I have an application.property like this:
somevalue.api.test=something
somevalue.anotherproperty=stuff
I have made a configuration bean like this:
#Configuration
#ConfigurationProperties("somevalue")
public class SomeProperties {
#NotNull
private String apiTest;
#NotNull
private String anotherproperty;
}
Is it possible to refer to api.test like apiTest?
Mainly my issue is that I want to use the somevalue starting point for both property. I know if I don't separate with a dot the apiTest and I use it in this way somevalue.api-test I can refer to that with apiTest in my bean, but in my case it's not possible the renaming. So with dot separation can I achieve the same result or I should create two separate config bean, one refering to somevalue.api and the another only to somevalue?
If you can't rename the property then no, you can't reference it using String apiTest. You need an additional class as follows:
#Configuration
#ConfigurationProperties("somevalue")
public class GcssProperties {
#NotNull
private GcssApiProperties api;
#NotNull
private String anotherproperty;
}
public class GcssApiProperties {
#NotNull
private String test;
}
This should work.
Related
Let me explain a problem. Suppose I have an entity class User:
public class User {
private UUID id;
private String login;
private String password;
private String firstName;
private String lastName;
private String email;
private int age;
// ... more fields and default getters and setters
}
In addition, I have two DTO classes:
public class UserLogin {
private UUID id;
private String login;
// ... getters and setters
}
public class UserLoginEmail {
private UUID id;
private String login;
private String email;
// ... getters and setters
}
Let's take a look to class UserController that has UserLoginEmail as request body and UserLogin as response body:
#RestController("/users")
public class UserController {
#PutMapping
public UserLogin someRequest(UserLoginEmail user) {
// ...
}
}
What is the best way to create some kind of projections in Spring Boot? Can I create an interface with required fields and just put them in the Java method as parameters (or some other way)? I want to build DTO classes with the least effort and agile in my code.
You could use JSON Views with Jackson with which you could define different views on a per endpoint basis (check https://www.baeldung.com/jackson-json-view-annotation for more details).
But in your case, I wouldn't do that. One of your DTOs is a request and the other is a response so you shouldn't mix them together in a single DTO. Even more than that, I don't really like JSON Views because they are simply hard to follow and the code becomes harder to read. Abstractions and code reusability are usually good but it makes the code much harder to read and for the case of DTOs I much more prefer to be explicit and have multiple DTOs even that they are similar. With this approach, you will make it possible to easily change one of the DTOs without affecting anything else, which is not the case when you reuse them in any way.
Having said that, keep both DTOs, but I would rename them: UserLoginRequest and UserLoginResponse.
I am using Spring Data's Rest Repositories from spring-boot-starter-data-rest, with Couchbase being used as the underlining DBMS.
My Pojo for the object is setup as so.
#Document
public class Item{
#Id #GeneratedValue(strategy = UNIQUE)
private String id;
#NotNull
private String name;
//other items and getters and setters here
}
And say the Item has an id of "xxx-xxx-xxx-xxx" and name of "testItem".
Problem is, that when I want to access the item, I need to be accessible by /items/testItem, but instead it is accessible by /items/xxx-xxx-xxx-xxx.
How do I get use its name instead of its generated id, to get the data.
I found out the answer to my own question.
I just need to override the config for the EntityLookup.
#Component
public class SpringDataRestCustomization extends RepositoryRestConfigurerAdapter {
#Override
public void configureRepositoryRestConfiguration(RepositoryRestConfiguration config) {
config.withEntityLookup().forRepository(UserRepository.class).
withIdMapping(User::getUsername).
withLookup(UserRepository::findByUsername);
}
}
Found the info here, though the method name changed slightly.
https://github.com/spring-projects/spring-data-examples/tree/master/rest/uri-customization
If you want query the item by name and want it perform as querying by id,you should make sure the name is unique too.You cant identify a explicit object by name if all objects have a same name,right?
With jpa you could do it like:
#NotNull
#Column(name="name",nullable=false,unique=true)
private String name;
I needed a RoleMappingService class(which is annotated by #Service) object into a Employee class (which is annotated by #Entity)
below are my classes
********************* RoleMappingsService class **********************
#Service
public class RoleMappingsService {
#Autowired
RolesMappingDao rolesMappingDao;
public List<RolesMappings> getRolesMappingByauthSystemRole(String authSystemRole) {
return rolesMappingDao.getRolesMappingByauthSystemRole(authSystemRole);
}
}
############### Employee class
#Configurable
#Component
#Entity
#NamedQuery(name = "Employee.findAll", query = "SELECT e FROM Employee e")
public class Employee implements Serializable, UserDetails {
#Autowired
#Transient
RoleMappingsService roleMappingsService;
public static final String STATUS_ACTIVE = "ACTIVE";
public static final String STATUS_INACTIVE = "INACTIVE";
public static final String STATUS_LOCKED = "LOCKED";
public static final String STATUS_ONLEAVE = "ONLEAVE";
public static final String STATUS_EXPIRED = "EXPIRED";
private static final long serialVersionUID = 1L;
#Id
#Column(name = "emp_id")
private String empId;
#Column(name = "emp_password")
private String empPassword;
#Column(name = "emp_email")
private String empEmail;
#Column(name = "emp_address")
private String empAddress;
#Column(name = "emp_age")
private int empAge;
#Column(name = "emp_firstname")
private String empFirstname;
}
Here Autowire is not working for roleMappingsService and the object is always found null. However I tried to autowire same object in some other service and there Autowire is perfectly working.
( I know Entity class is only used for representing database table but in my case I need to set some field values which depend on another table so need to fetch data using service)
JB Nizet is totally right
I'll try to provide more explanations here.
Spring can Autowire only beans, objects that it manages, and not arbitrary objects.
Entities are usually created from within a JPA (Hibernate) and are not something that you want to manage by Spring.
There is a related discussion available here but bottom line you should never do something like this.
Why not?
Here are a couple of questions/reasons:
Maybe these entities will go outside spring context at all (serialization), what should that reference contain? Should we also serialize the service? How?
What will happen if the method that turns to the service will be called "outside" the spring driven application (maybe even in different JVM)?
If there are, say 1000 objects returned by that query, do you really want all of them to reside in application context? Or maybe should they be of "prototype" scope?
As you see, it doesn't play nice with spring concepts. I think the reason for it is that Hibernate and JPA do not "support" an idea of methods inside entities, it's just a different framework. I know there are other frameworks that do allow such a concept, but Hibernate/JPA just doesn't, period
So instead of trying to inject the service into the entity bean, probably you should redesign the application so that the service method will be called from outside, maybe via some facade, and entities will be just populated by query, and then "enriched" with additional information if we're talking about SELECT queries, or, alternatively, some information should be pre-set on entity objects, generated by the Business Logic Layer and only then the entity object should be stored in DB
I have a spring-boot application (1.4RC1, I know it's RC, but Spring Data Redis 1.7.2 is not) where I'm using spring-boot-starter-redis.
The application uses a Spring Data Repository (CrudRepository) which should save an object (using #RedisHash annotation) with String and Boolean properties and one custom class property, which also has only Strings and Longs as properties.
When I save an object (via the repository), everything went fine and I can see all the properties in the database as I would expect.
When I want to read the data from the database (via the repository) I only get the properties from the parent object. The custom class property is null.
I would expect to get the property loaded from the database as well. As the documentation states you can write a custom converter, but since I don't need to do that, when I want to write the data, I shouldn't need to write a reading converter as well.
I wonder if I need to annotate the custom class property, but I couldn't find anything in the documentation. Can you point me in the right direction?
The classes are as follows:
Class sample:
#Data
#EqualsAndHashCode(exclude = {"isActive", "sampleCreated", "sampleConfiguration"})
#RedisHash
public class Sample {
#Id
private String sampleIdentifier;
private Boolean isActive;
private Date sampleCreated;
private SampleConfiguration sampleConfiguration;
public Sample(String sampleIdentifier, SampleConfiguration sampleConfiguration){
this.sampleIdentifier = sampleIdentifier;
this.sampleConfiguration = sampleConfiguration;
}
}
Class SampleConfiguration:
#Data
public class SampleConfiguration {
private String surveyURL;
private Long blockingTime;
private String invitationTitle;
private String invitationText;
private String participateButtonText;
private String doNotParticipateButtonText;
private String optOutButtonText;
private Long frequencyCappingThreshold;
private Long optOutBlockingTime;
}
I added #NoArgsConstructor to my Sample class as Christoph Strobl suggested. Then the repository reads the SampleConfiguration correctly. Thanks, Christoph!
In a Spring bean, I need to process a configuration property before using is, e.g.:
#Component
class UsersController {
#Value("${roles}")
private String rolesAsString;
private List<String> roles;
#PostConstruct
public void initRoles() {
// just an example, not necessarily string splitting
roles = rolesAsString.split(",");
}
This works, but I am left with an unneeded member variable 'rolesString'. What would be a clean concise way to only keep the processed value?
Properties is
roles=role1,role2,role3
Code is :
#Value("#{'${roles}'.split(',')}")
private List<String> roles;