JPA one to many, fetch children with specific column value - spring-boot

I have two entities in one to many relationship in my spring-data-jpa project.
Parent entity -
#Entity
#Table(name = "code_group")
public class CodeGroup implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE)
private Long id;
#NaturalId
#Column(nullable = false)
private String entityId;
#OneToMany
#JoinColumn(name = "codeGroupId", referencedColumnName = "entityId")
private List<SystemCode> systemCodes;
// .. getters setters
}
Child entity -
#Entity
#Table(name = "system_code")
public class SystemCode implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.SEQUENCE)
private Long id;
#Column(nullable = false)
private String codeGroupId;
#Column(nullable = false)
#Enumerated(EnumType.STRING)
private ActiveOrInactive status;
// getters and setters
}
status column is of enum type, it can only have Active or Inactive value.
My existing code works fine. It is fetching code group with associated system codes. I want to filter system code with status='Active'. How to do this?

Try like this:
#OneToMany
#JoinColumn(name = "codeGroupId", referencedColumnName = "entityId")
#Where(clause = "status= 'Active'")
private List<SystemCode> systemCodes;

You can create such methods in your repo:
List<CodeGroup> getAllBySystemCodes_Status(ActiveOrInactive status);
default List<CodeGroup> getAllActive() {
return getAllBySystemCodes_Status(ActiveOrInactive.Active);
}
default List<CodeGroup> getAllInactive() {
return getAllBySystemCodes_Status(ActiveOrInactive.Inactive);
}

Related

Spring Data Projection with OneToMany error

I have a entity call Circuit.
#Entity
public class Circuit implements Comparable<Circuit>, Serializable {
#Column
private String id;
#OneToMany(mappedBy = "circuit", cascade = CascadeType.ALL, fetch = FetchType.EAGER, orphanRemoval = true)
private Set<Step> workflow = new HashSet<>();
...
}
I have a class called CircuitLight
public class CircuitLight {
private String id;
private Set<Step> workflow;
/* constructor, getters and setters */
}
In my CircuitRepository, i'm trying to make a projection
#Transactional(readOnly = true)
#Query("select new com.docapost.circuit.CircuitLight(c.id, c.workflow) from Circuit c where c.account.siren = :siren")
Set<CircuitLight> findAllByAccountSirenProjection(#Param("siren") String siren);
When i execute, i have a error message:
could not extract ResultSet; SQL [n/a] com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: Unknown column 'circuit0_.id' in 'on clause'
I try with other entity. Every time i have a property with a relation #OneToMany, i have the issue...
Is it possible to make a projection with class (Without use a interface) when there are a relation OneToMany ?
UPDATE:
Step.class
#Entity
public class Step implements Comparable<Step>, Serializable {
private static final List<String> INDEXABLE_PROCESSES = Arrays.asList(
ParapheurWorkflowModel.SERVER,
ParapheurWorkflowModel.SIGN,
ParapheurWorkflowModel.VISA
);
#Id
#GeneratedValue
#Expose
#SerializedName("step_id")
public long id;
#ManyToOne
public Circuit circuit;
#ManyToMany(cascade = CascadeType.ALL)
#JoinTable(joinColumns = #JoinColumn(name = "step_id"), inverseJoinColumns = #JoinColumn(name = "technicalGroup_id"))
private List<TechnicalGroup> technicalGroups = new ArrayList<>();
#Column(name = "step_type", nullable = false)
#Expose
#SerializedName("subprocess_ref")
public String type;
#Column(nullable = false)
public int orderIndex;
/* contructor, getters and setters */
}
UPDATE 2:
Hum.... My bad, in my circuit class, i have a EmbeddedId
#EmbeddedId
private CircuitPK key;
#Embeddable
public static class CircuitPK implements Serializable {
public String id;
public String siren;
}
I try with this code in Step.class
#ManyToOne
#JoinColumns(value = {
#JoinColumn(name = "circuit_siren", referencedColumnName = "siren"),
#JoinColumn(name = "circuit_id", referencedColumnName = "id")
})
public Circuit circuit;
The result is the same
Write the following code in the Step entity
#ManyToOne
#JoinColumn(name="id", nullable=false)
private Circuit circuit;

Fetching all entities with many to many relationships in repository layer : Hibernate with JPA

in my current project, I am using Hibernate with JPA.
I have entities as follows:
Entity A:
#Entity
#Table(name = "a")
public class A implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GenericGenerator(name = "uuid", strategy = "uuid2")
private String id;
#Column(name = "name")
private String name;
#OneToMany
private Set<Association> associations = new HashSet<>();
}
Entity B:
#Entity
#Table(name = "b")
public class B implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GenericGenerator(name = "uuid", strategy = "uuid2")
private String id;
#Column(name = "description")
private String description;
#OneToMany
private Set<Association> associations = new HashSet<>();
}
Entity Association:
#Entity
#Table(name = "association")
public class Association implements Serializable {
private static final long serialVersionUID = 1L;
#ManyToOne
#JoinColumn(name = "a_id", referencedColumnName = "id")
A a;
#ManyToOne
#JoinColumn(name = "b_id", referencedColumnName = "id")
B b;
...other columns..
}
Now I would like to implement repository layer for A as follows:
#Repository
public interface ARepository extends JpaRepository<A, Long> {
//Here I would like to write the function/query get all the As with many-to-many relationships.
}

Get data from multiple tables using one Mapping Table in Spring Boot

Procedure.java
#Entity
#Table(name = "procedures")
#JsonIgnoreProperties({ "hibernateLazyInitializer", "handler" })
public class Procedure implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "ProcedureId")
private int id;
#Column(name = "ProcedureName")
private String name;
#Column(name = "ProcedureCode")
private String code;
#Column(name = "ProcedureDesc")
private String desc;
// getters and setters
}
CPTClinicianDescriptor
#Entity
#Table(name = "cliniciandescriptor")
public class CPTClinicianDescriptor {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "Id")
private int id;
#Column(name = "ConceptId")
private int conceptId;
#Column(name = "CPTCode")
private String cptCode;
#Column(name = "ClinicianDescriptorId")
private int clinicianDescriptorId;
#Column(name = "ClinicianDescriptor")
private String clinicianDescriptor;
// getters and setters
}
CPTProcedures
#Entity
#Table(name = "cptprocedures")
public class CPTProcedures {
#Id
#GeneratedValue(strategy = GenerationType.IDENTITY)
#Column(name = "Id")
private int Id;
#OneToOne(fetch=FetchType.EAGER)
#JoinColumn(name = "ProcedureId")
private Procedure procedure;
#Transient
private int procedureId;
#OneToOne(fetch=FetchType.EAGER)
#JoinColumn(name = "CPTCodeSet")
private CPTClinicianDescriptor cptClinicianDescriptor;
#Transient
private int cptCodeSet;
// getters and setters
}
Here I have 3 table in mySql in those 2 are different separate tables, I created one table for Mapping that has foreign keys of Procedures and CPT when i get a list using Procedure It should get corresponding cpt data also.
ServiceImpl Like:
public List<Procedure> getCombinedProcedureList(int id) {
// TODO Auto-generated method stub
List<Procedure> pList = new ArrayList<Procedure>();
Procedure procedureList = procedureRepository.findCombById(id);
pList.add(procedureList);
return pList;
}
When i use
Repository like
#Query(value = "SELECT * FROM procedures JOIN cliniciandescriptor ON cliniciandescriptor.Id = ?1",nativeQuery = true)
Procedure findCombById(int id);
this query in Procedures Repository it is getting only procedures. So, what can i do to get the combined(joined) list of 2(procedures & CPT) tables using 3rd mapping table.

Spring JPA: How to insert data to join many tables with #ManytoMany relationship

I'm starting to learn Spring Java Framework . I created some Enity to join 2 Model like my Database. And now I want to insert to Join Table by JpaRepository. What i have to do?
This is my Code (Please fix help me me if something is not right)
Model Users_RoomId to define Composite Primary Key
#Embeddable
public class Users_RoomId implements Serializable {
private static final long serialVersionUID = 1L;
#Column(name = "ID_room", nullable = false)
private String idRoom;
#Column(name = "user_id", nullable = false)
private int idUser;
}
Model Users_Room to join 2 Model Users and Room
#Entity
#Table(name ="bookroom")
public class Users_Room {
#EmbeddedId
private Users_RoomId usersroomId;
#ManyToOne
#MapsId("idRoom")
private Room room;
#ManyToOne
#MapsId("idUser")
private Users users;
#Column(name = "Bookday")
private String bookday;
Model Users and Room I used annotation #OneToMany
Model Users
#Entity
#Table(name = "users")
public class Users implements Serializable{
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "user_id", nullable = false)
private int id;
#Column(name = "name", nullable = false)
private String name;
#Column(name = "email")
private String email;
#Column(name = "pass")
private String pass;
#Column(name = "role")
private int role;
#OneToMany(mappedBy = "users")
private List<Users_Room> user;
Model Room
#Entity
#Table(name ="room")
public class Room implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy = GenerationType.AUTO)
#Column(name = "ID_room", nullable = false)
private String id;
#Column(name = "name_room", nullable = false)
private String name;
#Column(name = "Description")
private String describe;
#ManyToOne
#JoinColumn(name = "ID_status")
private Status status;
#Column(name = "room_image")
private String image;
public Room() {
super();
}
#ManyToOne
#JoinColumn(name = "ID_kind")
private KindRoom kind;
#OneToMany(mappedBy = "room")
private List<Users_Room> rooms;
This is my database
So I don't know how to insert a new bookroom with iduser,idroom and bookday with JPA repository.. It'necessary to write Query in JPARepository or We just need to use method save() to insert data
Thanks everyone
I had same problem and solved with following code. I used method save() to insert data. Following code is 'createRoom' method in 'RoomService.java'.
RoomService.java
private final RoomRepository roomRepository;
private final UserRoomRepository userRoomRepository;
private final UserRepository userRepository;
public RoomService(RoomRepository roomRepository, UserRoomRepository userRoomRepository, UserRepository userRepository) {
this.roomRepository = roomRepository;
this.userRoomRepository = userRoomRepository;
this.userRepository = userRepository;
}
#Transactional
public RoomDto createRoom(Long userId, Long chattingUserId) {
Room room = roomRepository.save(new Room());
room.addUserRoom(userRepository.findById(userId).orElseThrow(()->new NoSuchElementException("No User")));
room.addUserRoom(userRepository.findById(chattingUserId).orElseThrow(()->new NoSuchElementException("No User")));
userRoomRepository.save(new UserRoom(userRepository.findById(userId).orElseThrow(()->new NoSuchElementException("No User")),room));
userRoomRepository.save(new UserRoom(userRepository.findById(chattingUserId).orElseThrow(()->new NoSuchElementException("No User")),room));
RoomDto roomDto = RoomDto.of(room);
return roomDto;
}

Hibernate 4 Entity Mapping with Spring

I've got 2 entity classes as follows:
#Entity
#Table(name = "USER_ACCT")
public class UserAccount implements Serializable{
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy=GenerationType.SEQUENCE, generator="USER_ACCT_ID_SEQ")
#SequenceGenerator(name="USER_ACCT_ID_SEQ", sequenceName="USER_ACCT_ID_SEQ")
#Column(name = "USER_ACCT_ID")
protected Long id;
#Basic(optional = false)
#Column(length = 50, unique = true)
private String username;
#Basic(optional = false)
#Column(length = 128, nullable = false)
private String password;
#ManyToMany(targetEntity = UserPermission.class)
#JoinTable(name = "USER_ACCT_PERM",
joinColumns = #JoinColumn(name = "USER_ACCT_ID"),
inverseJoinColumns = #JoinColumn(name = "USER_PERM_ID", referencedColumnName = "USER_PERM_ID"))
private Set<UserPermission> permissions;
// getters and setters...
}
AND
#Entity
#Table(name = "USER_PERM")
public class UserPermission implements Serializable {
private static final long serialVersionUID = 1L;
#Id
#GeneratedValue(strategy=GenerationType.SEQUENCE, generator="USER_PERM_ID_SEQ")
#SequenceGenerator(name="USER_PERM_ID_SEQ", sequenceName="USER_PERM_ID_SEQ")
#Column(name = "USER_PERM_ID")
protected Long id;
#Column(name = "PERM", unique = true, length = 255, nullable = false)
private String authority;
// getters and setters...
}
Now when I create an object of UserAccount and try to save it using the session factory it gives me the following error:
org.hibernate.TransientObjectException: object references an unsaved transient instance - save the transient instance before flushing: com.rpm.domain.UserPermission
Shouldn't the UserPermission class be saved by itself??
This is the code that is used to persist:
#Transactional
public void addUser(){
Set<UserPermission> permissions = new HashSet<UserPermission>();
permissions.add(new UserPermission("ROLE_ADMIN"););
sessionFactory.getCurrentSession().save(new UserAccount("admin", "d033e22ae348aeb5660fc2140aec35850c4da997", permissions));
}
Not unless you specify the cascade options.

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