Consider the following
Sample Input
SalesBoyName Product Amount
------------ ------- ------
Boy1 P1 100
Boy1 P1 40
Boy1 P2 100
Boy2 P1 100
Boy2 P3 12
Desired Output
SalesBoyName P1 P2 P3
------------ ---- ---- ----
Boy1 140 100 null
Boy2 100 null 12
The below SQL SERVER 2005 query will do the work
SELECT SalesBoyName, [P1] AS P1, [P2] AS P2,[P3] AS P3
FROM
(SELECT * FROM tblSales ) s
PIVOT
(
SUM (Amount)
FOR Product IN
( [P1], [P2], [P3])
) AS pvt
I want to perform the same thing in Oracle 10g.
How to do this?
This may be trivial, but since i am very new to Oracle, so I am seeking for help.
Thanks
You can do it like this in 10G:
select salesboyname,
sum (case when product='P1' then amount end) as p1,
sum (case when product='P2' then amount end) as p2,
sum (case when product='P3' then amount end) as p3
from tblsales
group by salesboyname;
In 11G there is a PIVOT keyword similar to SQL Server's.
Related
I have a pretty lengthy SQL query which I'm going to run on Oracle via hibernate. It consists of two nested selects. In the first select statement, a number of sums are calculated, but in one of them I want to filter the results using unique ids.
SELECT ...
SUM(NVL(CASE WHEN SECOND_STATUS= 50 OR SECOND_STATUS IS NULL THEN RECEIVE_AMOUNT END, 0) +
NVL(CASE WHEN FIRST_STATUS = 1010 THEN AMOUNT END, 0) +
NVL(CASE WHEN FIRST_STATUS = 1030 THEN AMOUNT END, 0) -
NVL(CASE WHEN FIRST_STATUS = 1010 AND (SECOND_STATUS= 50 OR SECOND_STATUS IS NULL) THEN RECEIVE_AMOUNT END, 0)) TOTAL, ...
And at the end:
... FROM (SELECT s.*, p.* FROM FIRST_TABLE s
JOIN SECOND_TABLE p ON s.ID = p.FIRST_ID
In one of the lines that start with NVL (second line actually), I want to add a distinct clause that sums the amounts only if first table ids are unique. But I don't know if this is possible or not. If yes, how would it be?
Assume such setup
select * from first;
ID AMOUNT
---------- ----------
1 10
2 20
select * from second;
SECOND_ID FIRST_ID AMOUNT2
---------- ---------- ----------
1 1 100
2 1 100
3 2 100
After the join you get the total sum of both amounts too high because the amount from the first table is duplicated.
select *
from first
join second on first.id = second.first_id;
ID AMOUNT SECOND_ID FIRST_ID AMOUNT2
---------- ---------- ---------- ---------- ----------
1 10 1 1 100
1 10 2 1 100
2 20 3 2 100
You must add a row_number that identifies the first occurence in the parent table and consider in the AMOUNT only the first row and resets it to NULL in the duplicated rows.
select ID,
case when row_number() over (partition by id order by second_id) = 1 then AMOUNT end as AMOUNT,
SECOND_ID, FIRST_ID, AMOUNT2
from first
join second on first.id = second.first_id;
ID AMOUNT SECOND_ID FIRST_ID AMOUNT2
---------- ---------- ---------- ---------- ----------
1 10 1 1 100
1 2 1 100
2 20 3 2 100
Now you can safely sum in a separate subquery
with tab as (
select ID,
case when row_number() over (partition by id order by second_id) = 1 then AMOUNT end as AMOUNT,
SECOND_ID, FIRST_ID, AMOUNT2
from first
join second on first.id = second.first_id
)
select id, sum(nvl(amount,0) + nvl(amount2,0))
from tab
group by id
;
ID SUM(NVL(AMOUNT,0)+NVL(AMOUNT2,0))
---------- ---------------------------------
1 210
2 120
Note also that this is an answer to your question. Some will argue that in your situation you should first aggregate and than join. This will also resolve your problem possible more elegantly.
I'm searching for a measure to utilize within SSAS Tabular model that will me to perform dynamic ranking that will automatically update the associated rank value based on filters and slicer values that are applied.
I am not in this kind of scearios : PowerPivot DAX - Dynamic Ranking Per Group (Min Per Group)
The difference is the following, my data are not in the same table :
I have a fact table like this :
-------------------------------------------------------------------------------------
ClientID | ProductID | Transaction Date | Sales
------------------------------------------------------------------------------------
C1 P3 1/1/2012 $100
C2 P1 8/1/2012 $150
C3 P4 9/1/2012 $200
C1 P2 3/5/2012 $315
C2 P2 9/5/2012 $50
C3 P2 12/9/2012 $50
------------------------------------------------------------------------------------
A Customer table
-------------------------------------------------------------------------------------
ClientID | ClientCountry |
C1 France
C2 France
C3 Germany
------------------------------------------------------------------------------------
...and also a Product table
-------------------------------------------------------------------------------------
ProductID | ProductSubCategory |
P1 SB1
P2 SB1
P3 SB2
P4 SB3
------------------------------------------------------------------------------------
So here is my visualization pivot table :
-------------------------------------------------------------------------------------
ProductSubCategory | Sales
SB1 565 (150 + 315 + 50 + 50)
SB2 100
SB3 200
And the measure I'm looking for should perform like this :
-------------------------------------------------------------------------------------
ProductSubCategory | Sales | Rank
SB1 565 (150 + 315 + 50 + 50) 1
SB2 100 3
SB3 200 2
...simple, I browse my cube into Excel, put the ProductSubCategory in line, sum of Sales and expect my measure gives me correct ranking by ProductSubCategory.
Now, scenario also includes using a slicer on ClientCountry.
So when I select 'France', I expect my measure gives me an adapted ranking, only including ProductSubCategory for Clients living in France (so C1 and C2).
I tried a lot of solutions but without any result. Has anyone and idea with this kind of scenario ?
I greatly appreciate your help with this!
Thank's all
Suppose we are having the following data:
Key Value Desired Rank
--- ----- ------------
P1 0.6 2
P1 0.6 2
P1 0.6 2
P2 0.8 1
P2 0.8 1
P3 0.6 3
P3 0.6 3
I want to select Distinct Keys ordered by Value DESC to be displayed in a grid that supports pagination.
I don’t know how to generate rank as the values displayed in Desired Rank column. So that I can paginate correctly over the data set
When I tried to use: DENSE_RANK() OVER(ORDER BY value), the result was
Key Value DENSE_RANK() OVER(ORDER BY value)
--- ----- ------------
P1 0.6 2
P1 0.6 2
P1 0.6 2
P2 0.8 1
P2 0.8 1
P3 0.6 2
P3 0.6 2
When I try to select the first two keys “rank between 1 and 2” I receive back 3 keys. And this ruins the required pagination mechanism.
Any ideas?
Thanks
If you want the distinct keys and values, why not use distinct?
select distinct
t.Key,
t.Value
from
YourTable t
order by
t.value
Do you actualle need the rank?
If you do, you still could
select distinct
t.Key,
t.Value,
dense_rank() over () order by (t.Value, t.Key) as Rank
from
YourTable t
order by
t.value
This whould work without the distinct as well.
'When I try to select the first two
keys “rank between 1 and 2” I receive
back 3 keys.'
That is because you are ordering just by VALUE, so all KEYS with the same value are assigned the same rank. So you need to include the KEY in the ordering clause. Like this:
DENSE_RANK() OVER (ORDER BY key ASC, value DESC)
I have 3 tables:
two with hierarchical structures
(like "dimensions" of recursive type of hierarchy);
one with summing data (like "facts" with X column).
They are here:
DIM1 (ID1, PARENT2, NAME1)
DIM2 (ID2, PARENT2, NAME2)
FACTS (ID1, ID2, X)
Example of DIM1 table:
-- 1 0 DIM1
---- 2 1 DIM1-A
------ 3 2 DIM1-A-A
-------- 4 3 DIM1-A-A-A
-------- 5 3 DIM1-A-A-B
------ 6 2 DIM1-A-B
-------- 7 6 DIM1-A-B-A
-------- 8 6 DIM1-A-B-B
------ 9 2 DIM1-A-C
---- 10 1 DIM1-B
------ 11 10 DIM1-B-C
------ 12 10 DIM1-B-D
---- 13 1 DIM1-C
Example of DIM2 table:
-- 1 0 DIM2
---- 2 1 DIM2-A
------ 3 2 DIM2-A-A
-------- 4 3 DIM2-A-A-A
-------- 5 3 DIM2-A-A-B
-------- 6 3 DIM2-A-B-C
------ 7 2 DIM2-A-B
---- 8 1 DIM2-B
---- 9 1 DIM2-C
Example of FACTS table:
1 1 100
1 2 30
1 3 500
-- ................
13 9 200
And I would like to create the only SELECT where I will specify the parent for DIM1 (for example ID1=2 for DIM1-A) and parent for DIM2 (for example ID2=2 for DIM2-A) and SELECT will generate a report like this:
Name_of_1 Name_of_2 Sum_of_X
--------- --------- ----------
DIM1-A-A DIM2-A-A (some sum)
DIM1-A-A DIM2-A-B (some sum)
DIM1-A-B DIM2-A-A (some sum)
DIM1-A-B DIM2-A-B (some sum)
DIM1-A-C DIM2-A-A (some sum)
DIM1-A-C DIM2-A-B (some sum)
I would like to use CONNECT BY phrase, START WITH phrase, SUM phrase, GROUP BY phrase, and OUTER or INNER (?) JOIN. I need no other extensions of Oracle 10.2.
In other words: only with "classic" SQL and
only Oracle extensions for hierarchy queries.
Is it possible?
I tried some experiments with question in
Mixing together Connect by, inner join and sum with Oracle
(where is a very nice solution but only for one
dimension table ("Tasks"), but I need to JOIN two dimension tables to one facts table), but I was not successful.
"Some sum" is not very descriptive, so I don't see why do you need CONNECT BY at all.
SELECT dim1.name, dim2.name, x
FROM (
SELECT id1, id2, SUM(x) AS x
FROM facts
GROUP BY
id1, id2
) f
JOIN dim1
ON dim1.id = f.id1
JOIN dim2
ON dim2.id = f.id2
I think what you're trying to do is get the sum of the value in the facts table for all of the children of the specified rows grouped by the topmost children. This would mean that in your example above, the results for the first row would be the sum any intersections of (DIM1-A-A, DIM1-A-A-A, DIM1-A-A-B) and (DIM2-A-A, DIM2-A-A-A, DIM2-A-A-B, DIM3-A-A-C) found in the FACTS table. With that assumption, I have come to the following solution:
SELECT root_name1, root_name2, SUM(X)
FROM ( SELECT CONNECT_BY_ROOT(name1) AS root_name,
id1
FROM dim1
CONNECT BY parent1 = PRIOR id1
START WITH parent1 = 2) d1
CROSS JOIN
( SELECT CONNECT_BY_ROOT(name2) AS root_name,
id2
FROM dim2
CONNECT BY parent2 = PRIOR id2
START WITH parent2 = 2) d2
LEFT OUTER JOIN
facts
ON d1.id1 = facts.id1
AND d2.id2 = facts.id2
GROUP BY root_name1, root_name2
(This also assumes that the columns of FACTS are named ID1, ID2, and X.)
First off, I'm a total Oracle noob although I'm very familiar with SQL. I have a single cost column. I need to calculate the total cost, the percentage of the total cost, and then a running sum of the percentages. I'm having trouble with the running sum of percentages because the only way I can think to do this uses nested SUM functions, which isn't allowed.
Here's what works:
SELECT cost, SUM(cost) OVER() AS total, cost / SUM(cost) OVER() AS per
FROM my_table
ORDER BY cost DESC
Here's what I'm trying to do that doesn't work:
SELECT cost, SUM(cost) OVER() AS total, cost / SUM(cost) OVER() AS per,
SUM(cost/SUM(cost) OVER()) OVER(cost) AS per_sum
FROM my_table
ORDER BY cost DESC
Am I just going about it wrong, or is what I'm trying to do just not possible? By the way I'm using Oracle 10g. Thanks in advance for any help.
You don't need the order by inside that inline view, especially since the outer select is doing an order by the order way around. Also, cost / SUM(cost) OVER () equals RATIO_TO_REPORT(cost) OVER ().
An example:
SQL> create table my_table(cost)
2 as
3 select 10 from dual union all
4 select 20 from dual union all
5 select 5 from dual union all
6 select 50 from dual union all
7 select 60 from dual union all
8 select 40 from dual union all
9 select 15 from dual
10 /
Table created.
Your initial query:
SQL> SELECT cost, SUM(cost) OVER() AS total, cost / SUM(cost) OVER() AS per
2 FROM my_table
3 ORDER BY cost DESC
4 /
COST TOTAL PER
---------- ---------- ----------
60 200 .3
50 200 .25
40 200 .2
20 200 .1
15 200 .075
10 200 .05
5 200 .025
7 rows selected.
Quassnoi's query contains a typo:
SQL> SELECT cost, total, per, SUM(running) OVER (ORDER BY cost)
2 FROM (
3 SELECT cost, SUM(cost) OVER() AS total, cost / SUM(cost) OVER() AS per
4 FROM my_table
5 ORDER BY
6 cost DESC
7 )
8 /
SELECT cost, total, per, SUM(running) OVER (ORDER BY cost)
*
ERROR at line 1:
ORA-00904: "RUNNING": invalid identifier
And if I correct that typo. It gives the right results, but wrongly sorted (I guess):
SQL> SELECT cost, total, per, SUM(per) OVER (ORDER BY cost)
2 FROM (
3 SELECT cost, SUM(cost) OVER() AS total, cost / SUM(cost) OVER() AS per
4 FROM my_table
5 ORDER BY
6 cost DESC
7 )
8 /
COST TOTAL PER SUM(PER)OVER(ORDERBYCOST)
---------- ---------- ---------- -------------------------
5 200 .025 .025
10 200 .05 .075
15 200 .075 .15
20 200 .1 .25
40 200 .2 .45
50 200 .25 .7
60 200 .3 1
7 rows selected.
I think this is the one you are looking for:
SQL> select cost
2 , total
3 , per
4 , sum(per) over (order by cost desc)
5 from ( select cost
6 , sum(cost) over () total
7 , ratio_to_report(cost) over () per
8 from my_table
9 )
10 order by cost desc
11 /
COST TOTAL PER SUM(PER)OVER(ORDERBYCOSTDESC)
---------- ---------- ---------- -----------------------------
60 200 .3 .3
50 200 .25 .55
40 200 .2 .75
20 200 .1 .85
15 200 .075 .925
10 200 .05 .975
5 200 .025 1
7 rows selected.
Regards,
Rob.
SELECT cost, total, per, SUM(per) OVER (ORDER BY cost)
FROM (
SELECT cost, SUM(cost) OVER() AS total, cost / SUM(cost) OVER() AS per
FROM my_table
)
ORDER BY
cost DESC