I have a column in table where it stores the value as a string but in following format:
column_value =([tag1 = 'abc']) and ([tag2 = 'xyz']) and ([tag3=123])
and I want output in following format:
tag1='abc'
tag2='xyz'
tag3=123
Can it be done using any regexp expression in oracle?
I don't know about regexp, but a few replaces do the job:
SQL> with
2 test (col) as
3 (select q'[([tag1 = 'abc']) and ([tag2 = 'xyz']) and ([tag3=123])]' from dual)
4 select replace(replace(replace(col, '([', ''), '])'), ' and ', chr(10)) result
5 from test;
RESULT
----------------------------------
tag1 = 'abc'
tag2 = 'xyz'
tag3=123
SQL>
As you use SQL Developer, you'll have to double-click the result, click the pencil button and see the result:
Related
I have a problem in updating a column in oracle which has a single quote.
The following example will clear the problem.
Lets Client name is Lucy'Mark
Now, I want to replace the Single quote with space
After output, it will be Lucy Mark
Now when I tried the following query it is not working as the query will be
select replace (Lucy'Mark , '''', '') from gen_clientvendor_m;
Please let me know the query.
I am using SQL developer
Use the column with client name and add space to the replace statement:
select replace (client_name , '''', ' ') from gen_clientvendor_m;
Multiple single quotes cause headache :) so - have a look at this option:
SQL> with test (name) as
2 (select q'[Lucy'Mark]' from dual)
3 select name,
4 replace(name, chr(39), ' ') result
5 from test;
NAME RESULT
--------- ---------
Lucy'Mark Lucy Mark
SQL>
My table contain column name accountnumber;
acctnum
-------
1234556777
2335678000
i want an output using oracle using sql query
acctnum
---------
123xxx6777
233xxx8000
i tried replace function ,but i did not get the output.pls help.
If I did not understand wrong, This maybe help you?
with a as
(select '1234567' as acctnum from dual)
select '###' || substr(acctnum,4) from a;
If you're trying to replace characters 4, 5 and 6 with an x you can do it with the SUBSTR function like this:
SELECT SUBSTR(acctnum, 1, 3) || 'xxx' || SUBSTR(acctnum, 7) AS acctnum
FROM mytable;
How can I get particular pattern of data using sql query?
I have a string which has data like "Valid data: emp no - 123 emp age - 23 emp type - M."
So here I want whatever I have in emp age i.e. 23. The string format will be same. I don't want to get emp age based on position as it can change ,is there any other way to get emp age?
Is a query which will find emp age tag in the string and then look three places after that tag to get emp age value?
If the text is always the same you can try something like the following.
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(ColumnA, 'emp age - ', -1), ' ', 1) AS Age
FROM table;
Oracle has built-in regular expression functions. If, as you say, the format is always the same, extracting the second group of numbers will give you the outcome you desire:
SQL> select regexp_substr('Valid data: emp no - 123 emp age - 23 emp type - M.'
2 , '[0-9]+', 1, 2) as emp_age
3 from dual
4 /
EM
--
23
SQL>
These functions are covered in the documentation. Find out more.
Use the built-in Regular Expression functions.
DB: Oracle 11g
Query:
SELECT CASE
WHEN rs.OPTION = '3'
THEN
(SELECT COUNT(DISTINCT ex.EXTS) AS TMPCOL0
FROM CRSIDM.SUB_OPTS ex
INNER JOIN CRSIDM.SUB_OPTS_GRP cg
ON cg.GROUP_ID = ex.GRP_ID
)
ELSE
(SELECT COUNT(DISTINCT ex.EXTS) AS TMPCOL0
FROM CRSIDM.SUB_OPTS ex
INNER JOIN CRSIDM.SUB_OPTS_POL cg
ON cg.GROUP_ID = ex.GRP_ID
)
END AS PROPTS
FROM PR_OPTS
I am getting error 'expected CHAR got NUMBER', here EXTS,GROUP_ID & GRP_ID are numeric. Then how there is a chance of expecting CHAR?
Generally when Oracle compares different datatypes such as a NUMBER with a CHARACTER, implicit conversion kicks in and all is well (provided the data can be converted.) For example, if you have a function that expects a CHARACTER value but you pass it a NUMBER, all is well - Oracle simply converts the NUMBER to character.
E.g. a function like this:
create or replace function get_something(p_id VARCHAR2) return number ...
works if you call it with this:
get_dno(10);
or this:
get_dno('10');
and in SQL:
select * from some_table where numeric_column = '10' -- no problem.
A popular place where you see this kind of error is with the return values in CASE statements. For instance, you'll get that error if you have something like this:
SQL> SELECT CASE WHEN 1 = 1 THEN '1' ELSE 2 END
2 FROM dual
3 ;
SELECT CASE WHEN 1 = 1 THEN '1' ELSE 2 END
*
ERROR at line 1:
ORA-00932: inconsistent datatypes: expected CHAR got NUMBER
(The datatype from the first WHEN clause is what it expects in the other WHEN/ELSE clauses that follow.)
But in your case the WHEN and THEN both return counts - the datatypes are consistent. So, I think you have a red-herring in there.
As Alex mentioned above, OPTION is a keyword and if you try and create a table with that as a column name, Oracle disagrees:
SQL> create table dummy
2 (option varchar2(10)
3 );
(option varchar2(10)
*
ERROR at line 2:
ORA-00904: : invalid identifier
This works:
SQL> create table dummy
2 (option_col varchar2(10)
3 );
Table created.
or you could do it with quotes:
SQL> create table dummy
2 ("option" varchar2(10));
Table created.
But now you're in a world of hurt - you need quotes from now on:
SQL> select option from dummy;
select option from dummy
*
ERROR at line 1:
ORA-00936: missing expression
SQL> select d.option from dummy d;
select d.option from dummy d
*
ERROR at line 1:
ORA-01747: invalid user.table.column, table.column, or column specification
With quotes:
SQL> select d."option" from dummy d;
no rows selected
So, if your query is really giving you "expected CHAR, got NUMBER", it looks to me like something is off.
Essentially, it means some of the fields you are using aren't compatible with each other. It's basically a "type mismatch". Just check to see if any types of CHAR are being used with types of NUMBER. Then you can either switch the type of one, or simply use a conversion as part of the query.
The issue is OPTION = '3', the quotation marks indicate that you're looking for a string containing the solitary character 3.
Try this instead:
SELECT CASE
WHEN rs.OPTION = 3
THEN
(SELECT COUNT(DISTINCT ex.EXTS) AS TMPCOL0
FROM CRSIDM.SUB_OPTS ex
INNER JOIN CRSIDM.SUB_OPTS_GRP cg
ON cg.GROUP_ID = ex.GRP_ID)
ELSE
(SELECT COUNT(DISTINCT ex.EXTS) AS TMPCOL0
FROM CRSIDM.SUB_OPTS ex
INNER JOIN CRSIDM.SUB_OPTS_POL cg
ON cg.GROUP_ID = ex.GRP_ID)
END AS PROPTS
FROM PR_OPTS
I have two rows that have a varchar column that are different according to a Java .equals(). I can't easily change or debug the Java code that's running against this particular database but I do have access to do queries directly against the database using SQLDeveloper. The fields look the same to me (they are street addresses with two lines separated by some new line or carriage feed/new line combo).
Is there a way to see all of the hidden characters as the result of a query?I'd like to avoid having to use the ascii() function with substr() on each of the rows to figure out which hidden character is different.
I'd also accept some query that shows me which character is the first difference between the two fields.
Try
select dump(column_name) from table
More information is in the documentation.
As for finding the position where the character differs, this might give you an idea:
create table tq84_compare (
id number,
col varchar2(20)
);
insert into tq84_compare values (1, 'hello world');
insert into tq84_compare values (2, 'hello' || chr(9) || 'world');
with c as (
select
(select col from tq84_compare where id = 1) col1,
(select col from tq84_compare where id = 2) col2
from
dual
),
l as (
select
level l from dual
start with 1=1
connect by level < (select length(c.col1) from c)
)
select
max(l.l) + 1position
from c,l
where substr(c.col1,1,l.l) = substr(c.col2,1,l.l);
SELECT DUMP('€ÁÑ', 1016)
FROM DUAL
... will print something like:
Typ=96 Len=3 CharacterSet=WE8MSWIN1252: 80,c1,d1