I have to set the start date as 01-01-year which would be pulled from the expense date field. I have written the below query
select to_date(extract(year from rpt.expense_date),'yyyy') from rpt
How can I set the date to 01-01-year which would be pulled from above query.
Thanks in advance.
Use TRUNC to truncate to the start of the year:
SELECT TRUNC(expense_date, 'YY') FROM rpt
You can just truncate the date value:
trunc(rpt.expense_date, 'YYYY')
By default the trunc() function truncates to midnight on the specified day, equivalent to trunc(<date>, 'DD'), but you can use other elements.
In your code:
to_date(extract(year from rpt.expense_date),'yyyy')
you are only supplying the year element to to_date(); in that situation the other date elements default to the first day of the current month - so today that would give you June 1st in that year, not January 1st. That's hidden away a bit in the documentation:
If you specify a date value without a time component, then the default time is midnight. If you specify a date value without a date, then the default date is the first day of the current month.
Related
How to convert the difference of 2 dates with a timestamp to date with timestamp again, Oracle giving number but i want to compare timestamp.
select emp_date>to_date(sysdate,'yyyy-MM-dd HH24:MI:SS')-todate('2021-03-22 10:20:12') from emp;
above query giving error: expected date but got NUMBER.
Thanks in advance
What you are saying makes no sense. Difference of two DATE datatype values is number of days between them. For example
SQL> select sysdate - to_date('21.03.2021 13:12', 'dd.mm.yyyy hh24:mi') diff from dual;
DIFF
----------
,943217593
SQL>
You CAN convert it to a prettier format (days, hours, minutes, seconds), but it is still a NUMBER, it is not a date.
Therefore, you can't compare EMP_DATE (which is a DATE datatype column, isn't it?) to a number as it just doesn't make sense.
Is 22nd of March 2021 larger or smaller than 0.94? It's neither.
[TL;DR] You cannot as your data types do not match and it does not make sense to compare a date/time value to an interval.
If you do:
date_value1 - date_value2
You will get a NUMBER data type representing the number of (fractional) days between the two date values.
You can explicitly cast the subtraction operation to get an INTERVAL DAY TO SECOND data type using:
(date_value1 - date_value2) DAY TO SECOND
So, for your code that would be:
SELECT emp_date > ( sysdate - TO_DATE( '2021-03-22 10:20:12', 'YYYY-MM-DD HH24:MI:SS' ) ) DAY TO SECOND
FROM emp;
However, that will fail as you cannot compare a DATE to an INTERVAL DAY TO SECOND and SQL does not have a boolean data type so > does not make sense.
To fix that later point you could use a CASE expression but the difference in data types is a show-stopper as you can't compare a date to an interval.
but i want to compare timestamp.
You don't have a TIMESTAMP data type, you have either a number (representing an interval in days) or an INTERVAL data type. If you want to convert it back to a DATE or TIMESTAMP then you need to add your interval to an epoch value.
Can we assign a default value '0000-00-00 00:00:00' in oracle as we do in mysql as shown below ?
Sample query in mysql:
ALTER TABLE . MODIFY COLUMN TIMESTAMP DEFAULT '0000-00-00 00:00:00';
No - in Oracle neither year, month, or day can be set to zero. I suggest using NULL instead.
dbfiddle here
EDIT
Of course, having now gone back through one of my old questions and crawled down a wormhole or two I see that you can get a year of zero to be accepted - but it still appears that month and day cannot be zero. To get the year of zero in you have to use an ANSI date literal - e.g. DATE '0000-01-01' is considered acceptable. I don't know if the various date routines and date calculations will like this - for example, TO_CHAR(DATE '0000-01-01', 'DD-MON-YYYY') produces a result of '00-000-0000', which is certainly not what I'd expect, but perhaps it's good enough for your purposes. Note that you can't go the other way with this - TO_DATE('00-000-0000', 'DD-MON-YYYY') produces the expected ORA-01847 - day of month must be between 1 and last day of month error.
Does anybody really know what time it is..? :-)
How can I convert date to the order day of the month in ORACLE?
Ex: 31/07/2000 -> "Monday, the Thirty-First of July, 2000".
Is there any format date which can solve this problem?
Thanks so much!
Yes, there is - you need to combine some format elements (and modifiers) with a bit of boilerplate text (to add "the" and "of"). Like this:
select to_char( to_date('31/07/2000', 'dd/mm/yyyy')
, 'fmDay, "the " Ddspth "of" Month, yyyy') as spelled_out_date
from dual;
SPELLED_OUT_DATE
---------------------------------------
Monday, the Thirty-First of July, 2000
Note that, while the names of days of the week and calendar months depend on your session's then-current NLS_DATE_LANGUAGE, the Ddspth element will always be in English. So, alas, this solution DOES NOT WORK for other languages.
I am new to OBIEE
I have date in ddmmyyyy format .
How can i create Year, Quarter, Month as separate fields out of that?
Example:
Order_date
21/11/2017
02/09/2016
OutPut
Year
2017
2016
Month
11
09
In OBIEE a time value (i.e. now()) evaluates to quarter of year as:
qarter_of_year(now())
to year as:
year(now())
to month as
month(now())
+1 to Christian - just use the actual OBI functions!
If it doesn't work you are probably not working with actual DATE data types but some numerical or varchar types.
I have a column name 'Cos_Date' with value like 14APR2017:00:00:00.
However, for a new column name 'Arrival_Date', I would like to keep the date information but omit time, and keep the data type as Date but not Character. Ex, 14APR2017.
I have tried:
select TO_CHAR(Cos_Date, 'DD-MON-YYYY') ARRIVAL_DATE
But it will delete time information, but data type turns to Character.
I search on this site, and tried both:
select TO_DATE(TO_CHAR(Cos_Date, 'DD-MON-YYYY'), 'DD-MON-YYYY') ARRIVAL_DATE
and:
select TRUNC(Cos_Date) ARRIVAL_DATE
But it will not omit time information.
Can I try something else?
Thank you!
You can't "omit" the time portion of a DATE column in Oracle. The DATE data type always contains a time component. If you don't want to see the time, don't display it, e.g.,
SELECT TO_CHAR(TRUNC(Cos_Date),'DD-MON-YYYY') FROM dual;
In Oracle there is no date data type that has only a year-month-day component.
The DATE data type is stored internally as 7- or 8-bytes which always has year (2-bytes), month (1-byte), day (1-byte), hour (1-byte), minute (1-byte) and second (1-byte).
The TIMESTAMP data type also has fractional seconds (and can also have a time zone).
Can I try something else?
No, you either use a VARCHAR2 string or use a DATE or TIMESTAMP and accept that it has a time component.
Selecting date values without time:
SELECT date_col
FROM table
WHERE TO_CHAR (date_col, 'HH24:MI:SS') = '00:00:00';