I am using the following code but the final 'echo $dirname' is giving empty output on console
for folderpath in find /u01/app/SrcFiles/commercial/ngdw/* -name "IQ*";
do
folder_count=ls -d $folderpath/* | wc -l
echo -e "Total Date folder created : $folder_count in $folderpath \n"
if [ $folder_count -ne 0 ];
then
for dirpath in `find $folderpath/* -name "2*" `;
do
dirname=${dirpath##*/}
(( dirname <= 20210106 )) || continue
echo $dirname
done
fi
done
First I would calculate the date it was 3 months ago with the date command:
# with GNU date (for example on Linux)
mindate=$(date -d -3month +%Y%m%d)
# with BSD date (for example on macOS)
mindate=$(date -v -3m +%Y%m%d)
Then I would use a shell arithmetic comparison for determining the directories to remove:
# for dirpath in "$directory"/*
for dirpath in "$directory"/{20220310,20220304,20220210,20220203,20210403,20210405}
do
dirname=${dirpath##*/}
(( dirname <= mindate )) || continue
echo "$dirpath"
# rm -rf "$dirpath"
done
== doesn't do wildcard matching. You should do that in the for statement itself.
There's also no need to put * at the beginning of the wildcard, since the year is at the beginning of the directory name, not in the middle.
for i in "$directory"/202104*; do
if [ -d "$i" ]; then
echo "$i"
rm -rf "$i"
fi
done
The if statement serves two purposes:
If there are no matching directories, the wildcard expands to itself (unless you set the nullglob option), and you'll try to remove this nonexistent directory.
In case there are matching files rather than directories, they're skipped.
Suggesting to find which are the directories that created before 90 days ago or older, with find command.
find . -type d -ctime +90
If you want to find which directories created 90 --> 100 days ago.
find . -type d -ctime -100 -ctime +90
Once you have the correct folders list. Feed it to the rm command.
rm -rf $(find . -type d -ctime +90)
I'm working on a bash script that should go through a directory and print all files and if it hits a folder it should call it's self and do it again. I believe my problem lies with if [[ $file =~ \.yml?yaml$ ]]; when I remove the tilda it runs but not correctly if [[ $file = \.yml?yaml$ ]];
It returns "this a file isn't need -> $file" even though it's a yaml.
#!/bin/bash
print_files_and_dirs() {
for file in $1/*;
do
if [ -f "$file" ];
then
if [[ $file =~ \.yml?yaml$ ]];
then
echo "this is a yaml file! -> $file"
else
echo "this a file isn't need -> $file"
fi
else
print_files_and_dirs $file
fi
done
}
print_files_and_dirs .
Maybe you can use find to find the yaml files and do something with them.
find "$PWD" \
-type f \( -name "*.yaml" -or -name "*.yml" \) \
-exec echo found {} \;
If you only want the file name without the path, you could use printf to get the names and pipe it to xargs.
find "$PWD" \
-type f \( -name "*.yaml" -or -name "*.yml" \) \
-printf '%f\n' \
| xargs -I{} echo found {}
Requirement:
i am having the path where the files will be present .
i need to get the path from it and delete the files older than 7 days with name as .logo or ,out0 ..
ISSUE:tried the below but its going to many paths that were not listed..
#reading source path from rem_logs.txt
cat rem_logs.txt | while read FILE_PATH
do
echo " Path obtained from rem_logs.txt --> '$FILE_PATH'"
echo "File has to be removed from '$FILE_PATH'"
#moving to the specified path above
find $FILE_PATH -type f -mtime +7 -print | while read FILE_NAME
echo "File is '$FILE_NAME'"
do
chmod 777 $FILE_NAME
echo "$FILE_NAME is received"
if [ "$FILE_NAME"=*.log0* -o "$FILE_NAME"=*.out0*]
then
echo " $FILE_PATH/$FILE_NAME" > $LOGPATH/abdul.txt
used above statement for testing in testing environment
else
echo "This file - $FILE_NAME need not be removed"
fi
done
UpdateLog_del.sh "$FILE_NAME is presently deleted from the above mentioned path"
done
Consider doing something like this:
while read FILE_PATH
do
#for each filename found
for FILE_NAME in $(find $FILE_PATH \( -name "*.log0" -o -name "*.out0" \) -type f -mtime +7 -print)
do
chmod 777 $FILE_NAME
echo "$FILE_NAME" >> $LOGPATH/abdul.txt
done
UpdateLog_del.sh "$FILE_NAME is presently deleted from the above mentioned path"
#read from rem_logs.txt which contains the paths
done < rem_logs.txt
Try this:
find /path -type f -mtime +7 -regex '$\|.*log0$\|.*out0$' -print | xargs -I '{}' -n1 rm -f {}
Currently I have multiple directories
Directory1 Directory2 Directory3 Directory4
each of these directories contain files (the files are somewhat cryptic)
what i wish to do is scan files within the folders to see if certain files are present, if they are then leave that folder alone, if the certain files are not present then just delete the entire directory. here is what i mean:
im searching for the files that have the word .pass. in the filename.
Say Directory 4 has that file that im looking for
Direcotry4:
file1.temp.pass.exmpl
file1.temp.exmpl
file1.tmp
and the rest of the Directories do not have that specific file:
file.temp
file.exmp
file.tmp.other
so i would like to delete Directory1,2 and3 But only keep Directory 4...
So far i have come up with this code
(arr is a array of all the directory names)
for x in ${arr[#]}
do
find $x -type f ! -name "*pass*" -exec rd {} $x\;
done
another way i have thought of doing this is like this:
for x in ${arr[#]}
do
cd $x find . -type f ! -name "*Pass*" | xargs -i rd {} $x/
done
SO far these don't seem to work, and im scared that i might do something wrong and have all my files deleted.....(i have backed up)
is there any way that i can do this? remember i want Directory 4 to be unchanged, everything in it i want to keep
To see if your directory contains a pass file:
if [ "" = "$(find directory -iname '*pass*' -type f | head -n 1)" ]
then
echo notfound
else
echo found
fi
To do that in a loop:
for x in "${arr[#]}"
do
if [ "" = "$(find "$x" -iname '*pass*' -type f | head -n 1)" ]
then
rm -rf "$x"
fi
done
Try this:
# arr is a array of all the directory names
for x in ${arr[#]}
do
ret=$(find "$x" -type f -name "*pass*" -exec echo "0" \;)
# expect zero length $ret value to remove directory
if [ -z "$ret" ]; then
# remove dir
rm -rf "$x"
fi
done
I need to loop through a directory recursively and remove all files with extension .pdf and .doc. I'm managing to loop through a directory recursively but not managing to filter the files with the above mentioned file extensions.
My code so far
#/bin/sh
SEARCH_FOLDER="/tmp/*"
for f in $SEARCH_FOLDER
do
if [ -d "$f" ]
then
for ff in $f/*
do
echo "Processing $ff"
done
else
echo "Processing file $f"
fi
done
I need help to complete the code, since I'm not getting anywhere.
As a followup to mouviciel's answer, you could also do this as a for loop, instead of using xargs. I often find xargs cumbersome, especially if I need to do something more complicated in each iteration.
for f in $(find /tmp -name '*.pdf' -or -name '*.doc'); do rm $f; done
As a number of people have commented, this will fail if there are spaces in filenames. You can work around this by temporarily setting the IFS (internal field seperator) to the newline character. This also fails if there are wildcard characters \[?* in the file names. You can work around that by temporarily disabling wildcard expansion (globbing).
IFS=$'\n'; set -f
for f in $(find /tmp -name '*.pdf' -or -name '*.doc'); do rm "$f"; done
unset IFS; set +f
If you have newlines in your filenames, then that won't work either. You're better off with an xargs based solution:
find /tmp \( -name '*.pdf' -or -name '*.doc' \) -print0 | xargs -0 rm
(The escaped brackets are required here to have the -print0 apply to both or clauses.)
GNU and *BSD find also has a -delete action, which would look like this:
find /tmp \( -name '*.pdf' -or -name '*.doc' \) -delete
find is just made for that.
find /tmp -name '*.pdf' -or -name '*.doc' | xargs rm
Without find:
for f in /tmp/* tmp/**/* ; do
...
done;
/tmp/* are files in dir and /tmp/**/* are files in subfolders. It is possible that you have to enable globstar option (shopt -s globstar).
So for the question the code should look like this:
shopt -s globstar
for f in /tmp/*.pdf /tmp/*.doc tmp/**/*.pdf tmp/**/*.doc ; do
rm "$f"
done
Note that this requires bash ≥4.0 (or zsh without shopt -s globstar, or ksh with set -o globstar instead of shopt -s globstar). Furthermore, in bash <4.3, this traverses symbolic links to directories as well as directories, which is usually not desirable.
If you want to do something recursively, I suggest you use recursion (yes, you can do it using stacks and so on, but hey).
recursiverm() {
for d in *; do
if [ -d "$d" ]; then
(cd -- "$d" && recursiverm)
fi
rm -f *.pdf
rm -f *.doc
done
}
(cd /tmp; recursiverm)
That said, find is probably a better choice as has already been suggested.
Here is an example using shell (bash):
#!/bin/bash
# loop & print a folder recusively,
print_folder_recurse() {
for i in "$1"/*;do
if [ -d "$i" ];then
echo "dir: $i"
print_folder_recurse "$i"
elif [ -f "$i" ]; then
echo "file: $i"
fi
done
}
# try get path from param
path=""
if [ -d "$1" ]; then
path=$1;
else
path="/tmp"
fi
echo "base path: $path"
print_folder_recurse $path
This doesn't answer your question directly, but you can solve your problem with a one-liner:
find /tmp \( -name "*.pdf" -o -name "*.doc" \) -type f -exec rm {} +
Some versions of find (GNU, BSD) have a -delete action which you can use instead of calling rm:
find /tmp \( -name "*.pdf" -o -name "*.doc" \) -type f -delete
For bash (since version 4.0):
shopt -s globstar nullglob dotglob
echo **/*".ext"
That's all.
The trailing extension ".ext" there to select files (or dirs) with that extension.
Option globstar activates the ** (search recursivelly).
Option nullglob removes an * when it matches no file/dir.
Option dotglob includes files that start wit a dot (hidden files).
Beware that before bash 4.3, **/ also traverses symbolic links to directories which is not desirable.
This method handles spaces well.
files="$(find -L "$dir" -type f)"
echo "Count: $(echo -n "$files" | wc -l)"
echo "$files" | while read file; do
echo "$file"
done
Edit, fixes off-by-one
function count() {
files="$(find -L "$1" -type f)";
if [[ "$files" == "" ]]; then
echo "No files";
return 0;
fi
file_count=$(echo "$files" | wc -l)
echo "Count: $file_count"
echo "$files" | while read file; do
echo "$file"
done
}
This is the simplest way I know to do this:
rm **/#(*.doc|*.pdf)
** makes this work recursively
#(*.doc|*.pdf) looks for a file ending in pdf OR doc
Easy to safely test by replacing rm with ls
The following function would recursively iterate through all the directories in the \home\ubuntu directory( whole directory structure under ubuntu ) and apply the necessary checks in else block.
function check {
for file in $1/*
do
if [ -d "$file" ]
then
check $file
else
##check for the file
if [ $(head -c 4 "$file") = "%PDF" ]; then
rm -r $file
fi
fi
done
}
domain=/home/ubuntu
check $domain
There is no reason to pipe the output of find into another utility. find has a -delete flag built into it.
find /tmp -name '*.pdf' -or -name '*.doc' -delete
The other answers provided will not include files or directories that start with a . the following worked for me:
#/bin/sh
getAll()
{
local fl1="$1"/*;
local fl2="$1"/.[!.]*;
local fl3="$1"/..?*;
for inpath in "$1"/* "$1"/.[!.]* "$1"/..?*; do
if [ "$inpath" != "$fl1" -a "$inpath" != "$fl2" -a "$inpath" != "$fl3" ]; then
stat --printf="%F\0%n\0\n" -- "$inpath";
if [ -d "$inpath" ]; then
getAll "$inpath"
#elif [ -f $inpath ]; then
fi;
fi;
done;
}
I think the most straightforward solution is to use recursion, in the following example, I have printed all the file names in the directory and its subdirectories.
You can modify it according to your needs.
#!/bin/bash
printAll() {
for i in "$1"/*;do # for all in the root
if [ -f "$i" ]; then # if a file exists
echo "$i" # print the file name
elif [ -d "$i" ];then # if a directroy exists
printAll "$i" # call printAll inside it (recursion)
fi
done
}
printAll $1 # e.g.: ./printAll.sh .
OUTPUT:
> ./printAll.sh .
./demoDir/4
./demoDir/mo st/1
./demoDir/m2/1557/5
./demoDir/Me/nna/7
./TEST
It works fine with spaces as well!
Note:
You can use echo $(basename "$i") # print the file name to print the file name without its path.
OR: Use echo ${i%/##*/}; # print the file name which runs extremely faster, without having to call the external basename.
Just do
find . -name '*.pdf'|xargs rm
If you can change the shell used to run the command, you can use ZSH to do the job.
#!/usr/bin/zsh
for file in /tmp/**/*
do
echo $file
done
This will recursively loop through all files/folders.
The following will loop through the given directory recursively and list all the contents :
for d in /home/ubuntu/*;
do
echo "listing contents of dir: $d";
ls -l $d/;
done