is there a way to emulate correctly replace function on XPATH 1? - xpath

Question

I have this function which tries to replace dots and/or - with _
I'm limited to use xpath 1 so replace function is NOT an option. The template works not to much fine because if I use something like this:
FOO-BAR.THING-MADRID.html
it gives me out on screen this thing:
FOO-BAR.THING-MADRID.html
the middle dot is not replaced.
Someone could help me?
<xsl:template name="replaceDots">
<xsl:param name="outputString"/>
<xsl:variable name="target">.</xsl:variable>
<xsl:variable name="source">-</xsl:variable>
<xsl:variable name="replacement">_</xsl:variable>
<xsl:choose>
<xsl:when test="contains($outputString,$source)">
<xsl:value-of select="concat(substring-before($outputString,$source),$replacement)" disable-output-escaping="yes"/>
<xsl:call-template name="replaceDots">
<xsl:with-param name="outputString" select="substring-after($outputString,$source)"/>
</xsl:call-template>
</xsl:when>
<xsl:when test="contains($outputString,$target)">
<xsl:value-of select="concat(substring-before($outputString,$target),$replacement)" disable-output-escaping="yes"/>
<xsl:call-template name="replaceDots">
<xsl:with-param name="outputString" select="substring-after($outputString,$target)"/>
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$outputString" disable-output-escaping="yes"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>

Answer 1

To replace all dots or dashes with underscores, you do not need an <xsl:template>. You can use:
<xsl:value-of select="translate(., '-.', '__')" />
If you want to keep the ".html", you can extend this like so:
<xsl:value-of select="
concat(
translate(substring-before(., '.html'), '-.', '__'),
'.hmtl'
)
" />
For a generic "string replace" template in XSLT, look at this question, for example.