I want to search by customer code in collection table. I get the following error. Can you help with this
Eror message;
Property [Collection] does not exist on this collection instance.
$cut = Cut::with('cutStatus', 'Collection', 'CollectionOrder', 'CollectionOrder.collectionColor')
->orderBy('end_date', 'DESC')
->where('cut_status_id', 3)
->get();
if ($request->search){
//i am getting the error here
$cut = $cut->Collection->where('customer_code', 'LIKE', "%".request('search')."%");
}
$cut_list = [];
foreach ($cut as $cut_item){
foreach ($cut_item->CollectionOrder as $collection_order_item){
$cut_list['cut_list'][$cut_item->id]['cut_info'] = $cut_item;
$cut_list['cut_list'][$cut_item->id]['color'][$collection_order_item->collectionColor->color_name] = $collection_order_item;
$cut_list['cut_list'][$cut_item->id]['cut_piece'] = $this->CutPiece($cut_item->id);
}
}
You are calling Collection relation on an array that's why you are facing this issue. You have to use use loop for specific result or get signle entry and apply relation.
Using Loop.
foreach($cut as $c)
{
dump($c->->Collection->where('customer_code', 'LIKE',
"%".request('search')."%"));
}
Related
$orders = Orders::select('orders.id as order_id', 'collection_color.color_name as color', 'collection_color.id as collection_color_id', DB::raw('SUM(order_piece.piece) As piece'))
->join('order_piece', 'order_piece.order_id', '=', 'orders.id')
->join('collection_color_size_barcode', 'collection_color_size_barcode.id', '=', 'order_piece.collection_color_size_barcode_id')
->join('collection_color', 'collection_color.id', '=', 'collection_color_size_barcode.collection_color_id')
->whereIn('orders.id', $request->order_id)
->groupBy('order_piece.order_id')
->orderBY('orders.delivery_date', 'ASC')
->get();
return $orders; => [{"order_id":30,"color":"Kahverengi","collection_color_id":21,"piece":"500"}]
return $ccfc = CollectionColorFabricColor::whereIn('collection_color_id', $orders->collection_color_id)->get();
Property [collection_color_id] does not exist on this collection instance. i am getting error can you help me
The error is most likely due to this in your second code snippet: $orders->collection_color_id. $orders is a collection, so the property doesn't exist in that object. What you actually need is to pluck those values from that collection like so:
return $ccfc = CollectionColorFabricColor::query()
->whereIn('collection_color_id', $orders->pluck('collection_color_id'))
->get();
Because your $orders is collection, you need to get collection_color_id array like this :
$arrayColors = $orders->pluck('collection_color_id')->toArray();
then
return $ccfc = CollectionColorFabricColor::whereIn('collection_color_id', $arrayColors)->get();
Can anyone help me to get the data .
$ticketList = Ticket::with('appliance', 'brand')->get();
$userAppliances = DB::table('user_appliances')
->where('user_id', 5)
->pluck('appliance_id')
->toArray();
$userBrands = DB::table('user_brands')
->where('user_id', 5)
->pluck('brand_id')
->toArray();
$ticketList = $ticketList->map(function ($ticket) use ($userAppliances) {
return $ticket->where($ticket->appliance_id,'=', $userAppliances);
});
dd($ticketList);
It returnd the collection. I want all the tickets, where ticket->brand_id and tickt->appliance_id includes {all the id i am getting in array from userBrands and userAppliances}. I am getting trouble in writing query
Try it out this
$userBrands = DB::table ('user_brands')
->where('user_id', 5)
->pluck('appliance_id')
->toArray();
$ticketList = Ticket::with('appliance', 'brand')
->where(function($query) use ($userBrands){
$query->whereIn('appliance_id', $userBrands);
})->get();
In laravel, I can use many where rules as an array a run one query to the database using laravel eloquent where method to get needed result.
Code:
$where = [];
$where[] = ['user_id', '!=', null];
$where[] = ['updated_at', '>=', date('Y-m-d H:i:s')];
if($request->searchTerm) {
$where[] = ['title', 'like', '%' . $request->searchTerm . '%'];
}
Model::where($where)->get();
Question part:
Now I need to use Laravel Eloquent method whereIn with array params to get needed result with one query.
I tried by looping method but with many queries to the database.
Code:
$model = new Model;
$whereIn = [];
$whereIn[] = ['date', '>=', Carbon::now()->subDays(10)];
$whereIn[] = ['user_role', 'candidate'];
if (!empty($scope) && is_array($scope)) {
$whereIn[] = ['user_id', $scope];
}
if(is_array($employment) && !empty($employment)) {
$whereIn[] = ['employment', $employment];
}
if(is_array($experience) && !empty($experience)) {
$whereIn[] = ['experience', $experience];
}
foreach ($whereIn as $v) {
$model = $model->whereIn($v[0], $v[1]);
}
dump($model->get());
First I tired $model->whereIn($whereIn)->get() but it's return error. It's possible get results with one query using whereIn without looping?
Note: My $whereIn array will be dynamic array!
whereIn is a query builder function so you can't use it on the model directly. Instead you should create a query builder instance. I also suggest you use when instead of the if statements:
$models = Model::when(!empty($scope) && is_array($scope), function ($query) use ($scope) {
$query->whereIn('user_id', $scope);
})->when(!empty($employment) && is_array($employment), function ($query) use ($employment) {
$query->whereIn('employment', $employment);
})->when(!empty($experience) && is_array($experience), function ($query) use ($experience) {
$query->whereIn('experience', $experience);
})->get();
dump($models);
when essentially runs the function when the first parameter is true. There's more detail in the documentation under conditional clauses.
Since your $whereIn variable is an array of arrays it will work like :
$model->whereIn($whereIn[0][0], $whereIn[0][1])->get();
If it just a simple array then you can use :
$model->whereIn($whereIn[0], $whereIn[1])->get();
Do in Eloquent
$model = Model::whereIn('id', array(1, 2, 3))->get();
Or using Query builder then :
$model = DB::table('table')->whereIn('id', array(1, 2, 3))->get();
I have the following query.
$projects = Project::orderBy('created_at', 'desc');
$data['sorted'] = $projects->groupBy(function ($project) {
return Carbon::parse($project->created_at)->format('Y-m-d');
})->simplePaginate(5);
When I try to paginate with the simplePaginate() method I get this error.
stripos() expects parameter 1 to be string, object given
How can I paginate grouped data in this case?
The created_at attribute is already casted as a Carbon Object (by default in laravel models). that's why you are getting that error. Try this:
$projects = Project::orderBy('created_at', 'desc')->get();
$data['sorted'] = $projects->groupBy(function ($project) {
return $project->created_at->format('Y-m-d');
})->simplePaginate(5);
this answer is just for the error you're getting. now if you want help with the QueryBuilder, can you provide an example of the results you're expecting to have and an example of the database structure ?
The pagination methods should be called on queries instead of collection.
You could try:
$projects = Project::orderBy('created_at', 'desc');
$data['sorted'] = $projects->groupBy('created_at');
The problem was solved. I was create custom paginator via this example:
https://stackoverflow.com/a/30014621/6405083
$page = $request->has('page') ? $request->input('page') : 1; // Use ?page=x if given, otherwise start at 1
$numPerPage = 15; // Number of results per page
$count = Project::count(); // Get the total number of entries you'll be paging through
// Get the actual items
$projects = Project::orderBy('created_at', 'desc')
->take($numPerPage)->offset(($page-1)*$numPerPage)->get()->groupBy(function($project) {
return $project->created_at->format('Y-m-d');
});
$data['sorted'] = new Paginator($projects, $count, $numPerPage, $page, ['path' => $request->url(), 'query' => $request->query()]);
simplePaginate Method is exist in the path below:
Illuminate\Database\Eloquent\Builder.php::simplePaginate()
Having a small problem with retrieving a new object on my view. I keep getting the error 'Trying to get property of non-object'.
The field I am trying to display 'oil_gas_skillsgap' is a valid field and when I do a simple return it spits out...
[{"oil_gas_job_id":"4","industry_job_id":"43","oil_gas_skillsgap":"test text here"}]
CONTROLLER
public function showjob($slug)
{
$job = OilGasJob::where("slug", "=", $slug)->first();
if (is_null($job))
{
return Redirect::to('/');
} else {
$jobId = $job->id;
$roleId = Session::get('industryrole');
$skills = DB::table('industry_job_oil_gas_job')
->where('oil_gas_job_id', '=', $jobId)
->where('industry_job_id', '=', $roleId)
->get();
return View::make('job')
->with('job', $job)
->with('skills', $skills);
}
}
VIEW
{{ $job->job_title}}
{{ $skills->oil_gas_skillsgap }}
$skills is probably an array, not an object, even if the query has only one result.
If you know for a fact that your query will return one result, use first() and you'll get it as an object directly.
$skills = DB::table('industry_job_oil_gas_job')
->where('oil_gas_job_id', '=', $jobId)
->where('industry_job_id', '=', $roleId)
->first();
Otherwise, remember the following: when using the DB class for queries, Laravel will always return an array. If you use an Eloquent model, it will return an Illuminate\Support\Collection object. In both cases that is true even if no row is found (the array or Collection will be empty). The first() method, on the other hand, will either return an object (stdClass when using DB, or a model when using Eloquent) or null.
#user3189734,
job_title is not a part of $job collection, that is why it is throwing 'Trying to get property of non-object'.