Is it possible to alias bean class names in Spring? - spring

I have a string property which looks similar to the following example:
<property name="mappingData">
<list>
<bean class="com.company.product.longNamingStandard.migration.extractor.FieldMapping">
<property name="elementName" value="entitlement.user"/>
<property name="mapping" value="DocUsers"/>
</bean>
<bean class="com.company.product.longNamingStandard.migration.extractor.FieldMapping">
<property name="elementName" value="entitlement.contributor"/>
<property name="mapping" value="DocContributors"/>
</bean>
</list>
</property>
The long class name(s) effect readability & also create a refactoring overhead.
Is it possible to alias the class name and use a short name to declare the beans? Or is there an alternate best practice I'm missing?

Probably a bit late for you, but hopefully useful for others:
You can use parent beans to accomplish this.
First declare a parent bean as a template:
<bean id="FieldMapping" class="com.company.product.longNamingStandard.migration.extractor.FieldMapping"/>
Then use it elsewhere, using the parent attribute.
<property name="mappingData">
<list>
<bean parent="FieldMapping">
<property name="elementName" value="entitlement.user"/>
<property name="mapping" value="DocUsers"/>
</bean>
<bean parent="FieldMapping">
<property name="elementName" value="entitlement.contributor"/>
<property name="mapping" value="DocContributors"/>
</bean>
</list>
</property>
Please note my convention here is to use upper case id's here for the parent template beans.

each <bean/> comes with an attribute of name and id to help you reference those beans later in your configuration.
I would suggest using the id for declaring the bean.
your config could look like:
<bean id="fooBean" class="com.example.foo"/>
<bean id="barBean" class="com.example.bar"/>
<list>
<ref>fooBean</ref>
<ref>barBean</ref>
</list>

You may try to represent your mapping in some short form, and then convert it to the list of FieldMappings. For example, mappings from your snippet may be represented as a map.
As a theoretic exercise in Spring 3 you can do this with Spring Expression Language (if FieldMapping has the apropriate constructor):
<util:map id = "m">
<entry name = "entitlement.user" value = "DocUsers" />
<entry name = "entitlement.contributor" value = "DocContributors" />
</util:map>
...
<property name = "mappingData"
value = "#{m.![new com.company.product.longNamingStandard.migration.extractor.FieldMapping(key, value)]}" />
If this expression is too obscure, you may implement a FactoryBean to take a short form of your mapping data (for example, a map, as in this example) and return a configured list of FieldMappings:
<property name = "mappingData">
<bean class = "FieldMappingListFactoryBean">
<property name = "mappings">
<map>
<entry name = "entitlement.user" value = "DocUsers" />
<entry name = "entitlement.contributor" value = "DocContributors" />
</map>
</property>
</bean>
</property>
However, if your field mappings are some kind of reusable DSL, you may try to think about implementing a namespace extension.

I found a way to simulate an effect similar to a "import com.Foo;" in java code. The best option I could find was to use a PropertyPlaceholderConfigurer with local properties defined. Using your example, here's the configuration that you would put at the top of your spring config file to define a "class_FieldMapping" property:
<bean
class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<description>Define properties equivalent to "import foo;" in java source</description>
<property name="properties">
<props>
<prop key="class_FieldMapping">com.company.product.longNamingStandard.migration.extractor.FieldMapping</prop>
</props>
</property>
</bean>
Then, you can use that property within your beans:
<property name="mappingData">
<list>
<bean class="${class_FieldMapping}">
...
</bean>
<bean class="${class_FieldMapping}">
...
</bean>
</list>
</property>
This has the benefit that use can also use it for things where you actually need the class name, and can't reference an instance of an object:
<util:constant static-field="${class_FieldMapping}.MYSTATICVAR" />

Why not declare those inner beans as separate top-level beans with their own names, and then reference them in the list ?

If I use PropertyPlaceholderConfigurer it leads to several exceptions in debug log. It works, but it seems it doesn't work on the first try.

Related

Manipulation of Spring Bean property

I want to change a property of a bean. I want to change it only once for performance (better when reading from XML), not in every bean instance instantiation. What is the best way to do it in Spring?
For elaborating and giving a concrete example:
Below is the datasource bean declaration in databaseContext.xml.
I want to decrypt ${jdbc.password} whose value is ENC(....) with JASYPT.
I could not do it with Jaspt Spring integration since Jaspt not compliant yet with Spring5 and not with Jasypt Hibernate integration since using a different datasource other than Hibernate.
<bean id="hikariConfig" class="com.zaxxer.hikari.HikariConfig">
<property name="poolName" value="springHikariCP" />
<property name="connectionTestQuery" value="SELECT 1 from dual" />
<property name="dataSourceClassName" value="oracle.jdbc.pool.OracleDataSource" />
<property name="maximumPoolSize" value="10" />
<property name="idleTimeout" value="30000" />
<property name="dataSourceProperties">
<props>
<prop key="url">${jdbc.url}</prop>
<prop key="user">${jdbc.user}</prop>
<prop key="password">${jdbc.password}</prop>
</props>
</property>
</bean>
This helped me a lot:
Spring property placeholder decrypt resolved property
Just want to add some small correction and extra notes about some findings:
In the link above it is written "location", but it must be "locations" as written below, where it resides at applicationContext.xml
<bean class="com.dummy.util.EncryptationAwarePropertySourcesPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath*:database.properties</value>
<value>classpath*:hibernate.properties</value>
</list>
</property>
</bean>
"PropertyPlaceholderConfigurer" is deprecated. But it still works. If you try to use the newly proposed class "PropertySourcesPlaceholderConfigurer", it has a bug that it does not call "convertPropertyValue" method as noted here: https://github.com/spring-projects/spring-framework/issues/13568. A workaround noted by the way there.
public class EncryptationAwarePropertySourcesPlaceholderConfigurer extends PropertyPlaceholderConfigurer {
#Override
protected String convertPropertyValue(String originalValue) {
if (originalValue != null && originalValue.startsWith("ENC(")) {
return decrypt(originalValue);
}
return originalValue;
}
.
.
}

Java based approach for injecting list of spring beans

I am trying to get rid of my XML beans definition file. I would like to know how can i convert the following XML configuration to Java code.
<bean id="CustomerBean" class="com.java2s.common.Customer">
<property name="lists">
<bean class="org.springframework.beans.factory.config.ListFactoryBean">
<property name="targetListClass">
<value>java.util.ArrayList</value>
</property>
<property name="sourceList">
<list>
<value>1</value>
<value>2</value>
<value>3</value>
</list>
</property>
</bean>
</property>
</bean>
I am especially interested in knowing how to convert a list, Set, Map and properties XML configurations to Java code.
And if in a list if i have defined the beans in order like
<bean p:order="1000"
How i can manage the same ordering in java code.
A <list> corresponds to java.util.List, <map> corresponds to java.util.Map, <props> corresponds to java.util.Properties and so on.
To set the order, use the org.springframework.core.annotation.Order annotation on your bean or let it implement org.springframework.core.Ordered.
The equivalent of your XML configuration is something like:
#Bean
public Customer CustomerBean() {
Customer customer = new Customer();
List<String> lists = new ArraysList<>();
lists.add("1");
lists.add("2");
lists.add("3");
customer.setLists(lists);
return customer;
}
Note that the name of the method will be the name of the bean.

How to get key value from properties file at runtime using spring

I want to get the changed key value from properties file at runtime.
test.properties file:
name = Hi
I have made Thread sleep with 5 sec and changed the key value as "Hello" but it is not getting changed.
<bean class="org.springframework.context.support.PropertySourcesPlaceholderConfigurer">
<property name="locations">
<list>
<value>classpath:test.properties</value>
</list>
</property>
<property name="ignoreResourceNotFound" value="true" />
<property name="ignoreUnresolvablePlaceholders" value="true" />
</bean>
<bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource">
<property name="basenames">
<list>
<value>classpath:test</value>
</list>
</property>
<property name="cacheSeconds" value="1" />
</bean>
<bean id="tempBean" name="tempBean1" class="org.sri.spring.temp.Temp"
lazy-init="false" scope="prototype">
<constructor-arg type="String" value="${name}" />
</bean>
The ${name} placeholder inside the XML configuration is resolved using the PropertySourcesPlaceholderConfigurer which, as you may notice, has nothing in common with your reloadable messageSource.
It wouldn't work either way because Spring instantiates the tempBean only once: on application startup, by passing the value of ${name} to the constructor. The bean itself is not aware of where the value came from (and in particular, it doesn't care if the properties file gets edited).
If you really think it's a good idea to do it†, you can inject the entire messageSource into your tempBean, and get the current value in each call, e.g.:
public class Temp {
#Autowired // or wired in XML, constructor, etc.
private MessageSource messages;
public String sayHello() {
return messages.getMessage("name", null, Locale.getDefault());
}
}
† injecting a configuration-related object makes testing more difficult and is arguably bad design (mixing concerns). Have a look at the Spring Cloud Config project as it's likely that this is how the future is going to look like.
I do not think that Spring will update already existing beans when the properties change.
Try to create a new bean (prototype scope)

Spring static factory with factory-method and parameter

I have a problem transfering code to Spring applicationContext.xml
The source is:
File inFile = new File ("path/to/file/", "fileName.docx")
WordprocessingMLPackage wordMLPackage = Docx4J.load(inFile);
My not working solution is:
<bean id="inFile" class="java.io.File">
<constructor-arg value="path/to/file/" />
<constructor-arg value="fileName.docx" />
</bean>
<bean id="docx4j" class="org.docx4j.Docx4J" factory-method="load">
<constructor-arg ref="inFile" />
</bean>
<bean id="wordprocessingMLPackage" class="org.docx4j.openpackaging.packages.WordprocessingMLPackage" factory-bean="docx4j" />
What I'm getting out of the bean "wordprocessingMLPackage" is indeed an instance of the Class WordprocessingMLPackage, but it seems empty although the File I'm trying to load isn't (and yes, the path is doublechecked).
When trying
MainDocumentPart mdp = wordprocessingMLPackage.getMainDocumentPart();
List<Object> content = mdp.getContent();
I'm getting a NullPointerException because mdp is null!
Has anyone an idea... or even a solution?
============================================================
I found a solution especially for my problem.
Here is the source of Docx4j.load():
public static WordprocessingMLPackage load(File inFile) throws Docx4JException {
return WordprocessingMLPackage.load(inFile);
}
That means I can create an instance of WordprocessingMLPackage by its static self!
The code which is working:
<bean id="wordprocessingMLPackage" class="org.docx4j.openpackaging.packages.WordprocessingMLPackage" factory-method="load">
<constructor-arg ref="baseDocument" />
</bean>
So I found a lucky "workaround" for the original problem.
Since this question isn't urgent any more, I'm still interested in the correct solution, especially in a solution which allows injecting the WordprocessingMLPackage in other beans.
Thank you!
Here you need to make use of MethodInvokingFactoryBean as detailed below.
<bean id="beanId"
class="org.springframework.beans.factory.config.MethodInvokingFactoryBean">
<property name="targetClass" value="org.docx4j.Docx4J" />
<property name="targetMethod" value="load"/>
<property name="arguments">
<list>
<ref bean="inFile" />
</list>
</property>
</bean>
In your code get hold of applicationContext instance and invoke the below LOC
WordprocessingMLPackage ml = (WordprocessingMLPackage) applicationContext.getBean("beanId");
Let know in comments if you face any issues.
As Bond - Java Bond stated this works:
<bean id="inFile" class="java.io.File">
<constructor-arg value="path/to/file/" />
<constructor-arg value="fileName.docx" />
</bean>
<bean id="beanId" class="org.springframework.beans.factory.config.MethodInvokingFactoryBean">
<property name="targetClass" value="org.docx4j.Docx4J" />
<property name="targetMethod" value="load"/>
<property name="arguments">
<list>
<ref bean="inFile" />
</list>
</property>
</bean>
You can now use the bean as
WordprocessingMLPackage ml = (WordprocessingMLPackage) applicationContext.getBean("beanId");
or you can inject the bean directly as
<bean id="service" class="app.service.Service">
<property name="wordprocessingMLPackage" ref="beanId" />
</bean>
Thank you!!!

Add precondition value to bean property

In the applicationContext rules xml file, I have rules defined to validate fileds for web forms. eg. The webFormCanadaConditionalRule will be triggered on the province filed and the rule checks to if the selected value is 5714 for Canada. If it is Canada are other filed will get validated.
here is a working example.
<entry key="province">
<list>
<value>webFormCanadaConditionalRule</value>
</list>
</entry>
<bean id="webFormCanadaConditionalRule"
class="ca.gc.cic.gol.eapp.rules.custom.WebFormConditionalRule">
<property name="preConditionValue" value="5714"/>
<property name="ruleNames" >
<list>
<value>mandatory</value>
</list>
</property>
</bean>
What I am trying to accomplish is to have a precondition value that checks to make sure the selected value is not 5714.
Is there a way I can add a precondition value to bean property where I can use the !=... Here is what I have and this doesn't seem to work.
<bean id="webFormAddressNotCanadaConditionalRule"
class="ca.gc.cic.gol.eapp.rules.custom.WebFormConditionalRule">
<property name="preConditionValue" value="${!=5714}" />
<property name="ruleNames" >
<list>
<value>mandatory</value>
</list>
</property>
</bean>
Thanks a lot.

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