Here's something I often do when programming:
code = ''
code << "next line of code #{something}" << "\n"
code << "another line #{some_included_expression}" << "\n"
Is there some better way than having << "\n" or + "\n" on every line? This seems quite inefficient.
I'm interested in Ruby solutions, in particular. I'm thinking something like
code = string.multiline do
"next line of code #{something}"
"another line #{some_included_expression}"
end
If you're looking to build a block of text, the easy way to do it is to just use the % operator. For example:
code = %{First line
second line
Third line #{2 + 2}}
'code' will then be
"First line\n second line\n Third line 4"
This would be one way:
code = []
code << "next line of code #{something}"
code << "another line #{some_included_expression}"
code.join("\n")
Use <<- operator:
code = <<-CODE
var1 = "foo"
var2 = "bar"
CODE
It would work for you to just embed ...\n" in your strings, I suppose. Here is a fun way to do it:
class String
def / s
self << s << "\n"
end
end
then
f = "" # => ""
f / 'line one' # => "line one\n"
f / 'line two' # => "line one\nline two\n"
f / 'line three' # => "line one\nline two\nline three\n"
This would enable something like:
"" / "line 1" / "line 2" / "line 3" # => "line 1\nline 2\nline 3\n"
Or even:
f/
"line one"/
"line two"/
"line three" # => "line one\nline two\nline three\n"
Here's a method presented here:
str = <<end.margin
|This here-document has a "left margin"
|at the vertical bar on each line.
|
| We can do inset quotations,
| hanging indentions, and so on.
end
This is accomplished by using this:
class String
def margin
arr = self.split("\n") # Split into lines
arr.map! {|x| x.sub!(/\s*\|/,"")} # Remove leading characters
str = arr.join("\n") # Rejoin into a single line
self.replace(str) # Replace contents of string
end
end
I guess the question with this is: does the lack of portability / presence of monkey patching make this solution bad.
What's wrong with:
code = "next line of code #{something}\n"+
"another line #{some_included_expression}"
You could place your multi-line text in a file, and use ERB to parse it (note ERB is included with Ruby)
require 'erb'
multi_line_string = File.open("multi_line_string.erb", 'r').read
template = ERB.new(multi_line_string)
template.result(binding)
(ERB can access variables from a Binding, an object that provides access to the instance methods and variables that are owned by another object. By setting it to "binding" it points to itself)
Documentation here.
Related
I need to reuse a textfile that is filled with one-liners such:
export NODE_CODE="mio12"
How can I do that in my Ruby program the var is created and assign as it is in the text file?
If the file were a Ruby file, you could require it and be able to access the variables after that:
# variables.rb
VAR1 = "variable 1"
VAR2 = 2
# ruby.rb
require "variables"
puts VAR1
If you're not so lucky, you could read the file and then loop through the lines, looking for lines that match your criteria (Rubular is great here) and making use of Ruby's instance_variable_set method. The gsub is to deal with extra quotes when the matcher grabs a variable set as a string.
# variables.txt
export VAR1="variable 1"
export VAR2=2
# ruby.rb
variable_line = Regexp.new('export\s(\w*)=(.*)')
File.readlines("variables.txt").each do |line|
if match = variable_line.match(line)
instance_variable_set("##{match[1].downcase}", match[2].gsub("\"", ""))
end
end
puts #var1
puts #var2
Creating a hash from this file can be a fairly simple thing.
For var.txt:
export BLAH=42
export WOOBLE=67
File.readlines("var.txt").each_with_object({}) { |line, h|
h[$1] = $2 if line =~ /^ export \s+ (.+?) \s* \= \s* (.+) $/x
}
# => {"BLAH"=>"42", "WOOBLE"=>"67"}
The following three lines of code:
array = ["line 2", "line 3"]
foo = array.join("\n")
bar = "line 1\n#{foo}\nline4"
result in
"line 1\nline 2\nline 3\nline4"
is it possible to combine the 2nd and 3rd line using interpolation? The following doesn't work:
bar = "line 1\n#{array.join('\n')}\nline4"
because it adds an extra backslash:
"line 1\nline 2\\nline 3\nline4"
You need to use double-quotes around "\n" if you want Ruby to treat it as a newline character instead of two separate characters:
bar = "line 1\n#{array.join("\n")}\nline4"
^^^^
How can I avoid a new line when I use puts line + "test"
Example code:
File.open("test.txt", "r") do |f|
f.each_line do |line|
puts line + "test" #=>line1\ntest
#puts "test" + line #=> testline1
end
end
When I use:
puts "test" + line`
It shows:
testline1
(line1 being the only thing in the test.txt)
However,
puts line + "test"
looks like:
test
line1
Is there anyway of stopping it from producing the extra line?
If you want to strip out the newline, use String#chomp to take care of it.
http://apidock.com/ruby/v1_9_3_392/String/chomp
puts line.chomp + "test"
Use String#strip to strip out all the leading and trailing whitespace characters (including new line):
puts line.strip + "test"
# => line1test
To delete only the trailing whitespaces, you can use String#rstrip:
puts line.rstrip + "test"
# => line1test
I'm learning Ruby and have failed to make a compound 'if' statement work. Here's my code (hopefully self explanatory)
commentline = Regexp.new('^;;')
blankline = Regexp.new('^(\s*)$')
if (line !~ commentline || line !~ blankline)
puts line
end
the variable 'line' is gotten from reading the following file:
;; alias filename backupDir
Prog_i Prog_i.rb ./store
Prog_ii Prog_ii.rb ./store
This fails and I'm not sure why. Basically I want the comment lines and blank lines to be ignored during the processing of the lines in the file. Thanks for your help.
you need to use an AND
basically you want not (blank or comment) which turns into not blank and not comment after applying DeMorgan
if (line !~ commentline && line !~ blankline)
puts line
end
or
unless(line ~= commentline || line ~= blankline)
puts line
end
depending on which you find more readable
You can write this much more terse, as
puts DATA.readlines.reject{|each|each =~ /^;;|^\s*$/}
__END__
;; alias filename backupDir
Prog_i Prog_i.rb ./store
Prog_ii Prog_ii.rb ./store
This is your code:
commentline = Regexp.new('^;;')
blankline = Regexp.new('^(\s*)$')
if (line !~ commentline || line !~ blankline)
puts line
end
and how I'd write the same thing:
[
';; alias filename backupDir',
'',
'Prog_i Prog_i.rb ./store',
'Prog_ii Prog_ii.rb ./store'
].each do |line|
puts line if (!line[/^(?:;;)?$/])
end
Which outputs:
;; alias filename backupDir
Prog_i Prog_i.rb ./store
Prog_ii Prog_ii.rb ./store
Here is a string str:
str = "line1
line2
line3"
We would like to add string "\n" to the end of each line:
str = "line1 \n
line2 \n
line3 \n"
A method is defined:
def mod_line(str)
s = ""
str.each_line do |l|
s += l + '\\n'
end
end
The problem is that '\n' is a line feed and was not added to the end of the str even with escape \. What's the right way to add '\n' literally to each line?
String#gsub/String#gsub! plus a very simple regular expression can be used to achieve that:
str = "line1
line2
line3"
str.gsub!(/$/, ' \n')
puts str
Output:
line1 \n
line2 \n
line3 \n
The platform-independent solution:
str.gsub(/\R/) { " \\n#{$~}" }
It will search for line-feeds/carriage-returns and replace them with themselves, prepended by \n.
\n needs to be interpreted as a special character. You need to put it in double quotes.
"\n"
Your attempt:
'\\n'
only escapes the backslash, which is actually redundant. With or without escaping on the backslash, it gives you a backslash followed by the letter n.
Also, your method mod_line returns the result of str.each_line, which is the original string str. You need to return the modified string s:
def mod_line(str)
...
s
end
And by the way, be aware that each line of the original string already has "\n" at the end of each line, so you are adding the second "\n" to each line (making it two lines).
This is the closest I got to it.
def mod_line(str)
s = ""
str.each_line do |l|
s += l
end
p s
end
Using p instead of puts leaves the \n on the end of each line.