I've a panel of size X by Y. I want to place up to N rectangles, sized randomly, upon this panel, but I don't want any of them to overlap. I need to know the X, Y positions for these rectangles.
Algorithm, anyone?
Edit: All the N rectangles are known at the outset and can be selected in any order. Does that change the procedure?
You can model this by a set of "free" rectangles, starting with single one with coordinates of 0,0, size (x, y). Each time you need to add one more rectangle, choose one of remaining "free" rectangles, generate new rectangle (with top-left coordinate and size such that it will be fully contained), and split that rectangle as well as any other overlapping "free" rectangle, such that children express remaining free space. This will result in 0 to 4 new rectangles (0 if new rectangle was exactly the size of old free rectangle; 4 if it's in the middle and so on). Over time you will get more and more smaller and smaller free areas, so rectangles you create will be smaller as well.
Ok, not a very elaborate explanation, it's easier to show on whiteboard. But the model is one I used for finding starting location for newly cut'n pasted gui components; it's easy to keep track of available chunks of screen, and choose (for example) left or topmost such area.
Here is a decent article on 2d packing algorithms: http://www.devx.com/dotnet/Article/36005
You'll generally want some sort of algorithm using heuristics to achieve decent results. A simple (but non-optimal) solution would be the first fit algorithm.
I used this Rectangle Packing algorithm in one of my applications, available as C# source files.
The algorithm is initialized with the size of the panel, then you iterate through all rectangles and get their position. The order of the rectangles may influence the result, depending on the packer.
I would advise you use StaxMans suggestion.
Here is my 2c:
Add a whole lot of rectangles randomly (overlapping each other).
delete overlapping rectangles:
for rectangle in list of rectangles:
if rectangle not deleted:
delete all rectangles touching rectangle.
to find all the rectangles touching a particular rectangle, you can use a quad tree or inequalities based on x1,y1 x2,y2 values.
Edit: In fact, most game engines such as pygame etc include collision detection of rectangles which is a common problem.
Or maintain a list of rectangles already added and create an algorithm that figures out where to place the new rectangle based on that list. You can create a basic Rectangle class to hold the information about your rectangles.
Shouldn't be so hard to create a custom algorithm.
Related
What I am asking here is an algorithm question. I'm not asking for specifics of how to do it in the programming language I'm working in or with the framework and libraries I'm currently using. I want to know how to do this in principle.
As a hobby, I am working on an open source virtual reality remake of the 1992 first-person shooter game Wolfenstein 3D. My program will support classic mods and map packs for WOLF3D made in the original format from the 90s. This means that my program will not know in advance what the maps are going to be. They are loaded in at runtime from user provided files.
A Wolfenstein 3D map is a 2D square grid of normally 64x64 tiles. let's assume I have a 2D array of bools which return true if a particular tile can be traversed by the player and false if the tile will never be traversable no matter what happens in the game.
I want to generate rectangular collision objects for a modern game engine which will prevent collisions into non traversable tiles on the map. Right now, I have a small collision object on each surface of each wall tile with a traversible tile next to it and that is very inefficient because it makes way more collision objects than necessary. What I should have instead is a smaller number of large rectangles which fill all of the squares on the grid where that 2D array I mentioned has a false value to indicate non-traversible.
When I search for any algorithms or research that might have been done for problems similar to this, I find lots of information about rectangle packing for the purposes of making texture atlases for games, which packs rectangles into a square, but I haven't found anything that tries to pack the smallest number of rectangles into an arbitrary set of selected / marked square tiles.
The naive approach which occurs to me is to first make 64 rectangles representing 64 rows and then chop out whatever squares are traversible. but I suspect that there's got to be an algorithm which can do better, meaning that it can fill the same spaces with a smaller number of rectangles. Maybe something that starts with my naive approach and then checks each rectangle for adjacent rectangles which it could merge with? But I'm not sure how far to take that approach or if it will even truly reduce the number of rectangles.
The result doesn't have to be perfect. I am just fishing here to see if anyone has any magic tricks that could take me even a little bit beyond the naive approach.
Has anyone done this before? What is it called? Just knowing what some of the vocabulary words I would need to even talk about this are would help. Thanks!
(later edit)
Here is some sample input as comma-separated values. The 1s represent the area that must be filled with the rectangles while the 0s represent the area that should not be filled with the rectangles.
I expect that the result would be a list of sets of 4 integers where each set represents a rectangle like this:
First integer would be the x coordinate of the left/western edge of the rectangle.
Second integer would be the y coordinate of the top/northern edge of the rectangle.
Third integer would be the width of the rectangle.
Fourth integer would be the depth of the rectangle.
My program is in C# but I'm sure I can translate anything in a normal mainstream general purpose programming language or psuedocode.
Mark all tiles as not visited
For each tile:
skip if the tile is not a top-left corner or was visited before
# now, the tile is a top-left corner
expand right until top-right corner is found
expand down
save the rectangle
mark all tiles in the rectangle as visited
However simplistic it looks, it will likely generate minimal number of rectangles - simply because we need at least one rectangle per pair of top corners.
For faster downward expansion, it makes sense to precompute a table holding sum of all element top and left from the tile (aka integral image).
For non-overlapping rectangles, worst case complexity for an n x n "image" should not exceed O(n^3). If rectangles can overlap (would result in smaller number of them), integral image optimization is not applicable and the worst case will be O(n^4).
I have a collection of different sized rectangles that need to be placed on a 2D surface of a known dimension, with the condition that:
there is no overlap between the blocks,
the rectangles may not be rotated,
there is no area left blank (whole surface needs to be filled).
The rectangles are actually generated by breaking down the surface area, so they ought to fill up the area completely once you start putting everything together.
I figured there would be a dozen algorithms available for this problem, but the algorithms I find are more like best effort algorithms such as sprite generators that do not have the precondition that the whole area needs to be (can be...) filled -- which obviously is not necessary when building sprites, however, it is in my case.
I am a bit lost here, either this problem isn't as simple as I thought, or I am searching on wrong keywords.
Some topics I have found but do not fully suit my needs:
What algorithm can be used for packing rectangles of different sizes into the smallest rectangle possible in a fairly optimal way? (in my case, the area is preset)
How to arrange N rectangles to cover minimum area (in my case, minimum area must equal zero)
Is there any algorithm out there that may suit my needs?
IMHO, the most natural solution is recursive. For the form of source area is not set. And after removing a rectangle from it, we have the same task, only with smaller area and -1 rectangle.
I would start from the edges, because there the possible variants are already limited. So, simply go by spiral, trying to put rectangles along the edge. If no rectangle fits, go back. That will be the simplest and not so slow raw force method.
I'm not sure if there's an algorithm that can solve this.
A given number of rectangles are placed side by side horizontally from left to right to form a shape. You are given the width and height of each.
How would you determine the minimum number of rectangles needed to cover the whole shape?
i.e How would you redraw this shape using as few rectangles as possible?
I've can only think about trying to squeeze as many big rectangles as i can but that seems inefficient.
Any ideas?
Edit:
You are given a number n , and then n sizes:
2
1 3
2 5
The above would have two rectangles of sizes 1x3 and 2x5 next to each other.
I'm wondering how many rectangles would i least need to recreate that shape given rectangles cannot overlap.
Since your rectangles are well aligned, it makes the problem easier. You can simply create rectangles from the bottom up. Each time you do that, it creates new shapes to check. The good thing is, all your new shapes will also be base-aligned, and you can just repeat as necessary.
First, you want to find the minimum height rectangle. Make a rectangle that height, with the width as total width for the shape. Cut that much off the bottom of the shape.
You'll be left with multiple shapes. For each one, do the same thing.
Finding the minimum height rectangle should be O(n). Since you do that for each group, worst case is all different heights. Totals out to O(n2).
For example:
In the image, the minimum for each shape is highlighted green. The resulting rectangle is blue, to the right. The total number of rectangles needed is the total number of blue ones in the image, 7.
Note that I'm explaining this as if these were physical rectangles. In code, you can completely do away with the width, since it doesn't matter in the least unless you want to output the rectangles rather than just counting how many it takes.
You can also reduce the "make a rectangle and cut it from the shape" to simply subtracting the height from each rectangle that makes up that shape/subshape. Each contiguous section of shapes with +ve height after doing so will make up a new subshape.
If you look for an overview on algorithms for the general problem, Rectangular Decomposition of Binary Images (article by Tomas Suk, Cyril Höschl, and Jan Flusser) might be helpful. It compares different approaches: row methods, quadtree, largest inscribed block, transformation- and graph-based methods.
A juicy figure (from page 11) as an appetizer:
Figure 5: (a) The binary convolution kernel used in the experiment. (b) Its 10 blocks of GBD decomposition.
I am looking for a sound algorithm that would randomly place a given number of rectangles of the same size into a bigger rectangle (canvas).
I see two ways to do it:
create an empty array that will contain the rectangles already placed on canvas. start with the empty canvas. in a loop, pick a position at random for a new rectangle to be placed. check if the array has a rectangle that overlaps with the new rectangle. if it does not, put the new rectangle in to the array and repeat the loop. otherwise, pick a new position, and rerun the check again. and so on. This might never terminate (theoretically) I think. I do not like it.
use a grid and place rectangles into the cells randomly. This might still look like a grid placement. I do not like it either.
any better ways to do it? "better" meaning more efficient, or more visually "random" than the grid approach. better in any respect.
Here is a simple heuristic. It will be non-overlapping and random.
Place a rectangle randomly. Then, calculate the intersections of extensions of the the two parallel edges of the first rectangle with the edges of the canvas. You will obtain four convex empty regions. Place other rectangles in these empty regions one-by-one independently and calculate the similar divisions for placements. And try to put the remaining rectangles in empty regions.
You can try different strategies. You can try to place the rectangles close to the corners. Or, you can place them around the center of the regions. We cannot discuss optimality because you introduced randomness.
You might find Quadtrees or R-trees useful for your purpose.
I create internal room-like dungeons using the following method.
1) Scatter N points at random, but not within a few pixels of each other.
2) For each point in turn, expand if possible in all four directions. Cease
expanding if you hit another rectangle.
3) Cease the algorithm when no rooms can expand.
The result is N rectancles with just a few rectangular small spaces.
Code is in the binary image library
https://github.com/MalcolmMcLean/binaryimagelibrary/blob/master/dungeongenerator3.c
#
What is the most efficient way to randomly fill a space with as many non-overlapping shapes? In my specific case, I'm filling a circle with circles. I'm randomly placing circles until either a certain percentage of the outer circle is filled OR a certain number of placements have failed (i.e. were placed in a position that overlapped an existing circle). This is pretty slow, and often leaves empty spaces unless I allow a huge number of failures.
So, is there some other type of filling algorithm I can use to quickly fill as much space as possible, but still look random?
Issue you are running into
You are running into the Coupon collector's problem because you are using a technique of Rejection sampling.
You are also making strong assumptions about what a "random filling" is. Your algorithm will leave large gaps between circles; is this what you mean by "random"? Nevertheless it is a perfectly valid definition, and I approve of it.
Solution
To adapt your current "random filling" to avoid the rejection sampling coupon-collector's issue, merely divide the space you are filling into a grid. For example if your circles are of radius 1, divide the larger circle into a grid of 1/sqrt(2)-width blocks. When it becomes "impossible" to fill a gridbox, ignore that gridbox when you pick new points. Problem solved!
Possible dangers
You have to be careful how you code this however! Possible dangers:
If you do something like if (random point in invalid grid){ generateAnotherPoint() } then you ignore the benefit / core idea of this optimization.
If you do something like pickARandomValidGridbox() then you will slightly reduce the probability of making circles near the edge of the larger circle (though this may be fine if you're doing this for a graphics art project and not for a scientific or mathematical project); however if you make the grid size 1/sqrt(2) times the radius of the circle, you will not run into this problem because it will be impossible to draw blocks at the edge of the large circle, and thus you can ignore all gridboxes at the edge.
Implementation
Thus the generalization of your method to avoid the coupon-collector's problem is as follows:
Inputs: large circle coordinates/radius(R), small circle radius(r)
Output: set of coordinates of all the small circles
Algorithm:
divide your LargeCircle into a grid of r/sqrt(2)
ValidBoxes = {set of all gridboxes that lie entirely within LargeCircle}
SmallCircles = {empty set}
until ValidBoxes is empty:
pick a random gridbox Box from ValidBoxes
pick a random point inside Box to be center of small circle C
check neighboring gridboxes for other circles which may overlap*
if there is no overlap:
add C to SmallCircles
remove the box from ValidBoxes # possible because grid is small
else if there is an overlap:
increase the Box.failcount
if Box.failcount > MAX_PERGRIDBOX_FAIL_COUNT:
remove the box from ValidBoxes
return SmallCircles
(*) This step is also an important optimization, which I can only assume you do not already have. Without it, your doesThisCircleOverlapAnother(...) function is incredibly inefficient at O(N) per query, which will make filling in circles nearly impossible for large ratios R>>r.
This is the exact generalization of your algorithm to avoid the slowness, while still retaining the elegant randomness of it.
Generalization to larger irregular features
edit: Since you've commented that this is for a game and you are interested in irregular shapes, you can generalize this as follows. For any small irregular shape, enclose it in a circle that represent how far you want it to be from things. Your grid can be the size of the smallest terrain feature. Larger features can encompass 1x2 or 2x2 or 3x2 or 3x3 etc. contiguous blocks. Note that many games with features that span large distances (mountains) and small distances (torches) often require grids which are recursively split (i.e. some blocks are split into further 2x2 or 2x2x2 subblocks), generating a tree structure. This structure with extensive bookkeeping will allow you to randomly place the contiguous blocks, however it requires a lot of coding. What you can do however is use the circle-grid algorithm to place the larger features first (when there's lot of space to work with on the map and you can just check adjacent gridboxes for a collection without running into the coupon-collector's problem), then place the smaller features. If you can place your features in this order, this requires almost no extra coding besides checking neighboring gridboxes for collisions when you place a 1x2/3x3/etc. group.
One way to do this that produces interesting looking results is
create an empty NxM grid
create an empty has-open-neighbors set
for i = 1 to NumberOfRegions
pick a random point in the grid
assign that grid point a (terrain) type
add the point to the has-open-neighbors set
while has-open-neighbors is not empty
foreach point in has-open-neighbors
get neighbor-points as the immediate neighbors of point
that don't have an assigned terrain type in the grid
if none
remove point from has-open-neighbors
else
pick a random neighbor-point from neighbor-points
assign its grid location the same (terrain) type as point
add neighbor-point to the has-open-neighbors set
When done, has-open-neighbors will be empty and the grid will have been populated with at most NumberOfRegions regions (some regions with the same terrain type may be adjacent and so will combine to form a single region).
Sample output using this algorithm with 30 points, 14 terrain types, and a 200x200 pixel world:
Edit: tried to clarify the algorithm.
How about using a 2-step process:
Choose a bunch of n points randomly -- these will become the centres of the circles.
Determine the radii of these circles so that they do not overlap.
For step 2, for each circle centre you need to know the distance to its nearest neighbour. (This can be computed for all points in O(n^2) time using brute force, although it may be that faster algorithms exist for points in the plane.) Then simply divide that distance by 2 to get a safe radius. (You can also shrink it further, either by a fixed amount or by an amount proportional to the radius, to ensure that no circles will be touching.)
To see that this works, consider any point p and its nearest neighbour q, which is some distance d from p. If p is also q's nearest neighbour, then both points will get circles with radius d/2, which will therefore be touching; OTOH, if q has a different nearest neighbour, it must be at distance d' < d, so the circle centred at q will be even smaller. So either way, the 2 circles will not overlap.
My idea would be to start out with a compact grid layout. Then take each circle and perturb it in some random direction. The distance in which you perturb it can also be chosen at random (just make sure that the distance doesn't make it overlap another circle).
This is just an idea and I'm sure there are a number of ways you could modify it and improve upon it.