Bash: piped argument to open command fails. Open commands excutes too early? - macos
I'm pretty much a novice to shell scripting. I'm trying to send the output of some piped commands to an open command in bash in OSX.
My ultimate goal is to compile a Flex/Actionscript application from TextWrangler by calling a bash script with a little Applescript and have the result played directly in a Flash Player. The Applescript is pretty much doing it's job. But the bash script doesn't work as I expect. Same results when I ommit the Applescript and simply put it directly in terminal.
This is what the Applescript is sending to terminal:
mxmlc -warnings=false DocumentClass.as | tail -n 1 | sed 's/[[:space:]].*$//' | open -a 'Flash Player'
So basically, I read the last line of the output of mxmlc, which usually looks something like this:
/Users/fireeyedboy/Desktop/DocumentClass.swf (994 bytes)
and I strip everything after the first space it encounters. I know it's hardly bulletproof yet, it's still just a proof of concept. When I get this roughly working I'll refine. It returns the desired result so far:
/Users/fireeyedboy/Desktop/DocumentClass.swf
But as you can see, I then try to pipe this sed result to the Flash Player and that's where it fails. The Flash Player seems to open way too early. I would expect the Flash Player to open only after the script finished the sed command. But it opens way earlier.
So my question is twofold:
Is it even possible to pipe an
argument to the open command this
way?
Do I need to use some type
of delay command to get this
working, since the open command doesn't seem to be waiting for the input?
You're trying to give the name of the swf file as input to stdin of the open command, which it doesn't support.
It expects the file name as an argument (similar to -a).
You can do something like this:
FILENAME=`xmlc -warnings=false DocumentClass.as | tail -n 1 | sed 's/[[:space:]].*$//'`
open -a 'Flash Player' $FILENAME
or on a single line:
open -a 'Flash Player' `xmlc -warnings=false DocumentClass.as | tail -n 1 | sed 's/[[:space:]].*$//'`
If you're using bash (or another modern POSIX shell), you can replace the pretty unreadable backtick character with $( and ):
open -a 'Flash Player' $(xmlc -warnings=false DocumentClass.as | tail -n 1 | sed 's/[[:space:]].*$//')
All commands in a pipe are started at the same time. During this step, their input/outputs are chained together.
My guess is that open -a 'Flash Player' doesn't wait for input but simply starts the flash player. I suggest to try to run the player with an argument instead:
name=$(mxmlc -warnings=false DocumentClass.as | tail -n 1 | sed 's/[[:space:]].*$//')
open -a 'Flash Player' "$name"
I'm not familiar with the "open" command as it seems to be a mac thing, but i think what you want to do is:
open -a 'Flash Player' $(mxmlc -warnings=false DocumentClass.as | tail -n 1 | sed 's/[[:space:]].*$//')
In general you can't pipe arguments to a command, you have to specify that you want the output of the previous command to be treated as arguments, either as in my example or with the xargs command. Note that there is a limit on the maximum size of a command line, though.
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How do I get grep to keep the file/pipe open?
I am trying to debug some errors in a live Merb app. There are a lot of lined of error code running by, but I jut need to see the first one. I can use grep to select these lines and print them but it closes as soon as it reached the end of the file. What I would like to do is use grep like the shift-F mode in less where it will keep the file open and report new matching line as they are written to the log. - or - Is there a way to do this directly with less that I don't know about?
try this tail -f dev.log | grep '^ERROR:' the -f option to tail tells it to wait for more data when it hits EOF.
Can't you do this with watch and tail? watch -n 30 "grep 'dev.log' '^ERROR:' | tail -n 30"
How to run the first process from a list in a file deleting the first line as if the file was a queue and I called "pop"?
How to run the first process from a list of processes stored in a file and immediately delete the first line as if the file was a queue and I called "pop"? I'd like to call the first command listed in a simple text file with \n as the separator in a pop-like fashion: Figure 1: cmdqueue.lst : proc_C1 proc_C2 proc_C3 . . Figure 2: Pop the first command via popcmd: proc_A | proc_B | popcmd cmdqueue.lst | proc_D Figure 3: cmdqueue.lst : proc_C2 proc_C3 proc_C4 . .
Ooh, that's an amusing one-liner. Okay, here's the deal. What you want is a program that, when called, prints the first line of the file to stdout, then delete that line from the file. Sounds like a job for sed(1). Try proc_A | proc_B | `(head -1 cmdstack.lst; sed -i -e '1d' cmdstack.lst)` | proc_D I'm sure that someone who had already had their coffee could change the sed program to not need the head(1) call, but that works, and shows off using a subshell ("( foo )" runs in a sub-process.)
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I think you would need to rewrite the file - e.g. run a command to list all lines but the first, write that to a temporary file and rename it to the original. That could be done using tail or awk or perl depending on the commands you have available.
If you want to treat a file like a stack, then a better approach would be to have the top of the stack at the end of the file. Thus you can easily cut off the file at the beginning of the last line (= pop), and simply append to the file as you push.
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You can't write to the beginning of a file, so cutting out line 1 would be a lot of work (rewrite the rest of the file (which isn't actually that much work for the programmer (it's what every other answer post has written for you :) ) ) ). I'd recommend keeping the whole thing in memory and using a classic stack rather than a file.