Print string variable that stores the output of a command in Bash [duplicate] - bash

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Add a prefix string to beginning of each line
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I need to place the output of a command in Bash into a string variable.
Each value should be separated by a space. There are many options to do that but I cannot use mapfileor read options (I'm using Bash < 4 version in macOS).
This is the output of the command:
values="$(mycommand | awk 'NR > 2 { printf "%s\n", $2 }')"
where mycommand is just a cloud command that gets some values like:
echo $values
mycommand output: (which I think is a string ending with \n for each value)
55369972
75369973
85369974
95369975
This is what I'm trying to do:
Here I should print the values like (I need to iterate over the variable values so I can print each value individually).
desired output in the foor loop
value: 55369972
value: 75369973
value: 85369974
value: 95369975
but I'm getting this:
value: 55369972 75369973 85369974 95369975
# Getting the id field of the values
values="$(mycommand| awk 'NR > 2 { printf "%s\n", $2 }')"
# Replacing the new line with a space so I can iterate over each value
new_values="${values//$'\n'/ }"
# new_values=("${values//$'\n'/ }")
# Checking if I can print each value correctly
for i in "${new_values[#]}"
# for i in "$new_values"
do
echo "value: ${i}"
done
Also, I cannot use things like
# shellcheck disable=xxx
values=($(echo "${values}" | tr "\n" " "))
As I'm getting error messages when checking the code...
Any idea what I'm doing wrong in my code?

Answer 1

try this:
#!/bin/bash
values="$(mycommand | awk 'NR > 2 { printf "%s\n", $2 }')"
for v in $values; do
echo value: $v
done

Answer 2

Your step that replaces the newlines with spaces renders it as a string. If you want to split that string into a list, you should put it in brackets (based on this answer )
This should do what you are expecting:
# Getting the id field of the values
values="$(mycommand| awk 'NR > 2 { printf "%s\n", $2 }')"
# Replacing the new line with a space
new_values=("${values//$'\n'/ }")
# Checking if I can print the values correctly
for i in ${new_values}
do
echo "value: ${i}"
done
where new_values=("${values//$'\n'/ }") is the crucial part, then you need to avoid putting it in quotes when you iterate it (or you turn it back into a string)

Answer 3

Since I can't paste code into the comments, I post an answer but the credits go to #akathimy above.
This works for me (solution #1):
#!/bin/bash
# Getting the id field of the values
values="55369972 75369973 85369974 95369975"
#
for v in $values; do
echo value: "$v"
done
and this also (solution #2):
#!/bin/bash
# Getting the id field of the values
values="55369972
75369973
85369974
95369975"
#
for v in $values; do
echo value: "$v"
done
Edit: And what about this one (solution #3)? :
#!/bin/bash
# Getting the id field of the values
values=("55369972
75369973
85369974
95369975")
#
for v in ${values[#]}; do
echo value: "$v"
done
This last one works for me, and perhaps also for you. Let me know.