Storing ksh input array to variable and passing to another script - ksh

Question

I have to modify an existing ksh script which looks at the command-line arguments using 'shift', and so empties $#, but now want to pass the original arguments to a second script afterwards.
In the mainline case I can do this by coping $# to a variable and passing that to the second script, but I can't get it to work for quoted command-line arguments.
If I have a script called 'printer' like below:
#!/bin/ksh
INPUT=$#
echo "Printing args"
until [[ $# -eq 0 ]];do
echo $1
shift
done
./printer2 $INPUT
and printer2 like below:
#!/bin/ksh
echo "Printing second args"
until [[ $# -eq 0 ]];do
echo $1
shift
done
I would like the output of
./printer first second "third forth"
to be :
Printing args
first
second
third forth
Printing second args
first
second
third forth
I've tried various combinations of quotes around variables (both in the assignment of $INPUT and when passing it to printer2) but can't figure it out. Can anyone help?

Answer 1

Ok I think I've found the solution after an awful lot of trial and error.
Assigning $INPUT like this:
set -A INPUT "$#"
and then passing it like this:
./printer2 "${INPUT[#]}"
produces the output I'm after.
The whole first script is therefore:
#!/bin/ksh
set -A INPUT "$#"
echo "Printing args"
until [[ $# -eq 0 ]];do
echo $1
shift
done
./printer2 "${INPUT[#]}"
and
./printer first second "third fourth"
outputs:
Printing args
first
second
third fourth
Printing second args
first
second
third fourth
If anyone wants to explain the problem with the other things I tried, please do, as I'm still interested!