I have 2 entities and 1 embeddable object :
#Entity
class CourseDetails extends Course {
#Id
Integer id;
#ElementCollection
#CollectionTable(name = "course_section", joinColumns = #JoinColumn(name = "courseId"), foreignKey = #ForeignKey(name = "course_section_fk"))
private List<CourseSection> courseSection;
}
#Embeddable
public class CourseSection extends BaseBo {
#OneToMany
#JoinColumn(name="contentId")
private Set<CourseContent> courseContent = new HashSet<>();
}
#Entity
public class CourseContent {
private static final long serialVersionUID = 1856738483334146418L;
#Id
private Integer contentId;
private String contentSummary;
}
I want to store coursesection as an embedded object of course and course_section should contain reference of course_content. I tried the above structure but it gives error :
#ElementCollection cannot be used inside an #Embeddable that is also contained within an #ElementCollection
How to achieve this in spring boot-jpa ?
Related
i want to implement a many to many association with quantity information in it . like this :
#Entity
#Table(name = "reserves")
#Getter #Setter #NoArgsConstructor
public class Reserve {
#Id
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "groupe_id")
private GroupeSanguin bloodGroup;
#Id
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
private Banque banque;
private int quantity;
}
the GroupSanguin and the Banque are two class stored in the database two . here is the code for the two if you need :
#Entity
#Table(name = "groupe_sanguins")
public class GroupeSanguin {
#Id
private String groupe;
#OneToMany(mappedBy = "groupeSanguin")
private List<Donneur> donneurs;
}
#Entity #Getter #Setter #NoArgsConstructor
public class Banque {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#Column(unique = true,nullable = false)
private String nom;
private String adresse;
#Column(unique = true)
private String telephone;
private String localisation;
}
so my i want to know how to annotate the JpaRepository to take the two as primary key like this and is my annotation good for it to work ?
public interface ReserveRepository extends JpaRepository<
Reserve,
//what to put here ?
>
This isn't a JPA question in fact, it's a relationnal database conception.
If Reserve has is own data and links with other entity it has it own Id
You can add unicity constraint
#Entity
#Table(name = "reserves", uniqueConstraints={
#UniqueConstraint(columnNames = {"banque_id", "groupe_id"})
#Getter #Setter #NoArgsConstructor
public class Reserve {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "groupe_id")
private GroupeSanguin bloodGroup;
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "banque_id")
private Banque banque;
private int quantity;
}
i've found this solutions too.
#Entity
#Table(name = "reserves")
#Getter #Setter #NoArgsConstructor
#IdClass(ReserveId.class) //this annotation will tell that id that the
// the id will be represented by a class
public class Reserve {
#Id
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "groupe_id")
private GroupeSanguin groupeSanguin;
#Id
#ManyToOne(cascade = CascadeType.ALL,fetch = FetchType.EAGER)
#JoinColumn(name = "banque_id")
private Banque banque;
private int quantity;
}
and the id class should implements Serializable like this :
#Getter #Setter
public class ReserveId implements Serializable {
private Banque banque;
private GroupeSanguin groupeSanguin;
}
and finally the repository will be like that :
#Repository
public interface ReserveRepo extends JpaRepository<Reserve, ReserveId>{}
See your Reserve class has nowhere mentioned composite primary key. First you need to fix the model, You can refer to the solution here How to create and handle composite primary key in JPA
I have a entity call Circuit.
#Entity
public class Circuit implements Comparable<Circuit>, Serializable {
#Column
private String id;
#OneToMany(mappedBy = "circuit", cascade = CascadeType.ALL, fetch = FetchType.EAGER, orphanRemoval = true)
private Set<Step> workflow = new HashSet<>();
...
}
I have a class called CircuitLight
public class CircuitLight {
private String id;
private Set<Step> workflow;
/* constructor, getters and setters */
}
In my CircuitRepository, i'm trying to make a projection
#Transactional(readOnly = true)
#Query("select new com.docapost.circuit.CircuitLight(c.id, c.workflow) from Circuit c where c.account.siren = :siren")
Set<CircuitLight> findAllByAccountSirenProjection(#Param("siren") String siren);
When i execute, i have a error message:
could not extract ResultSet; SQL [n/a] com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'circuit0_.id' in 'on clause'
I try with other entity. Every time i have a property with a relation #OneToMany, i have the issue...
Is it possible to make a projection with class (Without use a interface) when there are a relation OneToMany ?
UPDATE:
Step.class
#Entity
public class Step implements Comparable<Step>, Serializable {
private static final List<String> INDEXABLE_PROCESSES = Arrays.asList(
ParapheurWorkflowModel.SERVER,
ParapheurWorkflowModel.SIGN,
ParapheurWorkflowModel.VISA
);
#Id
#GeneratedValue
#Expose
#SerializedName("step_id")
public long id;
#ManyToOne
public Circuit circuit;
#ManyToMany(cascade = CascadeType.ALL)
#JoinTable(joinColumns = #JoinColumn(name = "step_id"), inverseJoinColumns = #JoinColumn(name = "technicalGroup_id"))
private List<TechnicalGroup> technicalGroups = new ArrayList<>();
#Column(name = "step_type", nullable = false)
#Expose
#SerializedName("subprocess_ref")
public String type;
#Column(nullable = false)
public int orderIndex;
/* contructor, getters and setters */
}
UPDATE 2:
Hum.... My bad, in my circuit class, i have a EmbeddedId
#EmbeddedId
private CircuitPK key;
#Embeddable
public static class CircuitPK implements Serializable {
public String id;
public String siren;
}
I try with this code in Step.class
#ManyToOne
#JoinColumns(value = {
#JoinColumn(name = "circuit_siren", referencedColumnName = "siren"),
#JoinColumn(name = "circuit_id", referencedColumnName = "id")
})
public Circuit circuit;
The result is the same
Write the following code in the Step entity
#ManyToOne
#JoinColumn(name="id", nullable=false)
private Circuit circuit;
I'm trying to have Spring Data JPA issue one query using joins to eagerly get a graph of entities:
#Entity
#NamedEntityGraph(name = "PositionKey.all",
attributeNodes = {#NamedAttributeNode("positionKey.account"),
#NamedAttributeNode("positionKey.product")
})
#Data
public class Position {
#EmbeddedId
private PositionKey positionKey;
}
#Embeddable
#Data
public class PositionKey implements Serializable {
#ManyToOne
#JoinColumn(name = "accountId")
private Account account;
#ManyToOne
#JoinColumn(name = "productId")
private Product product;
}
Here's my Spring Data repo:
public interface PositionRepository extends JpaRepository<Position, PositionKey> {
#EntityGraph(value = "PositionKey.all", type = EntityGraphType.LOAD)
List<Position> findByPositionKeyAccountIn(Set<Account> accounts);
}
This produces the following exception:
java.lang.IllegalArgumentException: Unable to locate Attribute with the the given name [positionKey.account] on this ManagedType
I want all of the accounts and products to be retrieved in one join statement with the positions. How can I do this / reference the embedded ID properties?
I would suggest refactoring the entity this way if it possible
#Entity
#NamedEntityGraph(name = "PositionKey.all",
attributeNodes = {#NamedAttributeNode("account"),
#NamedAttributeNode("product")
})
#Data
public class Position {
#EmbeddedId
private PositionKey positionKey;
#MapsId("accountId")
#ManyToOne
#JoinColumn(name = "accountId")
private Account account;
#MapsId("productId")
#ManyToOne
#JoinColumn(name = "productId")
private Product product;
}
#Embeddable
#Data
public class PositionKey implements Serializable {
#Column(name = "accountId")
private Long accountId;
#Column(name = "productId")
private Long productId;
}
Such an EmbeddedId is much easier to use. For instance, when you are trying to get an entity by id, you do not need to create a complex key containing two entities.
in my current project, I am using Hibernate with JPA.
I have entities as follows:
Entity A:
#Entity
#Table(name = "a")
public class A implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GenericGenerator(name = "uuid", strategy = "uuid2")
private String id;
#Column(name = "name")
private String name;
#OneToMany
private Set<Association> associations = new HashSet<>();
}
Entity B:
#Entity
#Table(name = "b")
public class B implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GenericGenerator(name = "uuid", strategy = "uuid2")
private String id;
#Column(name = "description")
private String description;
#OneToMany
private Set<Association> associations = new HashSet<>();
}
Entity Association:
#Entity
#Table(name = "association")
public class Association implements Serializable {
private static final long serialVersionUID = 1L;
#ManyToOne
#JoinColumn(name = "a_id", referencedColumnName = "id")
A a;
#ManyToOne
#JoinColumn(name = "b_id", referencedColumnName = "id")
B b;
...other columns..
}
Now I would like to implement repository layer for A as follows:
#Repository
public interface ARepository extends JpaRepository<A, Long> {
//Here I would like to write the function/query get all the As with many-to-many relationships.
}
I have two entities in one to many relationship in my spring-data-jpa project.
Parent entity -
#Entity
#Table(name = "code_group")
public class CodeGroup implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE)
private Long id;
#NaturalId
#Column(nullable = false)
private String entityId;
#OneToMany
#JoinColumn(name = "codeGroupId", referencedColumnName = "entityId")
private List<SystemCode> systemCodes;
// .. getters setters
}
Child entity -
#Entity
#Table(name = "system_code")
public class SystemCode implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE)
private Long id;
#Column(nullable = false)
private String codeGroupId;
#Column(nullable = false)
#Enumerated(EnumType.STRING)
private ActiveOrInactive status;
// getters and setters
}
status column is of enum type, it can only have Active or Inactive value.
My existing code works fine. It is fetching code group with associated system codes. I want to filter system code with status='Active'. How to do this?
Try like this:
#OneToMany
#JoinColumn(name = "codeGroupId", referencedColumnName = "entityId")
#Where(clause = "status= 'Active'")
private List<SystemCode> systemCodes;
You can create such methods in your repo:
List<CodeGroup> getAllBySystemCodes_Status(ActiveOrInactive status);
default List<CodeGroup> getAllActive() {
return getAllBySystemCodes_Status(ActiveOrInactive.Active);
}
default List<CodeGroup> getAllInactive() {
return getAllBySystemCodes_Status(ActiveOrInactive.Inactive);
}