Related
In Oracle SQL Developer, if I'm viewing the information on a table, I can view the constraints, which let me see the foreign keys (and thus which tables are referenced by this table), and I can view the dependencies to see what packages and such reference the table. But I'm not sure how to find which tables reference the table.
For example, say I'm looking at the emp table. There is another table emp_dept which captures which employees work in which departments, which references the emp table through emp_id, the primary key of the emp table. Is there a way (through some UI element in the program, not through SQL) to find that the emp_dept table references the emp table, without me having to know that the emp_dept table exists?
No. There is no such option available from Oracle SQL Developer.
You have to execute a query by hand or use other tool (For instance PLSQL Developer has such option). The following SQL is that one used by PLSQL Developer:
select table_name, constraint_name, status, owner
from all_constraints
where r_owner = :r_owner
and constraint_type = 'R'
and r_constraint_name in
(
select constraint_name from all_constraints
where constraint_type in ('P', 'U')
and table_name = :r_table_name
and owner = :r_owner
)
order by table_name, constraint_name
Where r_owner is the schema, and r_table_name is the table for which you are looking for references. The names are case sensitive
Be careful because on the reports tab of Oracle SQL Developer there is the option "All tables / Dependencies" this is from ALL_DEPENDENCIES which refers to "dependencies between procedures, packages, functions, package bodies, and triggers accessible to the current user, including dependencies on views created without any database links.". Then, this report have no value for your question.
To add this to SQL Developer as an extension do the following:
Save the below code into an xml file (e.g. fk_ref.xml):
<items>
<item type="editor" node="TableNode" vertical="true">
<title><![CDATA[FK References]]></title>
<query>
<sql>
<![CDATA[select a.owner,
a.table_name,
a.constraint_name,
a.status
from all_constraints a
where a.constraint_type = 'R'
and exists(
select 1
from all_constraints
where constraint_name=a.r_constraint_name
and constraint_type in ('P', 'U')
and table_name = :OBJECT_NAME
and owner = :OBJECT_OWNER)
order by table_name, constraint_name]]>
</sql>
</query>
</item>
</items>
Add the extension to SQL Developer:
Tools > Preferences
Database > User Defined Extensions
Click "Add Row" button
In Type choose "EDITOR", Location is where you saved the xml file above
Click "Ok" then restart SQL Developer
Navigate to any table and you should now see an additional tab next to SQL one, labelled FK References, which displays the new FK information.
Reference
http://www.oracle.com/technetwork/issue-archive/2007/07-jul/o47sql-086233.html
Replace [Your TABLE] with emp in the query below
select owner,constraint_name,constraint_type,table_name,r_owner,r_constraint_name
from all_constraints
where constraint_type='R'
and r_constraint_name in (select constraint_name
from all_constraints
where constraint_type in ('P','U')
and table_name='[YOUR TABLE]');
You may be able to query this from the ALL_CONSTRAINTS view:
SELECT table_name
FROM ALL_CONSTRAINTS
WHERE constraint_type = 'R' -- "Referential integrity"
AND r_constraint_name IN
( SELECT constraint_name
FROM ALL_CONSTRAINTS
WHERE table_name = 'EMP'
AND constraint_type IN ('U', 'P') -- "Unique" or "Primary key"
);
SQL Developer 4.1, released in May of 2015, added a Model tab which shows table foreign keys which refer to your table in an Entity Relationship Diagram format.
SELECT DISTINCT table_name,
constraint_name,
column_name,
r_table_name,
position,
constraint_type
FROM (SELECT uc.table_name,
uc.constraint_name,
cols.column_name,
(SELECT table_name
FROM user_constraints
WHERE constraint_name = uc.r_constraint_name) r_table_name,
(SELECT column_name
FROM user_cons_columns
WHERE constraint_name = uc.r_constraint_name
AND position = cols.position) r_column_name,
cols.position,
uc.constraint_type
FROM user_constraints uc
inner join user_cons_columns cols
ON uc.constraint_name = cols.constraint_name
WHERE constraint_type != 'C')
START WITH table_name = '&&tableName'
AND column_name = '&&columnName'
CONNECT BY NOCYCLE PRIOR table_name = r_table_name
AND PRIOR column_name = r_column_name;
This has been in the product for years - although it wasn't in the product in 2011.
But, simply click on the Model page.
Make sure you are on at least version 4.0 (released in 2013) to access this feature.
How about something like this:
SELECT c.constraint_name, c.constraint_type, c2.constraint_name, c2.constraint_type, c2.table_name
FROM dba_constraints c JOIN dba_constraints c2 ON (c.r_constraint_name = c2.constraint_name)
WHERE c.table_name = <TABLE_OF_INTEREST>
AND c.constraint_TYPE = 'R';
To add to the above answer for sql developer plugin, using the below xml will help in getting the column associated with the foreign key.
<items>
<item type="editor" node="TableNode" vertical="true">
<title><![CDATA[FK References]]></title>
<query>
<sql>
<![CDATA[select a.owner,
a.constraint_name,
a.table_name,
b.column_name,
a.status
from all_constraints a
join all_cons_columns b ON b.constraint_name = a.constraint_name
where a.constraint_type = 'R'
and exists(
select 1
from all_constraints
where constraint_name=a.r_constraint_name
and constraint_type in ('P', 'U')
and table_name = :OBJECT_NAME
and owner = :OBJECT_OWNER)
order by table_name, constraint_name]]>
</sql>
</query>
</item>
</items>
I like to do this with a straight SQL query, rather than messing about with the SQL Developer application.
Here's how I just did it. Best to read through this and understand what's going on, so you can tweak it to fit your needs...
WITH all_primary_keys AS (
SELECT constraint_name AS pk_name,
table_name
FROM all_constraints
WHERE owner = USER
AND constraint_type = 'P'
)
SELECT ac.table_name || ' table has a foreign key called ' || upper(ac.constraint_name)
|| ' which references the primary key ' || upper(ac.r_constraint_name) || ' on table ' || apk.table_name AS foreign_keys
FROM all_constraints ac
LEFT JOIN all_primary_keys apk
ON ac.r_constraint_name = apk.pk_name
WHERE ac.owner = USER
AND ac.constraint_type = 'R'
AND ac.table_name = nvl(upper(:table_name), ac.table_name)
ORDER BY ac.table_name, ac.constraint_name
;
Only Replace table_name with your primary table name
select *
from all_constraints
where r_constraint_name in (
select constraint_name
from all_constraints
where table_name='table_name'
);
Replace MY_OWNER_NAME and MY_TABLE_NAME below and you are ready to go RECURSIVELY:
DECLARE
FUNCTION list_all_child_tables_and_constraints(asked_table_name in VARCHAR2, parent_table_name in VARCHAR2)
RETURN VARCHAR2 IS
current_path VARCHAR2(100);
BEGIN
FOR item IN
(SELECT fk.TABLE_NAME, constraint_parent.FK FK1, constraint_child.FK FK2
FROM all_constraints fk, all_constraints pk,
(SELECT acc.CONSTRAINT_NAME, LISTAGG(acc.COLUMN_NAME, ', ') WITHIN GROUP (ORDER BY acc.COLUMN_NAME) AS FK
FROM ALL_CONS_COLUMNS acc
WHERE acc.OWNER = 'MY_OWNER_NAME'
GROUP BY acc.CONSTRAINT_NAME) constraint_parent,
(SELECT acc.CONSTRAINT_NAME, LISTAGG(acc.COLUMN_NAME, ', ') WITHIN GROUP (ORDER BY acc.COLUMN_NAME) AS FK
FROM ALL_CONS_COLUMNS acc
WHERE acc.OWNER = 'MY_OWNER_NAME'
GROUP BY acc.CONSTRAINT_NAME) constraint_child
WHERE pk.owner = fk.r_owner
AND pk.constraint_name = fk.r_constraint_name
AND fk.constraint_type = 'R'
AND pk.table_name = asked_table_name
AND constraint_parent.CONSTRAINT_NAME = fk.CONSTRAINT_NAME
AND constraint_child.CONSTRAINT_NAME = fk.R_CONSTRAINT_NAME
AND pk.owner = 'MY_OWNER_NAME'
AND fk.owner = 'MY_OWNER_NAME')
LOOP
current_path := parent_table_name || ' // ' || item.TABLE_NAME;
DBMS_OUTPUT.PUT_LINE(current_path);
DBMS_OUTPUT.PUT_LINE(' [' || item.FK1 || '] [' || item.FK2 || ']');
DBMS_OUTPUT.PUT_LINE('');
current_path := list_all_child_tables_and_constraints(item.TABLE_NAME, current_path);
END LOOP;
RETURN '-----------FINISHED-----------';
EXCEPTION
WHEN OTHERS THEN
RETURN '-----------FINISHED-----------';
END list_all_child_tables_and_constraints;
BEGIN
DBMS_OUTPUT.PUT_LINE(list_all_child_tables_and_constraints('MY_TABLE_NAME', ''));
END;
I got query below:
SELECT TABLE_NAME, CONSTRAINT_NAME FROM USER_CONSTRAINTS
WHERE R_OWNER = 'OWNERNAME' AND STATUS ='ENABLED' AND CONSTRAINT_TYPE = 'R'
AND R_CONSTRAINT_NAME IN ( SELECT CONSTRAINT_NAME FROM ALL_CONSTRAINTS
WHERE CONSTRAINT_TYPE IN ('P', 'U') AND TABLE_NAME = 'REGIONS'
AND OWNER = 'OWNERNAME' )
It took 4 Secs to get output of it.
Is there any better way to get the name of referential table name?
Thanks in advance.
Joon
There is a join condition missing in your query:
SELECT TABLE_NAME,
CONSTRAINT_NAME
FROM USER_CONSTRAINTS
WHERE R_OWNER = 'OWNERNAME'
AND STATUS ='ENABLED'
AND CONSTRAINT_TYPE = 'R'
AND (R_OWNER, R_CONSTRAINT_NAME) IN ( SELECT OWNER, CONSTRAINT_NAME
FROM ALL_CONSTRAINTS
WHERE CONSTRAINT_TYPE IN ('P', 'U')
AND TABLE_NAME = 'REGIONS'
AND OWNER = 'OWNERNAME' )
You are not limiting R_OWNER to 'OWNERNAME' which means that is has to look at all constraints in the schema OWNERNAME not only those that link to the table OWNERNAME.REGIONS.
How can I do to (left)join user_tab_columns with user_cons_columns and user_constraints to get the result below:
Table, Column, SourceTable, SourceColumn
ORDER, ORDER_ID, null, null
ORDER, ORDER_DATE, null, null
ORDER, ORDER_CLIENT, CLIENT, CLIENT_ID
CLIENT, CLIENT_ID, null, null
ORDER_DETAIL, ORDER_ID, ORDER, ORDER_ID
ORDER_DETAIL, PRODUCT_ID, PRODUCT, PRODUCT_ID
PRODUCT PRODUCT_ID, null, null
So... I need all table and columns but once a column is a foreign key,
I need to know the table and the column (primary key) related.
Slight edits to linked answer:
List of foreign keys and the tables they reference
all_ to user sources.
Course you could just use all and then filter on owner.
SELECT a.table_name, a.column_name, a.constraint_name, c.owner,
c.r_owner, c_pk.table_name r_table_name, c_pk.constraint_name r_pk
FROM user_cons_columns a
LEFT JOIN user_constraints c
ON a.owner = c.owner
AND a.constraint_name = c.constraint_name
LEFT JOIN user_constraints c_pk
ON c.r_owner = c_pk.owner
AND c.r_constraint_name = c_pk.constraint_name
WHERE c.constraint_type = 'R'
--AND a.table_name = :TableName
check following query :
select a.table_name,c1.column_name,b.table_name,c2.column_name from USER_constraints a,USER_constraints b,user_cons_columns c1,user_cons_columns c2
where a.r_constraint_name = b.constraint_name and a.table_name = c1.table_name and b.table_name = c2.table_name if you just need FK constraint use a.constraint_type ='R' in where clouse.
How to get unique constraint_name of The corresponding column in oracle database?
in other words I want to get constraint name by column name.
pseudo query for this question:
select constraint_name from table_name tname where tname.column_name = 'columnName';
is this possible?
Use the Oracle dictionary views ALL_CONS_COLUMNS or USER_CONS_COLUMNS (if you want to restrict it by column type - i.e. unique or primary key constraints - then you can join in ALL_CONSTRAINTS or USER_CONSTRAINTS):
SELECT acc.constraint_name
FROM ALL_CONS_COLUMNS acc
INNER JOIN ALL_CONSTRAINTS ac
ON ( acc.CONSTRAINT_NAME = ac.CONSTRAINT_NAME )
WHERE ac.OWNER = 'YOUR_SCHEMA_NAME'
AND ac.TABLE_NAME = 'YOUR_TABLE_NAME'
AND acc.COLUMN_NAME = 'YOUR_COLUMN_NAME'
AND ac.CONSTRAINT_TYPE IN ( 'U', 'P' ) -- Unique or primary key constraints
or:
SELECT ucc.constraint_name
FROM USER_CONS_COLUMNS ucc
INNER JOIN ALL_CONSTRAINTS uc
ON ( ucc.CONSTRAINT_NAME = uc.CONSTRAINT_NAME )
WHERE uc.OWNER = 'YOUR_SCHEMA_NAME'
AND uc.TABLE_NAME = 'YOUR_TABLE_NAME'
AND ucc.COLUMN_NAME = 'YOUR_COLUMN_NAME'
AND uc.CONSTRAINT_TYPE IN ( 'U', 'P' ) -- Unique or primary key constraints
Try this.
select CONSTRAINT_NAME from USER_CONS_COLUMNS
where table_name='YOUR_TABLE'
and column_name='YOUR_COLUMN'
I'm trying to find a query which will return me a list of the foreign keys for a table and the tables and columns they reference. I am half way there with
SELECT a.table_name,
a.column_name,
a.constraint_name,
c.owner
FROM ALL_CONS_COLUMNS A, ALL_CONSTRAINTS C
where A.CONSTRAINT_NAME = C.CONSTRAINT_NAME
and a.table_name=:TableName
and C.CONSTRAINT_TYPE = 'R'
But I still need to know which table and primary key are referenced by this key. How would I get that?
The referenced primary key is described in the columns r_owner and r_constraint_name of the table ALL_CONSTRAINTS. This will give you the info you want:
SELECT a.table_name, a.column_name, a.constraint_name, c.owner,
-- referenced pk
c.r_owner, c_pk.table_name r_table_name, c_pk.constraint_name r_pk
FROM all_cons_columns a
JOIN all_constraints c ON a.owner = c.owner
AND a.constraint_name = c.constraint_name
JOIN all_constraints c_pk ON c.r_owner = c_pk.owner
AND c.r_constraint_name = c_pk.constraint_name
WHERE c.constraint_type = 'R'
AND a.table_name = :TableName
Try this:
select * from all_constraints where r_constraint_name in (select constraint_name
from all_constraints where table_name='YOUR_TABLE_NAME');
Here is an all-purpose script we use that has been incredibly handy.
Save it off so you can execute it directly (#fkeys.sql). It will let you search by Owner and either the Parent or Child table and show foreign key relationships. The current script does explicitly spool to C:\SQLRPTS so you will need to create that folder of change that line to something you want to use.
REM ########################################################################
REM ##
REM ## fkeys.sql
REM ##
REM ## Displays the foreign key relationships
REM ##
REM #######################################################################
CLEAR BREAK
CLEAR COL
SET LINES 200
SET PAGES 54
SET NEWPAGE 0
SET WRAP OFF
SET VERIFY OFF
SET FEEDBACK OFF
break on table_name skip 2 on constraint_name on r_table_name skip 1
column CHILDCOL format a60 head 'CHILD COLUMN'
column PARENTCOL format a60 head 'PARENT COLUMN'
column constraint_name format a30 head 'FK CONSTRAINT NAME'
column delete_rule format a15
column bt noprint
column bo noprint
TTITLE LEFT _DATE CENTER 'FOREIGN KEY RELATIONSHIPS ON &new_prompt' RIGHT 'PAGE:'FORMAT 999 SQL.PNO SKIP 2
SPOOL C:\SQLRPTS\FKeys_&new_prompt
ACCEPT OWNER_NAME PROMPT 'Enter Table Owner (or blank for all): '
ACCEPT PARENT_TABLE_NAME PROMPT 'Enter Parent Table or leave blank for all: '
ACCEPT CHILD_TABLE_NAME PROMPT 'Enter Child Table or leave blank for all: '
select b.owner || '.' || b.table_name || '.' || b.column_name CHILDCOL,
b.position,
c.owner || '.' || c.table_name || '.' || c.column_name PARENTCOL,
a.constraint_name,
a.delete_rule,
b.table_name bt,
b.owner bo
from all_cons_columns b,
all_cons_columns c,
all_constraints a
where b.constraint_name = a.constraint_name
and a.owner = b.owner
and b.position = c.position
and c.constraint_name = a.r_constraint_name
and c.owner = a.r_owner
and a.constraint_type = 'R'
and c.owner like case when upper('&OWNER_NAME') is null then '%'
else upper('&OWNER_NAME') end
and c.table_name like case when upper('&PARENT_TABLE_NAME') is null then '%'
else upper('&PARENT_TABLE_NAME') end
and b.table_name like case when upper('&CHILD_TABLE_NAME') is null then '%'
else upper('&CHILD_TABLE_NAME') end
order by 7,6,4,2
/
SPOOL OFF
TTITLE OFF
SET FEEDBACK ON
SET VERIFY ON
CLEAR BREAK
CLEAR COL
SET PAGES 24
SET LINES 100
SET NEWPAGE 1
UNDEF OWNER
This will travel the hierarchy of foreign keys for a given table and column and return columns from child and grandchild, and all descendant tables. It uses sub-queries to add r_table_name and r_column_name to user_constraints, and then uses them to connect rows.
select distinct table_name, constraint_name, column_name, r_table_name, position, constraint_type
from (
SELECT uc.table_name,
uc.constraint_name,
cols.column_name,
(select table_name from user_constraints where constraint_name = uc.r_constraint_name)
r_table_name,
(select column_name from user_cons_columns where constraint_name = uc.r_constraint_name and position = cols.position)
r_column_name,
cols.position,
uc.constraint_type
FROM user_constraints uc
inner join user_cons_columns cols on uc.constraint_name = cols.constraint_name
where constraint_type != 'C'
)
start with table_name = 'MY_TABLE_NAME' and column_name = 'MY_COLUMN_NAME'
connect by nocycle
prior table_name = r_table_name
and prior column_name = r_column_name;
Here is an another solution. Using sys's default views are so slow (approx 10s in my situation). This is much faster than that (approx. 0.5s).
SELECT
CONST.NAME AS CONSTRAINT_NAME,
RCONST.NAME AS REF_CONSTRAINT_NAME,
OBJ.NAME AS TABLE_NAME,
COALESCE(ACOL.NAME, COL.NAME) AS COLUMN_NAME,
CCOL.POS# AS POSITION,
ROBJ.NAME AS REF_TABLE_NAME,
COALESCE(RACOL.NAME, RCOL.NAME) AS REF_COLUMN_NAME,
RCCOL.POS# AS REF_POSITION
FROM SYS.CON$ CONST
INNER JOIN SYS.CDEF$ CDEF ON CDEF.CON# = CONST.CON#
INNER JOIN SYS.CCOL$ CCOL ON CCOL.CON# = CONST.CON#
INNER JOIN SYS.COL$ COL ON (CCOL.OBJ# = COL.OBJ#) AND (CCOL.INTCOL# = COL.INTCOL#)
INNER JOIN SYS.OBJ$ OBJ ON CCOL.OBJ# = OBJ.OBJ#
LEFT JOIN SYS.ATTRCOL$ ACOL ON (CCOL.OBJ# = ACOL.OBJ#) AND (CCOL.INTCOL# = ACOL.INTCOL#)
INNER JOIN SYS.CON$ RCONST ON RCONST.CON# = CDEF.RCON#
INNER JOIN SYS.CCOL$ RCCOL ON RCCOL.CON# = RCONST.CON#
INNER JOIN SYS.COL$ RCOL ON (RCCOL.OBJ# = RCOL.OBJ#) AND (RCCOL.INTCOL# = RCOL.INTCOL#)
INNER JOIN SYS.OBJ$ ROBJ ON RCCOL.OBJ# = ROBJ.OBJ#
LEFT JOIN SYS.ATTRCOL$ RACOL ON (RCCOL.OBJ# = RACOL.OBJ#) AND (RCCOL.INTCOL# = RACOL.INTCOL#)
WHERE CONST.OWNER# = userenv('SCHEMAID')
AND RCONST.OWNER# = userenv('SCHEMAID')
AND CDEF.TYPE# = 4 /* 'R' Referential/Foreign Key */;
If you need all the foreign keys of the user then use the following script
SELECT a.constraint_name, a.table_name, a.column_name, c.owner,
c_pk.table_name r_table_name, b.column_name r_column_name
FROM user_cons_columns a
JOIN user_constraints c ON a.owner = c.owner
AND a.constraint_name = c.constraint_name
JOIN user_constraints c_pk ON c.r_owner = c_pk.owner
AND c.r_constraint_name = c_pk.constraint_name
JOIN user_cons_columns b ON C_PK.owner = b.owner
AND C_PK.CONSTRAINT_NAME = b.constraint_name AND b.POSITION = a.POSITION
WHERE c.constraint_type = 'R'
based on Vincent Malgrat code
I know it's kinda late to answer but let me answer anyway, some of the answers
above are quite complicated hence here is a much simpler take.
SELECT a.table_name child_table, a.column_name child_column, a.constraint_name,
b.table_name parent_table, b.column_name parent_column
FROM all_cons_columns a
JOIN all_constraints c ON a.owner = c.owner AND a.constraint_name = c.constraint_name
join all_cons_columns b on c.owner = b.owner and c.r_constraint_name = b.constraint_name
WHERE c.constraint_type = 'R'
AND a.table_name = 'your table name'
My version, in my humble opinion, more readable:
SELECT PARENT.TABLE_NAME "PARENT TABLE_NAME"
, PARENT.CONSTRAINT_NAME "PARENT PK CONSTRAINT"
, '->' " "
, CHILD.TABLE_NAME "CHILD TABLE_NAME"
, CHILD.COLUMN_NAME "CHILD COLUMN_NAME"
, CHILD.CONSTRAINT_NAME "CHILD CONSTRAINT_NAME"
FROM ALL_CONS_COLUMNS CHILD
, ALL_CONSTRAINTS CT
, ALL_CONSTRAINTS PARENT
WHERE CHILD.OWNER = CT.OWNER
AND CT.CONSTRAINT_TYPE = 'R'
AND CHILD.CONSTRAINT_NAME = CT.CONSTRAINT_NAME
AND CT.R_OWNER = PARENT.OWNER
AND CT.R_CONSTRAINT_NAME = PARENT.CONSTRAINT_NAME
AND CHILD.TABLE_NAME = ::table -- table name variable
AND CT.OWNER = ::owner; -- schema variable, could not be needed
Its a bit late to anwser, but I hope my answer been useful for someone, who needs to select Composite foreign keys.
SELECT
"C"."CONSTRAINT_NAME",
"C"."OWNER" AS "SCHEMA_NAME",
"C"."TABLE_NAME",
"COL"."COLUMN_NAME",
"REF_COL"."OWNER" AS "REF_SCHEMA_NAME",
"REF_COL"."TABLE_NAME" AS "REF_TABLE_NAME",
"REF_COL"."COLUMN_NAME" AS "REF_COLUMN_NAME"
FROM
"USER_CONSTRAINTS" "C"
INNER JOIN "USER_CONS_COLUMNS" "COL" ON "COL"."OWNER" = "C"."OWNER"
AND "COL"."CONSTRAINT_NAME" = "C"."CONSTRAINT_NAME"
INNER JOIN "USER_CONS_COLUMNS" "REF_COL" ON "REF_COL"."OWNER" = "C"."R_OWNER"
AND "REF_COL"."CONSTRAINT_NAME" = "C"."R_CONSTRAINT_NAME"
AND "REF_COL"."POSITION" = "COL"."POSITION"
WHERE "C"."TABLE_NAME" = 'TableName' AND "C"."CONSTRAINT_TYPE" = 'R'
SELECT a.table_name, a.column_name, a.constraint_name, c.owner,
-- referenced pk
c.r_owner, c_pk.table_name r_table_name, c_pk.constraint_name r_pk
FROM all_cons_columns a
JOIN all_constraints c ON a.owner = c.owner
AND a.constraint_name = c.constraint_name
JOIN all_constraints c_pk ON c.r_owner = c_pk.owner
AND c.r_constraint_name = c_pk.constraint_name
WHERE c.constraint_type = 'R'
AND a.table_name :=TABLE_NAME
AND c.owner :=OWNER_NAME;
In case one wants to create FK constraints from UAT environment table to Live, fire below dynamic query.....
SELECT 'ALTER TABLE '||OBJ.NAME||' ADD CONSTRAINT '||CONST.NAME||' FOREIGN KEY ('||COALESCE(ACOL.NAME, COL.NAME)||') REFERENCES '
||ROBJ.NAME ||' ('||COALESCE(RACOL.NAME, RCOL.NAME) ||');'
FROM SYS.CON$ CONST
INNER JOIN SYS.CDEF$ CDEF ON CDEF.CON# = CONST.CON#
INNER JOIN SYS.CCOL$ CCOL ON CCOL.CON# = CONST.CON#
INNER JOIN SYS.COL$ COL ON (CCOL.OBJ# = COL.OBJ#) AND (CCOL.INTCOL# = COL.INTCOL#)
INNER JOIN SYS.OBJ$ OBJ ON CCOL.OBJ# = OBJ.OBJ#
LEFT JOIN SYS.ATTRCOL$ ACOL ON (CCOL.OBJ# = ACOL.OBJ#) AND (CCOL.INTCOL# = ACOL.INTCOL#)
INNER JOIN SYS.CON$ RCONST ON RCONST.CON# = CDEF.RCON#
INNER JOIN SYS.CCOL$ RCCOL ON RCCOL.CON# = RCONST.CON#
INNER JOIN SYS.COL$ RCOL ON (RCCOL.OBJ# = RCOL.OBJ#) AND (RCCOL.INTCOL# = RCOL.INTCOL#)
INNER JOIN SYS.OBJ$ ROBJ ON RCCOL.OBJ# = ROBJ.OBJ#
LEFT JOIN SYS.ATTRCOL$ RACOL ON (RCCOL.OBJ# = RACOL.OBJ#) AND (RCCOL.INTCOL# = RACOL.INTCOL#)
WHERE CONST.OWNER# = userenv('SCHEMAID')
AND RCONST.OWNER# = userenv('SCHEMAID')
AND CDEF.TYPE# = 4
AND OBJ.NAME = <table_name>;
I used below code and it served my purpose-
SELECT fk.owner, fk.table_name, col.column_name
FROM dba_constraints pk, dba_constraints fk, dba_cons_columns col
WHERE pk.constraint_name = fk.r_constraint_name
AND fk.constraint_name = col.constraint_name
AND pk.owner = col.owner
AND pk.owner = fk.owner
AND fk.constraint_type = 'R'
AND pk.owner = sys_context('USERENV', 'CURRENT_SCHEMA')
AND pk.table_name = :my_table
AND pk.constraint_type = 'P';
select d.table_name,
d.constraint_name "Primary Constraint Name",
b.constraint_name "Referenced Constraint Name"
from user_constraints d,
(select c.constraint_name,
c.r_constraint_name,
c.table_name
from user_constraints c
where table_name='EMPLOYEES' --your table name instead of EMPLOYEES
and constraint_type='R') b
where d.constraint_name=b.r_constraint_name
WITH reference_view AS
(SELECT a.owner, a.table_name, a.constraint_name, a.constraint_type,
a.r_owner, a.r_constraint_name, b.column_name
FROM dba_constraints a, dba_cons_columns b
WHERE a.owner LIKE UPPER ('SYS') AND
a.owner = b.owner
AND a.constraint_name = b.constraint_name
AND constraint_type = 'R'),
constraint_view AS
(SELECT a.owner a_owner, a.table_name, a.column_name, b.owner b_owner,
b.constraint_name
FROM dba_cons_columns a, dba_constraints b
WHERE a.owner = b.owner
AND a.constraint_name = b.constraint_name
AND b.constraint_type = 'P'
AND a.owner LIKE UPPER ('SYS')
)
SELECT
rv.table_name FK_Table , rv.column_name FK_Column ,
CV.table_name PK_Table , rv.column_name PK_Column , rv.r_constraint_name Constraint_Name
FROM reference_view rv, constraint_view CV
WHERE rv.r_constraint_name = CV.constraint_name AND rv.r_owner = CV.b_owner;
For Load UserTable (List of foreign keys and the tables they reference)
WITH
reference_view AS
(SELECT a.owner, a.table_name, a.constraint_name, a.constraint_type,
a.r_owner, a.r_constraint_name, b.column_name
FROM dba_constraints a, dba_cons_columns b
WHERE
a.owner = b.owner
AND a.constraint_name = b.constraint_name
AND constraint_type = 'R'),
constraint_view AS
(SELECT a.owner a_owner, a.table_name, a.column_name, b.owner b_owner,
b.constraint_name
FROM dba_cons_columns a, dba_constraints b
WHERE a.owner = b.owner
AND a.constraint_name = b.constraint_name
AND b.constraint_type = 'P'
) ,
usertableviewlist AS
(
select TABLE_NAME from user_tables
)
SELECT
rv.table_name FK_Table , rv.column_name FK_Column ,
CV.table_name PK_Table , rv.column_name PK_Column , rv.r_constraint_name Constraint_Name
FROM reference_view rv, constraint_view CV , usertableviewlist UTable
WHERE rv.r_constraint_name = CV.constraint_name AND rv.r_owner = CV.b_owner And UTable.TABLE_NAME = rv.table_name;
The more simple solution:
SELECT *
FROM all_indexes
WHERE index_name like '%FK_PROCESS%'