I am dealing with a massive nest of files and need to find a .htaccess file that is redirecting a single page in my website. I know how ridiculous this sounds: why not just check the directories the page is located within? But the problem is slightly more complicated than that. All I need though, is to search for every .htaccess file under the web folder. Trying a normal search doesn't allow me to select that type of file to search for, and searching for hidden files has just been (who knows why) ignoring the .htaccess files anyway. I can't download any new software to do this for me. but - there must be a way! Even if I could somehow list every file within a directory (and its subdirs) and then organize by file type and scroll down?
I could search for any file with the word "RewriteEngine" , but there are so many files, this would take forever.
Any ideas?
Thanks!
=/ notepad++ is not installed, and I don't have auth to install anything
Use the commandline.
findstr /s RewriteEngine .htaccess
Searches the current directory and all sub directories for .htaccess files containing the string RewriteEngine.
Try searching for files of the form: *htaccess
(spelled precisely like that in the search field)
have you tried using Notepad++. It has a 'Find in files...' option that you could specify the page that it's trying to redirect to, and you could have it check only in *.htaccess files.
Just a thought
Search All files and folders, in All or part of the filename: put ".htaccess" including the quotes.
in the command prompt:
for hidden files: dir /s /b /a:sh *.htaccess>C:\results.txt
for non-hidden files: dir /s /b *.htaccess>C:\results.txt
to search for "RewriteEngine" type dir /s /b rewriteengine
both of these will output the search results to a text file called "results"
Related
I have ZERO bat knowledge so thought I would ask here, if I may.
I have an image C:\Users\Dane\Pictures\Doom.jpg. I wish for this image to be copied and for it to be renamed to the exact name of 379 non-image type files which are in another folder which is G:\Doom. So I will have the same image 379 times but named to match the 379 files.
Would anyone be kind enough to write a bat file to do that? Thank you in advance.
This site is not a free code writing service; Rather give the subject an attempt and we will be happy to assist you. However, because I'm nice, I have a response for you.
This problem is pretty common and can be solved very easily using a FOR statement. In this example we will be searching a directory for every item stored inside. Each item will be added to the integer %%A. For more information do FOR /? inside a command window.
for %%a in ("Directory") DO (Action)
For copying files, we will use the copy command. Please keep note that we will be using parameter extensions to expand the %%A to have no extension using %%~na. More info here: Parameter Extensions
This script will copy & rename Doom.jpg to G:\Doom for each item in the directory.
Batch File:
for %%a in ("G:\Doom\*") do (copy "C:\Users\Dane\Pictures\Doom.jpg" "G:\Doom\%%~na.png")
Command Prompt:
for %a in ("G:\Doom\*") do (copy "C:\Users\Dane\Pictures\Doom.jpg" "G:\Doom\%~na.png")
i want to rename different files in bash with pattern and found this option:
rename 's/.2007/(2007)/g' *.*
with this pattern I can rename every file with ".2007" in name to "(2007)"
--> this is exactly what i want to do.
Next step:
i want to automate this, because i have files with 1995 - 2017. It is a possibility to do:
rename 's/.2007/(2007)/g' *.*
rename 's/.2008/(2008)/g' *.*
rename 's/.2009/(2009)/g' *.*
etc.
but actually, is there another solution?
my files are named like (they are not the same length...):
FILENAME.ANOTHERFILENAME.2007.jpg
FILENAME.2007.jpg
FILENAME.ANOTHERFILENAME.SOMETIMESONEMORE.2007.jpg
With Perl‘s rename:
rename -n 's/.([1-2][0-9]{3})/($1)/' *.*
This renames all files with 1000 to 2999. If everything looks fine remove -n.
For the use-cases where it's not so much about automation but rather about batch processing of a set of files, I find renameutils and its qmv ("quick move") very useful: it enables you to edit the target filenames in a text editor which may be easier/faster than designing regex's for some.
https://www.nongnu.org/renameutils/ (it's in *buntu repos)
But for applications that need to run w/o human intervention, rename is certainly more suitable.
I have read many posts covering copy and xcopy, but i am unable to get my command to work.
I aim is to create a batch file that will do the following;
Search a directory structure for a list of files 'names only' if found copy them to another directory. If not found create an error list.
The txt format of files I am looking for can be in any format however in testing i have a text file like this;
1603010853
1603020845
1603141400
1604061215
The files are .PDF or .TIF
The directory structure that I am searching is like this;
X:DEL>16>160314>1603141400.pdf
X:DEL>16>160301>1603010853.tif
I am struggling to get it to work as the list is not the full path.
for /f "tokens=*" %i in (File-list.txt) DO xcopy /S/E "c:Test\In%i" "c:out"
Thanks in advance
Fostersimported
Alrighty, if tool doesn't matter much, I'd suggest going with the PowerShell script attached to this SuperUser post. It seems to do everything you want (including logging errors). You'd need only copypasta that into a text file, name it accordingly, and go from there.
need some help with this one
I have a directory that contains subdirectories from various applications so let's say directory is c:\home and each application has a subdirectory called the application name so we will have
c:\home\app1
c:\home\app2
etc.
These applications write large log files and they then get recreated every hour but into a different directory, called according t date and time like dd/mm/yyyy/hr and this is created within the actual subdirectory and a log file with the exact same name will be within each directory for each app. so we will end up with this
c:\home\app1\1015201410\app1.log
c:\home\app1\1015201411\app1.log
c:\home\app1\1015201412\app1.log
c:\home\app2\1015201410\app2.log
c:\home\app2\1015201411\app2.log
c:\home\app2\1015201412\app2.log
I want to list through the directories every hour and collect the latest log from each application, in other words in this instance I want to collect the following 2 only as they are the latest (end time 12 shows it is the 12th hour)
c:\home\app1\1015201412\app1.log
c:\home\app4\1015201412\app2.log
Now getting the file one by one is easy enough but the script is going to become too long and needs to be edited on a regular base to allow for new applications added to the directories.
I am able to do the copying, formatting the time/date section etc. I just need to find a way to search through the home directories for all subdirectories containing the latest timedate and then copy a file from it elsewhere.
So I tried this. Note timedateformat has been predefined:
for /D %%d in (c:\home\*\%timedateformat%\*) do (
for %%f in (%%d\.log) do (
xcopy %%f C:\destination\
)
)
but this obviously does not like the * part and therefore I will get no result.
Please if anyone is able to assist, I would greatly appreciate.
for /d %%F in ("c:\home\*") do xcopy "%%F\%timedateformat%\*.log" "c:\destination\"
I'm trying to find a way to copy all *.exe files (and more, *.dtd, *.obj, etc.) from a directory structure to another path.
For example I might have:
Code
\classdirA
\bin
\classA.exe
\classdirB
\bin
\classB.exe
\classdirC
\bin
\classC.exe
\classdirD
\bin
\classD.exe
And I want to copy all *.exe files into a single directory, say c:\bins
What would be the best way to do this?
Constraints for my system are:
Windows
Can be Perl, Ruby, or .cmd
Anyone know what I should be looking at here?
Just do in Ruby, using method Dir::glob :
# this will give you all the ".exe" files recursively from the directory "Code".
Dir.glob("c:/Code/**/*.exe")
** - Match all directories recursively. This is used to descend into the directory tree and find all files in sub-directories of the current directory, rather than just files in the current directory. This wildcard is explored in the example code.
* - Match zero or more characters. A glob consisting of only the asterisk and no other characters or wildcards will match all files in the current directory. The asterisk is usually combined with a file extension, if not more characters to narrow down the search.
Nice blog Using Glob with Directories.
Now to copy the files to your required directory, you need to look into the method, FileUtils.cp_r :
require 'fileutils'
FileUtils.cp_r Dir.glob("c:/Code/**/*.exe"), "c:\\bins"
I just have tested, that FileUtils.cp method will also work, in this case :
require 'fileutils'
FileUtils.cp Dir.glob("c:/Code/**/*.exe"), "c:\\bins"
My preference here is to use ::cp method. Because Dir::glob is actually collecting all the files having .exe extensions recursively, and return them as an array. Now cp method is enough here, now just taking each file from the array and coping it to the target file.
Why I am not liking in such a situation, the method ::cp_r ?
Okay, let me explain it here also. As the method name suggests, it will copy all the files recursively from the source to target directory. If there is a need to copy specific files recursively, then ::cp_r wouldn't be able to do this by its own power ( as it can't do selections by itself, which ::glob can do ). Thus in such a situation, you have to give it the specific file lists, it would then copy then to the target directory. If this is the only task, I have to do, then I think we should go with ::cp, rather than ::cp_r.
Hope my explanation helps.
From cmd command line
for /r "c:\code" %f in (*.exe) do copy "%~ff" "c:\bins"
For usage inside a batch file, double the percent signs (%% instead of %)
Windows shell (cmd) command:
for /r code %q in (*.exe) do copy "%q" c:\bin
Double the % characters if you place this in a batch file.