How to replace/populate a bash case statement automatic - bash

Question

How to improve the following batch script by making so whenever a new script is added into the directory, it doesn't require to manually hardcode an extra line of code in script.
like: 3) source $(pwd)/script-3.sh; myfunc;;
script:
#Menu script
title="Menu"
prompt="Pick an option(number): "
#options=(
# "script-1.sh" \
# "script-2.sh" \
# "script-3.sh" \
# )
path=$(pwd)
array=($path/*.sh)
options=( "${array[#]##*/}" )
echo "$title"
PS3="$prompt"
select opt in "${options[#]}" "Quit"; do
case "$REPLY" in
1) source $(pwd)/script-1.sh; myfunc;;
2) source $(pwd)/script-2.sh; myfunc;;
3) source $(pwd)/script-3.sh; myfunc;;
$((${#options[#]}+1))) echo "Goodbye!"; break;;
*) echo "Invalid option. Try another one.";continue;;
esac
done
How to automate this part ?
select opt in "${options[#]}" "Quit"; do
case "$REPLY" in
1) source $(pwd)/script-1.sh; myfunc;;
2) source $(pwd)/script-2.sh; myfunc;;
3) source $(pwd)/script-3.sh; myfunc;;
$((${#options[#]}+1))) echo "Goodbye!"; break;;
*) echo "Invalid option. Try another one.";continue;;
esac
done
this is the current manual part, where need to be hard-coded a value everytime a new script is added.
for example, lets say I added a new script called" script-99.sh
then it would need to hardcode it in the main script like this:
case "$REPLY" in
1) source $(pwd)/script-1.sh; myfunc;;
2) source $(pwd)/script-2.sh; myfunc;;
3) source $(pwd)/script-3.sh; myfunc;;
4) source $(pwd)/script-99.sh; myfunc;; ##Had to hardcode this line

Answer 1

A simple solution would be
select opt in "${options[#]}" "Quit"; do
script=script-$REPLY.sh
if [[ -f $script ]]
then
source $script
else
echo Goodbye
break
fi
done
This also catches the case that someone deletes a script while the select-loop is still in process.
A more stable solution would be
quitstring=Quit
select opt in "${options[#]}" $quitstring; do
[[ $opt == $quitstring ]] && break
source $opt
done

Answer 2

After lots attempts, come up with this:
select opt in "${options[#]}" "Quit"; do
source $(pwd)/$opt; myfunc
done
it is working!
however to exit the script it need to press Ctrl+z
this part of the code bellow which used to exit the script, I wasn't able to figure out how to adapt into the solution above.
$((${#options[#]}+1))) echo "Goodbye!"; break;;
*) echo "Invalid option. Try another one.";continue;;
so this is not a complete answer.