Can #yield() and #section() be used with #include() files? - laravel

I have 3 views:
post/index.blade.php
post/container.blade.php
layouts/app.blade.php
Index view #expands('layout.app') and also #include('container'). The Idea behind the container is to use the same structure to show posts in different views. But the thing is that container.blade.php is not going to be 100% the same on each view. So I thought maybe I can add an #yield('append') on the container.blade.php so that way I could add more on that post container, using #section(). Like this:
inside the index.blade.php
#extends('layouts.app')
#section('content')
#include('post.container')
#section('append')
<p>This is not being outputted correctly.</p>
#endsection
#endsection
This #section('append') belongs to, or actually matches the #yield('append') on the container.blade.php. The question is how can this be done? How to add #section('') that should belong to #include() files in this case container.blade.php?

You can pass data to the #Include
#php $data=[
'title' => "test title",
'description' => ""
] #endphp
#extends('layouts.app')
#section('content')
#include('post.container', $data)
#endsection

Related

How can i send array of data from laravel blade to controller

I have created a form and I used alpine js to add something to the array data, but I don't know how to pass it to the controller as a post method
It is super important that you read the official Laravel documentation, you are not a magician, so you must get this knowledge from somewhere.
You are not sharing a controller code, so I will assume you have this one:
Route::get('/', function () {
return view('greeting', ['name' => 'James']);
});
If you have this on your view, it will render that name:
<html>
<body>
<h1>Hello, {{ $name }}</h1>
</body>
</html>

How can I prevent multiple includes of the same view by developing component views with Laravel Blade?

I have a blog that shows 25 posts on the home page. Each post is displayed as a "block", with a dedicated "component" view being included 25 times. In this view there are 5 more inclusions (partials) leading to a total of 125 filesystem calls. I don't like this.
Code to understand better:
// home.blade.php
#foreach($posts as $post)
#include('components.post', ['post' => $post])
#endforeach
// components/post.blade.php
<div class="card">
#include('components.post.partials.category')
#include('components.post.partials.header')
#include('components.post.partials.content')
#include('components.post.partials.tags')
#include('components.post.partials.share')
</div>
What is the best practice for handling this situation? I was not been able to find information about it although it is a common operation...

Collect multiple files into single PDF

I use in my project barryvdh laravel-dompdf package.
Users might generate a PDF with some personal information, till here everything is ok:
$pdf = PDF::loadView('personalInfo', $userData);
$pdfFileName = "personal-info-{$userData['username']}.pdf";
return $pdf->download($pdfFileName);
Admin should be able to download information of users, and in case of selecting several users, instead of generating several files I would like to collect all users PDFs into a single file.
How can I do it?
You can create like this below
For example you have personalInfo blade template which is now for particular user .So loop that view and store it in array like below
$pages=[];
foreach($userDataList as $key=>$userData){
$pages[]=(string)view('personalInfo', $userData);
}
$pdf = App::make('dompdf.wrapper');
$pdf->loadView('index', ['pages' => $pages]);
return $pdf->stream();
then you can create seperate blade template to show these views.Here i will name it as index.blade.php
<style type="text/css" media="print">
div.page
{
page-break-after: always;
page-break-inside: avoid;
}
</style>
#foreach($pages as $page)
<div class="page">
{!! html_entity_decode($page) !!}
</div>
#endforeach
Method:2
loop all user detail inside personalInfo blade template and at the end of each loop add below page break style
<p style="page-break-before: always;"></p>
Example inside personalinfo blade
#foreach($pages as $page)
personal information content
<p style="page-break-before: always;"></p>
#endforeach
Also i personally prefer laravel snappy for multiple page because it render faster than laravel dompdf.Only thing is to server configuration bit head ache if you are using windows
Ref:https://github.com/barryvdh/laravel-snappy

laravel blade append to #section in #forelse

My main template blade has a #yield('section_name') in the <head> tag to append css/ js.
Now I have a forelse like this:
#forelse($collection as $item)
some text
#section('section_name')
// link to stylesheet
#endsection
#empty
// something went wrong
#endforelse
When this loops for like 5 times, only one stylesheet is added. After that, it seems like the #yield is not working anymore. Is there a way to make this work so I can keep appending items to that section?
Use #append instead of #endsection
#forelse($collection as $item)
some text
#section('section_name')
// link to stylesheet
#append
#empty
// something went wrong
#endforelse

Laravel Sub-menu Within View

Hi I am very new to Laravel and MVC frameworks in general and am looking to create a list of links (in a view within a template) that links to some content. I am using this to display a list of nine people and to display their profile description when the link is clicked on. I have created a model of what the page looks like at http://i.imgur.com/8XhI2Ba.png. The portion that I am concerned with is in blue. Is there a way to route these links to something like /about/link2 or /about?link2 while maintaining the same exact page structure but modifying the ‘link content’ section (on the right of the link menu) to show the specific link's content? I would greatly appreciate it if someone could point me in the right direction, as I have literally no clue where to go with this!
There are a couple ways you can go about doing this.
Templates
Create your route.
Im assuming a lot about your app here but hopefully you get the picture. If you need help with anything in particular, be sure to update your question with the code youve tried so it will be easier to help you.
Route::get('about/{page}', function($page)
{
$profile = Profile::where('name', $page)->first();
return View::make('about')->with('profile', $profile);
});
Modify Template.blade.php
Put this line where you wish for About.blade.php to appear.
#yield('content')
Create your view which will extend your template
#extends('Template')
#section('content')
<h2>User Profile</h2>
<ul>
<li>Name: {{ $profile->name }}</li>
<li>Last Updated: {{ $profile->updated_at }}</li>
</ul>
#stop
AJAX
This solution will utilize AJAX to grab the data from the server and output it on the page.
Route for initial page view
Route::get('about', function($page)
{
$profiles = Profile::all();
return View::make('about')->with('profiles', $profiles);
});
Feel free to follow the same templating structure as before but this time we need to add some javascript into the template to handle the AJAX. Will also need to id everything which needs to be dynamically set so we can easily set it with jquery.
#extends('Template')
#section('content')
<h2>Links</h2>
#foreach($profiles as $profile)
{{ $profile->name }}
#endforeach
<h2>User Profile</h2>
<ul>
<li>Name: <span id="profile_name">{{ $profile->name }}</span></li>
<li>Last Updated: <span id="profile_updated_at">{{ $profile->updated_at }}</span></li>
</ul>
<script>
function setProfile(a)
{
$.ajax({
method: 'get',
url: 'getProfile',
dataType: 'json',
data: {
profile: $(a).data('id')
},
success: function(profile) {
$('#profile_name').html(profile.name);
$('#profile_updated_at').html(profile.updated_at);
},
error: function() {
alert('Error loading data.');
}
});
}
</script>
#stop
Route to handle the AJAX request
Route::get('getProfile', function()
{
$profile_id = Input::get('profile');
$profile = Profile::find($profile_id);
return $profile->toJson();
});
Now, the page should not have to reload and only the profile information should be updated.
Making some assumptions here as no code posted and assuming you're using the latest version of Laravel, Laravel 5.
Lets say you have a table in your database named users and you have a Model named Users (Laravel 5 comes with the Users model as default, see app/Users.php). The users will be the base of our data for the links.
Firstly, you want to register a route so you can access the page to view some information. You can do this in the routes file. The routes file can be found here: app/Http/routes.php.
To register a route add the following code:
Route::get('users', ['uses' => 'UserController#index']);
Now what this route does is whenever we hit the URL http://your-app-name/public/users (URL might be different depending on how you have your app set up, i.e. you may not have to include public) in our web browser it will respond by running the index method on the UserController.
To respond to that route you can set up your UserController as so:
<?php namespace App\Http\Controllers;
class UserController extends Controller {
public function index()
{
}
}
Controllers should be stored in app/Http/Controllers/.
Now lets flesh out the index method:
public function index()
{
// grab our users
$users = App\Users::all();
// return a view with the users data
return view('users.index')->with('users');
}
This grabs the users from the database and loads up a view passing the users data.
Here's what your view could look like:
<!DOCTYPE html>
<html>
<head>
<title>Users Page</title>
</head>
<body>
#foreach($users as $user)
<a href="{{ URL::route('user', ['id' => $user->id]) }}">
{{ $user->username }}
</a>
#endforeach
</body>
</html>
The view code will loop through each user from the $users data we passed to the view and create a link to their user page which is different for each user based on their id (their unique identifier in the DB)
Due to the way I've named it, this would be found in app/views/users/index.blade.php - if you save files ending in blade.php you can use Laravel's templating language, blade.
Now you need to finally set up another route to respond to a user page, for example http://your-app-name/public/user/22.
Route::get('user/{id}', ['uses' => 'UserController#show']);
Then add the show method to UserController
public function show($id)
{
// this will dump out the user information
return \App\User::find($id);
}
Hope that helps a little! Wrote most of it off the top of my head so let me know if you get any errors via comment.
This question is very bare, and it is difficult to actually help your situation without you showing any code. Just to point you in the right direction though, here is what you would need.
A Model called People, this is how you will access your data.
A controller. In this controller you will do the following
Get the ID of the profile you want from the functions parameters
Find that persons information e.g. People::find($person_id);
return the profile view with that persons data e.g. return view('profile')->with('person', $person);
In your view you can then use that data on that page e.g. {{ $person->name }}
For the page that needs to display the links to the people you would have a method in your controller which..
Get all the people data e.g. People::all();
Return a view with that data return view('all-people')->with('people', $people);
You will then need a route to access an individual person. The route will need to pass the persons ID into a controller method e.g.
Route::get('get-person/{id}',
[ 'as' => 'get-person',
'uses' => 'PeopleController#getPerson' ]);
You can then use this route in your view to get the links to each person
#foreach($people as $person)
{{$person->name}}
#endforeach
This would produce the list of links you want.

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