I've posted this question for C# but I may be working in Ruby instead. So I'm asking the same question about Ruby:
I'm looking for a Ruby class/library/module that works similarly to the Perl module Date::Manip as far as business/holiday dates. Using that module in Perl, I can pass it a date and find out whether it's a business day (ie, Mon-Fri) or a holiday. Holidays are very simple to define in a config file (see Date::Manip::Holidays). You can enter a 'fixed' date that applies to every year like:
12/25 = Christmas
or 'dynamic' dates for every year like:
last Monday in May = Memorial Day
or 'fixed' dates for a given year like:
5/22/2010 = Bob's Wedding
You can also pass in a date and get back the next/previous business day (which is any day that's not a weekend and not a holiday).
Does anyone know of anything like that in the Ruby world?
You may use the holidays-gem.
http://rubygems.org/gems/holidays
Some national (and regional) holidays are already predefined, you may define your own holiday definitions.
The business_time gem should do what you need.
The example at bottom of the README doc is a good starting example:
require 'rubygems'
require 'active_support'
require 'business_time'
# We can adjust the start and end time of our business hours
BusinessTime::Config.beginning_of_workday = "8:30 am"
BusinessTime::Config.end_of_workday = "5:30 pm"
# and we can add holidays that don't count as business days
# July 5 in 2010 is a monday that the U.S. takes off because
# our independence day falls on that Sunday.
three_day_weekend = Date.parse("July 5th, 2010")
BusinessTime::Config.holidays << three_day_weekend
friday_afternoon = Time.parse("July 2nd, 2010, 4:50 pm")
tuesday_morning = 1.business_hour.after(friday_afternoon)
You probably going to need the chronic gem to help you build the holiday dates from your config file. However YMMV because your example last monday in may doesn't work in chronic. Hackaround is do something like this:
# last monday in May (2010)
Chronic.parse('last monday', :now => Time.parse('2010-06-01'))
And look at the tickle gem which works on top of chronic for a way to add recurring events.
/I3az/
You could take a look at my Workpattern gem. It allows you to specify working and resting times. It was aimed at producing a "Calendar" like is used in planning tools such as Microsoft Project and Primavera P6, so you can specify right down to the minute.
Here is a simple example:
Create a new Workpattern mywp=Workpattern.new('My Workpattern',2011,10) This is for 10 years from 2011 but you can make it longer or shorter.
Tell it you want the Weekends to be resting and that you also want to rest during the week so you work between 9 and 12 in the morning and 1 and 6 in the afternoon.
mywp.resting(:days => :weekend)
mywp.resting(:days =>:weekday, :from_time=>Workpattern.clock(0,0),:to_time=>Workpattern.clock(8,59))
mywp.resting(:days =>:weekday, :from_time=>Workpattern.clock(12,0),:to_time=>Workpattern.clock(12,59))
mywp.resting(:days =>:weekday, :from_time=>Workpattern.clock(18,0),:to_time=>Workpattern.clock(23,59))
Now just calculate using minutes
mydate=DateTime.civil(2011,9,1,9,0)
result_date = mywp.calc(mydate,1920) # => 6/9/11#18:00
1920 is 4 days * 8 hours a day * 60 minutes and hour.
I wrote the gem to learn Ruby - only scratched the surface.
Check out the biz gem.
Here's an example configuration:
require 'biz'
Biz.configure do |config|
config.hours = {
mon: {'09:00' => '17:00'},
tue: {'00:00' => '24:00'},
wed: {'09:00' => '17:00'},
thu: {'09:00' => '12:00', '13:00' => '17:00'},
sat: {'10:00' => '14:00'}
}
config.holidays = [Date.new(2014, 1, 1), Date.new(2014, 12, 25)]
config.time_zone = 'America/Los_Angeles'
end
When you use the optional core extensions, it's as easy as the following to find out if a date is a business day:
require 'biz/core_ext'
Date.new(2014, 12, 25).business_day? # => false
Related
I'm creating multiple Schedule objects, which have a started_at datetime which begins on Mondays.
I have Location objects which have a visit_frequency. Some of these are set to :bi_weekly, in which case I only need to see them every other week.
However, things don't always go according to plan and sometimes Locations are visited more or less often than the need to.
Right now I'm doing
Location.all.each do |location|
...
elsif location.frequency.rate == 'biweekly'
if (#schedule.start_date - location.last_visit_date) > 7
schedule_for_week location
end
The problem is, if I make a Schedule more than 7 days from now, the Location's last_visit_date will ALWAYS be > 7 days. I need to calculate if it falls into a bi-weekly rate.
Example:
Location 1 visit_frequency set to :bi_weekly
Location 1 is visited on Week 1
Week 2 Schedule Generated -- Location 1 is left out because it is within 7 days
Week 3 Schedule Generated -- Location 1 is included because it is within 7 days
Week 4 Schedule Generated -- Location 1 is included because it is within 7 days
The last line should not have happened. Location 1 should not be included because it was visited on Week 1 and scheduled for Week 3.
How can I calculate if a week is within a bi-weekly frequency succintly? I"m guessing I need to use beginning_of_week?
As I understand your question, I believe this would do it:
require 'date'
def schedule?(sched_start_date, last_visit_date)
(sched_start_date - last_visit_date) % 14 > 7
end
sched_start_date = Date.parse("2014-12-29")
#=> #<Date: 2014-12-29 ((2457021j,0s,0n),+0s,2299161j)> a Monday
schedule?(sched_start_date, Date.parse("2014-12-04")) #=> true
schedule?(sched_start_date, Date.parse("2014-12-14")) #=> false
schedule?(sched_start_date, Date.parse("2014-12-20")) #=> true
schedule?(sched_start_date, Date.parse("2014-12-23")) #=> false
Working on a 3 week new registration chart for metrics, I have the following code:
(3.weeks.ago.to_date..Date.today).map { |date| Metrics.registrations_on(date) }
In Metrics.rb:
def self.registrations_on(date)
date = date.midnight
end_date = date + 24.hours
User.where(:created_at => date..end_date).count
end
Before the day is done here in California, a new day's numbers are already starting to increase. The created_at timestamp is UTC as well.
I'd like to be able to see the stats from today, using our time zone. With my data already saved as UTC I'm curious as to how about accomplishing this.
Open config/application.rb, find config.time_zone, and assign it with appropriate value:
config.time_zone = 'Pacific Time (US & Canada)'
Restart your app, and all ruby date/time operation should be adjusted automatically to your time zone.
For a list of all supported time zone strings, use:
bundle exec rake time:zones:all
I made new object Date.new with args (year, month). After create ruby added 01 number of day to this object by default. Is there any way to add not first day, but last day of month that i passed as arg(e.g. 28 if it will be 02month or 31 if it will be 01month) ?
use Date.civil
With Date.civil(y, m, d) or its alias .new(y, m, d), you can create a new Date object. The values for day (d) and month (m) can be negative in which case they count backwards from the end of the year and the end of the month respectively.
=> Date.civil(2010, 02, -1)
=> Sun, 28 Feb 2010
>> Date.civil(2010, -1, -5)
=> Mon, 27 Dec 2010
To get the end of the month you can also use ActiveSupport's helper end_of_month.
# Require extensions explicitly if you are not in a Rails environment
require 'active_support/core_ext'
p Time.now.utc.end_of_month # => 2013-01-31 23:59:59 UTC
p Date.today.end_of_month # => Thu, 31 Jan 2013
You can find out more on end_of_month in the Rails API Docs.
So I was searching in Google for the same thing here...
I wasn't happy with above so my solution after reading documentation
in RUBY-DOC was:
Example to get 10/31/2014
Date.new(2014,10,1).next_month.prev_day
require "date"
def find_last_day_of_month(_date)
if(_date.instance_of? String)
#end_of_the_month = Date.parse(_date.next_month.strftime("%Y-%m-01")) - 1
else if(_date.instance_of? Date)
#end_of_the_month = _date.next_month.strftime("%Y-%m-01") - 1
end
return #end_of_the_month
end
find_last_day_of_month("2018-01-01")
This is another way to find
You can do something like that:
def last_day_of_month?
(Time.zone.now.month + 1.day) > Time.zone.now.month
end
Time.zone.now.day if last_day-of_month?
This is my Time based solution. I have a personal preference to it compared to Date although the Date solutions proposed above read somehow better.
reference_time ||= Time.now
return (Time.new(reference_time.year, (reference_time.month % 12) + 1) - 1).day
btw for December you can see that year is not flipped. But this is irrelevant for the question because december always has 31 day. And for February year does not need flipping. So if you have another use case that needs year to be correct, then make sure to also change year.
Here is taking the first and third answers to find the last day of the previous month.
today_c = Date.civil(Date.today.prev_month.year, -1, -1)
p today_c
I'm trying to figure out how to extract dates from unstructured text using Ruby.
For example, I'd like to parse the date out of this string "Applications started after 12:00 A.M. Midnight (EST) February 1, 2010 will not be considered."
Any suggestions?
Try Chronic (http://chronic.rubyforge.org/) it might be able to parse that otherwise you're going to have to use Date.strptime.
Assuming you just want dates and not datetimes:
require 'date'
string = "Applications started after 12:00 A.M. Midnight (EST) February 1, 2010 will not be considered."
r = /(January|February|March|April|May|June|July|August|September|October|November|December) (\d+{1,2}), (\d{4})/
if string[r]
date =Date.parse(string[r])
puts date
end
Also you can try a gem that can help find date in string.
Exapmle:
input = 'circa 1960 and full date 07 Jun 1941'
dates_from_string = DatesFromString.new
dates_from_string.get_structure(input)
#=> return
# [{:type=>:year, :value=>"1960", :distance=>4, :key_words=>[]},
# {:type=>:day, :value=>"07", :distance=>1, :key_words=>[]},
# {:type=>:month, :value=>"06", :distance=>1, :key_words=>[]},
# {:type=>:year, :value=>"1941", :distance=>0, :key_words=>[]}]
I am trying to get the difference in hours for two different Time instances. I get these values from the DB as a :datetime column
How can I do this so that it includes the months and years as well in the calculation while ignoring or rounding the minutes? Can this only be done manually or is there a function to do this?
((date_2 - date_1) / 3600).round
or
((date_2 - date_1) / 1.hour).round
Try Time Difference gem for Ruby at https://rubygems.org/gems/time_difference
start_time = Time.new(2013,1)
end_time = Time.new(2014,1)
TimeDifference.between(start_time, end_time).in_years
this works great, example for number of hours since user created account
(Time.parse(DateTime.now.to_s) - Time.parse(current_user.created_at.to_s))/3600
You can use a gem called time_diff to get the time difference in very useful formats
You can use a Rails' method distance_of_time_in_words
distance_of_time_in_words(starting_time, ending_time, options = {include_seconds: true })
In Rails, there is now a far more natural way to achieve this:
> past = Time.now.beginning_of_year
2018-01-01 00:00:00 +0100
> (Time.now - past) / 1.day
219.50031326506948
in_hours (Rails 6.1+)
Rails 6.1 introduces new ActiveSupport::Duration conversion methods like in_seconds, in_minutes, in_hours, in_days, in_weeks, in_months, and in_years.
As a result, now, your problem can be solved as:
date_1 = Time.parse('2020-10-19 00:00:00 UTC')
date_2 = Time.parse('2020-10-19 03:35:38 UTC')
(date_2 - date_1).seconds.in_hours.to_i
# => 3
Here is a link to the corresponding PR.