Using VB6
Code.
Dim posn As Integer, i As Integer
Dim fName As String
posn = 0
For i = 1 To Len(flname)
If (Mid(flname, i, 1) = "\") Then posn = i
Next i
fName = Right(flname, Len(flname) - posn)
posn = InStr(fName, ".")
If posn <> 0 Then
fName = Left(fName, posn - 1)
End If
GetFileName = fName
FileName: Clockings8.mis06042009 120442.fin
But it is showing a filename is “Clockings8”. It should show “Clockings8.mis06042009 120442”
How to modify a code?
Need vb6 code Help
It is a bit cleaner to use the Scripting.FileSystemObject component. Try:
Dim fso as New Scripting.FileSystemObject
GetFileName = fso.GetBaseName(fname)
The reason why your code stops short is that InStr works from the beginning of the string to the end and stops wherever it finds a match. The filename "Clockings8.mis06042009 120442.fin" contains two periods. For this reason, you should use InStrRev instead to start the search from the end of the string.
Going with FileSystemObject's GetBaseName like David suggests is a good idea. If you can't or don't want to (and there are reasons why you might not want to) work with the FileSystemObject there's a simple solution: Remove all characters from a filename string starting with the last dot in the name.
Here's what I mean:
Dim fn As String
fn = "Clockings8.mis06042009 120442.fin"
Dim idx As Integer
idx = InStrRev(fn, ".")
GetFileName = Mid(fn, 1, idx - 1)
If your filename does not have an extenstion but has a dot somewhere in the filename string, then this method will return bad results.
Related
I'm trying to make a program that can take the letters of a string and invert their case. I know that in vb.net there exists the IsUpper() command, but I don't know of such a thing in vb6.
What can I use in place of it?
Thanks!
Something like this should work:
Private Function Invert(strIn As String) As String
Dim strOut As String
Dim strChar As String
Dim intLoop As Integer
For intLoop = 1 To Len(strIn)
strChar = Mid(strIn, intLoop, 1)
If UCase(strChar) = strChar Then
strChar = LCase(strChar)
Else
strChar = UCase(strChar)
End If
strOut = strOut + strChar
Next
Invert = strOut
End Function
This loops through the supplied string, and extracts each character. It then tries to convert it to upper case and checks it against the extracted character. If it's the same then it was already upper case, so it converts it to lower case.
It handles non alpha characters just fine as UCase/LCase ignores those.
Suppose I have a variable set to the path of an image.
Let img = "C:\Users\Example\Desktop\Test\Stuff\Icons\test.jpg"
I want to slice everything before "\Icons" using Vb6. So after slicing the string it would be "\Icons\test.jpg" only.
I have tried fiddling with the Mid$ function in VB6, but I haven't really had much success. I am aware of the fact that Substring isn't a function available in vb6, but in vb.net only.
After the first \icons
path = "C:\Users\Example\Desktop\Test\Stuff\Icons\test.jpg"
?mid$(path, instr(1, path, "\icons\", vbTextCompare))
> \Icons\test.jpg
Or after the last should there be > 1
path = "C:\Users\Example\Desktop\Test\Icons\Stuff\Icons\test.jpg"
?right$(path, len(path) - InStrRev(path, "\icons\", -1, vbTextCompare) + 1)
> \Icons\test.jpg
This is pretty easy to do generically using the Split function. I wrote a method to demonstrate it's use and for grins it takes an optional parameter to specify how many directories you want returned. Passing no number returns a file name, passing a very high number returns a full path (either local or UNC). Please note there is no error handling in the method.
Private Function GetFileAndBasePath(ByVal vPath As String, Optional ByVal baseFolderLevel = 0) As String
Dim strPathParts() As String
Dim strReturn As String
Dim i As Integer
strPathParts = Split(vPath, "\")
Do While i <= baseFolderLevel And i <= UBound(strPathParts)
If i > 0 Then
strReturn = strPathParts(UBound(strPathParts) - i) & "\" & strReturn
Else
strReturn = strPathParts(UBound(strPathParts))
End If
i = i + 1
Loop
GetFileAndBasePath = strReturn
End Function
I have a string like X5BC8373XXX. Where X = a special character equals a Square.
I also have some special characters like \n but I remove them, but I can't remove the squares...
I'd like to know how to remove it.
I Found this method:
Dim Test As String
Test = Replace(Mscomm1.Input, Chr(160), Chr(64) 'Here I remove some of the special characters like \n
Test = Left$(Test, Len(Test) -2)
Test = Right$(Test, Len(Test) -2)
This method DOES remove those special characters, but it's also removing my first character 5.
I realize that this method just remove 2 characters from the left and the right,
but how could I work around this to remove these special characters ?
Also I saw something with vblF, CtrlF something like this, but I couldn't work with this ;\
You can use regular expressions. If you want to remove everything that's not a number or letter, you can use the code below. If there are other characters you want to keep, regular expressions are highly customizable, but can get a little confusing.
This also has the benefit of doing the whole string at once, instead of character by character.
You'll need to reference Microsoft VBScript Regular Expressions in your project.
Function AlphaNum(OldString As String)
Dim RE As New RegExp
RE.Pattern = "[^A-Za-z0-9]"
RE.Global = True
AlphaNum = RE.Replace(OldString, "")
End Function
Cleaning out non-printable characters is easy enough. One brute-force but easily customizable method might be:
Private Function Printable(ByVal Text As String) As String
Dim I As Long
Dim Char As String
Dim Count As Long
Printable = Text 'Allocate space, same width as original.
For I = 1 To Len(Text)
Char = Mid$(Text, I, 1)
If Char Like "[ -~]" Then
'Char was in the range " " through "~" so keep it.
Count = Count + 1
Mid$(Printable, Count, 1) = Char
End If
Next
Printable = Left$(Printable, Count)
End Function
Private Sub Test()
Dim S As String
S = vbVerticalTab & "ABC" & vbFormFeed & vbBack
Text1.Text = S 'Shows "boxes" or "?" depending on the font.
Text2.Text = Printable(S)
End Sub
This will remove control characters (below CHR(32))
Function CleanString(strBefore As String) As String
CleanString = ""
Dim strAfter As String
Dim intAscii As Integer
Dim strTest As String
Dim dblX As Double
Dim dblLen As Double
intLen = Len(strBefore)
For dblX = 1 To dblLen
strTest = Mid(strBefore, dblX, 1)
If Asc(strTest) < 32 Then
strTest = " "
End If
strAfter = strAfter & strTest
Next dblX
CleanString = strAfter
End Function
So I have a number of text files that I'm trying to read with Visual Basic. They all have the same formatting:
[number of items in the file]
item 1
item 2
item 3
...etc.
What I'm trying to do is declare an array of the size of the integer in the first line, and then read each line into corresponding parts of the array (so item 1 would be array[0], item 2 would be array[1], etc. However, I'm not sure where to start on this. Any help would be appreciated.
Pretty basic stuff (no pun intended):
Dim F As Integer
Dim Count As Integer
Dim Items() As String
Dim I As Integer
F = FreeFile(0)
Open "data.txt" For Input As #F
Input #F, Count
ReDim Items(Count - 1)
For I = 0 To Count - 1
Line Input #F, Items(I)
Next
Close #F
try this for VB6
Dim file_id As Integer
Dim strline as string
Dim array_item() as string
'Open file
file_id = FreeFile
Open "C:\list.txt" For Input AS #file_id
Dim irow As Integer
irow = 0
'Loop through the file
Do Until EOF(file_id)
'read a line from a file
Line Input #file_id, strline
'Resize the array according to the line read from file
Redim Preserve array_item(irow)
'put the line into the array
array_item(irow) = strline
'move to the next row
irow = irow + 1
Loop
Close #file_id
The VB function you're looking for is "split":
http://www.vb-helper.com/howto_csv_to_array.html
Try this:
Dim FullText As String, l() As String
'''Open file for reading using Scripting Runtime. But you can use your methods
Dim FSO As Object, TS As Object
Set FSO = createbject("Scripting.FileSystemObject")
Set TS = createbject("Scripting.TextStream")
Set TS = FSO.OpenTextFile(FilePath)
TS.ReadLine 'Skip your first line. It isn't needed now.
'''Reading the contents to FullText and splitting to the array.
FullText = TS.ReadAll
l = Split(FullText, vbNewLine) '''the main trick
Splitting automatically resizes l() and stores all data.
Now the l() array has everything you want.
Using VB6
I want to delete the last 5 words of the filename, then i want to give so other filename.\
Code.
Name FileName As NewFileName
The above code is working for rename, but i don't want to rename, i want to delete the last 5 letter of the filename.
Expected Output
Filename
sufeshcdk.txt - I want to take (sufeshcd) only
Modifyulla.txt - I want to take (Modifyul) only
How to do this?
Need VB6 Code Help.
Here you go.
private function RemoveLast5(FileName as string) as String
if len(FileName) > 5 then
RemoveLast5 = left$(FileName, Len(FileName) - 5)
else
RemoveLast5 = FileName
end
end function
dim FileName as string
FileName = "Modifyulla.txt"
dim NewFileName as string
NewFileName = RemoveLast5(FileName)
Name FileName As NewFileName
Untested, but this is the basic idea...
FileNameLength = Len(FileName)
NewFileName = Mid$(FileName, 1, FileNameLength - 5)
Name FileName As NewFileName
edit: fixed the syntax per below comments.