Calculate numbers in file by bash script - bash

Question

I have file with the following content.
e.g. 2 images with FRAGMENT size. I want to calculate the fragments total size in bash script.
IMAGE admindb1 8 admindb1_1514997916 bus 4 Default-Application-Backup 2 3 1 1517676316 0 0
FRAG 1 1 10784 0 2 6 2 HSBRQ2 fuj 65536 329579 1514995208 60 0 *NULL* 1517676316 0 3 1 *NULL*
IMAGE admindb1 8 admindb1_1514995211 bus 4 Default-Application-Backup 2 3 1 1517673611 0 0
FRAG 1 1 13168256 0 2 6 12 HSBQ8I fuj 65536 173783 1514316708 52 0 *NULL* 1517673611 0 3 1 *NULL*
FRAG 1 2 24288384 0 2 6 1 HSBRJ7 fuj 65536 2 1514995211 65 0 *NULL* 0 0 3 1 *NULL*
FRAG 1 3 24288384 0 2 6 1 HSBRON fuj 65536 2 1514995211 71 0 *NULL* 0 0 3 1 *NULL*
FRAG 1 4 13806752 0 2 6 1 HSBRRK fuj 65536 2 1514995211 49 0 *NULL* 0 0 3 1 *NULL*
Output should be like this:
For Image admindb1_1514997916 total size is 10784
For Image admindb1_1514995211 total size is 75551776
4th column at line which is beginning with FRAG should be calculated.
My script is not working:
#!/bin/bash
file1=/home/turgun/Desktop/IBteck/script-last/frags
imagelist=/home/turgun/Desktop/IBteck/script-last/imagelist
counter=1
for counter in `cat $imagelist`
do
n=`awk '/'$counter'/{ print NR; exit }' $file1`
for n in `cat $file1`
do
if [[ ! $n = 'IMAGE' ]]; then
echo "For Image $counter total size is " \
`grep FRAG frags | awk '{print total+=$4}'`
fi
done
done

Answer 1

awk 'function summary() {print "For Image",image,"total size is",sum}
$1=="IMAGE" {image=$4}
$1=="FRAG" {sum+=$4}
$1=="" {summary(); sum=0}
END{summary()}' file
Output:
For Image admindb1_1514997916 total size is 10784
For Image admindb1_1514995211 total size is 75551776
I assume that the last line is not empty.

Answer 2

cat -s file.txt | sed -n '/^IMAGE /{s:^[^ ]* *[^ ]* *[^ ]* *\([^ ]*\).*$:echo -n "For image \1 total size is "; echo `echo ":;s:\*::g;p};/^$/{s:^:0"`|bc:;p};/^FRAG /{s:^[^ ]* *[^ ]* *[^ ]* *\([^ ]*\).*$:\1\+:;s:\*::g;p};' | bash
Output:
For image admindb1_1514997916 total size is 10784
For image admindb1_1514995211 total size is 75551776

Answer 3

Awk solution:
awk '/^IMAGE/{
if (t) { printf "For image %s total size is %d\n",img,t; t=0 } img=$4
}
/^FRAG/{ t+=$4 }
END{ if (t) printf "For image %s total size is %d\n",img,t }' file
The output:
For image admindb1_1514997916 total size is 10784
For image admindb1_1514995211 total size is 75551776

Answer 4

Gnarly combo of cut, GNU sed, (with a careless use of evaluate), and datamash:
cut -d' ' -f4 file | datamash --no-strict transpose |
sed 's#\tN/A\t#\n#g;y#\t# #' |
sed 's/ \(.*\)/ $((\1))/;y/ /+/;s/+/ /;
s/\(.*\) \(.*\)/echo For image \1 total size is \2/e'
Output:
For image admindb1_1514997916 total size is 10784
For image admindb1_1514995211 total size is 75551776
Cyrus's answer is just better. This answer shows some limits of sed. Also if the data file is huge, (say millions of numbers to sum), the evaluate used to farm out the addition to the shell would probably exceed its command line length limit.