I have Spring Boot Security app with login form which works with BCryptPasswordEncoder.
My user has password 100.
So what I should put as a password in login form - hash of number 100?
like $2a$12$X.omeLbXLKHzA9Hp5hNY8.Buc0Fuisz6eG0gyizubZPu0l2pgwKM.?
If user's password already exists in DB as a hash, just put 100 as a password. Spring Security automatically gets hash of your input and compares it with DB hash.
Related
I need to hash and salt user entered passwords and store it in the database. I also need to validate the hashed & salted password when a user login to the site.
I read from the following adobe blog by David Byers:
https://coldfusion.adobe.com/2020/04/best-practices-secure-password-storage-coldfusion/
This blog explains and gives sample codes on how to hash and add salt to user password with screen shots.
My First question is:
Do I need to create two columns in my database table to store the hashed password and the salt just like how he explained in this blog?
If yes,
than my second question is:
How do I validate user password that's been hashed and salted? If the values of hashed and salted password are separated in two columns like that do I have to concatenate the two strings when validating?
My last question is:
How to authenticate/validate user password when the password is hashed and salted? is there any codes example I can see? Thank you
I'm trying to understand how spring security can match the raw password entered by user with the encoded password in the database in the case of random password salting by BCryptPasswordEncoder.
My questions: AFSK bcrypt(random salt + password) = random encoded password, so since bcrypt is a one-way hashing function and the encoded password is fixed in the database, I guess spring security will somehow get the salt while encoding password and before check matches using BCryptPasswordEncoder：boolean matches(java.lang.CharSequence rawPassword, java.lang.String encodedPassword), right?
If so, where the salt is stored, in the database or somewhere else?
If salt is in the database, how to defend against cracking if the database is exposed?
The salt is stored in the same column as the hashed password. Salts are not considered to be secret. Since each is unique it prevents pre-calculating rainbow tables.
If you want higher security, consider peppering (password stays in application and HMACs the salted hashes)
I have 2 database tables consisting of 2 different user types.
Users and Players.
Players is with user data from in-game plugin where passwords are BCrypted.
Users one is empty and is intended to store the user info from the Players table.
I am comparing the usernames and passwords.
The problem is that from the user input in the website get plain text password, and from the other table the passwords are already bcrypted and the Laravel bcrypt does not match the bcrypted cipher from Players table.
What are my options to compare the passwords in order to confirm that this is the user trying to log in.
In-game plugin cipher:
$2a$10$lpVYpSJ4O6Mt03eItJeipOWR8LGHP8dgk4a09.e6BFKVoYNAgjz86
Laravel plain text bcrypted:
$2y$10$yZoq3xBsfow49pL6UyGD2.5NKlmHOmfnCFc9JD5ZjDz3pf5K1XMhG
Both passwords are the same.
Try using Hash::check() function to compare plain password and hashed password.
if (Hash::check('plain-text', $hashedPassword)) {
// The passwords match...
}
I found a solution, by using a library which helped me integrate the plugin on my website.
On top of that I had to do some minor configurations in the config file of the plugin. Changing the encryption method, so it matches the one in my Laravel application (BCrypt).
Later on I found out that I don't need to decrypt the password but just compare the hashes.
i want a authentication ,many people to login with a particular username and password at the same time and it is not good , where User A logs in with username = sammy and password = sammy123, User B cannot login with the same username = sammy and in one session password = sammy123 while I am still logged into an application...,i am using ruby 1.8.7 and devise gem for authentication, rails 2
1.add a column(flag) in table mdl_user store a 'false' value when user create new account .
2.Make a function which accept three value table name,flag field and username(which user enter) .this function return the value of flag field (true or false) .This function call if the user exist in database.
2.1 if 'false' returned then allow to login user and insert value into flag field 'true'.
2.2 if 'true'retuned then do not allow to login and print the message below the username and password field "This user already logged".Do not insert any value in database.
2.3 Now when sign out user then insert into flag field value 'flase'.
3.User allow to login only when flag field value 'false'.
better use this link http://www.gotealeaf.com/blog/how-to-use-devise-in-rails-for-authentication and check the version of devise gem you had used in your application.
I'm working on a Razor project and need to integrate an existing User database into the SimpleMembership Provider DB Schema. This is done by specifying my existing User table and which columns are to be used by the SimpleMembership API for the Username and UserID.
WebSecurity.InitializeDatabaseConnection("DB_ConnStr", "User", "UserId", "Username", true);
In the process though, I am populating the webpages_Membership table with a new record for each User row in my existing database. This has gone fine and I have written some code to handle the inserts for each existing user.
During the insert, I use a dummy encrypted password token for simplicity and set the password to be the same for everyone. Then I need to run another script over the records to set the correct password for each user in the webpages_Membership table. This involves decrypting the current password from the existing User table, and then calling:
WebSecurity.ChangePassword( username, dummyPwd, newPwd)
on each user, passing the decrypted current password as the 'newPwd' parameter.
This works fine in 99% of the cases that it's called - for over 100,000 records. But it is failing in about 40 cases.
What reasons could cause this method to fail?
My first guess would be that the hash of the new password might be exceeding the 128 character limit.
When the ChangePassword call fails, can you catch the exception to get details behind the reason of the failure?