How to send a command with arguments without spaces in Windows - windows

Is there a way to execute a command with arguments in Windows without spaces?
echo 1 > a
Needs to be:
echo1>a
In Linux you can use ${IFS} but I didn't find it to work in Windows:
echo${IFS}1${IFS}>a

Does this produce what you are seeking?
ECHO]1>a

(echo(1)>a
or
(echo/1)>a
can be done.
An alternative is
>a=echo/1
because the =-sign is a token separator just like the SPACE (you may also use , or ; instead).
But regard, that
echo/1>a
cannot be used, because 1> is then taken as the redirection operator.
A completely different solution is to first assign a SPACE to a variable and then to use it:
rem // This assigns a single space character:
set "SPC= "
rem // A space before `>` would also be echoed out, hence use parenthesis:
(echo%SPC%1)>%SPC%a
rem // Alternatively, rearrange the command line:
>%SPC%a%SPC%echo%SPC%1
This works, because immediate variable (%-)expansion happens before command token recognition.

Related

Interactive Command Prompt character escaping %

I need to escape the % character in interactive Command Prompt (NOT in a batch file). How do I echo the text a %pathext% b; %pathext% expands to the environment variable; ^, %, \ and "quotes" all do not work. Please base the answer on: echo a %pathext% b.
Many thanks in advance.
There is one simple solution, but it's not 100% bullet proof
echo a %path^ext% b
The position of the caret can be moved to any position.
This works, because the variable expansion on the command line works different than in batch files.
If an undefined variable should be expanded, in a batch file it results in an empty text, but on the cli the percent expression will be used unchaged.
The caret will be removed in a later step of the parser.
But it can still fail when there exists a variable named path^ext
For a bullet proof solution, you need to create a percent sign and expand it.
for /F "delims==" %# in ("%=%=") do echo a %#pathext%# b
echo a %^pathext% b
Use a caret inside the variable (it can be anywhere inside the % signs) to prevent the parser from recognizing and substituting the variable.

Batch script interpreting content inside comment?

When I run the following batch script:
#echo off
REM %~ will strip surrounding quotes if any
echo HERE
I get the following error:
C:\>test.cmd
The following usage of the path operator in batch-parameter
substitution is invalid: %~ will strip surrounding quotes if any
For valid formats type CALL /? or FOR /?
Same effect if REM is changed to ::.
Seems like the parser is ignoring the comment indicator and parsing the %~. If I put a space between the % and ~ then it works fine.
Windows 7 Enterprise (have not checked any other versions).
Seems like a bug to me, but am I missing something?
The %-expansion, hence expanding normal environment variables (like %VAR%) as well as command line arguments (like %0), is the very first step after having read a line, therefore it happens even before the rem command is recognised. Thus you need to avoid the %~ (by writing rem % + ~ ..., for instance).
Given that the command extensions are enabled, which is the default anyway, %~ is recognised as invalid argument syntax (the ~ is expected to be followed by a decimal digit denoting the argument position or by a valid modifier like f, d, p, n, x, etc.; see Command Line arguments (Parameters)) and results in a fatal error, meaning that an error message is thrown and batch file processing is aborted (the %ErrorLevel% is not set though).
The same effect comes up when you try to do sub-string substitution but specifying an empty search string (like %VAR:=replace% or %VAR:*=replace%, given that VAR is defined), also with command extensions enabled.
See also this thread: How does the Windows Command Interpreter (CMD.EXE) parse scripts?
I think it is clearly covered in quite a few docs that cmd will interpret the arguments before comments, see the example in #LotPings comment as well as #aschiphl's post. That being said, you can momentarily disableextensions and then turn it back on when needed. The below example shows how disabling it will allow you to use it in the REM comment and then enabled again after to show allow extensions:
#echo off
setlocal disableextensions
REM %~ will strip surrounding quotes if any"
endlocal
echo my batch file is %~0

Use an environment variable in a windows cmd file as substring length parameter

I need to output the first X characters of the content of OLD_ENTRY, say 33 chars. I grab the number of chars with another script. What is, in the following command in a Windows cmd script, the correct syntax to use a variable, say POS, instead of the hardcoded value 33?
echo %OLD_ENTRY:~0,33%
Thanks for any help,
Rip
Alright, I tend to call something like this as "nested variables". Anyway, to expand such nested variables, you need to establish a second parsing or expansion phase, and you need to ensure that the inner variable (POS) becomes expanded first, and the outer one (OLD_ENTRY) becomes expanded during the second phase. There are some options:
Using call:
This option avoids delayed variable expansion, which could be problematic with literal ! symbols, but it is quite slow, and it doubles quoted ^ characters:
In command prompt window:
call echo %^OLD_ENTRY:~0,%POS%%
This looks like "escaping" (^) the outer variable, but actually, this has got nothing to do with true escaping. In command prompt, an undefined variable does not become replaced by an empty string, it is just kept literally. So in the first pass, the undefined variable ^OLD_ENTRY is simply kept (you can verify that by defining such a variable by set "^OLD_ENTRY=something"), scanning for the closing % is skipped after the : for undefined variables strangely, the variable %POS% becomes expanded, and the last (orphaned) % is kept too; immediately after this phase, the escape sequence ^O is recognised, which results in a literal O; so we get echo %OLD_ENTRY:~0,33%, which becomes expanded in the second pass.
In a batch file:
call echo %%OLD_ENTRY:~0,%POS%%%
In the first pass, the first two consecutive percent symbols become replaced by one literal % sign, the variable %POS% becomes expanded, and the remaining two consecutive percent symbols become replaced by one literal % sign too, so we have echo %OLD_ENTRY:~0,33%, which becomes expanded in the second pass.
Using delayed variable expansion:
This is the better option, I think, because it is faster and does not mess around with ^:
echo !OLD_ENTRY:~0,%POS%!
This option works in both command prompt window and batch files. Here the first pass is the normal/immediate expanssion (%) which handles the %POS% variable, so the second pass the delayed expansion (!) receives echo !OLD_ENTRY:~0,33! to expand.
Refer also to this post: How does the Windows Command Interpreter (CMD.EXE) parse scripts?

How to reliably use `rem` within a command line without ignoring adjacent commands?

I am trying to use the rem command to place a remark in a command line that contains several commands. Here are some examples to illustrate what I mean:
echo Hello & rem.Comment & echo world!
(echo Hello & rem.Comment) & echo world!
This works perfectly fine, both echo commands in each line are executed as I expect. The . seems to modify the behaviour of the rem command so that it does not treat the remaining line as comment:
Hello
world!
If I placed a SPACE (or any other delimiter TAB, ,, ;, =) instead of the ., the remaining line and therefore the second echo would be ignored (for the second example a More? prompt appears, because the ) is part of the remark and cmd expects a closing ) because of the ():
Hello
I found out that beside ., the following characters work as well: :, /, \, [, ] and +.
What else works is escaped delimiters: ^SPACE, ^TAB, ^,, ^; and ^=.
Nevertheless, is there a secure and reliable way to do that?
I would be very glad about a solution that works for both command prompt and batch-files.
According to this external reference, the familiar syntax echo. for returning a blank line fails under certain circumstances, hence using echo( is recommended as this is the only reliable method.
However, for rem, the ( does not work, everything after rem( is not recognised as a command.
Since I am aware of a weird bug of the rem command in Windows XP (reference this external link: rem %~), I am interested in a solution that applies to Windows Vista, Windows 7 or higher.
The "weird" REM %~ "bug" is not limited to XP. It is present in all modern versions of Windows that use CMD.EXE. After reading your question, I wrote Simon of SS64 a note to give clarification on the issue. REM can also fail if variable var exists, and you have rem %var:=.
So technically, there is no guaranteed safe way to blindly use REM.
But, if you are willing to accept the fatal % expansion risk, most of your listed hacks are safe to use, but only if the line includes at least one additional command via & or &&.
REM. is never safe to use in any situation if there exists a file named REM (without extension).
The folder dividers \ and / always fail if the current folder contains a file named test.bat and you use REM\..\test.bat.
In a similar fashion, REM:\..\test.bat always fails.
Every one of the other hacks can fail stand-alone in a similar situation. For example, REM^[tab]\..\test.bat fails stand-alone, but works if concatenated with another command. This is the only type of situation I've found where +, [, ], or ^[tab] can fail.
There are additional cases where some of the other hacks can fail.
Any character in the set C (^[space], ^,, ^;, ^=) that are valid in file names can fail stand-alone if remC.bat exists. For example, the following fails stand-alone:
rem^ Fails if "rem .bat" exists
Yet they are all safe when concatenated with another command:
echo OK&rem^ This is safe
rem^ This is safe &echo OK
Temporary Update
Some of the above is wrong. Investigations are ongoing at http://www.dostips.com/forum/viewtopic.php?f=3&t=6895&p=44813#p44813.
I believe the following are the simplest forms that are guaranteed to work in all cases (disregarding invalid % expansion)
REM: At least one space (or other token delimiter) must be after :
REM\ At least one space (or other token delimiter) must be after \
REM/ At least one space (or other token delimiter) must be after /
REM^[tab] At lease one space (or other token delimiter) must be after [tab]
But I won't correct the earlier info until the dust has settled
End Temporary Update
My favorite way to use inline comments is to use impossible variables. Only dynamic pseudo variables can contain = in a name, and no variable name can ever contain two =. So I like to use %= Remark goes here =%. The beauty of this form is it can be used pretty much anywhere with impunity, as long as the comment does not contain % or :. It can even be used safely within parenthesized blocks of code.
for %%F in (*) do (
%= Comment within code block =%
%= 2nd comment within code block =%
FINDSTR /B %=Must match beginning of line=% "string" %= Search string =% "%%F" %= File to search =%
)
This variants of REM seems to be a safe way to enable the & sign in the comment part.
REM/
REM\
REM:
Despite of #dbenham's comment, I can't create any file which would iterfere with these REM variants (I tried REM.bat, REM;.bat and so on).
It's always a good idea to add a space after the REM^<char>.
The problem with %~ can't be solved, as the cmd.exe uses multiple parser phases for each line.
And the %~ error is detected in an early phase (percent expansion phase), just before the phase where a REM would be detected.
But at all, I prefere percent comments for inline comments, described by dbenham
EDIT:
I removed the carets from REM^<char> as it's doesn't matter.
Normally a REM remarks the rest of the line, as the batch parser detects the REM keyword in phase2 of the parser and switches to a specialized parser only for REM.
But when a character is appended to REM the keyword will nt be detected in phase2.
If the character is one of \/;,=+( the parser will remove it later and executes a normal REM command.
That's the cause why the command operators &, &&, |, || can be recognized in this case.
Why rem/ | break fails, but (REM/) | break works?
It's because the pipe starts two seperate cmd child processes.
With surrounding parenthesis the command will be parsed the first time in the child process.
But without parenthesis, the parent process has already parsed the REM/ and checks if the file exists (but doesn't execute it).
But when such a file exists then the parser is smart enough to remove the seperator character and detects that REM is an internal command.
This behaviour looks a bit strange.

Echo misses ^ characters when long string

I have the following command in a windows batch script
echo =%%k-16,INDIRECT.EXT^("'C:\Users\...\Analysis\[ObsStreamflow.xlsx]Sheet1'^!A%%k"^),INDIRECT.EXT^("'C:\Users\...\Analysis\[sim%%j.xlsx]Sheet1'^!B!val!"^),^=C%%k/1000,^=D%%k-B%%k,^=ABS^(E%%k^),^=(E%%k^)^^2,=^(B%%k-B10^),=Sqrt^(B%%k^),=SQRT^(D%%k^),=^(J%%k - B13^)^^2 >>t%%j.csv
where the omitted file path is 38 characters long (I don't think I'm hitting the line limits, but just in case this is the problem). This is a single line in my .bat file, shown here as multiple lines just to make things more readable.
The output is mostly correct, except that where I have ^^2, it just becomes 2 (so I have =(E1)2 and =(J1-B13)2. If I omit the Indirect.Ext text, and just have
echo =%%k-16,a1,b1,^=C%%k/1000,^=D%%k-B%%k,^=ABS^(E%%k^),^=(E%%k^)^^2,=^(B%%k-B10^),=Sqrt^(B%%k^),=SQRT^(D%%k^),=^(J%%k - B13^)^^2 >>t%%j.csv
it prints correctly, so the relevant comments show as =(E1)^2 and =(J1-B13)^2, which is what I am after.
I've not had any luck finding an answer, everything I have found just points to using ^^ to get echo to return ^. I cannot break this command into multiple lines, I need it to be a single row in csv format.
Any suggestions for a fix much appreciated, I only really need to use this for a week or so, don't need an elegant solution, just one that works. - I'm very new to bat scripts (and indeed programming in general), will keep trying different ideas in the mean time.
It's only the exclamation mark that creates the problems for you.
If at least one ! is in your line (and delayed expansion is enabled), then a second caret escape phase will be started.
In this phase quotes aren't regarded, only carets.
A small test
setlocal EnableDelayedExpansion
echo one^1
echo two^^2
echo two^^2 With exclam!
echo five^^^^^& With exclam!
Output
one1
two^2
two2 With exclam
four^& With exclam
So in your sample, you need five carets.
Four to create one caret and the last one to escape the ), as the escape of the special character is only once required.
Not sure what your specific problem is but you can use a trick in Windows to emulate echo -n (echo without a newline).
The commands:
<nul: >file.csv set /p junk=first field
<nul: >>file.csv set /p junk=,second field
>>file.csv echo ,third field
will result in a single line:
first field,second field,third field
That may make it easier for you to avoid the specific problem and, as a bonus, clean up your script so it's a little more readable (such as one field per script line).
It works because set /p var=prompt is the input command. It first outputs prompt without a newline then waits for the user to enter something, assigning it to the var environment variable.
By getting input from nul:, you basically give it an empty string so it doesn't wait. The prompt is output to file.csv without the newline.
In any case, for something this complex, I'd be bypassing cmd.exe for something a little more powerful such as the UNIX text processing tools under CygWin or MinGW (which require installation but are well worth it), or even VBScript scripts (which should be on Windows by default), where you can more easily control the output.

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