I want to add char in Select statement.
Ex:
SELECT '.' + OUTTRUNK as NUMBER
Expected Result:
.348977834
.456935534
.090922834
.234999734
How can I do this?
Thanks.
Try the more SQL-ish:
SELECT '.' || OUTTRUNK as NUMBER
but keep in mind that, if OUTRUNK is a numeric rather than string type, you'll probably find that 090922834 will actually be 90922834 and will render as .90922834, not what you want.
If that's the case, you're probably looking for something more like:
SELECT OUTTRUNK / 1000000000 as NUMBER
(check the number of zeros there, I tried to get it right but testing is rightly your concern).
Related
I have the following:
string text = "Select [id] AS [FROMId] FROM [TASK] ORDER BY id"
and I want to use text.IndexOf("FROM") in order to find where the FROM starts.
I want to find the position of FROM and not the position of FROMId.
LastIndexOf or FirstIndexOf are not correct answers cause the text could be anything like
string text = #"Select [id] AS [FROMId],
newId as [newFROMId] FROM [TASK] ORDER BY [FROMId]"
I need the indexof to do exact matching.
Any ideas?
Since FROM is an SQL reserved word that will generally have spaces on either side, you could look for that then, since that will give you the address of the space before the F, add one to get the location of the F itself:
int index = text.IndexOf(" FROM ") + 1
This may not necessarily take care of all edge cases(a) but, to do that properly, you may have to implement an SQL parser to ensure you can correctly locate the real from keyword and distinguish it from other possibilities.
(a) Such as things like:
select [a]FROM[tble] ...
select 'got data from unit #' | unit from tbl ...
and so on.
I want to fetch substring from string in column between last '/' and last '.' .
Here is sample date for IMAGE_PATH column name:
sph/images/30_Fairhall_Court.jpeg
sph/images/9_Pennethorne_House.jpeg
rbkc/images/TAVISTOCK_CRESCENT.jpeg
haringey/images/399932thumb.jpg
urbanchoice/images/18190862.jpg
wandle/images/f13c10d2-2692-457d-a208-8bb9e10b27dc.png
housingmoves/images/No14_Asterid Heights_DS37620.jpg
wandle/images/f13c10d2-2692-457d-a208-8bb9e10b27dc.png
So the required output is like
30_Fairhall_Court
9_Pennethorne_House
TAVISTOCK_CRESCENT
399932thumb
18190862
f13c10d2-2692-457d-a208-8bb9e10b27dc
No14_Asterid Heights_DS37620
f13c10d2-2692-457d-a208-8bb9e10b27dc
Please suggest how to fetch. I need to update another blank column in table with this value. The table has around 10 lacks records.
One of possible solutions is to use functions substr() and instr() with negative third parameter:
select image_path,
substr(image_path,
instr(image_path, '/', -1) + 1,
instr(image_path, '.', -1)-instr(image_path, '/', -1) - 1) img
from test
SQL Fiddle
Results:
IMAGE_PATH IMG
-------------------------------------------------------- -------------------------------------
sph/images/30_Fairhall_Court.jpeg 30_Fairhall_Court
sph/images/9_Pennethorne_House.jpeg 9_Pennethorne_House
rbkc/images/TAVISTOCK_CRESCENT.jpeg TAVISTOCK_CRESCENT
haringey/images/399932thumb.jpg 399932thumb
urbanchoice/images/18190862.jpg 18190862
wandle/images/f13c10d2-2692-457d-a208-8bb9e10b27dc.png f13c10d2-2692-457d-a208-8bb9e10b27dc
housingmoves/images/No14_Asterid Heights_DS37620.jpg No14_Asterid Heights_DS37620
wandle/ima.ges/f13c10d2-2692-457d-a208-8bb9e10b27dc.png f13c10d2-2692-457d-a208-8bb9e10b27dc
This regex works with the sample data you provided:
select regexp_substr(image_path
, '(/)([a-z0-9_ \-]+)(\.)([a-z]+)$'
, 1
, 1
, 'i'
, 2)
from t23
/
We have to include all the optional parameters after pattern so we can use the subexpr parameter to select just the filename element. Find out more.
As far as the updating goes, a million row table isn't that big. Given that you have to update all the rows there's not much you can do to tune it. Just issue the UPDATE statement and let it rip.
"its not working"
Hmmm, here's a SQL Fiddle which proves it does work. You've probably introduced a typo.
"The regexp looks unnecessary complex. Why not simply"
Perhaps it is too complicated. However your simplified version doesn't produce the correct result if there's more than one dot in the IMAGE_PATH. If that's never going to happen then your solution works just fine.
Excuse me, occasionally I refer with some problem that maybe it's already been fixed. In any case, I would appreciate a clarification on vs.
I have a TariffeEstere table with the fields country, Min, Max, tariff
from which to extract the rate for the country concerned, depending on whether the value is between a minimum and a maximum and I should return a single record from which to extract its tariff:
The query is:
stsql = "Select * from QPagEstContanti Where country = ' Spain '
and min <= ImpAss and max >= ImpAss"
Where ImpAss is a variable of type double.
When I do
rstariffa.open ststql,.....
the recodset contains a record if e.g. ImpAss = 160 (i.e. an integer without decimals), and then the query works, but if it contains 21,77 ImpAss (Italian format) does not work anymore and gives me a syntax error.
To verify the contents of the query string (stsql) in fact I find:
Select * from QPagEstContanti Where country = 'Spain' and min < = 21,77 and max > = 21,77
in practice the bothering and would like a comma decimal, but do not know how do.
I tried to pass even a
format (ImpAss, "####0.00"),
but the value you found in a stsql is 21,77 always.
How can I fix the problem??
It sounds like the underlying language setting in SQL is expecting '.' decimals instead of ',' decimal notation.
To check this out - run the DBCC useroptions command and see what the 'language' value is set to. If the language is set to English or another '.' decimal notation - it explains why your SQL string is failing with values of double.
If that's the problem, the simplest way to fix it is to insert the following line after your stsql = statement:
stsql = REPLACE(stsql, ",", ".")
Another way to fix it would be to change the DEFAULT_LANGUAGE for the login using the ALTER LOGIN command (but this changes the setting permanently)
Another way to fix it would be to add this command to the beginning of your stsql, which should change the language for the duration of the rs.Open:
"SET LANGUAGE Italian;"
In Oracle I want to check whether the string has "=' sign at the end. could you please let me know how to check it. If it has '=' sign at the end of string, I need to trailing that '=' sign.
for eg,
varStr VARCHAR2(20);
varStr = 'abcdef='; --needs to trailing '=' sign
I don't think you need "pattern matching" here. Just check if the last character is the =
where substr(varstr, -1, 1) = '='
substr when called with a negative position will work from the end of the string, so substr(varstr,-1,1) extracts the last character of the given string.
Use the REGEX_EXP function. I'm putting a sql command since you didn't specify on your question.:
select *
from someTable
where regexp_like( someField, '=$' );
The pattern $ means that the precedent character should be at the end of the string.
see it here on sql fiddle: http://sqlfiddle.com/#!4/d8afd/3
It seems that substr is the way to go, at lease with my sample data of about 400K address lines this returns 1043 entries that end in 'r' in an average of 0.2 seconds.
select count(*) from addrline where substr(text, -1, 1) = 'r';
On the other hand, the following returns the same results but takes 1.1 seconds.
select count(*) from addrline where regexp_like(text, 'r$' );
I would like to know whats the XPath equivalent to SQL In query. Basically in sql i can do this:
select * from tbl1 where Id in (1,2,3,4)
so i want something similar in XPath/Xsl:
i.e.
//*[#id= IN('51417','1121','111')]
Please advice
(In XPath 2,) the = operator always works like in.
I.e. you can use
//*[#id = ('51417','1121','111')]
A solution is to write out the options as separate conditions:
//*[(#id = '51417') or (#id = '1121') or (#id = '111')]
Another, slightly less verbose solution that looks a bit like a hack, though, would be to use the contains function:
//*[contains('-51417-1121-111-', concat('-', #id, '-'))]
Literally, this means you're checking whether the value of the id attribute (preceeded and succeeded by a delimiter character) is a substring of -51417-1121-111-. Note that I am using a hyphen (-) as a delimiter of the allowable values; you can replace that with any character that will not appear in the id attribute.