I'm using Cygwin to start some servers.
Each server is launched inside an xterm with a bunch of command like this one:
xterm -e $my_cmd /C &
Is there an easy way to kill all launched children (xterm and their running commands) in a row ?
I want also to be able kill a particular launched command when I close its parent xterm.
Someone knows how to perform that ?
killall xterm? That command is in the psmisc package. Xterm will notify its child process with a SIGHUP ("hangup") before it exits. Normally that will cause the child process to exit too, although some servers interpret that signal differently.
Related
Consider this snippet as being saved in a file called snippet.sh:
nohup xmessage HI </dev/null &>/dev/null & disown
sleep 3
From the same directory, do xterm -e bash snippet.sh.
After 3 seconds, the xterm should disappear while the xmessage window lingers. All good and well. But what if the nohup is removed from the command in the snippet file? Then the xmessage which disappears along with the xterm. The bash documentation seems to indicate that disown should, by itself, be sufficient to prevent SIGHUP from being sent:
The shell exits by default upon receipt of a SIGHUP. Before exiting, an interactive shell resends
the SIGHUP to all jobs, running or stopped. Stopped jobs are sent SIGCONT to ensure that they
receive the SIGHUP. To prevent the shell from sending the signal to a particular job, it should be
removed from the jobs table with the disown builtin (see SHELL BUILTIN COMMANDS below) or marked to
not receive SIGHUP using disown -h.
So, the question is, why won't the xmessage window linger without nohup?
disown is sufficient to prevent the shell from sending the signal, but it doesn't stop anyone else.
In particular, the shell is the controlling process of the terminal with xmessage in its process group, and POSIX says that on exit:
If the process is a controlling process, the SIGHUP signal shall be sent to each process in the foreground process group of the controlling terminal belonging to the calling process.
I'm trying to achieve the following:
from a fish script, open a PDF reader as a background job. Once it is opened, spawn another fish process (that runs an infinite while loop), also as a background job.
Next, open an editor (neovim) and allow it to take control of the running terminal. Once neovim terminates, also suspend the previous 2 background jobs (mupdf and the other fish process).
My current attempt looks something along the lines of:
mupdf $pdfpath &
set pid_mupdf $last_pid
fish -c "while inotifywait ...; [logic to rebuild the pdf file..]; end" &
set pid_sub $last_pid
nvim $mdpath && kill -2 $pid_mudf $pid_sub
First I open mupdf as a background job and save its PID in a variable. Next I spawn the other fish process, also as a background job, and I save its PID as well.
Next I run nvim (but not as a background job, as I intend to actually control it), and after it is terminated by the user, I gracefully kill the previous 2 background jobs.
However this doesn't work as intended.
mupdf and the second fish process open successfully, and so does nvim, but it quickly closes after around half a second, after which I get the following in the controlling terminal window: image (bote is just the filename of the script from which the lines above originate)
The 2 background processes stay running after that and I have to kill them manually.
I understand that the script is sent a SIGHUP because the controlling terminal now executes another application (neovim), but why does neovim close after that?
I also tried disowning the background processes after they're spawned but that didn't help.
How would I solve this issue?
The problem is that $last_pid, in fish 3, and %last, in fish 2, doesn't work by default in scripts. See https://github.com/fish-shell/fish-shell/issues/5036. You can "fix" this by putting status job-control full at the top of the script or using the (jobs -lp) hack that Glenn mentioned.
Regarding the background process remaining running... I can't reproduce that. It works for me. However, note that your nvim && kill will only run the kill if nvim exits with a status of zero. If you always want the kill to be run you should just unconditionally execute it. Also, your use of signal two (SIGINT) should produce the desired result but is unusual. You should use kill -15 or just omit the signal in which case it defaults to 15 (SIGTERM).
You're getting the PID incorrectly. The $pid_mudf and $pid_sub variables are empty. You want
set pid_mupdf (jobs -lp)
I run a series of silent instances of phantomjs in a script, when the script ends I want to kill them off, all at once. However to make the script look nice and not overload the screens with this message
./runTests.sh: line 74: 26002 Killed phantomjs Lib/loadtester/runTests.js $TEST_COUNT $CLIENT_LIMIT $ACTION $PROFILE $TEST_SERVER $TEST_INCREMENT $DEBUG_MODE > "/tmp/"$TEST_COUNT"_log.txt"
What is the best way to do so, I was currently trying:
(killall -9 phantomjs 2>&1) >/dev/null
And have tried pretty much everything I can think of including all quiet options in killall
Those messages aren't coming from the killall command. They're coming from the shell when it notices that one of its background child processes has died.
You can prevent this by running the commands in a subshell:
(phantomjs Lib/loadtester/runTests $TEST_COUNT $CLIENT_LIMIT $ACTION $PROFILE $TEST_SERVER $TEST_INCREMENT $DEBUG_MODE > "/tmp/"$TEST_COUNT"_log.txt" &)
The background process is now a child of the subshell, not the original script shell, so the script shell is not notified when it dies. (Actually, since the subshell exits immediately after creating the background process, the background process becomes a child of init.)
I'm trying to use a shell script to start a command. I don't care if/when/how/why it finishes. I want the process to start and run, but I want to be able to get back to my shell immediately...
You can just run the script in the background:
$ myscript &
Note that this is different from putting the & inside your script, which probably won't do what you want.
Everyone just forgot disown. So here is a summary:
& puts the job in the background.
Makes it block on attempting to read input, and
Makes the shell not wait for its completion.
disown removes the process from the shell's job control, but it still leaves it connected to the terminal.
One of the results is that the shell won't send it a SIGHUP(If the shell receives a SIGHUP, it also sends a SIGHUP to the process, which normally causes the process to terminate).
And obviously, it can only be applied to background jobs(because you cannot enter it when a foreground job is running).
nohup disconnects the process from the terminal, redirects its output to nohup.out and shields it from SIGHUP.
The process won't receive any sent SIGHUP.
Its completely independent from job control and could in principle be used also for foreground jobs(although that's not very useful).
Usually used with &(as a background job).
nohup cmd
doesn't hangup when you close the terminal. output by default goes to nohup.out
You can combine this with backgrounding,
nohup cmd &
and get rid of the output,
nohup cmd > /dev/null 2>&1 &
you can also disown a command. type cmd, Ctrl-Z, bg, disown
Alternatively, after you got the program running, you can hit Ctrl-Z which stops your program and then type
bg
which puts your last stopped program in the background. (Useful if your started something without '&' and still want it in the backgroung without restarting it)
screen -m -d $command$ starts the command in a detached session. You can use screen -r to attach to the started session. It is a wonderful tool, extremely useful also for remote sessions. Read more at man screen.
I wanted to know why i am seeing a different behaviour in the background process in Bash shell
Case 1: Logged in to Unix server using Putty(SSH)
By default it uses csh shell
I changed to bash shell
typed sleep 2000 &
press enter
It gave me the job number. Now i killed my session by clicking the x in the putty window
Now open another session and tried to lookup the process..the process died.
Case 2:Case 1: Logged in to Unix server using Putty(SSH)
By default it uses csh shell
I changed to bash shell
vi mysleep.sh
sleep 2000 & Saved mysleep.sh
./mysleep.sh
Diff here is..instead of executing the sleep command directly i am storing the sleep command in a file and executing the file.
Now i killed my session by clicking the x in the putty window
Now open another session and tried to lookup the process..the process is still there
Not sure why this is happening. I thought i need to do disown in bash to run the process even after logging out.
One diff i see in the parent process id..In the second case..the parent process id for the sleep 2000 becomes 1. Looks like as soon as process for mysleep.sh died the kernel assigned the parent process to 1.
The difference here is indeed the intervening process.
When you close the terminal window, a HUP signal (related to "nohup" as an0nymo0usc0ward mentioned) is sent to the processes running in it. The default action on receiving HUP is to die - from the signal(3) manpage,
No Name Default Action Description
1 SIGHUP terminate process terminal line hangup
In your first example, the sleep process directly receives this HUP signal and dies because it isn't set to do anything else. (Some processes catch HUP and use it to perform some action, e.g. reread some configuration files)
In the second example, the shell process running your shell script has already died, so the sleep process never gets the signal. In UNIX, every process must have a parent process due to the internals of how the wait(2) family of calls works and indeed processes in general. So when the parent process dies, the kernel gives it to init (pid 1, as you note) as a foster child.
Orphan process (on wikipedia) has some more information available about it, also see Zombie process for some additional technical details.
Already running process?
^z
bg
disown %<jobid>
New process/script (on local machine's console)?
nohup script.sh &
New process/script (on remote machine's console)?
Depending on your need,
there are two options [ there will be more ;-) ]
ssh remotehost 'nohup /path/to/script.sh </dev/null > nohup.out 2>&1 &'
OR
use 'screen'
Try "nohup cmd args..."
Steven's answer is correct, but I'd like to highlight the tricky part here again:
=> Using a bash script that just executes sleep in the background
The effect of this is that the "script" exits almost immediately (since it's done all its commands). However, it did create a child process (sleep) during its lifetime. The effect of this is that:
The "script" cannot be the parent anymore, and sleep is orphaned to init (which shows nicely in a pstree)
The bash shell where you started the script from has no underlying jobs anymore
Note that this stuff all happens when you executed the script, and has nothing to do with any ssh logout/putty closing.
When you then finally close your putty session, bash receives a "SIGHUP", but doesn't forward it to any other process (since there are no jobs left)
In the other case, bash did still have a job left, which it then sent the SIGHUP to, causing it to end (as you noticed)
Hope this helps