bash script doesnt run correctly as background process - bash

I have bash script which works well but when I send it back with nohup script &
and close my terminal session then it's not working correctly. It only works well within my terminal session open.
What could be possible reasons which affects my script run not correctly without my terminal session? Could it be one of the terminal variables or something?
solaris 10

call:
script &
disown $!
& launches your script in the background and disown $! detaches last executed command from the current shell. $! is the PID of the last background executed command.

Without the source we can only make guesses. However, your usecase might be a good fit for using GNU Screen: http://www.gnu.org/software/screen/ You can detach shell sessions from your current login and pick them up later on.
In my humble opinion one of the most useful programs on earth ;)

Related

Is there a way to send a running terminal command to the background AND change the output to pipe to a log file?

Sometimes when I run a log running terminal command, I'd like to send it to the background and start doing something else in the same shell. I can do this with Ctrl+Z and bg.
However, the annoying effect this has is that it keeps showing output of the above command intermittently. Instead, when I move the process to the background, I'd also like to change where the output goes as well.
Importantly, I'm asking how to do this for an already-running command - I know that do this from scratch I could do something like command arg1 arg2 &> ~/logs/output.log &.
I have used Reptyr for this in the past.
It does have its limitations (especially with GUIs / Curses) but has worked well for me.
https://linux.die.net/man/1/reptyr
You can either start a Screen session and use reptyr to grab your running process into the screen session. Or start a new bash session which is outputting to a file and then grab the running process with reptyr.

Blocking a bash script running with &

I may have inadvertently launched a bash script containing an infinite cycle whose exit condition may be met next century, if ever. The fact is that I launched the script, as I would do with a nohup program, with
bash [scriptname].sh &
so that (as I get it, which is most probably wrong) I can close the terminal and still keep the script running, as was my intention in developing it. The script should run calculation programmes in my absence and let me gather the results after some time.
Now I want to stop it, but nothing seems to do the trick: I killed the programmes the script had launched, I removed the input file the script was getting orders from and - last and most perfect of accomplishments - I accidentally closed the terminal trying to "exit" the script, which was still giving me error messages.
How can I check whether the script is running (as it does not appear in "top")? Is the '&' relevant? Should I just ask permission to reboot the pc, if that will work and kill everything?
Thank you.
[I put a "Hi everyone" at the beginning but the editor won't let me show it. Oh, well. It's that kind of day.]
Ok, I'll put it right here to prove my stupidity, as I wandered the internet shortly (after a long wandering before writing this post) and found that the line:
kill -9 $(pgrep -f [SCRIPTNAME].sh)
does the trick from any terminal window.
I write this answer to help anyone in the same situation, but feel free to remove the thread if unnecessary (and excuse me for disturbing).
Good you found it, here is another way if you do not use bash -c and run it in current shell not a separate shell.
# put a job in background
sleep 100 &
# save the last PID of background job
MY_PID=$!
# later
kill $MY_PID

Disown, nohup or & on Mac OS zsh… not working as hoped

Hi. I'm new to the shell and am working on my first kludged together script. I've read all over the intertube and SO and there are many, MANY places where disown, nohup, & and return are explained but something isn't working for me.
I want a simpler timer. The script asks for user input for the hours, mins., etc., then:
echo "No problem, see you then…"
sleep $[a*3600+b*60+c]
At this point (either on the first or second lines, not sure) I want the script OR the specific command in the script to become a background process. Maybe a daemon? So that the timer will still go off on schedule even if
that terminal window is shut
the terminal app is quit completely
the computer is put to sleep (I realize I probably need some different code still to wake the mac itself)
Also after the "No problem" line I want a return command so that the existing shell window is still useful in the meantime.
The terminal-notifier command (the timer wakeup) is getting called immediately under certain usage of the above (I can't remember which right now), then a second notification at the right time. Using the return command anywhere basically seems to quit the script.
One thing I'm not clear on is whether/how disown, nohup, etc. are applicable to a command process vs. a script process, i.e., will any of them work properly on only a command inside a script (and if not, how to initialize a script as a background process that still asks for input).
Maybe I should use some alternative to sleep?
It isn't necessary to use a separate script or have the script run itself in order to get part of it to run in the background.
A much simpler way is to place the portions that you want to be backgrounded (the sleep and following command) inside of parentheses, and put an ampersand after them.
So the end of the script would look like:
(
sleep $time
# Do whatever
)&
This will cause that portion of the code to be run inside a subshell which is placed into the background, since there's no code after that the first shell will immediately exit returning control to your interactive shell.
When your script is run, it is actually run by starting a new shell to execute it. In order for you to get your script into the background, you would need to send that shell into the background, which you can't do because you would need to communicate with its parent shell.
What you can do is have your script call itself with a special argument to indicate that it should do the work:
#! /bin/zsh
if [ "$1" != '--run' ] ; then
echo sending to background
$0 --run $# &
exit
fi
sleep 1
echo backgrounded $#
This script first checks to see if its first argument is --run. If it is not, then it calls itself ($0) with that argument and all other arguments it received ($#) in the background, and exits. You can use a similar method, performing the test when you want to enter the background, and possibly sending the data you will need instead of every argument. For example, to send just the number of seconds:
$0 --run $[a*3600+b*60+c] &

How do you make a bash script wait for second script to finish before continuing?

I have a script that does some processing and then will call another relevant script. This second script may not be the same each time.
How do I call the second script from bash and have my first script wait until it is finished before it continues. I also want to run the second script in its own window.
Currently I have:
gnome-terminal -x sh second.sh
But the first script continues whilst second is running.
Your problem here is not with bash (which processes commands in sequence unless you explicitly tell it not to using &), it's with gnome-terminal, which hands off your execution request to a background process and then terminates the one you called.
As far as I can tell, there is no way to get gnome-terminal to behave differently. An alternative might be to use xterm, which is synchronous by default.

need a script which will invoke other process/script and exit, but the invoked process should continue running

I'm trying to run a script, which internally invokes other script
but, the main script should exit after invoking and the invoked script should run independently on the background.
How can i achieve this in shell scripting? or is there any other alternative way to do this?
Regrads,
senny
nohup otherscript &
The nohup will ensure that the process keeps running even if the current terminal goes away (for example if you close the window).
(Just to make it clear: the "&" puts the other script in the background, which means the first will keep running, and the second script won't exit when the first one does.)
If your script is in Perl, use exec() command to start the second script.
exec() returns immediately after executing the command, and the calling script can exit, while the second script keeps running.
http://perl.about.com/od/programmingperl/qt/perlexecsystem.htm

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