How do I take a numeric month, day and year from three separate text inputs and parse a proper value for my DateTime field in the db?
date = Date.civil(params[:year].to_i, params[:month].to_i, params[:day].to_i)
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I have to get the max payment date on an invoice and I am having trouble with the date format. I do not need the max in this formula as I am using the format in a reporting tool that is pulling the max from what it finds for me.
Using "to_char({datefield},'mm/dd/yyyy')" works for displaying that date the way we would like BUT when you use summary function MAX it does not pull the correct date because it is looking at a string and not a date (it will think 12/3/21 is larger than 3/2/22).
Another thing I have tried is trunc - "trunc({datefield})" which gives us the correct max date but it changes the formatting. For example if the date prior to the formula being applied is "8/12/21 12:00:00:000" the trunc formula will display it as 12-08-21 which is horribly wrong.
Long story short is I need a way to change a date/time to date with the format of 'mmmm/dd/yyyy' WITHOUT converting it to a string with something like to_char. Thank you!!!!
A DATE is a binary data type consisting of 7 bytes representing: century, year-of-century, month, day, hour, minute and second. It ALWAYS has all of those components and it is NEVER stored with any (human-readable) format.
What you are seeing when a date is displayed is the client application you are using to access the database making a decision to be helpful to you, the user, and display the binary DATE provided by the database in a human-readable format.
If you want to change how the DATE is displayed then you either need to:
Change the settings on the client application that controls how it formats dates when it displays them to you; or
Change the data-type so that it is no longer a DATE (which does not have a format) to a data type where the values of the date can be formatted (such as a string). You can do this using TO_CHAR.
If you want to find the maximum then do it BEFORE applying the formatting:
SELECT TO_CHAR(MAX({datefield}),'mm/dd/yyyy')
FROM your_table;
I have a Django model with a timestamp field. I want to filter and get the number of rows that does not contain today's date. The timestamp field contains the date, time, and time zone.
I understand that to get rows with today's date, we do the following:
tablename.objects.filter(timestamp__date=date.today()).count()
Thank you.
.exclude returns the inverse of .filter, so it would be
tablename.objects.exclude(timestamp__date=date.today()).count()
Django docs
I'm stuck with sorting and showing the correct date in Xpages.
It is saved in format "dd.MM.yyyy" and it's a string.
Now why it's a string and formated that way, is because my boss has special wishes. And when I want to sort it from the newest date to older it does something like this:
26.05.2015
24.06.2014
22.04.2015
21.04.2015
20.03.2014
It starts sorting by day.
Is there a way to make it sort it like it should?
I see that i can write a Computed value to Sort column in view column header for date. But i don't know how to even start.
Change the underlying Notes view to get your date column into right order.
Convert the date strings to real date values in views column formula. Assuming your field is called DateText then your formula would be
#Date(#ToNumber(#Right(DateText; 4));
#ToNumber(#Middle(DateText; 3; 2));
#ToNumber(#Left(DateText; 2)))
It would be easier to use just #ToTime(DateText) but this can fail depending on server's local settings. Your date string format would work for a server with German locale settings but not for US. That's why is my suggested solution "safer".
If the date time value doesn't solve your problem and you do not transform your date via #Text (as mentioned in the comments) then create another (hidden) column BEFORE your column that should be displayed. Make this a true date (from your item), sort it and unsort the column to display.
Otherwise use this formula in the newly created sorted column:
#Text(#Year(yourDate))+"-"+#Right("00"+#Text(#Month(yourDate));2)+"-"+#Right("00"+#Text(#Day(yourDate));2)
I have a table of data which have date and time as two separate field where date format is
dd/mm/yyyy and dd-mm-yyyy and time format is like hh:mm:ss(eg: 6:52:53)
i need to filter the record for a particular time period that both time and date wise filtering.
is there any predefined filter available with hive or pig?
Hive does recognize certain strings as unixtime dates.
You might try a where condition while concatenating the time & date together into unixtime format.
Some documentation on Hive date functions/formats are located here: https://cwiki.apache.org/confluence/display/Hive/LanguageManual+UDF#LanguageManualUDF-DateFunctions
I suppose you have one column having two date format ie. dd/mm/yyyy and dd-mm-yyyy
What You can try
1) Replacing '/' to '-' so that complete column will be in dd-mm-yyyy format.
2) Try concatanating this field with time field
3) filter it by Casting concatinated field.
Hope this helps.
just possibility :- Have you tried casting that concatenated field to date datatype and then try date functions for desired output ?
eg. to_date()
https://cwiki.apache.org/confluence/display/Hive/LanguageManual+UDF
I have an object that is generated from XSDs, so I can't change it. In it I have a String DATE and a String TIME (representing the time of day without the date).
DATE = yyyy-mm-dd
TIME = hh:MM:ss:mmmm
In the OracleDB, I don't want to represent these as VARCHAR. I'd like to use DATE or DATETIME. Therefore, I'd need to map both DATE + TIME to one single column, DATETIME.
This is not possible. You can map two columns to a single property (using composites or user types) but not the other way around.
Using the same column name twice in the mapping file usually results in strange exceptions (index out of bounds).
I would use two columns in the database. Convert them to DATE-kind data types using a user type.