In Oracle SQL Developer, if I'm viewing the information on a table, I can view the constraints, which let me see the foreign keys (and thus which tables are referenced by this table), and I can view the dependencies to see what packages and such reference the table. But I'm not sure how to find which tables reference the table.
For example, say I'm looking at the emp table. There is another table emp_dept which captures which employees work in which departments, which references the emp table through emp_id, the primary key of the emp table. Is there a way (through some UI element in the program, not through SQL) to find that the emp_dept table references the emp table, without me having to know that the emp_dept table exists?
No. There is no such option available from Oracle SQL Developer.
You have to execute a query by hand or use other tool (For instance PLSQL Developer has such option). The following SQL is that one used by PLSQL Developer:
select table_name, constraint_name, status, owner
from all_constraints
where r_owner = :r_owner
and constraint_type = 'R'
and r_constraint_name in
(
select constraint_name from all_constraints
where constraint_type in ('P', 'U')
and table_name = :r_table_name
and owner = :r_owner
)
order by table_name, constraint_name
Where r_owner is the schema, and r_table_name is the table for which you are looking for references. The names are case sensitive
Be careful because on the reports tab of Oracle SQL Developer there is the option "All tables / Dependencies" this is from ALL_DEPENDENCIES which refers to "dependencies between procedures, packages, functions, package bodies, and triggers accessible to the current user, including dependencies on views created without any database links.". Then, this report have no value for your question.
To add this to SQL Developer as an extension do the following:
Save the below code into an xml file (e.g. fk_ref.xml):
<items>
<item type="editor" node="TableNode" vertical="true">
<title><![CDATA[FK References]]></title>
<query>
<sql>
<![CDATA[select a.owner,
a.table_name,
a.constraint_name,
a.status
from all_constraints a
where a.constraint_type = 'R'
and exists(
select 1
from all_constraints
where constraint_name=a.r_constraint_name
and constraint_type in ('P', 'U')
and table_name = :OBJECT_NAME
and owner = :OBJECT_OWNER)
order by table_name, constraint_name]]>
</sql>
</query>
</item>
</items>
Add the extension to SQL Developer:
Tools > Preferences
Database > User Defined Extensions
Click "Add Row" button
In Type choose "EDITOR", Location is where you saved the xml file above
Click "Ok" then restart SQL Developer
Navigate to any table and you should now see an additional tab next to SQL one, labelled FK References, which displays the new FK information.
Reference
http://www.oracle.com/technetwork/issue-archive/2007/07-jul/o47sql-086233.html
Replace [Your TABLE] with emp in the query below
select owner,constraint_name,constraint_type,table_name,r_owner,r_constraint_name
from all_constraints
where constraint_type='R'
and r_constraint_name in (select constraint_name
from all_constraints
where constraint_type in ('P','U')
and table_name='[YOUR TABLE]');
You may be able to query this from the ALL_CONSTRAINTS view:
SELECT table_name
FROM ALL_CONSTRAINTS
WHERE constraint_type = 'R' -- "Referential integrity"
AND r_constraint_name IN
( SELECT constraint_name
FROM ALL_CONSTRAINTS
WHERE table_name = 'EMP'
AND constraint_type IN ('U', 'P') -- "Unique" or "Primary key"
);
SQL Developer 4.1, released in May of 2015, added a Model tab which shows table foreign keys which refer to your table in an Entity Relationship Diagram format.
SELECT DISTINCT table_name,
constraint_name,
column_name,
r_table_name,
position,
constraint_type
FROM (SELECT uc.table_name,
uc.constraint_name,
cols.column_name,
(SELECT table_name
FROM user_constraints
WHERE constraint_name = uc.r_constraint_name) r_table_name,
(SELECT column_name
FROM user_cons_columns
WHERE constraint_name = uc.r_constraint_name
AND position = cols.position) r_column_name,
cols.position,
uc.constraint_type
FROM user_constraints uc
inner join user_cons_columns cols
ON uc.constraint_name = cols.constraint_name
WHERE constraint_type != 'C')
START WITH table_name = '&&tableName'
AND column_name = '&&columnName'
CONNECT BY NOCYCLE PRIOR table_name = r_table_name
AND PRIOR column_name = r_column_name;
This has been in the product for years - although it wasn't in the product in 2011.
But, simply click on the Model page.
Make sure you are on at least version 4.0 (released in 2013) to access this feature.
How about something like this:
SELECT c.constraint_name, c.constraint_type, c2.constraint_name, c2.constraint_type, c2.table_name
FROM dba_constraints c JOIN dba_constraints c2 ON (c.r_constraint_name = c2.constraint_name)
WHERE c.table_name = <TABLE_OF_INTEREST>
AND c.constraint_TYPE = 'R';
To add to the above answer for sql developer plugin, using the below xml will help in getting the column associated with the foreign key.
<items>
<item type="editor" node="TableNode" vertical="true">
<title><![CDATA[FK References]]></title>
<query>
<sql>
<![CDATA[select a.owner,
a.constraint_name,
a.table_name,
b.column_name,
a.status
from all_constraints a
join all_cons_columns b ON b.constraint_name = a.constraint_name
where a.constraint_type = 'R'
and exists(
select 1
from all_constraints
where constraint_name=a.r_constraint_name
and constraint_type in ('P', 'U')
and table_name = :OBJECT_NAME
and owner = :OBJECT_OWNER)
order by table_name, constraint_name]]>
</sql>
</query>
</item>
</items>
I like to do this with a straight SQL query, rather than messing about with the SQL Developer application.
Here's how I just did it. Best to read through this and understand what's going on, so you can tweak it to fit your needs...
WITH all_primary_keys AS (
SELECT constraint_name AS pk_name,
table_name
FROM all_constraints
WHERE owner = USER
AND constraint_type = 'P'
)
SELECT ac.table_name || ' table has a foreign key called ' || upper(ac.constraint_name)
|| ' which references the primary key ' || upper(ac.r_constraint_name) || ' on table ' || apk.table_name AS foreign_keys
FROM all_constraints ac
LEFT JOIN all_primary_keys apk
ON ac.r_constraint_name = apk.pk_name
WHERE ac.owner = USER
AND ac.constraint_type = 'R'
AND ac.table_name = nvl(upper(:table_name), ac.table_name)
ORDER BY ac.table_name, ac.constraint_name
;
Only Replace table_name with your primary table name
select *
from all_constraints
where r_constraint_name in (
select constraint_name
from all_constraints
where table_name='table_name'
);
Replace MY_OWNER_NAME and MY_TABLE_NAME below and you are ready to go RECURSIVELY:
DECLARE
FUNCTION list_all_child_tables_and_constraints(asked_table_name in VARCHAR2, parent_table_name in VARCHAR2)
RETURN VARCHAR2 IS
current_path VARCHAR2(100);
BEGIN
FOR item IN
(SELECT fk.TABLE_NAME, constraint_parent.FK FK1, constraint_child.FK FK2
FROM all_constraints fk, all_constraints pk,
(SELECT acc.CONSTRAINT_NAME, LISTAGG(acc.COLUMN_NAME, ', ') WITHIN GROUP (ORDER BY acc.COLUMN_NAME) AS FK
FROM ALL_CONS_COLUMNS acc
WHERE acc.OWNER = 'MY_OWNER_NAME'
GROUP BY acc.CONSTRAINT_NAME) constraint_parent,
(SELECT acc.CONSTRAINT_NAME, LISTAGG(acc.COLUMN_NAME, ', ') WITHIN GROUP (ORDER BY acc.COLUMN_NAME) AS FK
FROM ALL_CONS_COLUMNS acc
WHERE acc.OWNER = 'MY_OWNER_NAME'
GROUP BY acc.CONSTRAINT_NAME) constraint_child
WHERE pk.owner = fk.r_owner
AND pk.constraint_name = fk.r_constraint_name
AND fk.constraint_type = 'R'
AND pk.table_name = asked_table_name
AND constraint_parent.CONSTRAINT_NAME = fk.CONSTRAINT_NAME
AND constraint_child.CONSTRAINT_NAME = fk.R_CONSTRAINT_NAME
AND pk.owner = 'MY_OWNER_NAME'
AND fk.owner = 'MY_OWNER_NAME')
LOOP
current_path := parent_table_name || ' // ' || item.TABLE_NAME;
DBMS_OUTPUT.PUT_LINE(current_path);
DBMS_OUTPUT.PUT_LINE(' [' || item.FK1 || '] [' || item.FK2 || ']');
DBMS_OUTPUT.PUT_LINE('');
current_path := list_all_child_tables_and_constraints(item.TABLE_NAME, current_path);
END LOOP;
RETURN '-----------FINISHED-----------';
EXCEPTION
WHEN OTHERS THEN
RETURN '-----------FINISHED-----------';
END list_all_child_tables_and_constraints;
BEGIN
DBMS_OUTPUT.PUT_LINE(list_all_child_tables_and_constraints('MY_TABLE_NAME', ''));
END;
I need to get column list of SYNONYMS in ORACLE. The table on which synonym is created is in other schema. Can anyone help me in this problem?
This will return a list of all synonyms in the db:
select * from DBA_SYNONYMS
order by synonym_name
This will return a list of synonyms with a 'like' name:
select * from DBA_SYNONYMS
where upper(synonym_name) like upper('%SYNONYM_NAME_HERE%')
order by synonym_name
Relevant column names in response:
SYNONYM_NAME
TABLE_NAME
Here is a query that I use to see synonyms and their targets.
You will need SELECT privileges on DBA_SYNONYMS and DBA_OBJECTS.
select decode(owner, 'PUBLIC', 'PUBLIC SYNONYM', 'SYNONYM') as objtype,
decode(owner, 'PUBLIC', '', owner) as objowner,
synonym_name as objname,
synonym_name || ' => ' ||
case
when db_link is null then '(' || (
select o1.object_type from dba_objects o1 where o1.owner = table_owner and o1.object_name = table_name and o1.object_type in ('VIEW','TABLE','SYNONYM','SEQUENCE','FUNCTION','PROCEDURE','PACKAGE','MATERIALIZED VIEW','JAVA CLASS','TYPE')
and not exists (select 1 from dba_objects o2 where o2.owner = o1.owner and o2.object_name = o1.object_name and o1.object_type = 'TABLE' and o2.object_type = 'MATERIALIZED VIEW')
) || ') ' || table_owner || '.' || table_name
else decode(table_owner, null, '', table_owner || '.') || table_name || decode(db_link, null, '', '#' || db_link)
end as objdesc
from dba_synonyms
where OWNER != 'PUBLIC'
order by 1,2,3,4
It's a bit wordy, but it makes nice output like this:
OBJTYPE OBJOWNER OBJNAME OBJDESC
------- ----------- -------------------- -----------------------------------------------------------------------------
SYNONYM SYSTEM PRODUCT_USER_PROFILE PRODUCT_USER_PROFILE => (TABLE) SYSTEM.SQLPLUS_PRODUCT_PROFILE
SYNONYM SYSTEM TAB TAB => (VIEW) SYS.TAB
This is actually part of a larger query I use for finding objects of various types, hence some of the redundant information.
I filtered out PUBLIC because that is one huge list.
it's never too late to respond
select * from all_tab_columns#&SYNONYM_DB_LINK
where upper(table_name) like '&TARGET_TABLE_NAME'
order by owner, table_name, column_id
In OWNER is the synonym owner
select * from all_synonyms
where table_owner=upper(:table_owner) and table_name=upper(:table_name)
What do you mean under "Column list"?
select * from all_tab_cols where table_name in
(select TABLE_NAME from all_synonyms where owner = <SCHEMA_NAME> )
Need to get the list of tables name from a schema which doesn't have a primary key. I tried the following query to get this, but it will list all other keys except primary keys.
SELECT a.constraint_name,a.table_name
FROM ALL_CONS_COLUMNS A
JOIN ALL_CONSTRAINTS C
ON A.CONSTRAINT_NAME = C.CONSTRAINT_NAME
WHERE
C.CONSTRAINT_TYPE not in('P')
and a.owner ='my_schema';
If you only want this for the current user, it's better to user the user_xxx views instead of the all_xxx views.
The following should do what you want:
select ut.table_name
from user_tables ut
where not exists (select 1
from user_constraints ac
where ac.table_name = ut.table_name
and ac.constraint_type = 'P'
);
If you do need this for a different user, then you can use the following.
select at.*
from all_tables at
where not exists (select 1
from all_constraints ac
where ac.owner = at.owner
and ac.table_name = at.table_name
and ac.constraint_type = 'P'
)
and at.owner = 'MY_SCHEMA';
Don't forget that Oracle is case sensitive and that user names are stored in uppercase, so a.owner ='my_schema' will most probably not return anything.
Another way:
select owner,table_name
from all_tables
where owner = 'my_schema'
MINUS
select owner,table_name
from all_constraints
where owner = 'my_schema'
and constraint_type = 'P'
Try like this,
SELECT table_name
FROM all_tables A
WHERE table_name NOT IN
(
SELECT table_name
FROM all_constraints WHERE constraint_type ='P'
)
AND a.owner = 'my_schema';
Select tables.owner || ‘.’ ||
tables.table_name
as table_owner
From all_tables tables,
(Select
owner,
TABLE_NAME,
constraint_type,
CONSTRAINT_NAME
FROM ALL_CONSTRAINTS
WHERE CONSTRAINT_TYPE = ‘P’ /* list of all tables with PK */
) constr
Where tables.owner = constr.owner (+)
And tables.table_name = constr.table_name (+)
and tables.owner <> ‘SYS’
and tables.owner <> ‘SYSTEM’
And constr.owner IS NULL
And constr.table_name IS NULL
ORDER BY 1
I want to collect the nullable fields from the db, is there any script which can help me ?
It is important to know which fields must be checked against null during the programming.
Thanks in advance.
Cs
SELECT * FROM USER_CONSTRAINTS
where constraint_type = 'C'
or, more precisely:
select owner, constraint_name, table_name, column_name
from all_cons_columns
UPDATE:To get nullable columns:
SELECT OWNER, TABLE_NAME, COLUMN_NAME
FROM ALL_TAB_COLS
MINUS
SELECT OWNER, TABLE_NAME, COLUMN_NAME
from all_cons_columns
select owner, table_name, column_name, data_type
from all_tab_cols
where nullable = 'Y';
I'm trying to get CONSTRAINTS from user_objects table like this:
select CASE object_type
WHEN 'DATABASE LINK' then 'dblinks'
WHEN 'FUNCTION' then 'functions'
WHEN 'INDEX' then 'indexes'
WHEN 'PACKAGE' then 'packages'
WHEN 'PROCEDURE' then 'procedures'
WHEN 'SEQUENCE' then 'sequences'
WHEN 'TABLE' then 'tables'
WHEN 'TRIGGER' then 'triggers'
WHEN 'VIEW' then 'views'
WHEN 'SYNONYM' then 'synonyms'
WHEN 'GRANT' then 'grants'
WHEN 'CONSTRAINT' then 'constraints'
ELSE object_type
END||'|'||
CASE object_type
WHEN 'DATABASE LINK' then 'DB_LINK'
ELSE object_type
END||'|'||object_name
from user_objects
where object_name not like 'BIN$%'
and object_type not like '%PARTITION'
and object_type not in ('PACKAGE BODY')
order by object_type
;
select distinct object_type
from user_objects
;
But..... USER_OBJECTS has only these types FUNCTION
INDEX, PACKAGE, PACKAGE BODY, PROCEDURE, SEQUENCE, TABLE, TRIGGER, VIEW because select distinct object_type from user_objects; returned them. So this query is not giving my the constraints at all.
Is there a way to get all constraints from Oracle? Which Oracle view should I use?
select * from user_constraints
Constraints aren't objects. So they're in a different view, namely USER_CONSTRAINTS. For foreign constraints, you'll need a self join:
select * from user_constraints c
left join user_constraints r on r.owner = c.r_owner and r.constraint_name = c.r_constraint_name
where c.constraint_type = 'R';
Some details can also be found in USER_CONS_COLUMNS.