I have created a form and I used alpine js to add something to the array data, but I don't know how to pass it to the controller as a post method
It is super important that you read the official Laravel documentation, you are not a magician, so you must get this knowledge from somewhere.
You are not sharing a controller code, so I will assume you have this one:
Route::get('/', function () {
return view('greeting', ['name' => 'James']);
});
If you have this on your view, it will render that name:
<html>
<body>
<h1>Hello, {{ $name }}</h1>
</body>
</html>
Related
I'm trying to learn vue and with that I want to integrate it with laravel too..
I simply want to send the user id from blade to vue component so I can perform a put request there.
Let's say I have this in blade:
<example></example>
How can I send Auth::user()->id into this component and use it.
I kept searching for this but couldn't find an answer that will make this clear.
Thanks!
To pass down data to your components you can use props. Find more info about props over here. This is also a good source for defining those props.
You can do something like:
<example :userId="{{ Auth::user()->id }}"></example>
OR
<example v-bind:userId="{{ Auth::user()->id }}"></example>
And then in your Example.vue file you have to define your prop. Then you can access it by this.userId.
Like :
<script>
export default {
props: ['userId'],
mounted () {
// Do something useful with the data in the template
console.dir(this.userId)
}
}
</script>
If you are serving files through Laravel
Then here is the trick that you can apply.
In Your app.blade.php
#if(auth()->check())
<script>
window.User = {!! auth()->user() !!}
</script>
#endif
Now you can access User Object which available globally
Hope this helps.
Calling component,
<example :user-id="{{ Auth::user()->id }}"></example>
In component,
<script>
export default {
props: ['userId'],
mounted () {
console.log(userId)
}
}
</script>
Note - When adding value to prop userId you need to use user-id instead of using camel case.
https://laravel.com/docs/8.x/blade#blade-and-javascript-frameworks
Rendering JSON
Sometimes you may pass an array to your view with the intention of rendering it as JSON in order to initialize a JavaScript variable. For example:
<script>
var app = <?php echo json_encode($array); ?>;
</script>
However, instead of manually calling json_encode, you may use the #json Blade directive. The #json directive accepts the same arguments as PHP's json_encode function. By default, the #json directive calls the json_encode function with the JSON_HEX_TAG, JSON_HEX_APOS, JSON_HEX_AMP, and JSON_HEX_QUOT flags:
<script>
var app = #json($array);
var app = #json($array, JSON_PRETTY_PRINT);
</script>
Just to add for those who still get error.
For me this <askquestionmodal :product="{{ $item->title }}"></askquestionmodal> still gives error in console and instead showing html page I saw white screen.
[Vue warn]: Error compiling template:
invalid expression: Unexpected identifier in
Coupling to connect 2 rods М14 CF-10
Raw expression: :product="Coupling to connect 2 rods М14 CF-10"
Though in error I can see that $item->title is replaced with its value.
So then I tried to do like that <askquestionmodal :product="'{{ $item->title }}'"></askquestionmodal>
And I have fully working code.
/components/askquestionmodal.vue
<template>
<div class="modal-body">
<p>{{ product }}</p>
</div>
</template>
<script>
export default {
name: "AskQuestionModal",
props: ['product'],
mounted() {
console.log('AskQuestionModal component mounted.')
}
}
</script>
Can someone please explain the ajax post method in Laravel 5.3 with a full-working minimum example?
I know there are some resources in the web, but I miss a concise, straight-forward minimum example.
I presume you have a basic understanding of the model-controler-view paradigm, a basic understanding of Laravel and a basic understanding of JavaScript and JQuery (which I will use for reasons of simplicity).
We will create an edit field and a button which posts to the server. (This works for all versions from Laravel 5.0 to 5.6)
1. The Routes
At first you need to add routes to your routes/web.php. Create one route for the view, just as you know from ordinary views:
Route::get('ajax', function(){ return view('ajax'); });
The second route you need to create is the route that handles the ajax post request. Take notice that it is using the post method:
Route::post('/postajax','AjaxController#post');
2. The Controller Function
In the (second) route you created just now, the Controller function post in the AjaxController is called. So create the Controller
php artisan make:controller AjaxController
and in the app/Http/Controllers/AjaxController.php add the function post containing the following lines:
<?php
namespace App\Http\Controllers;
use Illuminate\Http\Request;
class AjaxController extends Controller {
public function post(Request $request){
$response = array(
'status' => 'success',
'msg' => $request->message,
);
return response()->json($response);
}
}
The function is ready to receive data via a Http request and returns a json-formatted response (which consists of the status 'success' and the message the function got from the request).
3. The View
In the first step we defined the route pointing to the view ajax, so now create the view ajax.blade.php.
<!DOCTYPE html>
<html>
<head>
<!-- load jQuery -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<!-- provide the csrf token -->
<meta name="csrf-token" content="{{ csrf_token() }}" />
<script>
$(document).ready(function(){
var CSRF_TOKEN = $('meta[name="csrf-token"]').attr('content');
$(".postbutton").click(function(){
$.ajax({
/* the route pointing to the post function */
url: '/postajax',
type: 'POST',
/* send the csrf-token and the input to the controller */
data: {_token: CSRF_TOKEN, message:$(".getinfo").val()},
dataType: 'JSON',
/* remind that 'data' is the response of the AjaxController */
success: function (data) {
$(".writeinfo").append(data.msg);
}
});
});
});
</script>
</head>
<body>
<input class="getinfo"></input>
<button class="postbutton">Post via ajax!</button>
<div class="writeinfo"></div>
</body>
</html>
If you wonder what's the matter with this csrf-token, read https://laravel.com/docs/5.3/csrf
Hi I am very new to Laravel and MVC frameworks in general and am looking to create a list of links (in a view within a template) that links to some content. I am using this to display a list of nine people and to display their profile description when the link is clicked on. I have created a model of what the page looks like at http://i.imgur.com/8XhI2Ba.png. The portion that I am concerned with is in blue. Is there a way to route these links to something like /about/link2 or /about?link2 while maintaining the same exact page structure but modifying the ‘link content’ section (on the right of the link menu) to show the specific link's content? I would greatly appreciate it if someone could point me in the right direction, as I have literally no clue where to go with this!
There are a couple ways you can go about doing this.
Templates
Create your route.
Im assuming a lot about your app here but hopefully you get the picture. If you need help with anything in particular, be sure to update your question with the code youve tried so it will be easier to help you.
Route::get('about/{page}', function($page)
{
$profile = Profile::where('name', $page)->first();
return View::make('about')->with('profile', $profile);
});
Modify Template.blade.php
Put this line where you wish for About.blade.php to appear.
#yield('content')
Create your view which will extend your template
#extends('Template')
#section('content')
<h2>User Profile</h2>
<ul>
<li>Name: {{ $profile->name }}</li>
<li>Last Updated: {{ $profile->updated_at }}</li>
</ul>
#stop
AJAX
This solution will utilize AJAX to grab the data from the server and output it on the page.
Route for initial page view
Route::get('about', function($page)
{
$profiles = Profile::all();
return View::make('about')->with('profiles', $profiles);
});
Feel free to follow the same templating structure as before but this time we need to add some javascript into the template to handle the AJAX. Will also need to id everything which needs to be dynamically set so we can easily set it with jquery.
#extends('Template')
#section('content')
<h2>Links</h2>
#foreach($profiles as $profile)
{{ $profile->name }}
#endforeach
<h2>User Profile</h2>
<ul>
<li>Name: <span id="profile_name">{{ $profile->name }}</span></li>
<li>Last Updated: <span id="profile_updated_at">{{ $profile->updated_at }}</span></li>
</ul>
<script>
function setProfile(a)
{
$.ajax({
method: 'get',
url: 'getProfile',
dataType: 'json',
data: {
profile: $(a).data('id')
},
success: function(profile) {
$('#profile_name').html(profile.name);
$('#profile_updated_at').html(profile.updated_at);
},
error: function() {
alert('Error loading data.');
}
});
}
</script>
#stop
Route to handle the AJAX request
Route::get('getProfile', function()
{
$profile_id = Input::get('profile');
$profile = Profile::find($profile_id);
return $profile->toJson();
});
Now, the page should not have to reload and only the profile information should be updated.
Making some assumptions here as no code posted and assuming you're using the latest version of Laravel, Laravel 5.
Lets say you have a table in your database named users and you have a Model named Users (Laravel 5 comes with the Users model as default, see app/Users.php). The users will be the base of our data for the links.
Firstly, you want to register a route so you can access the page to view some information. You can do this in the routes file. The routes file can be found here: app/Http/routes.php.
To register a route add the following code:
Route::get('users', ['uses' => 'UserController#index']);
Now what this route does is whenever we hit the URL http://your-app-name/public/users (URL might be different depending on how you have your app set up, i.e. you may not have to include public) in our web browser it will respond by running the index method on the UserController.
To respond to that route you can set up your UserController as so:
<?php namespace App\Http\Controllers;
class UserController extends Controller {
public function index()
{
}
}
Controllers should be stored in app/Http/Controllers/.
Now lets flesh out the index method:
public function index()
{
// grab our users
$users = App\Users::all();
// return a view with the users data
return view('users.index')->with('users');
}
This grabs the users from the database and loads up a view passing the users data.
Here's what your view could look like:
<!DOCTYPE html>
<html>
<head>
<title>Users Page</title>
</head>
<body>
#foreach($users as $user)
<a href="{{ URL::route('user', ['id' => $user->id]) }}">
{{ $user->username }}
</a>
#endforeach
</body>
</html>
The view code will loop through each user from the $users data we passed to the view and create a link to their user page which is different for each user based on their id (their unique identifier in the DB)
Due to the way I've named it, this would be found in app/views/users/index.blade.php - if you save files ending in blade.php you can use Laravel's templating language, blade.
Now you need to finally set up another route to respond to a user page, for example http://your-app-name/public/user/22.
Route::get('user/{id}', ['uses' => 'UserController#show']);
Then add the show method to UserController
public function show($id)
{
// this will dump out the user information
return \App\User::find($id);
}
Hope that helps a little! Wrote most of it off the top of my head so let me know if you get any errors via comment.
This question is very bare, and it is difficult to actually help your situation without you showing any code. Just to point you in the right direction though, here is what you would need.
A Model called People, this is how you will access your data.
A controller. In this controller you will do the following
Get the ID of the profile you want from the functions parameters
Find that persons information e.g. People::find($person_id);
return the profile view with that persons data e.g. return view('profile')->with('person', $person);
In your view you can then use that data on that page e.g. {{ $person->name }}
For the page that needs to display the links to the people you would have a method in your controller which..
Get all the people data e.g. People::all();
Return a view with that data return view('all-people')->with('people', $people);
You will then need a route to access an individual person. The route will need to pass the persons ID into a controller method e.g.
Route::get('get-person/{id}',
[ 'as' => 'get-person',
'uses' => 'PeopleController#getPerson' ]);
You can then use this route in your view to get the links to each person
#foreach($people as $person)
{{$person->name}}
#endforeach
This would produce the list of links you want.
I am totally new to laravel, I am now want to use laravel 4.
Suppose I have a page A.php, and it contains a form & a submit button. After I submit the post request to B.php, and in B.php I query data from database.
My question is I want to show my result on B.php , that it is to say the same page of A.php request, how do I write in routes.php.
My code:
master.blade.php
<!DOCTYPE HTML>
<html>
<head>
<metacharset="UTF-8">
<title>course query</title>
</head>
<body>
<div class="container">
#yield('container')
</div>
<h1 class="ret">The result is:
#yield('ret')
<input id="result" type="text"/>
</h1>
</body>
</html>
A.php
#extends('course.master')
#section('container')
<h1>My Courses</h1>
{{Form::open(array('url' => 'csOp'))}}
{{Form::label('course', 'Your course')}}
{{Form::text('course')}}
{{Form::submit('Submit')}}
{{Form::close()}}
#endsection
routes.php
Route::get('course', function(){
return View::make('course.B');
});
Route::post('csOp', function(){
// do something
//$inputCourse = Input::get('course');
//$records = Courses::where('name', '=', $inputCourse)->get();
// how do I return
//return View::make('csOp', $records);
});
As you can see, in A.php I have a form and request to csOp
Form::open(array('url' => 'csOp')
csOp is B.php, and in B.php I query data from db, and now I got the results,
but how can I put result to the page (B.php) itself? That it is to say I want to put the result to
<input id="result" type="text"/>
You know in jquery is easy, how do I use it in laravel 4 ?
And if return to csOp, absolutlly will get an error, it is in a circle. So how can I solve it ?
Thanks very much.
If you want to populate a form based on model contents, i,e. populate form using database data.
So in laravel you can use Form Model Binding. To do so, use the Form::model method. so in your case
Route::post('csOp', function(){
// do something
$inputCourse = Input::get('course');
$records = Courses::where('name', '=', $inputCourse)->get();
// how do I return
return View::make('csOp')->with('records',$records);
});
And your csOp.blade.php
#extends('course.master')
#section('container')
<h1>My Courses</h1>
{{Form::model($records,array('url' => 'csOp'))}}
{{Form::label('course', 'Your course')}}
{{Form::text('course')}}
{{Form::close()}}
#endsection
Now, when you generate a form element, like a text input, the model's value matching the field's name will automatically be set as the field value. So, for example, for a text input named course, the Courses model's course attribute would be set as the value.
I am using a fresh build today of Laravel 4.
I have a dashboardController
class DashboardController extends BaseController {
protected $layout = 'layouts.dashboard';
public function index()
{
$this->layout->content = View::make('dashboard.default');
}
}
I have a simple route
Route::get('/', 'DashboardController#index');
I have a blade layout in views/layouts/dashboard.blade.php
For the sake of saving everyone from all of the actual HTML ill use a mock up.
<html>
<head>
<title></title>
</head>
<body>
#yield('content')
</body>
</html>
I have a default blade file in views/dashboard/ that has the following (edited for simplicity)
#section('content')
<p>This is not rocket science</p>
#stop
For some reason the content gets generated before the layout.
I am using a different approach to set the layouts globally to routes using a custom filter. Put the following filter into the app/filters.php
Route::filter('theme', function($route, $request, $response, $layout='layouts.default')
{
// Redirects have no content and errors should handle their own layout.
if ($response->getStatusCode() > 300) return;
//get original view object
$view = $response->getOriginalContent();
//we will render the view nested to the layout
$content = View::make($layout)->nest('_content',$view->getName(), $view->getData())->render();
$response->setContent($content);
});
and now instead of setting layout property in the controller class, you can group the routes and apply the filter as shown below.
Route::group(array('after' => 'theme:layouts.dashboard'), function()
{
Route::get('/admin', 'DashboardController#getIndex');
Route::get('/admin/dashboard', function(){ return View::make('dashboard.default'); });
});
When creating the views, make sure to use the #section('sectionName') in all the sub views and use #yield('sectionName') in the layout views.
I find it easier to do my layout like this for example. I would create my master blade file like so
<html>
<body>
#yield('content');
</body>
</html
And in the blade files that I want to use the master at the top i would put
#extends('master')
then content like so
#section('content')
// content
#stop
Hope this helps.
When you use controller layouts, i.e. $this->layout->..., then you get access to data as variables, not sections. So to access content in your layout you should use...
<html>
<head>
<title></title>
</head>
<body>
<?php echo $content; ?>
</body>
</html>
And in your partial, you would not use #section or #stop...
<p>This is not rocket science</p>