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How can I calculate time elapsed in a Bash script?
(20 answers)
Closed 10 months ago.
I want to know the time duration since a systemd service was started, using the --property=ActiveEnterTimestamp i can see the time it has started, and i would like to compare it with current time and get a value in seconds or minutes, how can i achieve this with bash
If i use this solution i am getting a string, but i cannot actually get any time object to make the decision, any help on this would be appreciated.
You could use GNU date to convert the ActiveEnterTimestamp value to seconds-since-the-epoch, then subtract the current seconds-since-the-epoch to get the running time in seconds.
servicestartsec=$(date -d "$(systemctl show --property=ActiveEnterTimestamp your-service-here | cut -d= -f2)" +%s)
serviceelapsedsec=$(( $(date +%s) - servicestartsec))
Substitute "your-service-here" for your actual service name.
The first line assigns the start time in seconds by extracting the date portion of systemctl show --property=ActiveEnterTimestamp... (using cut to extract the second =-delimited field) and then passing it to GNU date and asking for output in seconds-since-the-epoch.
The second line simply subtracts that start time from the current time to get an elapsed time in seconds. Divide that as needed to get elapsed minutes, hours, etc.
Related
When viewing submitted jobs managed by Slurm, I would like to have the time limit column (specified by %l) to show only hours, instead of the usual days-hours:minutes:seconds format. This is the command I am currently using:
squeue --format="%.6i %.5P %.25j %.8u %.8T %.10M %.5l %.15b %.5C %.6D %R" --sort=+i --me
and this is the example output:
276350 qgpu jobname username RUNNING 1:14:14 1-00:00:00 gres:gpu:v100:1 18 1 s31n02
So, in this case, I would like the elapsed time to remain as is (1:14:14), but the time limit to change from 1-00:00:00 to 24. Is there a way to do it?
This is the way Slurm displays the dates. Elapsed time will eventually be displayed the same way (days-hours:minutes:seconds) after 23:59:59.
You can use a wrapper script to convert into a different format. Or if you know the time limit is no more than a day, just set the time limit to 23:59:00 by using --time=1439.
salloc -N1 --time=1439 bash
Using your squeue command:
166 mypartition interactive jyvet RUNNING 7:36 23:59:00 N/A 1 1 mynode
How do I find epoch time of 30 days from current time in shell script? If my current time is X in epoch milliseconds.Then I need epoch milliseconds of 30 days older in shell script
#!/bin/sh
current=$(date +'%s%3N')
echo $current
oldtimestamp=$((current - 30*24*60*60))
echo "old is $oldtimestamp"
This doesnt seem to give 30 days old epoch ms. Please let me know how to get it. Thanks in advance
The date command supports some natural language expressions:
date +'%s%3N' --date='30 days ago'
Of course, this will be some milliseconds off when compared to ${current} because of the time it takes to execute these commands themselves, but perhaps it's close enough for you.
Otherwise, the correct arithmetic expression is what Jonathan Leffler wrote:
oldtimestamp=$((current - 30*24*60*60*1000))
but note that things like leap seconds may throw you off in that approach.
I have a file "file_XYZ_18548".
Here the name's ending 18548 is a timestamp in days, and it is changing day by day, like "file_XYZ_18550".
I would like to get this date via variable but I couldn't find a date command to get the timestamp in days.
I can get the date result but I can't get the timestamp in reverse.
timeinday=18550
timestp=timeinday*86400
datetm=$(echo $timestp | gawk '{print(strftime("%Y-%m-%d %H:%M:%S", $0))}')
echo $datetm
2020-10-14 10:09:10
How can I get this with date command in bash scripting? Is there any way of this via awk/gawk etc..?
Given that 2020-10-14 - 18548 days corresponds to 1970-01-03, it is reasonable to guess that the 'epoch' for the day count is 1970-01-01. It is likely that day 1 was 1970-01-01, so day zero was 1969-12-31.
Converting day count to date
You can use the GNU date command like this:
daycount=18548
date -u -d "#$(( ($daycount-1) * 86400 ))" +"%Y-%m-%d %H:%M:%S"
That yields the result 2020-10-12 00:00:00. You can drop the time component of the format if you wish (you probably do; midnight isn't very exciting when it is always midnight). You can calibrate the -1 to resolve exactly what day should correspond to 18548. Just in case it isn't obvious, there are 86,400 seconds in a day (24 hours • 60 minutes per hour • 60 seconds per minute).
The $(( … )) notation is Bash's Arithmetic Expansion notation.
Converting current time to day count
If you want to convert the current time to the day offset, then you can use the %s specifier to get the seconds since 1970-01-01 00:00:00Z and divide by 86400 to get the number of days:
echo $(( $(date +'%s') / 86400 ))
which (at 2020-10-14 23:30 -06:00, aka 1602739800 seconds since the Unix Epoch) yields the result:
18550
Again, if need be, you can adjust the value of the division to account for when day 1 was in this scheme. Shell arithmetic in Bash is integer arithmetic, which is exactly what is wanted. You might need to use -u to get UTC as the time zone (as I did earlier), and so on.
This question already has answers here:
Bash script compare two date variables [duplicate]
(5 answers)
Closed 1 year ago.
I have to read a epoch timestamp (in seconds) from a directory /usr/local/healthcheck.txt on my Red Hate Enterprise Linux machine every ~10 minutes (polling). I need perform a comparison on the time to check if the timestamp in the healthcheck.txt file is OLDER than 50 minutes from the current time/timestamp OR if the healthcheck.txt is non-existent, to throw an error. The timestamp in the healthcheck.txt file generally looks like this (its in seconds, as stated above) :
1591783065
I was using date -d #1591783065 to convert the timestamp to Human Readable and get something like this:
Tue Jun 9 16:22:57 UTC 2020
What would be the best approach to compare the current timestamp to this timestamp in the file and check if its older than 50 minutes?
In Java , we have a Date package , and can just use compareTo to compare the times/dates, is there a simple way to do this with shell/bash scripts?
Why don't you stick with epoch-time? You can get the current time as seconds since epoch by
date +%s, so you just have to compare
if (( (healthcheck_time + 50*60) < $(date +%s) ))
then
# .... healthcheck older than 50 minutes
fi
I need a Bash script to accept 1 argument representing a time in hhmmss format, and from that derive a second time 3 minutes before that.
I've been trying to use date -d:
#! /bin/bash
DATE=`date +%Y%m%d`
TIME=$1
NEWTIME=`date -d "$DATE $TIME - 3 minutes" +%H%M%S`
echo $NEWTIME
In action:
$ ./myscript.sh 123456
invalid date `20141022 123456 - 3 minutes'
It seems the problem is with the 6 character time format because 4 characters (eg 1234) works. The subtraction of the 3 minutes is not the problem because I get the same error when I remove it.
It has occurred to me I could parse the time into a more palatable format before sending it to date. I tried inserting delimiters by adding this line:
TIME=${TIME:0:2}:${TIME:2:2}:${TIME:4:2}
It accepted that format but the answer to the - 3 minutes part was inexplicably very wrong (it subtracted 2 hours and 1 minute):
$ ./myscript.sh 123456
103356
Vexing.
It has also occurred to me that I might be able to provide date with an input format, like strptime which I'm familiar with from Python. I've found references to strptime in the context of Bash but I've been unable to get it to do anything.
Does anyone have any suggestions on getting the hhmmss time-string to work? Any help is much appreciated.
FYI: I'm trying to avoid changing the 6 character input format because that would involve changing other scripts as well as getting certain human users to alter long-entrenched habits. I'm also trying to avoid outsourcing this task to another language. (I could easily do this in Python). I want a Bash solution to this problem, if there is one.
TIME=093000
TIME=${TIME:0:2}:${TIME:2:2}:${TIME:4:2} # your line
date -d "2014-10-20 $TIME 3 mins ago" +%H%M%S
Output:
092700