I have a table with a date field. By default, select max(date) from table; returns the date in 'dd-mmm-yy' format. How do I select the date in 'MM/DD/YYYY' format, without changing the table 's structure or the field's format.
Thanks,
Supraja
select to_char(max(date), 'MM/DD/YYYY') from table;
Try the following:
select to_char(sysdate,'mm/dd/yyyy') as maxdate from dual;
Some information on the oracle-specific function to_char():
http://www.techonthenet.com/oracle/functions/to_char.php
Check out the to_char function and the date/time formats it accepts.
select to_char(sysdate, 'MM/DD/YYYY')
from dual;
Exists a table or view v$nls_parameters search here the parameter 'NLS_DATE_FORMAT', this is perfect for not be changing the format each while.
SELECT *
FROM v$nls_parameters WHERE UPPER(PARAMETER) = 'NLS_DATE_FORMAT';
ALTER SESSION SET NLS_DATE_FORMAT = 'YYYYMMDD';
There is also the possibility from make for register of win. in tree
HKEY_LOCAL_MACHINE\SOFTWARE\Wow6432Node\ORACLE\KEY_OraClient11g_home9
Here key NLS_DATE_FORMAT, change for your format date.
Related
I have a oracle view in which we have column called dayofset which defined from subtraction of two date columns like(to_date(date_column1)-to_date(date_column2)) and it is stored as number(38) datatype.
2.so,when I run session in informatica to get data from oracle view to redshift.im getting error like "not a valid month".
3.Input values for that column is like (25-JAN-21,10-APR-13)
4.im getting the output values like 1,2,3,4... Like this all are integer values.(this column just do the datediff operation) and provide the difference between two dates.
Could you guys please help on this.
I have a oracle view in which we have column called dayofset which defined from subtraction of two date columns like to_date(date_column1)-to_date(date_column2) and it is stored as number(38) datatype.
Never use TO_DATE on a column that is already a DATE data type. Just use.
CREATE VIEW your_view (dayofset)
SELECT date_column1 - date_column2
FROM your_table;
If you use TO_DATE then it takes a string as the first argument so you are effectively performing an implicit conversion to a string to convert it back to a date and your code is the equivalent of:
CREATE VIEW your_view (dayofset)
SELECT TO_DATE(
TO_CHAR(
date_column1,
(SELECT value FROM NLS_SESSION_PARAMETERS WHERE parameter = 'NLS_DATE_FORMAT')
),
(SELECT value FROM NLS_SESSION_PARAMETERS WHERE parameter = 'NLS_DATE_FORMAT')
)
-
TO_DATE(
TO_CHAR(
date_column2,
(SELECT value FROM NLS_SESSION_PARAMETERS WHERE parameter = 'NLS_DATE_FORMAT')
),
(SELECT value FROM NLS_SESSION_PARAMETERS WHERE parameter = 'NLS_DATE_FORMAT')
)
FROM your_table;
Depending on your NLS_DATE_FORMAT session parameter, this could just be a waste of time or it could truncate the date and give you an unexpected result; however, any user can change their session parameters at any time so you may get different results for different users so you should NEVER rely on implicit conversions.
If your columns are not a DATE data-type but are strings then use an explicit format model (and, if required, language) in the conversion:
CREATE VIEW your_view (dayofset)
SELECT TO_DATE(string_column1, 'DD-MON-RR', 'NLS_DATE_LANGUAGE=English')
- TO_DATE(string_column2, 'DD-MON-RR', 'NLS_DATE_LANGUAGE=English')
FROM your_table;
In Oracle 12, if I create a very simple table, TEST_TABLE, with a single varchar2(128) column 'name' and populate that column with lots of strings of '20170831', and my sysdate shows:
SELECT sysdate FROM dual;
29-SEP-17
then why does this SQL query return 0 rows:
SELECT TO_DATE(name,'YYYYMMDD'),
TO_DATE(TRUNC(SYSDATE),'DD-MM-YYYY')
FROM TEST_TABLE
WHERE TO_DATE(name,'YYYYMMDD') < TO_DATE(TRUNC(SYSDATE),'DD-MM-YYYY');
(This is a very simplified example of a problem I'm facing in my partition maintenance script and have not been able to solve for the last week).
Thank you in advance for any assistance related to the above query.
Midnight(time part is 00:00:00.000):
SELECT TO_DATE(name,'YYYYMMDD'), TRUNC(SYSDATE)
FROM TEST_TABLE
WHERE TO_DATE(name,'YYYYMMDD') <= TRUNC(SYSDATE);
You could also try:
ALTER SESSION SET NLS_DATE_FORMAT = 'YYYY-MM-DD HH24:MI:SS';
Just don't apply a to_date() to an already date field, this because, it will implicitly convert that date into varchar and then apply the to_date() function to it, for example your query part TO_DATE(TRUNC(SYSDATE),'DD-MM-YYYY') is interpreted like this:
TO_DATE(TO_CHAR(TRUNC(SYSDATE)),'DD-MM-YYYY')
TO_CHAR(TRUNC(SYSDATE)) is getting a char something like: '31-AUG-17', and that is not in 'DD-MM-YYYY' format.
And because of that, TO_DATE(TRUNC(SYSDATE),'DD-MM-YYYY') gets something like this: 29/09/0017 and your filter goes FALSE and gets no results.
Why does below query work successfully?
select to_char(sysdate,'MM-YYYY') from dual;
But the following queries give an invalid number error:
select to_char('28-JUL-17','MM-YYYY') from dual;
select to_char('7/28/2017','MM-YYYY') from dual;
Though, below query gives you the same date format.
select sysdate from dual; -- 7/28/2017 11:29:01 AM
TO_CHAR function accepts only date or number. Maybe you can try this
select to_char(to_date('28-JUL-17', 'DD-MON-YY'),'MM-YYYY') from dual;
As a side note, if you're planning to convert a bunch of dates to strings so you can look for all records in a certain month of a certain year, be aware that the TRUNC function can be used to reduce the precision of a date (e.g. to "month and year"). The following query pulls all records created this month, from the table. It should be faster than converting dates to char and doing string comparison..
SELECT * FROM table WHERE trunc(create_date, 'MON') = trunc(sysdate, 'MON')
Because function TO_CHAR() accepts date or timestamp values. However, neither '28-JUL-17' nor '7/28/2017' are dates or timestamps - they are STRINGS.
Oracle gently tries to convert these stings into DATE values. This implicit conversion may work or may fail, it depends on your current session NLS_DATE_FORMAT, resp. NLS_TIMESTAMP_FORMAT settings.
As given already in other answers you have to convert the string explicitly:
TO_DATE('28-JUL-17', 'DD-MON-RR')
TO_DATE('7/28/2017', 'MM/DD/YYYY')
to_char() isn't expecting you to start with a char value. If you really want that to work, you'll need to wrap it around a to_date() function.
to_char(
to_date(
'28-JUL-17'
, 'DD-Mon-YY'
)
,'MM-YYYY'
)
You are using an incorrect mask, for more information read here.
The correct one should be:
select to_char(to_date('28-JUL-17','DD-MON-YY'), 'MON-YY') from dual;
You can also extract the month using EXTRACT:
select EXTRACT (MONTH FROM to_date('28-JUL-17','DD-MON-YY')) from dual;
Cheers
I was trying the TO_DATE function. Specifically, I noted that the following queries
1. SELECT TO_CHAR(TO_DATE('01-01-2015','DD-MM-YYYY'),'DD-MON-YY') FROM DUAL
2. SELECT TO_DATE('01-01-2015','DD-MM-YYYY') FROM DUAL
have the same output: 01-JAN-2015.
Why does the TO_DATE function return the month in its abbreviated form?
My expected output for the second query is something like 01-01-2015 (simply, a TYPE conversion, NOT a format conversion).
Am I wrong?
Thanks
Dates do not have a format - they are represented by 7- or 8-bytes.
SELECT DUMP( SYSDATE ) FROM DUAL;
Might output:
Typ=13 Len=8: 220,7,11,26,16,41,9,0
This format is very useful for computers to compare dates but not so useful to people; so, when the SQL client (SQL/plus, SQL Developers, TOAD, etc) displays a date it does not display the the bytes but displays it as a string.
It does this by making an implicit call to TO_CHAR() (or some other internal method of stringifying dates) and uses a default format mask to perform this conversion.
SQL/Plus and SQL Developer will use the user's session parameter NLS_DATE_FORMAT to perform this conversion - see this answer regarding this.
So your second query is implicitly being converted to do something approaching this (but, almost certainly, more efficiently):
SELECT TO_CHAR(
TO_DATE('01-01-2015','DD-MM-YYYY'),
( SELECT VALUE FROM NLS_SESSION_PARAMETERS WHERE PARAMETER = 'NLS_DATE_FORMAT' )
)
FROM DUAL
The default output format of DATE value, resp TO_DATE() function is set by NLS_DATE_FORMAT value. You can verify it with this query:
SELECT *
FROM V$NLS_PARAMETERS
WHERE PARAMETER = NLS_DATE_FORMAT';
You can change it on session level for example with
alter session set NLS_DATE_FORMAT = 'DD-MM-YYYY';
The output format of TO_CHAR is not correct, try:
SELECT TO_CHAR(TO_DATE('01-01-2015','DD-MM-YYYY'),'DD-MM-YYYY') FROM DUAL;
Oracle TO_DATE: is used to convert a character string to a date format.
and related to your concern; you need to alter your session like below:
alter session set nls_date_format='DD-MM-YYYY'
in your apps right after the connect.
So now if you run again your query :
SELECT TO_DATE ('01-01-2015', 'DD-MM-YYYY')
FROM DUAL;
the result would be as expected:
01-01-2015
Hope that will help.
My table has two DATE format attributes, however, when i try to insert value it throws an error: date format picture ends before converting entire input string.
Here is my attempted code:
insert into visit
values(123456, '19-JUN-13', '13-AUG-13 12:56 A.M.');
I think the problem is with 12:56 but Oracle documentation says date implies both date and time.
Perhaps you should check NLS_DATE_FORMAT and use the date string conforming the format.
Or you can use to_date function within the INSERT statement, like the following:
insert into visit
values(123456,
to_date('19-JUN-13', 'dd-mon-yy'),
to_date('13-AUG-13 12:56 A.M.', 'dd-mon-yyyy hh:mi A.M.'));
Additionally, Oracle DATE stores date and time information together.
you need to alter session
you can try before insert
sql : alter session set nls_date_format = 'YYYY-MM-DD HH24:MI:SS'
What you're trying to insert is not a date, I think, but a string. You need to use to_date() function, like this:
insert into table t1 (id, date_field) values (1, to_date('20.06.2013', 'dd.mm.yyyy'));
I had this error today and discovered it was an incorrectly-formatted year...
select * from es_timeexpense where parsedate > to_date('12/3/2018', 'MM/dd/yyy')
Notice the year has only three 'y's. It should have 4.
Double-check your format.