How can I create a unique 7-digit code for an entity? - random

Question

When a user adds a new item in my system, I want to produce a unique non-incrementing pseudo-random 7-digit code for that item. The number of items created will only number in the thousands (<10,000).
Because it needs to be unique and no two items will have the same information, I could use a hash, but it needs to be a code they can share with other people - hence the 7 digits.
My original thought was just to loop the generation of a random number, check that it wasn't already used, and if it was, rinse and repeat. I think this is a reasonable if distasteful solution given the low likelihood of collisions.
Responses to this question suggest generating a list of all unused numbers and shuffling them. I could probably keep a list like this in a database, but we're talking 10,000,000 entries for something relatively infrequent.
Does anyone have a better way?

Answer 1

Pick a 7-digit prime number A, and a big prime number B, and
int nth_unique_7_digit_code(int n) {
return (n * B) % A;
}
The count of all unique codes generated by this will be A.
If you want to be more "secure", do pow(some_prime_number, n) % A, i.e.
static int current_code = B;
int get_next_unique_code() {
current_code = (B * current_code) % A;
return current_code;
}

Answer 2

You could use an incrementing ID and then XOR it on some fixed key.
const int XORCode = 12345;
private int Encode(int id)
{
return id^XORCode;
}
private int Decode(int code)
{
return code^XORCode;
}

Answer 3

Honestly, if you want to generate only a couple of thousand 7-digit codes, while 10 million different codes will be available, I think just generating a random one and checking for a collision is good enough.
The chance of a collision on the first hit will be, in the worst case scenario, about 1 in a thousand, and the computational effort to just generate a new 7-digit code and check for a collision again will be much smaller than keeping a dictionary, or similar solutions.
Using a GUID instead of a 7-digit code as harryovers suggested will also certainly work, but of course a GUID will be slightly harder to remember for your users.

Answer 4

i would suggest using a guid instead of a 7 digit code as it will be more unique and you don't have to worry about generateing them as .NET will do this for you.

Answer 5

All solutions for a "unique" ID must have a database somewhere: Either one which contains the used IDs or one with the free IDs. As you noticed, the database with free IDs will be pretty big so most often, people use a "used IDs" database and check for collisions.
That said, some databases offer a "random ID" generator/sequence which already returns IDs in a range in random order.
This works by using a random number generator which can create all numbers in a range without repeating itself plus the feature that you can save it's state somewhere. So what you do is run the generator once, use the ID and save the new state. For the next run, you load the state and reset the generator to the last state to get the next random ID.

Answer 6

I assume you'll have a table of the generated ones. In that case, I don't see a problem with picking random numbers and checking them against the database, but I wouldn't do it individually. Generating them is cheap, doing the DB query is expensive relative to that. I'd generate 100 or 1,000 at a time and then ask the DB which of those exists. Bet you won't have to do it twice most of the time.

Answer 7

You have <10.000 items, so you need only 4 digits to store a unique number for all items.
Since you have 7 digits, you have 3 digits extra.
If you combine a unique sequence number of 4 digits with a random number of 3 digits, you will be unique and random. You increment the sequence number with every new ID you generate.
You can just append them in any order, or mix them.
seq = abcd,
rnd = ABC
You can create the following ID's:
abcdABC
ABCabcd
aAbBcCd
If you use only one mixing algorithm, you will have unique numbers, that look random.

Answer 8

I would try to use an LFSR (Linear feedback shift register) the code is really simple you can find examples everywhere ie Wikipedia and even though it's not cryptographically secure it looks very random. Also the implementation will be very fast since it's using mainly shift operations.

Answer 9

With only thousands of items in the database, your original idea seems sound. Checking the existance of a value in a sorted (indexed) list of a few tens of thousands of items would only require a few data fetches and comparisons.
Pre-generating the list doesn't sound like a good idea, because you will either store way more numbers than are necessary, or you will have to deal with running out of them.

Answer 10

Probability of having hits is very low.
For instance - you have 10^4 users and 10^7 possible IDs.
Probability that you pick used ID 10 times in row is now 10^-30.
This chance is lower than once in a lifetime of any person.

Answer 11

Well, you could ask the user to pick their own 7-digit number and validate it against the population of existing numbers (which you would have stored as they were used up), but I suspect you would be filtering a lot of 1234567, 7654321, 9999999, 7777777 type responses and might need a few RegExs to achieve the filtering, plus you'd have to warn the user against such sequences in order not to have a bad, repetitive, user input experience.