Drupal 6 AHAH / AJAX Form Submission - ajax

I'm building a custom module in Drupal 6 which display a block with a form and some other elements like text and images. When it's submitted, using AHAH, some logic takes place in PHP and then the result is passed to JQuery which will update the elements in the block. Mainly a few images and some text.
I can't wrap my head around using AHAH, but it seems like that's what I'm supposed to be using. Currently I have my form with the submit button implementing '#ahah' and the path is set to a path defined in my menu hook. The menu hook passes it to the callback function which performs the logic then I'm at a dead end. How do I get the results to jQuery?
Any ideas?
Howie

Figured out a solution using: http://drupal.org/project/examples.

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In octoberCMS I have created a custom formWidget that uses the Google Maps API.
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If I use the following code in my widget class:
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The JS loads with the Page load and not when the widget is rendered. This produces these issues:
The google-maps API returns an error saying it has been loaded multiple times.
Events tied to DOM elements in the child fail since the elements are not in the DOM until the form is called.
The workaround I am using is to embed my JS into the formWidget partial.
Is there a way to make the addJS method work for the formWidget when it is part of a child form?
After some investigation, I realised that my formWidget using the addJs() method would make the widget JS available globally to the entire page even before the formWidget existed or was even needed.
While I could have created an elaborate, fancy JS involving listeners for DOM insertions and blah blah blah, this was not ideal (mainly because the widget properties change based on implementation).
The quickest/safest way to include JS that is tightly bound to a complex formWidget is to include it in the partial. This ensures the form widget will work properly both in a standalone form and in situations where the widget is part of child form that is created via an Ajax load.
(If you know of a better way please let me know)

CodeIgniter jQueryUI dialog form example

I am trying to use CodeIgniter and jQuery-ui dialog to create a modal window with form to update user information.
The process should be like:
1. Press a button on a view page.
2. A modal window pops up.
3. Inside the window is a form that a user can fill.
4. If the user filled something before, the information should be shown in corresponding field
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I used ajax to pass the data but it didn't work when I was trying to update the data to the database. It would be nice if an example of how to pass data from ajax to php and how php handle that.
Thanks,
Milo
well the jquery bit for post(), get(), ajax() works the same in any measure you would normally use it.. key difference here is with CI you can't post directly to a file-name file-location due to how it handles the URI requests. That said your post URL would be the similar to how you would access a view file normally otherwise
ie: /viewName/functionName (how you've done it with controllers to view all along. post, get, ajax doesnt have to end in a extension. I wish I had a better example then this but I can't seem to find one at the moment..
url = '/home/specialFunction';
jQuery.get(url, function(data) {
jQuery("#div2display").html(data);
});
in the case of the above you notice despite it not being a great example that. you have the url with 2 parameters home and specialFunction
home in this case is the controller file for home in the control folder for the home file in views the specialFunction is a "public function" within the class that makes the home controller file. similar to that of index() but a separate function all together. Best way I have found to handle it is through .post() and a callback output expected in JSON cause you can form an array of data on the php side json_encode it and echo out that json_encode and then work with that like you would any JSON output. or if your just expecting a sinlge output and not multiples echoing it out is fine but enough of the end run output thats for you to decide with what your comfortable doing currently. Hopefully all around though this gives you some clairity and hopefully it works out for you.

update the row using ajax in cakephp

i am using cakephp in my project. in this at one section i need to update the particular row onclick of the image. using ajax. i used mootools as javascript library. so please help me how could i do this.
thanks in advance
Simply speaking:
Create a CakePHP controller action that performs the row update.
Determine the URL of the controller action you just created. (ie. /controllername/actionname)
Determine if you need to do a GET or POST request to this URL for it to work.
Put code in your view that attaches an "onclick" event that makes and AJAX (GET/POST) request to the above controller.
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Either way, in your view you need to have something like: <?php echo $js->link(.. or <script>Moo.. or <a onclick="Moo.. to attach your Javascript to that link.
You may also wish for your controller action to return some sort of response indicating whether or not the row update failed or succeeded. In that case you need to make sure the CakePHP controller action you are calling has a view that outputs this. JSON seems to be the ideal format for this (eg. { success: true }), but you need to remember to turn off Cake's debug output. This response can be captured into a variable by your Mootools code where you can decide what to do with it (eg. displaying an error).
As i know most programmer work with protype.js library.
i am giving you link see
go to there

AJAX and iFrame: Calling AJAX from inside the iFrame to Update an Outside DIV

I have a page where a user can upload a file along with some other input. Because I wanted this to be AJAX-like, I resorted to using an iFrame to accomplish this.
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Can this be done? Am I approaching this the wrong way?
Thank you!
UPD: Can the returned client code from within the iFrame "see" elements outside that iFrame?
Write your code in the onload event of the page loaded into the iframe. Then top will give you the top frame or parent will give you the parent frame.
Yes , it can be done. But you can do away with,the need for an AJAX-call , to update the outside the div.
Have your, servlet(assuming you are using JSP/servlets) that accepts the mutlipart request(the servlet that accepts the upload), return the intended response (to be shown on the refreshed iFrame), and ALONG WITH IT, the necessary information from the file input. This way you have all the necessary details on the client, in one response. A simple javascript function can achieve , updating the outer div with the information from the file input.

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After I load a page through a WebBrowser, and I click a link that fires an AJAX script, I need to detect when the AJAX java script finishes loading HTML changes into a div. Since no DocumentCompleted event is fired when the AJAX script is run, I don't know when it finish running. Is there a way I can attach an event to be raised after I know 100% that the javascript finished changing the div?
The project is in C#.
Thanks
I did something similar recently (using jQuery):
$('#mydiv').change(function(){
// do stuff
}
);
Granted, I also use jQuery to set the HTML of that div. I suppose one non-jQuery approach for you could be to set HTML through your own function, which in turn can fire an onchange event.
#New in town: From my experience that is not correct. I use this on multiple DIVs that never get focus in the first place, and it works well and consistently. The normal behavior is as you describe, and normally only applies to the INPUT and SELECT elements, but this is not the case with jQuery.
There is no event. You must patch the JavaScript callback that the browser runs when the reply for the AJAX request comes in. This will contains code like "div.innerHTML = ...". Just put your code below that.

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