SwiftUI Delete a List Section - xcode

Question

Is there a way to delete an entire list section with a function in SwiftUI? I have a list that you can add sections to as you please, but don't know how to delete them when you want to. I know that you can delete a list item itself using the deleteItems function, but I would like to use a button to delete the entire section. When I try to use the standard "deleteItems" function, it asks for "offsets: IndexSet". I am unsure what this IndexSet would be.
I can't find out what should go in the IndexSet field.
Here is my code
struct SampleView: View {
#Environment(\.managedObjectContext) private var viewContext
#Environment(\.presentationMode) var presentationMode
#FetchRequest(
sortDescriptors: [NSSortDescriptor(keyPath: \Category.categoryString, ascending: false)],
animation: .default)
private var listedCategory: FetchedResults<Category>
#State var categoryString: String = ""
var body: some View {
VStack{
TextField("Enter Text Here", text: $categoryString)
Button {
let newlistedCategory = Category(context: viewContext)
newlistedCategory.categoryString = categoryString
do {
try viewContext.save()
} catch {
let nsError = error as NSError
fatalError("Unresolved error \(nsError), \(nsError.userInfo)")
}
categoryString = ""
} label: {
Text("Save")
}
List{
ForEach(listedCategory) { listedCategory in
if listedCategory.typeString == "Item" {
Section(header: Text(listedCategory.categoryString!)) {
Button {
//deleteCategories(offsets: <#T##IndexSet#>)
} label: {
Text("Delete")
}
}
}
}
}
Spacer()
}
}
private func deleteCategories(offsets: IndexSet) {
withAnimation {
offsets.map { listedCategory[$0] }.forEach(viewContext.delete)
do {
try viewContext.save()
} catch {
// Replace this implementation with code to handle the error appropriately.
// fatalError() causes the application to generate a crash log and terminate. You should not use this function in a shipping application, although it may be useful during development.
let nsError = error as NSError
fatalError("Unresolved error \(nsError), \(nsError.userInfo)")
}
}
}
}