IDENTITY full-time and part-time students - oracle

have a query and test CASE that shows the number of full-time and part-time students. A full-time student is enrolled in at least 4 courses. A part-time student is enrolled in at least 1 course, but no more than 3.
Although the query appears to work it seems a bit verbose. I was wondering if there is a more succinct way to rewrite the query. In addition, I can would like to display the students first/last names with each row that meets the criteria
Perhaps with something like this?
, LISTAGG(
NVL2(s.student_id, s.last_name || ', ' || s.first_name, NULL),
'; '
) WITHIN GROUP (ORDER BY s.last_name, s.first_name) AS students
Below are my tables, data and query I would like to shorten if possible. Thanks to all who answer and for your expertise.
CREATE TABLE students(student_id, first_name, last_name) AS
SELECT 1, 'Faith', 'Aaron' FROM dual UNION ALL
SELECT 2, 'Lisa', 'Saladino' FROM dual UNION ALL
SELECT 3, 'Leslee', 'Altman' FROM dual UNION ALL
SELECT 4, 'Patty', 'Kern' FROM dual UNION ALL
SELECT 5, 'Beth', 'Cooper' FROM dual UNION ALL
SELECT 95, 'Zak', 'Despart' FROM dual UNION ALL
SELECT 96, 'Owen', 'Balbert' FROM dual UNION ALL
SELECT 97, 'Jack', 'Aprile' FROM dual UNION ALL
SELECT 98, 'Nicole', 'Kramer' FROM dual UNION ALL
SELECT 99, 'Jill', 'Coralnick' FROM dual;
CREATE TABLE student_courses (student_id,course_id) AS
SELECT 1, 1 FROM dual UNION ALL
SELECT 2, 1 FROM dual UNION ALL
SELECT 3, 1 FROM dual UNION ALL
SELECT 4, 1 FROM dual UNION ALL
SELECT 5, 1 FROM dual UNION ALL
SELECT 1, 2 FROM dual UNION ALL
SELECT 2, 2 FROM dual UNION ALL
SELECT 3, 2 FROM dual UNION ALL
SELECT 4, 2 FROM dual UNION ALL
SELECT 5, 2 FROM dual UNION ALL
SELECT 1, 3 FROM dual UNION ALL
SELECT 2, 3 FROM dual UNION ALL
SELECT 3, 3 FROM dual UNION ALL
SELECT 4, 3 FROM dual UNION ALL
SELECT 5, 3 FROM dual UNION ALL
SELECT 97, 1 FROM dual UNION ALL
SELECT 97, 3 FROM dual UNION ALL
SELECT 97, 5 FROM dual UNION ALL
SELECT 97, 6 FROM dual UNION ALL
SELECT 98, 3 FROM dual UNION ALL
SELECT 98, 4 FROM dual UNION ALL
SELECT 98, 5 FROM dual UNION ALL
SELECT 99, 2 FROM dual UNION ALL
SELECT 99, 4 FROM dual UNION ALL
SELECT 99, 5 FROM dual UNION ALL
SELECT 99, 6 FROM dual;
WITH enrolled_student_course_counts AS (
SELECT
s.student_id
, s.first_name
, s.last_name
, COUNT(sc.course_id) AS course_count
FROM students s
LEFT JOIN student_courses sc
ON s.student_id = sc.student_id
GROUP BY
s.student_id
, s.first_name
, s.last_name
HAVING COUNT(sc.course_id) > 0
)
, student_enrollment_statuses AS (
SELECT
student_id
, first_name
, last_name
, CASE WHEN course_count >= 4 THEN 'full-time'
WHEN course_count BETWEEN 1 AND 3 THEN 'part-time'
END AS student_enrollment_status
FROM enrolled_student_course_counts
)
SELECT
UPPER(student_enrollment_status) AS student_enrollment_status
, COUNT(student_enrollment_status) AS student_enrollment_status_count
FROM student_enrollment_statuses
GROUP BY student_enrollment_status;

As you only need the numbers (and not any other data), shorten the query so that it searches only the student_courses table:
SQL> with temp as
2 (select student_id,
3 count(course_id) cnt
4 from student_courses
5 group by student_id
6 )
7 select
8 sum(case when cnt < 4 then 1 else 0 end) part_time,
9 sum(case when cnt >= 4 then 1 else 0 end) full_time
10 from temp;
PART_TIME FULL_TIME
---------- ----------
6 2
SQL>

Related

Use listagg to group all students for teacher, course, semster

I have a relationship where a teacher -> courses -> enrollmenr-> students. I am trying to use listagg to get all the students first/last names on the same line as the teacher_id and course_id. In addition, I want to add the count of each teacher_id, course_id, semester.
Below is my test CASE, which has the tables, data and a part of the query. I would appreciate any help completing the query. Thanks in advance to all who answer.
CREATE TABLE teachers(teacher_id, first_name, last_name) AS
SELECT 101, 'Keith', 'Stein' FROM dual UNION ALL
SELECT 102, 'Roger', 'Wood' FROM dual UNION ALL
SELECT 103, 'Douglas', 'Kern' FROM dual UNION ALL
SELECT 104, 'Paul', 'Weber' FROM dual UNION ALL
SELECT 105, 'Jeffrey', 'Lebowitz' FROM dual UNION ALL
SELECT 106, 'Carol', 'Seltzer' FROM dual;
CREATE TABLE students(student_id, first_name, last_name) AS
SELECT 1, 'Faith', 'Aaron' FROM dual UNION ALL
SELECT 2, 'Lisa', 'Saladino' FROM dual UNION ALL
SELECT 3, 'Leslee', 'Altman' FROM dual UNION ALL
SELECT 4, 'Patty', 'Kern' FROM dual UNION ALL
SELECT 5, 'Beth', 'Cooper' FROM dual UNION ALL
SELECT 99, 'Jill', 'Coralnick' FROM dual;
CREATE TABLE courses(course_id, course_name, teacher_id, semester) AS
SELECT 1, 'Geometry', 101, '2022-2' FROM DUAL UNION ALL
SELECT 2, 'Trigonometry', 102, '2022-2' FROM DUAL UNION ALL
SELECT 3, 'Calculus', 103, '2022-2' FROM DUAL UNION ALL
SELECT 4, 'Chemistry', 104, '2022-2' FROM DUAL UNION ALL
SELECT 5, 'Biology', 105, '2022-2' FROM DUAL UNION ALL
SELECT 6, 'Physcology', 106, '2022-2' FROM DUAL;
CREATE TABLE enrollment(student_id,course_id) AS
SELECT 1, 1 FROM dual UNION ALL
SELECT 2, 1 FROM dual UNION ALL
SELECT 3, 1 FROM dual UNION ALL
SELECT 4, 1 FROM dual UNION ALL
SELECT 5, 1 FROM dual UNION ALL
SELECT 1, 2 FROM dual UNION ALL
SELECT 2, 2 FROM dual UNION ALL
SELECT 3, 2 FROM dual UNION ALL
SELECT 4, 2 FROM dual UNION ALL
SELECT 5, 2 FROM dual UNION ALL
SELECT 1, 3 FROM dual UNION ALL
SELECT 2, 3 FROM dual UNION ALL
SELECT 3, 3 FROM dual UNION ALL
SELECT 4, 3 FROM dual UNION ALL
SELECT 5, 3 FROM dual UNION ALL
SELECT 99, 3 FROM dual;
/* list all teachers, courses, student count, all students for teacher_id, course_id, semester
*/
SELECT
t.teacher_id
, t.first_name
, t.last_name
, c.course_id
, c.course_name
, c.semester
FROM teachers t
LEFT JOIN courses c
ON t.teacher_id = c.teacher_id
ORDER BY teacher_id;
TEACHER_ID FIRST_NAME LAST_NAME COURSE_ID COURSE_NAME SEMESTER
101 Keith Stein 1 Geometry 2022-2
102 Roger Wood 2 Trigonometry 2022-2
103 Douglas Kern 3 Calculus 2022-2
104 Paul Weber 4 Chemistry 2022-2
105 Jeffrey Lebowitz 5 Biology 2022-2
106 Carol Seltzer 6 Physcology 2022-2
You can use a correlated sub-query:
SELECT t.teacher_id
, t.first_name
, t.last_name
, c.course_id
, c.course_name
, c.semester
, (
SELECT LISTAGG(s.last_name || ', ' || s.first_name, '; ')
WITHIN GROUP (ORDER BY s.last_name, s.first_name)
FROM enrollment e
INNER JOIN students s
ON (e.student_id = s.student_id)
WHERE e.course_id = c.course_id
) AS students
FROM teachers t
LEFT JOIN courses c
ON t.teacher_id = c.teacher_id
ORDER BY
teacher_id;
Which, for the sample data, outputs:
TEACHER_ID
FIRST_NAME
LAST_NAME
COURSE_ID
COURSE_NAME
SEMESTER
STUDENTS
101
Keith
Stein
1
Geometry
2022-2
Aaron, Faith; Altman, Leslee; Cooper, Beth; Kern, Patty; Saladino, Lisa
102
Roger
Wood
2
Trigonometry
2022-2
Aaron, Faith; Altman, Leslee; Cooper, Beth; Kern, Patty; Saladino, Lisa
103
Douglas
Kern
3
Calculus
2022-2
Aaron, Faith; Altman, Leslee; Cooper, Beth; Coralnick, Jill; Kern, Patty; Saladino, Lisa
104
Paul
Weber
4
Chemistry
2022-2
null
105
Jeffrey
Lebowitz
5
Biology
2022-2
null
106
Carol
Seltzer
6
Physcology
2022-2
null
Or you can use JOINs and aggregate:
SELECT t.teacher_id
, MAX(t.first_name) AS first_name
, MAX(t.last_name) AS last_name
, c.course_id
, MAX(c.course_name) AS course_name
, MAX(c.semester) AS semester
, LISTAGG(
NVL2(s.student_id, s.last_name || ', ' || s.first_name, NULL),
'; '
) WITHIN GROUP (ORDER BY s.last_name, s.first_name) AS students
, COUNT(s.student_id) AS num_students
FROM teachers t
LEFT OUTER JOIN courses c
ON t.teacher_id = c.teacher_id
LEFT OUTER JOIN (
enrollment e
INNER JOIN students s
ON (e.student_id = s.student_id)
)
ON (e.course_id = c.course_id)
GROUP BY
t.teacher_id,
c.course_id
ORDER BY
t.teacher_id,
c.course_id;
db<>fiddle here

how to make into an array and also count

I have this data:
app
asscs
mod_asscs
a
56
cb-56
a
67
cb-67
b
38
cb-38
a
12
12
I want to group by column 'app' and count the cases where 'mod_asscs' value is equal to concat('cb-', asscs). I also want to output the array in a separate column 'mod_asscs_array' so that the output is the following:
app
mod_asscs_array
scs_count
a
cb-56, cb-67
2
b
cb-38
1
So far this is what I have:
SELECT DISTINCT
app,
( CASE WHEN concat('cb-', asscs) = mod_asscs THEN mod_asscs || ',') AS mod_asscs_array,
COUNT( CASE WHEN concat('cb-', asscs) = mod_asscs THEN mod_asscs || ',') AS scs_count
FROM data_table
GROUP BY
app
Looks like aggregation.
Sample data:
SQL> with test (app, asscs, mod_asscs) as
2 (select 'a', 56, 'cb-56' from dual union all
3 select 'a', 67, 'cb-67' from dual union all
4 select 'b', 38, 'cb-38' from dual union all
5 select 'a', 12, '12' from dual
6 )
Query:
7 select app,
8 listagg(mod_asscs, ', ') within group (order by mod_asscs) array,
9 count(*) cnt
10 from test
11 where mod_asscs = 'cb-'|| asscs
12 group by app;
A ARRAY CNT
- -------------------- ----------
a cb-56, cb-67 2
b cb-38 1
SQL>
If you need to show all the "apps", even those with a "count" of zero, then you need conditional aggregation, something like this:
with
test (app, asscs, mod_asscs) as (
select 'a', 56, 'cb-56' from dual union all
select 'a', 67, 'cb-67' from dual union all
select 'b', 38, 'cb-38' from dual union all
select 'a', 12, '12' from dual union all
select 'c', 33, 'cb-23' from dual
)
select app,
listagg(case when mod_asscs = 'cb-' || asscs
then mod_asscs end, ', ')
within group (order by asscs) as mod_asscs_array,
count(case when mod_asscs = 'cb-' || asscs
then mod_asscs end) as scs_count
from test
group by app
order by app -- if needed
;
APP MOD_ASSCS_ARRAY SCS_COUNT
--- -------------------- ----------
a cb-56, cb-67 2
b cb-38 1
c 0
if there are duplicates in the array, do I do listagg(distinct.. and count(distinct case when ...?
You cannot use LISTAGG(DISTINCT ... as the LISTAGG function does not currently support the DISTINCT keyword; instead you need to use DISTINCT first in a sub-query and then use LISTAGG:
SELECT app,
LISTAGG(mod_asscs, ',') WITHIN GROUP (ORDER BY mod_asscs)
AS mod_asscs_array,
COUNT(*) AS scs_count
FROM (
SELECT DISTINCT
app,
mod_asscs
FROM data_table
WHERE 'cb-' || asscs = mod_asscs
)
GROUP BY app
Which, for the sample data:
CREATE TABLE data_table (app, asscs, mod_asscs) AS
SELECT 'a', 56, 'cb-56' FROM DUAL UNION ALL
SELECT 'a', 56, 'cb-56' FROM DUAL UNION ALL
SELECT 'a', 67, 'cb-67' FROM DUAL UNION ALL
SELECT 'b', 38, 'cb-38' FROM DUAL UNION ALL
SELECT 'a', 12, '12' FROM DUAL;
Outputs:
APP
MOD_ASSCS_ARRAY
SCS_COUNT
a
cb-56,cb-67
2
b
cb-38
1
db<>fiddle here

PL/SQL program using CURSOR for frequency distribution in table

finaltableA has two columns WORDS, WCOUNTS. The program should insert every word of intitaltableA into finaltableA exactly once. In the column WCOUNTS the program should put how often the word occurs.
intitaltableA
COVID
is
a
disease
COVID
can
be
treated
with
antibodies
COVID
is
a
serious
disease
there
is
a
vaccination
available
for
COVID
finaltableA should look like this -
WORDS
WCOUNTS
a
3
antibodies
1
available
1
be
1
can
1
COVID
4
disease
2
for
1
is
3
serious
1
there
1
treated
1
vaccination
1
with
1
I should use a cursor to insert and update the table. I am new to PL/SQL.
It is quite obvious that you can do this without any cursor in PLSQL, so I guess that means that you are trying to solve a homework problem or a training question. Anyway, here you can see two simple options to get the result you want, with and without PLSQL.
Option 1 - Without PLSQL
with x ( words )
as
(
select 'COVID' from dual union all
select 'is' from dual union all
select 'a' from dual union all
select 'disease' from dual union all
select 'COVID' from dual union all
select 'can' from dual union all
select 'be' from dual union all
select 'treated' from dual union all
select 'with' from dual union all
select 'antibodies' from dual union all
select 'COVID' from dual union all
select 'is' from dual union all
select 'a' from dual union all
select 'serious' from dual union all
select 'disease' from dual union all
select 'there' from dual union all
select 'is' from dual union all
select 'a' from dual union all
select 'vaccination' from dual union all
select 'available' from dual union all
select 'for' from dual union all
select 'COVID' from dual
)
select words, count(words) as counter
from x
group by words
order by 2 desc;
If you execute it, it gives you the output you want
SQL> with x ( words )
2 as
3 (
4 select 'COVID' from dual union all
5 select 'is' from dual union all
6 select 'a' from dual union all
7 select 'disease' from dual union all
8 select 'COVID' from dual union all
9 select 'can' from dual union all
10 select 'be' from dual union all
11 select 'treated' from dual union all
12 select 'with' from dual union all
13 select 'antibodies' from dual union all
14 select 'COVID' from dual union all
15 select 'is' from dual union all
16 select 'a' from dual union all
17 select 'serious' from dual union all
18 select 'disease' from dual union all
19 select 'there' from dual union all
20 select 'is' from dual union all
21 select 'a' from dual union all
22 select 'vaccination' from dual union all
23 select 'available' from dual union all
24 select 'for' from dual union all
25 select 'COVID' from dual
26 )
27 select words, count(words) as counter
28 from x
29 group by words
30* order by 2 desc
SQL> /
WORDS COUNTER
----------- ----------
COVID 4
is 3
a 3
disease 2
there 1
available 1
for 1
serious 1
antibodies 1
can 1
vaccination 1
WORDS COUNTER
----------- ----------
treated 1
be 1
with 1
14 rows selected.
Option 2 - Using PLSQL and a CURSOR
In the below example, I'm going to use dbms_output to show the results. Keep in mind that here there are dozens of ways to do the same, I am just using the simplest one I can think of.
SQL> create table t ( words varchar2(40) ) ;
Table created.
SQL> insert into t
2 with x ( words )
3 as
4 (
5 select 'COVID' from dual union all
6 select 'is' from dual union all
7 select 'a' from dual union all
8 select 'disease' from dual union all
9 select 'COVID' from dual union all
10 select 'can' from dual union all
11 select 'be' from dual union all
12 select 'treated' from dual union all
13 select 'with' from dual union all
14 select 'antibodies' from dual union all
15 select 'COVID' from dual union all
16 select 'is' from dual union all
17 select 'a' from dual union all
18 select 'serious' from dual union all
19 select 'disease' from dual union all
20 select 'there' from dual union all
21 select 'is' from dual union all
22 select 'a' from dual union all
23 select 'vaccination' from dual union all
24 select 'available' from dual union all
25 select 'for' from dual union all
26 select 'COVID' from dual
27* ) select words from x
SQL> /
22 rows created.
SQL> commit ;
Commit complete.
SQL> declare
2 begin
3 for i in ( select words, count(words) as counter from t group by words order by 2 desc )
4 loop
5 dbms_output.put_line( 'Words: '||i.words||' - Wcount is: '||i.counter||' ');
6 end loop;
7* end;
SQL> /
Words: COVID - Wcount is: 4
Words: is - Wcount is: 3
Words: a - Wcount is: 3
Words: disease - Wcount is: 2
Words: antibodies - Wcount is: 1
Words: for - Wcount is: 1
Words: be - Wcount is: 1
Words: vaccination - Wcount is: 1
Words: can - Wcount is: 1
Words: available - Wcount is: 1
Words: treated - Wcount is: 1
Words: there - Wcount is: 1
Words: with - Wcount is: 1
Words: serious - Wcount is: 1
PL/SQL procedure successfully completed.

Duplicated rows numbering

I need to number the rows so that the row number with the same ID is the same. For example:
Oracle database. Any ideas?
Use the DENSE_RANK analytic function:
SELECT DENSE_RANK() OVER (ORDER BY id) AS row_number,
id
FROM your_table
Which, for the sample data:
CREATE TABLE your_table ( id ) AS
SELECT 86325 FROM DUAL UNION ALL
SELECT 86325 FROM DUAL UNION ALL
SELECT 86326 FROM DUAL UNION ALL
SELECT 86326 FROM DUAL UNION ALL
SELECT 86352 FROM DUAL UNION ALL
SELECT 86353 FROM DUAL UNION ALL
SELECT 86354 FROM DUAL UNION ALL
SELECT 86354 FROM DUAL;
Outputs:
ROW_NUMBER
ID
1
86325
1
86325
2
86326
2
86326
3
86352
4
86353
5
86354
5
86354
db<>fiddle here

Oracle is giving error while creating stored procedure. ORA-22905: cannot access rows from a non-nested table item

Hi all I have requirement to pick records using dynamic pivoting in Oracle. I have done with my query which is working fine using "antonsPivoting" https://technology.amis.nl/2006/05/24/dynamic-sql-pivoting-stealing-antons-thunder/.
When i add the query in procedure it gives error: ORA-22905: cannot access rows from a non-nested table item.
Sample table script:
CREATE TABLE DEPARTMENT(DEPT_ID NUMBER PRIMARY KEY, DEPT_NAME VARCHAR2(25))
CREATE TABLE EMPLOYEE(EMP_ID NUMBER, EMP_NAME VARCHAR(100), DEPT_ID NUMBER , FOREIGN KEY(DEPT_ID) REFERENCES DEPARTMENT(DEPT_ID))
INSERT INTO DEPARTMENT(DEPT_ID, DEPT_NAME)
SELECT 1, 'HR' FROM DUAL
UNION ALL SELECT 2, 'OPS' FROM DUAL
UNION ALL SELECT 3, 'MKT' FROM DUAL
UNION ALL SELECT 4, 'FIN' FROM DUAL
UNION ALL SELECT 5, 'IT' FROM DUAL
UNION ALL SELECT 6, 'SERV' FROM DUAL
COMMIT;
INSERT INTO EMPLOYEE(EMP_ID, EMP_NAME, DEPT_ID)
SELECT 1, 'A', 1 FROM DUAL
UNION ALL SELECT 1, 'A', 1 FROM DUAL
UNION ALL SELECT 2, 'B', 1 FROM DUAL
UNION ALL SELECT 3, 'C', 2 FROM DUAL
UNION ALL SELECT 4, 'D', 3 FROM DUAL
UNION ALL SELECT 5, 'E', 3 FROM DUAL
UNION ALL SELECT 6, 'F', 4 FROM DUAL
UNION ALL SELECT 7, 'G', 4 FROM DUAL
UNION ALL SELECT 8, 'H', 4 FROM DUAL
UNION ALL SELECT 9, 'I', 5 FROM DUAL
UNION ALL SELECT 10, 'J', 5 FROM DUAL
UNION ALL SELECT 11, 'K', 1 FROM DUAL
UNION ALL SELECT 12, 'L', 1 FROM DUAL
COMMIT;
sample query script working fine:
SELECT D.DEPT_NAME, COUNT(E.EMP_ID) TOTAL_EMP
FROM DEPARTMENT D
LEFT JOIN EMPLOYEE E ON D.DEPT_ID= E.DEPT_ID
GROUP BY D.DEPT_NAME
;
Dynamic pivoting example working fine:
select * from table( pivot( '
SELECT D.DEPT_NAME, COUNT(E.EMP_ID) TOTAL_EMP
FROM DEPARTMENT D
LEFT JOIN EMPLOYEE E ON D.DEPT_ID= E.DEPT_ID
GROUP BY D.DEPT_NAME' ) )
;
adding in procedure which gives error:
CREATE OR REPLACE PROCEDURE GET_EMPLOYEE (P_RESULT OUT SYS_REFCURSOR)
IS
BEGIN
OPEN P_RESULT FOR
select * from table( pivot( '
SELECT D.DEPT_NAME, COUNT(E.EMP_ID) TOTAL_EMP
FROM DEPARTMENT D
LEFT JOIN EMPLOYEE E ON D.DEPT_ID= E.DEPT_ID
GROUP BY D.DEPT_NAME' ) )
;
END
;
Have you created the Pivot function ?
Please go through below link where this is already answered.
Link

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