How to create files in the shell where variables are not replaced - bash

Question

I need to create a file for subsequent nohup execution, the file contains some variables, I don't want the variables to be replaced when I generate through the file.
When I executed the code with the following code, all the variables were replaced in the generated script, which was not what I expected.
#!/bin/bash
gen_script() {
filepath=$1
if [ ! -f "$filepath" ]; then
cat >${filepath} <<EOF
#!/bin/bash
# Code generated by main.sh; DO NOT EDIT.
test(){
ip=$1
port=$2
restorefile=$3
redis-cli -h $ip -p $port --pipe < $restorefile
}
test "$#"
EOF
fi
}
main(){
gen_script exec.sh
nohup bash exec.sh $1 $2 > nohup.out 2>&1 &
}
main "$#"
How can I change my code please? I really appreciate any help with this.

Answer 1

To disable expansions in here document, quote the delimieter:
cat <<'EOF'
... $not_expanded
EOF
Instead, let bash serialize the function.
#!/bin/bash
work() {
ip=$1
port=$2
restorefile=$3
redis-cli -h $ip -p $port --pipe < $restorefile
}
gen_script() {
filepath=$1
if [ ! -f "$filepath" ]; then
cat >${filepath} <<EOF
#!/bin/bash
# Code generated by main.sh; DO NOT EDIT.
$(declare -f work)
work "\$#"
EOF
fi
}
main() {
gen_script exec.sh
nohup bash exec.sh "$1" "$2" > nohup.out 2>&1 &
}
main "$#"
Check your script with shellcheck. Do not define a function named test, there is already a super standard command test which is an alias for command [.