I am running a program and writing output in a .txt file. Is there a method or a way to do this without closing and opening .txt file after each run? Basically the program runs and the .txt file updates on its own?
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I have a C++ program that when run on my local machine runs some simulations and saves the results in a .csv file.
I am now running the same program on a cluster. Jobs are scheduled with SLURM, queued, and then run to completion. Rather than a .csv file output, the output is a slurmid.out file. How can I access this file to see the results of my simulation?
I typically use the cat command to view slurm output files-
cat slurmid.out
You could also use vim, or any other text editor/viewer. The script should probably output the csv file as well- If its not because it's failing, the .out file will tell you about it.
I currently have a Batch script that produces a file in the current working directory (a.bat), but I am unable to edit it.
I also have a second Batch script (b.bat) that calls it.
I would like to be able to change the output directory of a.bat, without directly editing it, possibly by implementing some form of configuration within b.bat.
Is this possible?
I have a bash script that uses awk to process some files that I have downloaded. If I run the script on any of the files it does not work properly. However, if I transfer the contents of a file in a newly created one it seems to work as supposed. Could it have anything to do with the settings of the files?
I have two files file hotel_12313.dat and hotel_99999.dat . The first one is downloaded and the second one is created by me. If I copy the data from the first file into the second one and I execute the script on both of them the output is different.
I am working on a batch file and trying to write the correct windows commands.
1) Command-line from Windows
2) Use commands to scan the zip file so that it will look inside of the zip file for a specific string in the file within the zip file.
3) If the scan finds that specific string in the file that is within the zip file then move that zip file to another specified directory.
Is it possible using dos commands within a batch file?
I want to learn more on this. Anyone have any guidance or suggestions?
I'm new to using meshlabserver and meshlab in general.
I created the .mlx file and tries to run a command in meshlabserver for one file and it worked. I would like to know how do I write a command for hundreds of files?
Thanks in Advance.
I've just created a batch file with necessary loops and calls the .mlx file that will run the meshlabserver command. However one should know that the resulting files will be saved in the same directory where meshlabserver.exe is.