how do I replace a information Fromm csv file? - bash

Question

I have the following program
#!/bin/bash
exec 3< lista.csv
read -u 3 header
declare -i id_nou
echo "ID: "
read id_nou
while IFS=, && read -u 3 -r id nume prenume seria grupa nota
do
if [ "$id_nou" -eq "$id" ]
then
echo "Nota noua: "
read nota_noua
nota=$nota_noua
print > lista.csv
fi
done
My csv file looks something like this:
id,nume,prenume,grupa,seria,nota
1,Ion,Andrada,1003,A,8
2,Simion,Raluca,1005,A,7
3,Gheorghita,Mihail,1009,B,5
4,Mihailescu,Georgina,1002,A,6
What I'm trying to do is replace the nota value of the correspondent's id with a given by the keyboard value, but this doesn't seem to work.
The error message is
line 14: print: command not found

Answer 1

Here's one in awk:
awk 'BEGIN {
FS=OFS="," # comma field separators
printf "id: " # ask for id
if((getline id < "/dev/stdin")<=0) # store to a variable
exit 1
printf "nota: " # ...
if((getline nota < "/dev/stdin")<=0)
exit 1
}
$1==id { # if firsst field matches
$NF=nota # replace last field value
}
1' file # output
Output:
id: 1
nota: THIS IS NEW VALUE
id,nume,prenume,grupa,seria,nota
1,Ion,Andrada,1003,A,THIS IS NEW VALUE
2,Simion,Raluca,1005,A,7
3,Gheorghita,Mihail,1009,B,5
4,Mihailescu,Georgina,1002,A,6
Here is some info on saving the changes.