How to insert comma delimited values in one column in oracle? - oracle

Question

I have a table by the name of personal_info and it contains id,name and phone_number as columns. So the following is table structure which I want to store data.
id
name
phone_number
1
ali
03434444, 03454544, 0234334
So how to store data in phone_number column in comma delimited format and how to filter that column in where clause for example
Select * from personal_info where phone_number = 03454544 ;
And which datatype is suitable for phone_number column.

Answer 1

Well, the real good practice would rather be to have another table PHONE with a 1xN association (for example a PHONE_ID primary key, and ID and PHONE columns.)
You may then have the result you want with a view based on your two tables and using the LISTAGG operator : https://fr.wikibooks.org/wiki/Oracle_Database/Utilisation_de_fonctions/fonction_LISTAGG, but this will be much efficient to work with, especially if you want WHERE clauses based on your phone numbers.

Answer 2

Use LIKE with the delimiters:
Select *
from personal_info
where ', ' || phone_number || ', ' LIKE '%, ' || '03454544' || ', %';
However
You should consider changing your data structure to store the phone numbers in a separate table:
CREATE TABLE phone_numbers (
person_id REFERENCES personal_info (id),
phone_number VARCHAR2(12)
);
And then you can get the data using a JOIN
SELECT pi.*,
pn.phone_number
FROM personal_info pi
INNER JOIN phone_numbers pn
ON (pi.id = pn.person_id)
WHERE pn.phone_number = '03434444'
or, if you want all the phone numbers:
SELECT pi.*,
pn.phone_numbers
FROM personal_info pi
INNER JOIN (
SELECT person_id,
LISTAGG(phone_number, ', ') WITHIN GROUP (ORDER BY phone_number)
AS phone_numbers
FROM phone_numbers
GROUP BY person_id
HAVING COUNT(CASE WHEN phone_number = '03434444' THEN 1 END) > 0
) pn
ON (pi.id = pn.person_id)
db<>fiddle here

Answer 3

VARCHAR2 is suitable for phone numbers.
You can get the values this way:
WITH personal_info AS
(
SELECT 1 AS ID, 'Ali' AS NAME, '03434444, 03454544, 0234334' AS phone_number FROM dual
)
SELECT *
FROM (SELECT id, name, TRIM(regexp_substr(phone_number, '[^,]+', 1, LEVEL)) AS phone_number
FROM personal_info
CONNECT BY LEVEL <= LENGTH (phone_number) - LENGTH(REPLACE(phone_number, ',' )) + 1)
WHERE phone_number = '03454544';

Answer 4

Wrong data model, it isn't normalized. You should create a new table:
create table phones
(id_phone number constraint pk_phone primary key,
id_person number constraint fk_pho_per references person (id_person),
phone_number varchar2(30) not null
);
Then you'd store as many numbers as you want, one-by-one (row-by-row, that is).
If you want to do it your way, store it just like that:
insert into person (id, name, phone_number)
values (1, 'ali', '03434444, 03454544, 0234334');
One option of querying such data is using the instr function:
select * from person
where instr(phone_number, '03434444') > 0;
or like:
select * from person
where phone_number like '%'% || '03434444' || '%'
or split it into rows:
select * from person a
where '03434444' in (select regexp_substr(b.phone_number, '[^,]+', 1, level)
from person b
where b.id_person = a.id_person
connect by level <= regexp_count(b.phone_number, ',') + 1
)
I'd do it my way, i.e. with a new table that contains only phone numbers.