I have two folders with many files of the same naming format but differing extensions. I would like to loop through the files of the first folder and extract their filenames to check if a file of the same name exists in the other folder, then create one (with the other extension) if it doesn't. I can't get a grapple on bash for whatever reason, so I was wondering if there's a simple way to do this.
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I have very little experience with the command line and I'm trying to do something very complicated (to me).
I have a directory with A LOT of subfolders and files in them. All file names contain the parent folder name, e.g.:
Folder1
data_Folder1.csv
other_file_Folder1.csv
Folder2
data_Folder2.csv
other_file_Folder2.csv
In another folder (all in one directory), I have a new version of all the data_FolderX.csv files and I need to replace them in the original folders. I cannot give them another name because of later analyses. Is there a way to replace the files in the original folders with the new version, in the command line?
I tried this Replacing a file into multiple folders/subdirectories but didn't work for me. Given that I have many .csv files in the derectories, I don't want to replace them all, so I don't think I should do it based on the file extension. I would also like to note that the name "FolderX" contains several other _, so in principal, I want to replace the .csv file starting with data in the FolderX.
Can anyone help?
Thanks in advance!
I would like some guide and help for this:
I have a text file with names listed in it. I will call it “source file”
I have multiple text files scattered in folders and sub folders
I would like to know how to make a script that would automatically add SPECIFIC LINE to every text file (in subfolders of chosen target folder) that contains exact name listed in “source file”
More detailed/Example:
I have a names.txt that contains many names. I want to find all the text files in target folder and it’s subfolders that contains names listed in names.txt and in those files automatically add “FALSE” line (in front or after specific existing line).
Kind of easy question, but I can't find the answer. I want to extract the contents of multiple zipped folders into a single directory. I am using the bash console, which is the only tool available on the particular website I am using.
For example, I have two folders: a.zip (which contains a1.txt and a2.txt) and b.zip (which contains b1.txt and b2.txt). I want to get extract all four text files into a single directory.
I have tried
unzip \*.zip -d \newdirectory
But it creates two directories (a and b) with two text files in each.
I also tried concatenating the two zipped folders into one big folder and extracting it, but it still creates two directories, even when I specify a new directory.
I can't figure what I am doing wrong. Any help?
Thanks in advance!
Use the -j parameter to ignore any directory structure.
unzip -j -d /path/to/your/directory '*.zip*'
I 7Zip'd a multi-gig folder which contained many folders each with many files using the split to volumes (9Meg) option. 7Zip created files of type .zip.001,
.zip.002, etc. When I extract .001 it appears to work correctly but I get an 'unexpected end of data' error. 7Zip does not automatically go to .002. When I extract .002, it also gives the same error and it does not continue the original folder/file structure. Instead it extracts a zip file in the same folder as the previously extracted files. How do I properly extract split files to obtain the original folder/file structure? Thank you.
I have a bunch of files I'm trying to organize quickly, and I had two questions about how to do that. I really appreciate any help! I tried searching but couldn't find anything on these specific commands for OSX.
First, I have about 100 folders in a directory - I'd like to place an folder in each one of those folders.
For example, I have
Cars/Mercedes/<br>
Cars/BMW/<br>
Cars/Audi/<br>
Cars/Jeep/<br>
Cars/Tesla/
Is there a way I can create a folder inside each of those named "Pricing" in one command, i.e. ->
Cars/Mercedes/Pricing <br>
Cars/BMW/Pricing<br>
Cars/Audi/Pricing<br>
Cars/Jeep/Pricing<br>
Cars/Tesla/Pricing
My second question is a little tougher to explain. In each of these folders, I'd like move certain files into these newly created folders (above) in the subdirectory.
Each file has a slightly different filename but contains the same string of letters - for example, in each of the above folders, I might have
Cars/Mercedes/payment123.html
Cars/BMW/payment432.html
Cars/Audi/payment999.html
Cars/Jeep/payment283.html
Is there a way to search each subdirectory for a file containing the string "payment" and move that file into a subfolder in that subdirecotry - i.e. into the hypothetical "Pricing" folders we just created above with one command for all the subdirectories in Cars?
Thanks so much~! help with either of these would be invaluable.
I will assume you are using bash, since it is the default shell in OS X. One way to do this uses a for loop over each directory to create the subdirectory and move the file. Wildcards are used to find all of the directories and the file.
for DIR in Cars/*/ ; do
mkdir "${DIR}Pricing"
mv "${DIR}payment*.html" "${DIR}Pricing/"
done
The first line finds every directory in Cars, and then runs the loop once for each, replacing ${DIR} with the current directory. The second line creates the subdirectory using the substitution. Note the double quotes, which are necessary only if the path could contain spaces. The third line moves any file in the directory whose name starts with "payment" and ends with ".html" to the subdirectory. If you have multiple files which match this, they will all be moved. The fourth line simply marks the end of the loop.
If you are typing this directly into the command line, you can combine it into a single line:
for DIR in Cars/*/ ; do mkdir "${DIR}Pricing"; mv "${DIR}payment*.html" "${DIR}Pricing/"; done