Check for a valid guid - vbscript

Question

How can you check if a string is a valid GUID in vbscript? Has anyone written an IsGuid method?

Answer 1

This function is working in classic ASP:
Function isGUID(byval strGUID)
if isnull(strGUID) then
isGUID = false
exit function
end if
dim regEx
set regEx = New RegExp
regEx.Pattern = "^({|\()?[A-Fa-f0-9]{8}-([A-Fa-f0-9]{4}-){3}[A-Fa-f0-9]{12}(}|\))?$"
isGUID = regEx.Test(strGUID)
set RegEx = nothing
End Function

Answer 2

This is similar to the same question in c#. Here is the regex you will need...
^[A-Fa-f0-9]{32}$|^({|()?[A-Fa-f0-9]{8}-([A-Fa-f0-9]{4}-){3}[A-Fa-f0-9]{12}(}|))?$|^({)?[0xA-Fa-f0-9]{3,10}(, {0,1}[0xA-Fa-f0-9]{3,6}){2}, {0,1}({)([0xA-Fa-f0-9]{3,4}, {0,1}){7}[0xA-Fa-f0-9]{3,4}(}})$
But that is just for starters. You will also have to verify that the various parts such as the date/time are within acceptable ranges. To get an idea of just how complex it is to test for a valid GUID, look at the source code for one of the Guid constructors.

Answer 3

In VBScript you can use the RegExp object to match the string using regular expressions.

Answer 4

Techek's function did not work for me in classic ASP (vbScript). It always returned True for some odd reason. With a few minor changes it did work. See below
Function isGUID(byval strGUID)
if isnull(strGUID) then
isGUID = false
exit function
end if
dim regEx
set regEx = New RegExp
regEx.Pattern = "{[0-9A-Fa-f-]+}"
isGUID = regEx.Test(strGUID)
set RegEx = nothing
End Function

Answer 5

there is another solution:
try
{
Guid g = new Guid(stringGuid);
safeUseGuid(stringGuid); //this statement will execute only if guid is correct
}catch(Exception){}