How can I compute sunrise/sunset times? [closed] - time

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I like to keep track of sunrise and sunset times. For the past couple of years I've been doing this with a small program written with a popular library for my favorite programming language. The last two months I've been keeping track of these times more regularly than usual, and I happened to notice that on the day of the equinox the sunrise time jumped eight minutes as compared to the day before! I knew this was impossible and compared with NOAA, finding out that my rise and set times had been off for several days and in fact seemed to be off by about a minute for most of the year.
At this point, I'd like to just implement the calculations myself. What algorithms or formulas are available to do this computation?

You may consider reading Wikipedia's article on sunrise equations. The lead paragraph gives the equation:
cos(ωo) = -tan(φ) * tan(δ)
where:
ωo is the hour angle in degrees at either sunrise (when negative value is taken) or sunset (when positive value is taken) in degree (°)
φ is the latitude of the observer on the Earth in degrees
δ is the sun declination in degrees

If you want to match NOAA, you'll have to consult Jean Meeus' Astronomical Algorithms (mostly Chapter 15). And it's complicated! Martin Beckett is correct, you have to define the sunset. Typically this is the apparent rise or set of upper limb of the sun, which makes your "standard" altitide -5/6 degrees (not zero). And you can't calculate the sunrise or sunset directly with NOAA's accuracy. You'll have to create a governing set of equations for apparent right ascension and declination for the day in question and then interpolate the apparent right ascension and declination over time to find the exact rising and setting times at the standard altitude.
Hope this helps. I spent about a month digesting AA and re-writing all our solar code when I came across the same thing, and it still took over a year to sort out some of the corner cases where my code broke. So it will take some time to figure out. I'm not aware of any public code examples of this algorithm and don't have any to share at this moment, but I'm happy to help you through some headaches if I can.

For accuracy in the 5min range you have to consider 'which' sunset.
Do you want the time the bottom of the sun touches the horizon or the time the top of the sun passes below the horizon?
It takes 2mins for the sun to cross the horizon.
Below the 1min level you also need to take into account atmospheric refraction.

Definitions of what constitutes sunrise/sunset can vary. For example, in ephem "rising and setting are defined as the moments when the upper limb of the body touches the horizon (that is, when the body’s alt plus radius equals zero)" [PyEphem Quick Reference].
#!/usr/bin/env python
import datetime
import ephem # to install, run `pip install pyephem`
o = ephem.Observer()
o.lat, o.long, o.date = '34:3', '-118:15', datetime.datetime.utcnow()
sun = ephem.Sun(o)
print "Los Angeles"
print "sunrise:", o.next_rising(sun), "UTC"
print "sunset:",o.next_setting(sun), "UTC"
Output
Los Angeles, CA
sunrise: 2010/3/30 13:42:43 UTC
sunset: 2010/3/30 02:11:50 UTC
If it is open-source library then you could fix it instead of creating a new one with new bugs.

Have a look at this book:
"Practical Astronomy with your Calculator (Paperback)" by Peter Duffett-Smith.
It is quite old but still in print...
link

In Ruby I wrote this for equation of time.
include Math
# degrees to radians = PI/180
to_r = PI/180.0
#radians to degrees = 180/PI
to_d = 180.0/PI
puts "Day, Declination, EofT"
# test a celestial year worth of values.
for jday in 1..366
et = -7.633 * sin(jday * (2 * PI)/365.24) + 9.65 * sin((jday - 78) * 180/92 * to_r)
a_sin = sin(23.433 * to_r) * sin((2 * PI/366) * (jday - 81))
declination = asin(a_sin) * to_d
puts "#{jday}, #{declination}, #{et}"
end
Then for the above equation:
# center disk and refraction factor have been considered.
cos_omega = sin(-0.83 * to_r) - tan(latitude * to_r) * tan(declination * to_r)
semi_diurnal_arc = acos(cos_omega)
There is a whole website devoted to this at http://www.analemma.com/
The key to these calculations are good libraries like the one for python above.
Also usage of Date and Time classes. I would look on rubyforge for something like ephem.

You might want to look at an earlier entry on calculating the position of the sun. Specifically, the Solpos program that I pointed to has support for sunrise/sunset.

I did see some interesting things on this NOAA page under the Technical Definitions and Computational Details heading, but I'm sure you've read that already.
The answer to the SO question "Position of the sun given time of day, and lat/long" and the above may actually be all you need.
As a side note (it doesn't answer your question directly), is there a reason you can't pull the NOAA data and use it as a lookup table instead of calculating it? Storage tends to be relatively cheap these days.

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Finding a value of a variant in a permutation equation [closed]

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I have a math problem that I can't solve: I don't know how to find the value of n so that
365! / ((365-n)! * 365^n) = 50%.
I am using the Casio 500ms scientific calculator but I don't know how.
Sorry because my question is too easy, I am changing my career so I have to review and upgrade my math, the subject that I have neglected for years.
One COULD in theory use a root-finding scheme like Newton's method, IF you could take derivatives. But this function is defined only on the integers, since it uses factorials.
One way out is to recognize the identity
n! = gamma(n+1)
which will effectively allow you to extend the function onto the real line. The gamma function is defined on the positive real line, though it does have singularities at the negative integers. And of course, you still need the derivative of this expression, which can be done since gamma is differentiable.
By the way, a danger with methods like Newton's method on problems like this is it may still diverge into the negative real line. Choose poor starting values, and you may get garbage out. (I've not looked carefully at the shape of this function, so I won't claim for what set of starting values it will diverge on you.)
Is it worth jumping through the above set of hoops? Of course not. A better choice than Newton's method might be something like Brent's algorithm, or a secant method, which here will not require you to compute the derivative. But even that is a waste of effort.
Recognizing that this is indeed a problem on the integers, one could use a tool like bisection to resolve the solution extremely efficiently. It never requires derivatives, and it will work nicely enough on the integers. Once you have resolved the interval to be as short as possible, the algorithm will terminate, and take vary few function evaluations in the process.
Finally, be careful with this function, as it does involve some rather large factorials, which could easily overflow many tools to evaluate the factorial. For example, in MATLAB, if I did try to evaluate factorial(365):
factorial(365)
ans =
Inf
I get an overflow. I would need to move into a tool like the symbolic toolbox, or my own suite of variable precision integer tools. Alternatively, one could recognize that many of the terms in these factorials will cancel out, so that
365! / (365 - n)! = 365*(365-1)*(365-2)*...*(365-n+1)
The point is, we get an overflow for such a large value if we are not careful. If you have a tool that will not overflow, then use it, and use bisection as I suggested. Here, using the symbolic toolbox in MATLAB, I get a solution using only 7 function evaluations.
f = #(n) vpa(factorial(sym(365))/(factorial(sym(365 - n))*365^sym(n)));
f(0)
ans =
1.0
f(365)
ans =
1.4549552156187034033714015903853e-157
f(182)
ans =
0.00000000000000000000000095339164972764493041114884521295
f(91)
ans =
0.000004634800180846641815683109605743
f(45)
ans =
0.059024100534225072005461014516788
f(22)
ans =
0.52430469233744993108665513602619
f(23)
ans =
0.49270276567601459277458277166297
Or, if you can't take an option like that, but do have a tool that can evaluate the log of the gamma function, AND you have a rootfinder available as MATLAB does...
f = #(n) exp(gammaln(365+1) - gammaln(365-n + 1) - n*log(365));
fzero(#(n) f(n) - .5,10)
ans =
22.7677
As you can see here, I used the identity relating gamma and the factorial function, then used the log of the gamma function, in MATLAB, gammaln. Once all the dirty work was done, then I exponentiated the entire mess, which will be a reasonable number. Fzero tells us that the cross-over occurs between 22 and 23.
If a numerical approximation is ok, ask Wolfram Alpha:
n ~= -22.2298272...
n ~= 22.7676903...
I'm going to assume you have some special reason for wanting an actual algorithm, even though you only have one specific problem to solve.
You're looking for a value n where...
365! / ((365-n)! * 365^n) = 0.5
And therefore...
(365! / ((365-n)! * 365^n)) - 0.5 = 0.0
The general form of the problem is to find a value x such that f(x)=0. One classic algorithm for this kind of thing is the Newton-Raphson method.
[EDIT - as woodchips points out in the comment, the factorial is an integer-only function. My defence - for some problems (the birthday problem among them) it's common to generalise using approximation functions. I remember the Stirling approximation of factorials being used for the birthday problem - according to this, Knuth uses it. The Wikipedia page for the Birthday problem mentions several approximations that generalise to non-integer values.
It's certainly bad that I didn't think to mention this when I first wrote this answer.]
One problem with that is that you need the derivative of that function. That's more a mathematics issue, though you can estimate the derivative at any point by taking values a short distance either side.
You can also look at this as an optimisation problem. The general form of optimisation problems is to find a value x such that f(x) is maximised/minimised. In your case, you could define your function as...
f(x)=((365! / ((365-n)! * 365^n)) - 0.5)^2
Because of the squaring, the result can never be negative, so try to minimise. Whatever value of x gets you the smallest f(x) will also give you the result you want.
There isn't so much an algorithm for optimisation problems as a whole field - the method you use depends on the complexity of your function. However, this case should be simple so long as your language can cope with big numbers. Probably the simplest optimisation algorithm is called hill-climbing, though in this case it should probably be called rolling-down-the-hill. And as luck would have it, Newton-Raphson is a hill-climbing method (or very close to being one - there may be some small technicality that I don't remember).
[EDIT as mentioned above, this won't work if you need an integer solution for the problem as actually stated (rather than a real-valued approximation). Optimisation in the integer domain is one of those awkward issues that helps make optimisation a field in itself. The branch and bound is common for complex functions. However, in this case hill-climbing still works. In principle, you can even still use a tweaked version of Newton-Raphson - you just have to do some rounding and check that you don't keep rounding back to the same place you started if your moves are small.]

Determining the level of dissonance between two frequencies [closed]

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Using continued fractions, I'm generating integer ratios between frequencies to a certain precision, along with the error (difference from integer ratio to the real ratio). So I end up with things like:
101 Hz with 200 Hz = 1:2 + 0.0005
61 Hz with 92 Hz = 2:3 - 0.0036
However, I've run into a snag on actually deciding which of these will be more dissonant than others. At first I thought low numbers = better, but something like 1:51 would likely be not very dissonant since it's a frequency up 51 octaves from the other. It might be a screaming high, ear bleeding pitch, but I don't think it would have dissonance.
It seems to me that it must be related to the product of the two sides of the ratio compared to the constituents somehow. 1 * 51 = 51, which doesn't "go up much" from one side. 2 * 3 = 6, which I would think would indicate higher dissonance than 1:51. But I need to turn this feeling into an actual number, so I can compare 5:7 vs 3:8, or any other combinations.
And how could I work error into this? Certainly 1:2 + 0 would be less dissonant than 1:2 + 1. Would it be easier to apply an algorithm that works for the above integer ratios directly to the frequencies themselves? Or does having the integer ratio with an error allow for a simpler calculation?
edit: Thinking on it, an algorithm that could extend to any set of N frequencies in a chord would be awesome, but I get the feeling that would be much more difficult...
edit 2: Clarification:
Let's consider that I am dealing with pure sine waves, and either ignoring the specific thresholds of the human ear or abstracting them into variables. If there are severe complications, then they are ignored. My question is how it could be represented in an algorithm, in that case.
Have a look at Chapter 4 of http://homepages.abdn.ac.uk/mth192/pages/html/maths-music.html. From memory:
1) If two sine waves are just close enough for the human ear to be confused, but not so close that the human ear cannot tell they are different, there will be dissonance.
2) Pure sine waves are extremely rare - most tones have all sorts of harmonics. Dissonance is very likely to occur from colliding harmonics, rather than colliding main tones - to sort of follow your example, two tones many octaves apart are unlikely to be dissonant because their harmonics may not meet, whereas with just a couple of octaves different and loads of harmonics a flute could sound out of tune with a double bass. Therefore dissonance or not depends not only on the frequencies of the main tones, but on the harmonics present, and this has been experimentally demonstrated by constructing sounds with peculiar pseudo-harmonics.
The answer is in Chapter 4 of Music: a Mathematical Offering. In particular, see the following two figures:
consonance / dissonance plotted against the x critical bandwidth in 4.3. History of consonance and dissonance
dissonance vs. frequency in 4.5. Complex tones
Of course you still have to find a nice way to turn these data into a formula / program that gives you a measure of dissonance but I believe this gives you a good start. Good luck!
This will help:
http://www.acs.psu.edu/drussell/demos/superposition/superposition.html
You want to look at superposition.
Discrete or Fast Fourier Transform is the most generic means to get what you're asking for.

how to test if time range has x number of laps

I'm trying to solve a 'decaying' puzzle that goes somewhat like this:
given A is 100 at DateTime.new(2012,5,10,0,0,0) and is decaying by 0.5 every 12 seconds, has it decayed exactly 20 by DateTime.new(2012,5,10,0,8,0)?
It so happens that the answer to that question is - well, true :)
But what about
A being 1304.5673,
the decay 0.00000197 every 1.2 msec
and end time being not one but 2000 DateTime.new's
I've tried with
fd=3.minutes.ago.to_datetime
td=Time.now
material=1304.5673
decay=0.00000197
step=0.00012.seconds
fd.step(td,step){ |n| material-=decay }
puts material
and the processing time is acceptable - but if I step any further back in time (like perhaps 10.hours or even 2.hours; my CPU cooler starts building up momentum, like it was about to propel the entire Mac into orbit :(
I've toiled with this problem for quite a while - even though the timespan from question to answer on SO does indicate the opposite <:)
(and the answer, to me, explicitly demonstrates why Ruby is such a wonderful language!)
# recap the variables in the question
total_decay = ((td.to_time - fd.to_time).divmod( step))[0]* decay
puts "new material: #{material - total_decay}"
The results will probably not pass scientific scrutiny, but I'm OK with that (for now) ;)

AI: selecting immediate acceleration/rotation to get to a final point

I'm working on a game where on each update of the game loop, the AI is run. During this update, I have the chance to turn the AI-controlled entity and/or make it accelerate in the direction it is facing. I want it to reach a final location (within reasonable range) and at that location have a specific velocity and direction (again it doesn't need to be exact) That is, given a current:
P0(x, y) = Current position vector
V0(x, y) = Current velocity vector (units/second)
θ0 = Current direction (radians)
τmax = Max turn speed (radians/second)
αmax = Max acceleration (units/second^2)
|V|max = Absolute max speed (units/second)
Pf(x, y) = Target position vector
Vf(x, y) = Target velocity vector (units/second)
θf = Target rotation (radians)
Select an immediate:
τ = A turn speed within [-τmax, τmax]
α = An acceleration scalar within [0, αmax] (must accelerate in direction it's currently facing)
Such that these are minimized:
t = Total time to move to the destination
|Pt-Pf| = Distance from target position at end
|Vt-Vf| = Deviation from target velocity at end
|θt-θf| = Deviation from target rotation at end (wrapped to (-π,π))
The parameters can be re-computed during each iteration of the game loop. A picture says 1000 words so for example given the current state as the blue dude, reach approximately the state of the red dude within as short a time as possible (arrows are velocity):
Pic http://public.blu.livefilestore.com/y1p6zWlGWeATDQCM80G6gaDaX43BUik0DbFukbwE9I4rMk8axYpKwVS5-43rbwG9aZQmttJXd68NDAtYpYL6ugQXg/words.gif
Assuming a constant α and τ for Δt (Δt → 0 for an ideal solution) and splitting position/velocity into components, this gives (I think, my math is probably off):
Equations http://public.blu.livefilestore.com/y1p6zWlGWeATDTF9DZsTdHiio4dAKGrvSzg904W9cOeaeLpAE3MJzGZFokcZ-ZY21d0RGQ7VTxHIS88uC8-iDAV7g/equations.gif
(EDIT: that last one should be θ = θ0 + τΔt)
So, how do I select an immediate α and τ (remember these will be recomputed every iteration of the game loop, usually > 100 fps)? The simplest, most naieve way I can think of is:
Select a Δt equal to the average of the last few Δts between updates of the game loop (i.e. very small)
Compute the above 5 equations of the next step for all combinations of (α, τ) = {0, αmax} x {-τmax, 0, τmax} (only 6 combonations and 5 equations for each, so shouldn't take too long, and since they are run so often, the rather restrictive ranges will be amortized in the end)
Assign weights to position, velocity and rotation. Perhaps these weights could be dynamic (i.e. the further from position the entity is, the more position is weighted).
Greedily choose the one that minimizes these for the location Δt from now.
Its potentially fast & simple, however, there are a few glaring problems with this:
Arbitrary selection of weights
It's a greedy algorithm that (by its very nature) can't backtrack
It doesn't really take into account the problem space
If it frequently changes acceleration or turns, the animation could look "jerky".
Note that while the algorithm can (and probably should) save state between iterations, but Pf, Vf and θf can change every iteration (i.e. if the entity is trying to follow/position itself near another), so the algorithm needs to be able to adapt to changing conditions.
Any ideas? Is there a simple solution for this I'm missing?
Thanks,
Robert
sounds like you want a PD controller. Basically draw a line from the current position to the target. Then take the line direction in radians, that's your target radians. The current error in radians is current heading - line heading. Call it Eh. (heading error) then you say the current turn rate is going to be KpEh+d/dt EhKd. do this every step with a new line.
thats for heading
acceleration is "Accelerate until I've reached max speed or I wont be able to stop in time". you threw up a bunch of integrals so I'm sure you'll be fine with that calculation.
I case you're wondering, yes I've solved this problem before, PD controller works. don't bother with PID, don't need it in this case. Prototype in matlab. There is one thing I've left out, you need to have a trigger, like "i'm getting really close now" so I should start turning to get into the target. I just read your clarification about "only accelerating in the direction we're heading". that changes things a bit but not too much. that means to need to approach the target "from behind" meaning that the line target will have to be behind the real target, when you get near the behind target, follow a new line that will guide you to the real target. You'll also want to follow the lines, rather than just pick a heading and try to stick with it. So don't update the line each frame, just say the error is equal to the SIGNED DISTANCE FROM THE CURRENT TARGET LINE. The PD will give you a turn rate, acceleration is trivial, so you're set. you'll need to tweak Kd and Kp by head, that's why i said matlab first. (Octave is good too)
good luck, hope this points you in the right direction ;)
pun intended.
EDIT: I just read that...lots of stuff, wrote real quick. this is a line following solution to your problem, just google line following to accompany this answer if you want to take this solution as a basis to solving the problem.
I would like to suggest that yout consider http://en.wikipedia.org/wiki/Bang%E2%80%93bang_control (Bang-bang control) as well as a PID or PD. The things you are trying to minimise don't seem to produce any penalty for pushing the accelerator down as far as it will go, until it comes time to push the brake down as far as it will go, except for your point about how jerky this will look. At the very least, this provides some sort of justification for your initial guess.

Eligibility trace algorithm, the update order

I am reading Silver et al (2012) "Temporal-Difference Search in Computer Go", and trying to understand the update order for the eligibility trace algorithm.
In the Algorithm 1 and 2 of the paper, weights are updated before updating the eligibility trace. I wonder if this order is correct (Line 11 and 12 in the Algorithm 1, and Line 12 and 13 of the Algorithm 2).
Thinking about an extreme case with lambda=0, the parameter is not updated with the initial state-action pair (since e is still 0). So I doubt the order possibly should be the opposite.
Can someone clarify the point?
I find the paper very instructive for learning the reinforcement learning area, so would like to understand the paper in detail.
If there is a more suitable platform to ask this question, please kindly let me know as well.
It looks to me like you're correct, e should be updated before theta. That's also what should happen according to the math in the paper. See, for example, Equations (7) and (8), where e_t is first computed using phi(s_t), and only THEN is theta updated using delta V_t (which would be delta Q in the control case).
Note that what you wrote about the extreme case with lambda=0 is not entirely correct. The initial state-action pair will still be involved in an update (not in the first iteration, but they will be incorporated in e during the second iteration). However, it looks to me like the very first reward r will never be used in any updates (because it only appears in the very first iteration, where e is still 0). Since this paper is about Go, I suspect it will not matter though; unless they're doing something unconventional, they probably only use non-zero rewards for the terminal game state.

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