I have a apparmor's raw_data file in linux. When open it using the 010editor, some of the content is compressed. How to parse it into a complete policy file which human can read?
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I have a xamarin application and its files are compressed using lz4 I could easily decompress the files it using lz4.block.decompress but I couldn't compress it again, can anyone help me with that?
I used the following script to decompress the file and I could read the content of the DLL file but when I modified something and try to recompress it again to patch the APK file I couldn't compress the file in the right format.
with open(input_filepath, "rb") as xalz_file:
data = xalz_file
header = data.read(8)
if header[:4] != b"XALZ":
sys.exit("The input file does not contain the expected magic bytes, aborting ...")
payload = data.read()
decompressed = lz4.block.decompress(payload)
with open(output_filepath, "wb") as output_file:
output_file.write(decompressed)
output_file.close()
print("result written to file")
Note that I couldn't decompress or compress the DLL file using lz4tools.
What is a .rl0 file format and how to access its data?
I have been searching for RL0 file format but what I get is r10 and rlo file format and I am unable to get the data inside the file.
How to get the data inside the file?
It is in hex format you can use the following code.
import binascii
with open (final_name, "rb") as myfile:
header=myfile.read()
header = str(binascii.hexlify(header))[2:-1]
print(header)
I am trying to decompress a file with following Ruby code.
File.open("file_compressed.gz") do |compressed|
File.open("file_decomp","w") do |decompressed|
gz = Zlib::GzipReader.new(compressed)
result = gz.read
decompressed.write(result)
gz.close
end
end
But I am getting following error -
not in gzip format (Zlib::GzipFile::Error)
./features/support/abc/abc_file.rb:44:in `initialize'
When I decompress the same file using gzip command on Mac it produced the correct uncompressed output.
For following command I can see -
$file file_compressed.gz
file_compressed.gz: gzip compressed data, from FAT filesystem (MS-DOS, OS/2, NT)
Do I need to put any header data while I create the compressed file with Zlib? Because when I use the inflate method instead of the GzipReader I get following error -
incorrect header check (Zlib::DataError)
./features/support/abc/abc_file.rb:69:in `inflate'
If you're on a platform that doesn't use LF delimiters, but CR+LF, you may need to open the file in binary mode for reading:
File.open("file_compressed.gz", "rb") do |compressed|
# ...
end
This should also avoid interpreting the input stream as anything but 8-bit binary.
Be sure to open your output file the same way using "wb" as the flag.
I wrote a Logparser Application and now I want to implement decompression of .gz files. I tried it with boost::iostreams and zlib which seems to work, but I don't know how to handle the input I get from compressed files.
Here's what I do:
input.open(p.source_at(i).c_str(), ios_base::in | ios_base::binary);
boost::iostreams::filtering_streambuf<boost::iostreams::input> in;
in.push(boost::iostreams::gzip_decompressor());
in.push(input);
boost::iostreams::copy(in, cout);
This code is run, if my sourcefile has the .gz ending. The last line outputs the decompressed filestream correctly to cout.
But how can i fetch line by line from the decompressed file? My Program uses getline(input, transfer) to read lines from the input stream, if it's not compressed.
Now I want to read from the decompressed file the same way, but how can I get a new line from in?
The boost decumentation didn't help me much with this.
Thanks in advance!
Ok I found it out. I just had to create an std::istream and pass a reference to the buffer:
std::istream incoming(&in);
getline(incoming, transfer);
Is it possible to list the contents of a LZMA file (.7zip) without uncompressing the whole file? Also, can I extract a single file from the LZMA file?
My problem: I have a 30GB .7z file that uncompresses to >5TB. I would like to manipulate the original .7z file without needing to do a full uncompress.
Yes. Start with XZ Utils. There are Perl and Python APIs.
You can find the file you want from the headers. Each file is compressed separately, so you can extract just the one you want.
Download lzma922.tar.bz2 from the LZMA SDK files page on Sourceforge, then extract the files and open up C/Util/7z/7zMain.c. There, you will find routines to extract a specific archive file from a .7z archive. You don't need to extract all the data from all the entries, the example code shows how to extract just the one you are interested in. This same code has logic to list the entries without extracting all the compressed data.
I solved this problem by installing 7zip (https://www.7-zip.org/) and using the parameter l. For example:
7z l file.7z
The output has some descriptive information and the list of files in the compressed files. Then, I call this inside python using the subprocess library:
import subprocess
output = subprocess.Popen(["7z","l", "file.7z"], stdout=subprocess.PIPE)
output = output.stdout.read().decode("utf-8")
Don't forget to make sure the program 7z is accessible in your PATH variable. I had to do this manually in Windows.