How can I get particular pattern of data using sql query?
I have a string which has data like "Valid data: emp no - 123 emp age - 23 emp type - M."
So here I want whatever I have in emp age i.e. 23. The string format will be same. I don't want to get emp age based on position as it can change ,is there any other way to get emp age?
Is a query which will find emp age tag in the string and then look three places after that tag to get emp age value?
If the text is always the same you can try something like the following.
SELECT SUBSTRING_INDEX(SUBSTRING_INDEX(ColumnA, 'emp age - ', -1), ' ', 1) AS Age
FROM table;
Oracle has built-in regular expression functions. If, as you say, the format is always the same, extracting the second group of numbers will give you the outcome you desire:
SQL> select regexp_substr('Valid data: emp no - 123 emp age - 23 emp type - M.'
2 , '[0-9]+', 1, 2) as emp_age
3 from dual
4 /
EM
--
23
SQL>
These functions are covered in the documentation. Find out more.
Use the built-in Regular Expression functions.
Related
I have a query that gets contract_types 1 to 10. This query is being used in an SSRS report to filter out a larger dataset. I am using -1 for nulls and -2 for all.
I would like to know how we would allow multiple values - does oracle concatenate the inputs together so '1,2,3' would be passed in? Say we get select -1,0,1 in SSRS, how could we alter the bottom query to return values?
My query to get ContractTypes:
SELECT
ContractType,
CASE WHEN ContractType = -2 THEN 'All'
WHEN ContractType = -1 THEN'Null'
ELSE to_Char(ContractType)
END AS DisplayFigure
FROM ContractTypes
which returns
ContractType DisplayFig
-1 Null
0 0
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 8
9 9
10 10
This currently is only returning single values or all, not muliple values:
SELECT *
FROM Employee
WHERE NVL(CONTRACT_TYPE, -1) = :contract_type or :contract_type = -2
I'm assuming we want to do something like:
WHERE NVL(CONTRACT_TYPE, -1) IN (:contract_type)
But this doesn't seem to work.
Data in Employee
Name ContractType
Bob 1
Sue 0
Bill Null
Joe 2
In my report, I want to be able to select contract_type as -1(null),0,1 using the 'allow muliple values' checkbox. At the moment, I can only select either 'all' using my -2 value, or single contract types.
My input would be: contract type = -1,1,2
My output would be Bill, Bob, Joe.
This is how I'm executing my code
I use SSRS with Oracle a lot so I see where you're coming from. Thankfully, they work pretty well together.
First make sure the parameter is set to allow multiple values. This adds a Select All option to your dropdown so you don't have to worry about adding a special case for "All". You'll want to make sure the dataset for the parameter has a row with -1 as the Value and a friendly description for the Label.
Next, the WHERE clause would be just as you mentioned:
WHERE NVL(CONTRACT_TYPE, -1) IN (:contract_type)
SSRS automatically populates the values. There is no XML or string manipulation needed. Keep in mind that this will not work with single-value parameters.
If for some reason this still doesn't work as expected in your environment, there is another workaround you can use which is more universal and works even with ODBC connections.
In the dataset parameter properties, use an expression like this to concatenate the values into a single, comma-separated string:
="," + Join(Parameters!Parameter.Value, ",") + ","
Then use an expression like this in your WHERE clause:
where :parameter like '%,' + Column + ',%'
Obviously, this is less efficient because it most likely won't be using an index, but it works.
I don't know SSRS, but - if I understood you correctly, you'll have to split that comma-separated values list into rows. Something like in this example:
SQL> select *
2 from dept
3 where deptno in (select regexp_substr('&&contract_type', '[^,]+', 1, level)
4 from dual
5 connect by level <= regexp_count('&&contract_type', ',') + 1
6 );
Enter value for contract_type: 10,20,40
DEPTNO DNAME LOC
---------- -------------------- --------------------
20 RESEARCH DALLAS
10 ACCOUNTING NEW YORK
40 OPERATIONS BOSTON
SQL>
Applied to your code:
select *
from employee
where nvl(contract_type, -1) in (select regexp_substr(:contract_type, '[^,]+', 1, level)
from dual
connect by level <= regexp_substr(:contract_type, ',') + 1
)
If you have the comma separated list of numbers and then if you like to split it then, the below seems simple and easy to maintain.
select to_number(column_value) from xmltable(:val);
Inputs: 1,2,3,4
Output:
I guess I understood your problem. If I am correct the below should solve your problem:
with inputs(Name, ContractType) as
(
select 'Bob', 1 from dual union all
select 'Sue', 0 from dual union all
select 'Bill', Null from dual union all
select 'Joe', 2 from dual
)
select *
from inputs
where decode(:ContractType,'-2',-2,nvl(ContractType,-1)) in (select to_number(column_value) from xmltable(:ContractType))
Inputs: -1,1,2
Output:
Inputs: -2
Output:
I have (and don't own, so I can't change) a table with a layout similar to this.
ID | CATEGORIES
---------------
1 | c1
2 | c2,c3
3 | c3,c2
4 | c3
5 | c4,c8,c5,c100
I need to return the rows that contain a specific category id. I starting by writing the queries with LIKE statements, because the values can be anywhere in the string
SELECT id FROM table WHERE categories LIKE '%c2%';
Would return rows 2 and 3
SELECT id FROM table WHERE categories LIKE '%c3%' and categories LIKE '%c2%'; Would again get me rows 2 and 3, but not row 4
SELECT id FROM table WHERE categories LIKE '%c3%' or categories LIKE '%c2%'; Would again get me rows 2, 3, and 4
I don't like all the LIKE statements. I've found FIND_IN_SET() in the Oracle documentation but it doesn't seem to work in 10g. I get the following error:
ORA-00904: "FIND_IN_SET": invalid identifier
00904. 00000 - "%s: invalid identifier"
when running this query: SELECT id FROM table WHERE FIND_IN_SET('c2', categories); (example from the docs) or this query: SELECT id FROM table WHERE FIND_IN_SET('c2', categories) <> 0; (example from Google)
I would expect it to return rows 2 and 3.
Is there a better way to write these queries instead of using a ton of LIKE statements?
You can, using LIKE. You don't want to match for partial values, so you'll have to include the commas in your search. That also means that you'll have to provide an extra comma to search for values at the beginning or end of your text:
select
*
from
YourTable
where
',' || CommaSeparatedValueColumn || ',' LIKE '%,SearchValue,%'
But this query will be slow, as will all queries using LIKE, especially with a leading wildcard.
And there's always a risk. If there are spaces around the values, or values can contain commas themselves in which case they are surrounded by quotes (like in csv files), this query won't work and you'll have to add even more logic, slowing down your query even more.
A better solution would be to add a child table for these categories. Or rather even a separate table for the catagories, and a table that cross links them to YourTable.
You can write a PIPELINED table function which return a 1 column table. Each row is a value from the comma separated string. Use something like this to pop a string from the list and put it as a row into the table:
PIPE ROW(ltrim(rtrim(substr(l_list, 1, l_idx - 1),' '),' '));
Usage:
SELECT * FROM MyTable
WHERE 'c2' IN TABLE(Util_Pkg.split_string(categories));
See more here: Oracle docs
Yes and No...
"Yes":
Normalize the data (strongly recommended) - i.e. split the categorie column so that you have each categorie in a separate... then you can just query it in a normal faschion...
"No":
As long as you keep this "pseudo-structure" there will be several issues (performance and others) and you will have to do something similar to:
SELECT * FROM MyTable WHERE categories LIKE 'c2,%' OR categories = 'c2' OR categories LIKE '%,c2,%' OR categories LIKE '%,c2'
IF you absolutely must you could define a function which is named FIND_IN_SET like the following:
CREATE OR REPLACE Function FIND_IN_SET
( vSET IN varchar2, vToFind IN VARCHAR2 )
RETURN number
IS
rRESULT number;
BEGIN
rRESULT := -1;
SELECT COUNT(*) INTO rRESULT FROM DUAL WHERE vSET LIKE ( vToFine || ',%' ) OR vSET = vToFind OR vSET LIKE ('%,' || vToFind || ',%') OR vSET LIKE ('%,' || vToFind);
RETURN rRESULT;
END;
You can then use that function like:
SELECT * FROM MyTable WHERE FIND_IN_SET (categories, 'c2' ) > 0;
For the sake of future searchers, don't forget the regular expression way:
with tbl as (
select 1 ID, 'c1' CATEGORIES from dual
union
select 2 ID, 'c2,c3' CATEGORIES from dual
union
select 3 ID, 'c3,c2' CATEGORIES from dual
union
select 4 ID, 'c3' CATEGORIES from dual
union
select 5 ID, 'c4,c8,c5,c100' CATEGORIES from dual
)
select *
from tbl
where regexp_like(CATEGORIES, '(^|\W)c3(\W|$)');
ID CATEGORIES
---------- -------------
2 c2,c3
3 c3,c2
4 c3
This matches on a word boundary, so even if the comma was followed by a space it would still work. If you want to be more strict and match only where a comma separates values, replace the '\W' with a comma. At any rate, read the regular expression as:
match a group of either the beginning of the line or a word boundary, followed by the target search value, followed by a group of either a word boundary or the end of the line.
As long as the comma-delimited list is 512 characters or less, you can also use a regular expression in this instance (Oracle's regular expression functions, e.g., REGEXP_LIKE(), are limited to 512 characters):
SELECT id, categories
FROM mytable
WHERE REGEXP_LIKE('c2', '^(' || REPLACE(categories, ',', '|') || ')$', 'i');
In the above I'm replacing the commas with the regular expression alternation operator |. If your list of delimited values is already |-delimited, so much the better.
For Sample purpose lets create a table with below schema and fill some sample values
CREATE TABLE games(ID INT ,Name VARCHAR(20));
INSERT INTO games(ID,Name) VALUES (2008,'Beijing');
INSERT INTO games(ID,Name) VALUES (2012,'London');
INSERT INTO games(ID,Name) VALUES (2012,12);
INSERT INTO games(ID,Name) VALUES (2012,654);
Output:
ID NAME
2008 Beijing
2012 London
2012 12
2012 654
In the above table we have both number and string data in the name column lets write a query that uses the REGX to filter only the numerical rows
SELECT TO_NUMBER(Name)as Trimmed FROM games where REGEXP_LIKE(Name, '(?<=\s|^)\d+(?=\s|$)', '')
Output:
TRIMMED
12
654
Now here is the problem if write a where clause of getting values greater than 12 from the above result it throws invalid number.
Select * from (SELECT TO_NUMBER(Name)as Trimmed FROM games where REGEXP_LIKE(Name, '(?<=\s|^)\d+(?=\s|$)', '')) T1 where T1.Trimmed >12 ;
I found this is how the oracle query planning works but is there any other way i can achieve this
This will work:
Select * from
(SELECT Name as Trimmed
FROM games where REGEXP_LIKE(Name, '(?<=\s|^)\d+(?=\s|$)', '')) T1
where to_number(T1.Trimmed) >12 ;
Unfortunately you need a subquery. It can't be done with one where.
This can be done in a single query:
with
inputs as (
select 2008 as id, 'Beijing' as name from dual union all
select 2012 , 'London' from dual union all
select 2012 , '12' from dual union all
select 2012 , '654' from dual
)
select id, name
from inputs
where translate(name, 'a0123456789', 'a') is null
and to_number(regexp_replace(name, '[^[:digit:]]', '')) > 12
;
ID NAME
---------- -------
2012 654
1 row selected.
regexp_replace removes all the characters except digits, so the test can be done regardless of what the name is. If there are no digits in the name, the result is NULL, which can be converted to number (it is still null).
The translate solution for testing for "all-digits" is more efficient than using regexp_like. The odd-looking 'a' in translate is needed due to an oddity in the translate function itself (see the documentation). This test is not needed if all the names are either "all letters" or "all digits" (if "all letters", the second test with regexp_replace would suffice); but the first test is needed if names like "Sydney 2000" are possible in the name column.
I have sample Data like:
Table empdata:
Name Desig Sal
-------------------------
john staff 26000
sen owner 50000
smith assistant 10000
i want to print each of the columns like
Current field value is : John
Current field value is : staff
Current field value is : 26000
Current field value is : sen
Current field value is : owner
Current field value is : 50000.. and so on
I am able to use cursor to fetch the emp data:
cursor c1 is
select name, desig, sal from empdata;
but i want to iterate over the columns too. I have shown 3 columns here, but there are atleast 30 columns in actual data, and i would like to print each of the field.
Please help.
Hi you can use this kind basic code.
begin
for i in (select * from emp where rownum < 5)
Loop
dbms_output.put_line('Current field value is: '||i.Emp_id);
dbms_output.put_line('Current field value is: '||i.emp_name);
end loop;
end;
If I understand you correctly, I think you're after something like:
select name,
desig,
sal,
(select approved from approval_table apv1 where apv1.data = emp.name) name_aprvd,
(select approved from approval_table apv2 where apv2.data = emp.desig) desig_aprvd,
(select approved from approval_table apv3 where apv3.data = emp.sal) sal_aprvd
from empdata emp;
Quite what you expect to do with the information once you've got it, I'm not sure. Maybe you return this as a cursor? Maybe you pass it into a procedure? I'm not sure, but hopefully you have enough information to sort out your requirement?
A weird request maybe but. My boss wants me to create an admin version of a page we have that displays data from an oracle query in a table.
The admin page, instead of displaying the data (query returns 1 row), needs to return the table name and column name
Ex: Instead of:
Name Initial
==================
Bob A
I want:
Name Initial
============================
Users.FirstName Users.MiddleInitial
I realize I can do this in code but would rather just modify the query to return the data I want so I can leave the report generation code mostly alone.
I don't want to do it in a stored procedure.
So when I spit out the data in the report using something like:
blah blah = MyDataRow("FirstName")
I can leave that as is but instead of it displaying "BOB" it would display "Users.FirstName"
And I want to do the query using select * if possible instead of listing all the columns
So for each of the columns I am querying in the * , I want to get (instead of the column value) the tablename.ColumnName or tablename|columnName
hope you are following- I am confusing myself...
pseudo:
select tablename + '.' + Columnname as WhateverTheColumnNameIs
from Table1
left join Table2 on whatever...
Join Table_Names on blah blah
Whew- after writing all this I think I will just do it on the code side.
But if you are up for it maybe a fun challenge
Oracle does not provide an authentic way(there is no pseudocolumn) to get the column name of a table as a result of a query against that table. But you might consider these two approaches:
Extract column name from an xmltype, formed by passing cursor expression(your query) in the xmltable() function:
-- your table
with t1(first_name, middle_name) as(
select 1,2 from dual
), -- your query
t2 as(
select * -- col1 as "t1.col1"
--, col2 as "t1.col2"
--, col3 as "t1.col3"
from hr.t1
)
select *
from ( select q.object_value.getrootelement() as col_name
, rownum as rn
from xmltable('//*'
passing xmltype(cursor(select * from t2 where rownum = 1))
) q
where q.object_value.getrootelement() not in ('ROWSET', 'ROW')
)
pivot(
max(col_name) for rn in (1 as "name", 2 as "initial")
)
Result:
name initial
--------------- ---------------
FIRST_NAME MIDDLE_NAME
Note: In order for column names to be prefixed with table name, you need to list them
explicitly in the select list of a query and supply an alias, manually.
PL/SQL approach. Starting from Oracle 11g you could use dbms_sql() package and describe_columns() procedure specifically to get the name of columns in the cursor(your select).
This might be what you are looking for, try selecting from system views USER_TAB_COLS or ALL_TAB_COLS.