Something like:
create table Employee(
ID int primary key,
Name nvarchar(200)
IDArea int foreign key references Area(ID)
);
go
create table Area(
ID int primary key,
Name nvarchar(200)
);
Does something like this exist in Oracle?
Yes, just leave out the "GO" keywords and put the statements in a file:
create table Area(
ID int primary key,
Name nvarchar2(200)
);
create table Employee(
ID int primary key,
Name nvarchar2(200),
IDArea int references Area(ID)
);
You must create the Area primary key before the foreign key that references it, so I have swapped these around. Also the foreign key syntax is slightly different in Oracle.
You should first create the master table, forget nvarchar datatype, and eventually the script would be :
create table Area(
ID number primary key,
Name varchar2(200)
);
create table Employee(
ID number primary key,
Name varchar2(200) ,
IDArea number, constraint fk_idarea foreign key (idarea) references Area(ID)
);
Related
I have a DB2 (for IBMi) table created as below. I would like to drop the forign key constraint while running in an SQLRPGLE program. Is this possible?
create table grid_action_details(id integer not null
generated always as identity
(start with 1 increment by 1)
PRIMARY KEY,grid_details_id integer,foreign key(grid_details_id)
references grid_details(id),action_code_details_id integer,
foreign key(action_code_details_id)
references action_code_details(id),action_code_status varchar(2),
created_date date default
current_date,created_by varchar(30),
last_updated_date date default current_date,updated_by
varchar(30),required_parameter clob);
I tried the below syntax but it just doesn't seem to work for me:
ALTER TABLE table-name
DROP FOREIGN KEY foreign_key_name
alter table iesqafile.grid_action_details
drop foreign key action_code_details_id
ACTION_CODE_DETAILS_ID in IESQAFILE type *N not found.
You drop the FK constraint via name, not via column.
Since you didn't specify one during create, you'll need to look to see what name the system generated.
Always a best practice to name things yourself.
CONSTAINT <name> FOREIGN KEY (<columns>)
create table grid_action_details (
id integer not null generated always as identity (
start with 1 increment by 1
)
,constraint grid_action_details_pk
primary key
,grid_details_id integer
,constraint grid_details_fk
foreign key (grid_details_id)
references grid_details (id)
,action_code_details_id integer
,constraint action_code_details_fk
foreign key (action_code_details_id)
references action_code_details (id)
,action_code_status varchar(2)
,created_date date default current_date
,created_by varchar(30)
,last_updated_date date default current_date
,updated_by varchar(30)
,required_parameter clob
);
Now you can drop by the known name
alter table iesqafile.grid_action_details
drop foreign key action_code_details_fk
EDIT
To find the generated name use:
the ACS Schema component
DSPFD
SQL against one of the catalog views (QSYS2.SYSCST, SYSIBM.SQLFOREIGNKEYS, SYSIBM.REFERENTIAL_CONSTRAINTS )
I want to create a table department:
COLUMN NAME DATATYPE SIZE CONSTRAINT
dept_id number 4 Primary key
prod_id number 4 Foreign key
I tried this:
CREATE TABLE Department(
dept_id number(4) primary key,
prod_id number(4) foreign key);
It shows error. How can I add a foreign key constraint to this table?
A foreign key defines a relationship between your table DEPARTMENT and another table with a primary key. It means, you cannot create a row in DEPARTMENT with a PROD_ID of 1234 unless there is a pre-existing row in the designated parent table with a value of 1234 as its primary key.
So do you have such an existing parent table? if so you need to include its name in the foreign key definition. Otherwise you must create it.
Let's say the parent table is PRODUCT:
create table product (
prod_id number(4) primary key
, name varchar2(32) not null
);
Then you can create DEPARTMENT with a foreign key like this:
CREATE TABLE Department(
dept_id number(4) primary key,
prod_id references PRODUCT );
Yep, that's all the syntax you need: it automatically creates a column PROD_ID with the same datatype and precision as the primary key column of the referenced table. More verbose syntax is available. Read the Oracle SQL documentation to find out more.
I assume that the other table is named other_table_name and that it contains a primary key named prod_id.
CREATE Department (
dept_id number(4) primary key,
prod_id number(4) REFERENCES other_table_name (prod_id)
);
or a different syntax
CREATE Department (
dept_id number(4) primary key,
prod_id number(4)
...
CONSTRAINT fk_prod_id
FOREIGN KEY (prod_id)
REFERENCES other_table_name (prod_id)
);
I have two table students and studentsprofilepic
'username' from students is unique key of the table
it is referenced as foreign key for the 'studentsprofilepic' table
the DDL for the tables are
CREATE TABLE students (
id NUMBER,
username VARCHAR2(30),
password VARCHAR2(30),
firstname VARCHAR2(30),
lastname VARCHAR2(40),
email VARCHAR2(300),
dob VARCHAR2(20),
alt_email VARCHAR2(300),
street_address VARCHAR2(50),
address_2 VARCHAR2(50),
city VARCHAR2(30),
state VARCHAR2(30),
zip VARCHAR2(10),
country VARCHAR2(60),
telephone VARCHAR2(10),
CONSTRAINT student_id_pk PRIMARY KEY (id),
CONSTRAINT student_username_uk UNIQUE (username)
);
CREATE TABLE studentsprofilepic (
id NUMBER,
photo_id NUMBER,
photo BLOB,
PRIMARY KEY (photo_id),
FOREIGN KEY (username) REFERENCES students (username)
);
YES, The foreign key column establishes a direct relationship with a primary key or unique key column (referenced key) usually in another table:
CREATE TABLE BOOK(
BNAME VARCHAR2(10)NOT NULL UNIQUE,
BTYPE VARCHAR2(10));
CREATE TABLE BOOKS_AUTH(
A_ID INT NOT NULL,
BNAME_REF VARCHAR2(10) NOT NULL,
FOREIGN KEY (BNAME_REF) REFERENCES BOOK (BNAME));
SQLFIDDLE DEMO
Yes, why not. It is possible to reference a UNIQUE constraint in a FOREIGN KEY.
You could have a Primary key and an Unique key, and you would like to validate both.
Yes, you can reference a column (or columns) governed by either a primary key constraint or a unique constraint.
The problem with your table "studentsprofilepic" is that your foreign key tries to use the column "studentsprofilepic"."username", but that column doesn't exist.
create table studentsprofilepic(
id number,
photo_id number,
photo blob,
-- Add the "username" column.
username varchar2(30) not null,
primary key (photo_id),
foreign key (username) references students (username)
);
Also, ask yourself "What's the point of "studentsprofilepic"."id"?" It's not the primary key. It's not a foreign key. It doesn't seem to serve any purpose besides letting you say, "Hey, my table has a column named 'id'!" That's a questionable feature.
Think about adding more not null constraints.
I am try to assign foreign key in Oracle 10g. But the error shows like
ORA-907: missing right parentheses
I have three tables
TblCustomer
TblProducts
TblSales
create table tblSales
(SalesID int primary key,
ProductId int foreign key references tblProducts(ProductId),
CustomerID int foreign key references tblCustomer(CustomerID),
SalesPrice numeric,
SalesDate date);
Whats going wrong can you suggest me.
You syntax must look like:
create table tblSales (SalesID int,
ProductId int ,
CustomerID int ,
SalesPrice numeric,
SalesDate date,
CONSTRAINT sales_pk PRIMARY KEY (SalesID ),
CONSTRAINT fk_produkt
foreign key (ProductId)references tblProducts(ProductId),
CONSTRAINT fk_customer
foreign key (CustomerID)references tblCustomer(CustomerID)
);
For in inline foreign key you don't specify the foreign key keyword:
create table tblSales
(
SalesID int primary key,
ProductId int references tblProducts(ProductId),
CustomerID int references tblCustomer(CustomerID),
SalesPrice numeric,
SalesDate date
);
With inline foreign keys, you don't even need to specify the target column:
create table tblSales
(
SalesID int primary key,
ProductId int references tblProducts,
CustomerID int references tblCustomer,
SalesPrice numeric,
SalesDate date
);
SQLFiddle example: http://sqlfiddle.com/#!4/420b9c
As a side note: prefixing each and every table with tbl doesn't really make sense. If you are programming, do you prefix every class with Cls or if you are naming a person, do you prefix every name with Pers?
I have a composite primary key in my Candidate table
CREATE TABLE CANDIDATE(
CANDIDATE_ID VARCHAR(5),
NAME VARCHAR(30),
TELEPHONE NUMBER,
PRIMARY KEY(CANDIDATE_ID, NAME));
When I create a child table, I get an error saying the number of referencing columns must match referenced columns when I create a foreign key for the CANDIDATE_ID
CREATE TABLE JOB(
POSITION_ID VARCHAR(5) PRIMARY KEY,
CANDIDATE_ID VARCHAR(5),
DATE2 DATE,
FOREIGN KEY(CANDIDATE_ID) REFERENCES CANDIDATE);
A table can only have one primary key-- you have a composite primary key. If you have a composite primary key, you have to reference the entire key in your child table. That would mean that the child table would need to have a CANDIDATE_ID column and a NAME column.
CREATE TABLE job (
position_id VARCHAR2(5) PRIMARY KEY,
candidate_id VARCHAR2(5),
name VARCHAR2(30),
date2 DATE,
FOREIGN KEY( candidate_id, name ) REFERENCES candidate( candidate_id, name )
);
Of course, you probably don't want to store the name in both tables. You probably want the candidate_id to be the prmiary key of candidate and you may want to create a separate unique constraint on name.
CREATE TABLE CANDIDATE(
CANDIDATE_ID VARCHAR(5) primary key,
NAME VARCHAR(30) unique,
TELEPHONE NUMBER);
CREATE TABLE JOB(
POSITION_ID VARCHAR(5) PRIMARY KEY,
CANDIDATE_ID VARCHAR(5),
DATE2 DATE,
FOREIGN KEY(CANDIDATE_ID) REFERENCES CANDIDATE(candidate_id));
Assuming that the combination of CANDIDATE_ID and NAME is required for the key to be unique, then you will need to add a reference to the NAME column in your referencing table.
I suspect that CANDIDATE_ID is enough to uniquely identify the candidates in your primary table. If that is the case then it should be your primary key and your relationship will work. If you want to index the NAME separately then do so, but leave it out of the primary key.
Last line should be like this;
CONSTRAINT FK_CANDIDATE_ID FOREIGN KEY (CANDIDATE_ID)REFERENCES CANDIDATE(CANDIDATE_ID);
CREATE TABLE dept
( did char(3) not null,
dname varchar2(20) not null,
CONSTRAINT dept_pk PRIMARY KEY (did)
);
strong text
create table emp
(
eid char(3) unique,
ename varchar2(10) not null,
sal number check (sal between 20000 AND 50000),
city varchar2(10) default 'texus',
did char(3) not null,
constraint fk_did_dept
FOREIGN KEY (did) references
dept(did)
);