I cannot see a table called "names". Neither can I see a view called "names". I can't find a custom type called "names".
If I look for one of the columns that is returned by the query select * from names using:
select * from sys.all_tab_columns where column_name like '%MyColumn%'
it finds a table called LSNAMES, but that has no rows.
Any ideas how I can find this "table"?
I'd start the research with understanding what type of object this is:
SELECT owner, object_name, object_type
FROM all_objects
WHERE object_name = 'NAMES'
Once you have a type, you could query some more information from all_<type>s
Look for:
A materialized view called NAMES
SELECT * FROM ALL_MVIEWS WHERE MVIEW_NAME = 'NAMES';
A synonym called NAMES
SELECT * FROM ALL_SYNONYMS WHERE SYNONYM_NAME = 'NAMES';
Related
I have a table named "libisatz" in my database, and there is no table, nor view with name "libiSatz" (with capital S instead of s) and I don't find any kind of object in my schema having name "libiSatz". But, surprisingly selecting from "libiSatz" results in the same result as if I had written "libisatz". If I change any other letter in this name from lower case to upper case (e.g. I write "Libisatz", then I get an error. How can this be?.
ADDENDUM
I've checked the ideas of #Jon Heller with the following result:
Both select * from DBA_OBJECTS where OBJECT_NAME like 'libi_atz'; and select * from DBA_OBJECTS where lower(OBJECT_NAME) = 'libisatz'; returns one single row (it is the "libisatz" table)
select * from DBA_OBJECTS where OBJECT_NAME = 'libisatz'; returns one row and select * from DBA_OBJECTS where OBJECT_NAME = 'libiSatz'; returns no row.
Both select * from DBA_SQL_TRANSLATIONS; and select * from DBMS_ADVANCED_REWRITE; results in ORA-00942: table or view does not exist
select * from DBA_REWRITE_EQUIVALENCES; results in no rows selected
select DUMP(OBJECT_NAME) from DBA_OBJECTS where lower(OBJECT_NAME) = 'libisatz'; returns Typ=1 Len=8: 108,105,98,105,115,97,116,122
So it seems that the puzzle is not yet solved.
ADDENDUM 2.
When I try to create a view named "libiSatz" then I get
ORA-00955: name is already used by an existing object
in spite of the results above.
After I renamed "libiSatz" to "oraclepuzzle",
select count(*) from "libisatz"; and "select count(*) from "oraclepuzzle"; works, but select count(*) from "libiSatz"; doesn't.
select * from dba_objects where object_name in ( 'oraclepuzzle', 'libisatz', 'libiSatz'); returns one row with object_name "oraclepuzzle".
Do you have SQL translations, rewrite equivalances, or UTF8 characters?
The SQL translation framework was built to allow applications designed for other database types to seamlessly query Oracle. But instead of translating syntaxes, the feature could also be used to silently change your queries. For example, here is an example of querying a table that does not exist in order to workaround table size limitations. Check the view DBA_SQL_TRANSLATIONS.
Rewrite equivalences can be created by the package DBMS_ADVANCED_REWRITE, and can be used to silently change the results of wrong queries or for some rare performance problems. (In my simple tests I wasn't able to get this query to work for invalid queries, but I bet there is a way to make it work.) Check the view DBA_REWRITE_EQUIVALENCES.
UTF8 characters may be silently swapped out for similar ASCII characters. This probably depends on your database and client character set settings. The below example is pretty obviously not an ASCII "S", but you may have a more subtle problem. Check the source of your values, retype them manually, and use the DUMP function to evaluate the binary of the characters.
SQL> create table "libisatz"(a number);
Table created.
SQL> -- An uppercase "S" does not work
SQL> select * from "libiSatz";
select * from "libiSatz"
*
ERROR at line 1:
ORA-00942: table or view does not exist
SQL> -- But a "LATIN SMALL LETTER S WITH CARON" works.
SQL> select * from "libišatz";
no rows selected
Lastly, are you 100% sure that the object doesn't exist on your database? The above examples are possible, but extremely rare. Triple-check DBA_OBJECTS.OBJECT_NAME for the mystery object.
My deafult Oracle object names are case insensitive.
So, when you issue teh command:
CREATE TABLE the_table ..
CREATE TABLE The_Table ..
CREATE TABLE THE_TABLE ..
The underlying object name in all cases is THE_TABLE, but you can access it using any mix of upper/lower case:
SELECT * FROM THE_TABLE
SELECT * FROM tHe_TaBlE
SELECT * FROM the_table
Will all work.
When a table is created with the name wrapped in double-quotes, the name becomes case-sensitive.
So, if you issue:
CREATE TABLE "libiSatz" ..
Then the table name in all SQL statements must match the exact name in the double quotes, i.e.
SELECT * FROM "libiSatz" is OK (Correction following comments)
SELECT * FROM libisatz is NOT OK
SELECT * FROM LibiSatz is NOT OK
When you search for this in USER_OBJECTS or USER_TABLES you will have to match the creation name:
SELECT * FROM USER_OBJECTS WHERE OBJECT_NAME = 'libiSatz';
I want to find the name of the stored procedure, package, function or trigger which is inserting data into a particular table, is there any inbuilt object so that i can use it. I am searching the name of the object from last 2 hours. Kindly help.
You cannot find the inserted PL/SQL block, but you can try out to identify the procedures/functions referring it. And increase your chances of finding.
select
proc_syn.nam,
proc_syn.referenced_owner,
proc_syn.referenced_name,
proc_syn.referenced_type,
syn_tab.table_name
from
dba_dependencies proc_syn, dba_synonyms syn_tab, dba_tables tables
where
REFERENCED_TYPE in ( 'SYNONYM','TABLE')
AND proc_syn.referenced_name = syn_tab.synonym_name
AND syn_tab.synonym_name = tables.table_name
AND syn_tab.owner = 'PUBLIC'
AND REFERENCED_NAME = 'YOUR_TABLE_NAME'
order by
proc_syn.referenced_owner, syn_tab.table_name;
The above query would return the table objects, that refer this table.
Note, this would return, when you use STATIC queries only. Any dynamic queries, is completely out of hand.
You can try by analyzing all the source of your DB with something like this:
select *
from dba_source
where upper(text) like '%TABLE_NAME%'
The pro of this approach is that you will get even dynamic code; the con is that you'll have even select, update, ...
If the table is statically referenced you can check the ALL_DEPENDENCIES view
SELECT * FROM ALL_DEPENDENCIES WHERE REFERENCED_NAME = '<your table>';
This will find all usages, not only insert
You can also search within source code:
SELECT * FROM ALL_SOURCE WHERE UPPER(TEXT) LIKE '%INSERT%<your table>%'
This will find the usage only if INSERT and your table are on the same line.
However if the command is built more dynamically then you will not find it that simply.
You can use user_source or user_dependencies table as below.
Using table user_source
select * from user_source
where upper(text) like '%<YOUR TABLE NAME in UPPER CASE>%'
You can select from user_source , all_source , dba_source depending on user you have logged in and permission that user have.
Using table user_dependencies
SELECT NAME FROM user_dependencies WHERE referenced_name = '<YOUR TABLE NAME in UPPER CASE>'
UNION
SELECT referenced_name FROM user_dependencies WHERE name = '<YOUR TABLE NAME in UPPER CASE>'
You can select from user_dependencies , all_dependencies , dba_dependencies depending on user you have logged in and permission that user have.
I know the title is saying nothing... but the argument is a little "complex" to explain in a single row.
All the code i'm writing is just an example, my current code is from other table etc, but the behaviour is the same.
i have defined a cursor like this:
CURSOR emp_cur (l_type)
IS
with emp_general AS (select *
from emp
where type = l_type),
emp_active AS (select *
from emp_geral
where status = ACTIVE_STATUS),
emp_inactive AS (select *
from emp_general
where status = INACTIVE_STATUS)
select distinct name, department
from emp_active
minus
select distinct name, department
from emp_inactive;
This cursor take a parameter for filter emp type and make a minus to fetch ACTIVE - INACTIVE emp.
This cursor return name and department.
Now have to declare different cursor with different "select" statemant, for example:
select location
from emp_active
select location
from emp_active
I would like to dont duplicate my cursor just to change the select. There is a way to do this and avoid code duplication (withuout using DynamicSQL - Difficult to debug in production enviroment)?
You could create two Global temporary tables explicitly once(not on the fly):
emp_active_gtt
emp_inactive_gtt
Such that, each temp table will have the entire result set of active and inactive records respectively.
For example, in the code you would do:
insert into emp_active_gtt
select *
from ....
where status ='ACTIVE'
Similarly, for inactive records:
insert into emp_inactive_gtt
select *
from ....
where status ='INACTIVE'
You could now use the two tables in the scope of the session anywhere to get the required rows.
Read more about GTT in the documentation here https://docs.oracle.com/database/121/SQLRF/statements_7002.htm#i2153132
i have a existing table called property i alter a column called overbook_percent (i change a number 2 to 3) but i want to do a source search to make sure that there is not a variable declaration that sets this to just 2 digits. how would i go about this?not sure you called this a source search.
how can i see where this table column is use?
i tried this but get no output
select text
from dba_source
where upper(text) like 'OVERBOOK_MAX'
;
I'm working on toad for oracle
may be you are looking for this:-
select owner, table_name from all_tab_columns where column_name = 'OVERBOOK_MAX';
This will search all tables with a column name OVERBOOK_MAX
For checking in stored procedures you may try this:-
SELECT DISTINCT type, name
FROM dba_source
WHERE owner = 'OWNER'
AND UPPER(text) LIKE '%OVERBOOK_MAX%';
EDIT
to search a string try this:-
SELECT owner, name, type, line, text
FROM dba_source
WHERE instr(UPPER(text), UPPER(:search_string)) > 0;
I want to find the foreign keys of a table but there may be more than one user / schema with a table with the same name. How can I find the one that the currently logged user is seeing? Is there a function that gives its owner? What if there are public synonyms?
You can query the ALL_OBJECTS view:
select owner
, object_name
, object_type
from ALL_OBJECTS
where object_name = 'FOO'
To find synonyms:
select *
from ALL_SYNONYMS
where synonym_name = 'FOO'
Just to clarify, if a user user's SQL statement references an object name with no schema qualification (e.g. 'FOO'), Oracle FIRST checks the user's schema for an object of that name (including synonyms in that user's schema). If Oracle can't resolve the reference from the user's schema, Oracle then checks for a public synonym.
If you are looking specifically for constraints on a particular table_name:
select c.*
from all_constraints c
where c.table_name = 'FOO'
union all
select cs.*
from all_constraints cs
join all_synonyms s
on (s.table_name = cs.table_name
and s.table_owner = cs.owner
and s.synonym_name = 'FOO'
)
HTH
-- addendum:
If your user is granted access to the DBA_ views (e.g. if your user has been granted SELECT_CATALOG_ROLE), you can substitute 'DBA_' in place of 'ALL_' in the preceding SQL examples. The ALL_x views only show objects which you have been granted privileges. The DBA_x views will show all database objects, whether you have privileges on them or not.
I found this question as the top result while Googling how to find the owner of a table in Oracle, so I thought that I would contribute a table specific answer for others' convenience.
To find the owner of a specific table in an Oracle DB, use the following query:
select owner from ALL_TABLES where TABLE_NAME ='<MY-TABLE-NAME>';
Interesting question - I don't think there's any Oracle function that does this (almost like a "which" command in Unix), but you can get the resolution order for the name by:
select * from
(
select object_name objname, object_type, 'my object' details, 1 resolveOrder
from user_objects
where object_type not like 'SYNONYM'
union all
select synonym_name obj , 'my synonym', table_owner||'.'||table_name, 2 resolveOrder
from user_synonyms
union all
select synonym_name obj , 'public synonym', table_owner||'.'||table_name, 3 resolveOrder
from all_synonyms where owner = 'PUBLIC'
)
where objname like upper('&objOfInterest')
Oracle views like ALL_TABLES and ALL_CONSTRAINTS have an owner column, which you can use to restrict your query. There are also variants of these tables beginning with USER instead of ALL, which only list objects which can be accessed by the current user.
One of these views should help to solve your problem. They always worked fine for me for similar problems.
To find the name of the current user within an Oracle session, use the USER function.
Note that the owner of the constraint, the owner of the table containing the foreign key, and the owner of the referenced table may all be different. It sounds like it’s the table owner you’re interested in, in which case this should be close to what you want:
select Constraint_Name
from All_Constraints
where Table_Name = 'WHICHEVER_TABLE'
and Constraint_Type = 'R' and Owner = User;
It is like #entpnerd said, but I suggest you to use upper() clause:
select *
from ALL_TABLES
where upper(TABLE_NAME) = upper('<table_name>')