Im using the codeigniter upload library to upload multiple files, which works fine ... What im having problems with is returning the information about the files.
Im using the following code to print the results for testing
echo '<pre>'; print_r($this->upload->data()); echo '</pre>';
A cut down version of the results are as follows
Array
(
[file_name] => Array
(
[0] => filename1.gif
[1] => filename2.jpg
)
)
The way my view is setup, is that i use jquery to insert multiple dynamic file input fields so the amount of files can be 1, it can be 50 and so on.
Im wondering how i would loop through that array to send each filename to the database
This would loop through the results and insert each into a table:
$data = $this->upload->data();
$table_name = 'files'; // change to whatever you need.
$column_name = 'file'; // change to whatever you need.
foreach ($data['file_name'] as $file_name){
$this->db->insert($table_name, array($column_name => $file_name));
}
Related
I am attempting to output a CSV from a query result. dbutil->csv_from_result() should work, but it only returns the column headers. No data is included.
I tracked it down to system/database/DB_utility.php which uses unbuffered_row().
Any calls to unbuffered_row() return NULL. If I change it to row(), I get a result. It makes no difference if I use unbuffered_row('array') or unbuffered_row('object')
Why does row() work but unbuffered_row() does not?
Is this a bug in CI or am I missing something?
Edit: row('array') doesn't seem to work either.
Edit: It seems that calling $query->result() spoils dbutil->csv_from_result($query). You apparently cannot iterate through query results AND then save the results in a CSV file. This was possible in CI 2.
Is there any way to show query results AND save the CSV without running the query twice?
I have faced similar problem and found this:
I have this query:
$query = $this->db->query("SELECT * FROM tablename");
print_r($query);
Then I get this and unbuffered_row works fine:
CI_DB_oci8_result Object
(
[stmt_id] => Resource id #106
[curs_id] =>
[limit_used] =>
[commit_mode] => 32
[conn_id] => Resource id #91
[result_id] => 1
[result_array] => Array
(
)
[result_object] => Array
(
)
[custom_result_object] => Array
(
)
[current_row] => 0
[num_rows] =>
[row_data] =>
)
BUT if I call $query->num_rows() before I get a different CI_DB_oci8_result object and unbuffered_row didn't work returning null
$query = $this->db->query("SELECT * FROM tablename");
echo $query->num_rows();
print_r($query);
Hope this help somebody.
I have a function in codeigniter that i want to use to update two tables. This is the code
if($loss_making_trade_amount > 5 && $loss_making_trade_amount < 20){
$user_data = array(
'trading_balance' => $trading_balance_float - 0.50
);
$data = array(
'trade_consequence' => '0.50',
'loss_in_amounts_cron_status' => 'seen'
);
$where = "id='$rid'";
$where_trading_balance = "email='$email'";
$this->db->where($where);
$this->db->set($data);
$this->db->update('mailbox_ke_01', $data);
//update users table at this level
$this->db->where($where_trading_balance);
$this->db->set($user_data);
$this->db->update('users', $user_data);
}
Will i be able to update the tables in the way i have done or will $this be pointing to the first table when updating the second table?.
Your code looks fine, once a query ran - you don't have to be worry about because the Query Builder resets itself after every query if it is finished - or dies in case of a DB Error.
You can take a closer look here
The documentation also clearly suggests that the query runs if the update function gets called.
$this->db->update() generates an update string and runs the query based on the data you supply.
For more information read the documentation here
The only thing i would change are your where clauses:
instead of
$where = "id='$rid'";
$this->db->where($where);
you should use the where function of the Querybuilder properly
$this->db->where("id", $rid);
The same applies for your $where_trading_balance
I am developing a php project using Laravel 5.2. In my app I am retrieving records from database using manual query. But I am having a problem with retrieving records by using where in statement with csv.
Example how I am retrieving
$csv = "1,3,5";
$sql = "SELECT * FROM `items` WHERE `id` IN (?)";
$rows = DB::select($sql,[$csv]);
As you can see above I am retrieving three rows. But it returns only one row where id is 1. Why is that?
You can't do it like that. Each entry in your csv is a separate parameter, so for your code you would actually need IN (?, ?, ?), and then pass in the array of values. It would be pretty easy to write the code to do this (explode the string to an array, create another array of question marks the same size, put it all together).
However, you are using Laravel, so it would be easier to use the functionality Laravel provides to you.
Using the query builder, you can do this like:
$csv = "1,3,5";
// turn your csv into an array
$ids = explode(",", $csv);
// get the data
$rows = DB::table('items')->whereIn('id', $ids)->get();
// $rows will be an array of stdClass objects containing your results
dd($rows);
Or, if you have an Item model setup for your items table, you could do:
$items = Item::whereIn('id', $params)->get();
// $items will be a Collection of Item objects
dd($items);
Or, assuming id is the primary key of your items table:
// find can take a single id, or an array of ids
$items = Item::find($params);
// $items will be a Collection of Item objects
dd($items);
Edit
If you really want to do it the manual way, you could use a loop, but you don't need to. PHP provides some pretty convenient array methods.
$csv = "1,3,5";
// turn your csv into an array
$ids = explode(",", $csv);
// generate the number of parameters you need
$markers = array_fill(0, count($ids), '?');
// write your sql
$sql = "SELECT * FROM `items` WHERE `id` IN (".implode(',', $markers).")";
// get your data
$rows = DB::select($sql, $ids);
In first function of my controller, I am fetching random records from mysql table using CI active record
$query = $this->db->query("SELECT DISTINCT * FROM questions WHERE `level` = '1' ORDER BY RAND() limit 0,5");
$result = $query->result_array();
and saving result in session as
// saving questions id in session
for($i = 0; $i < count($result); $i++)
{
$session['questionsId'][] = $result[$i]['qId'];
}
$this->session->set_userdata($session);
and if print session variable it shows output like:
$qIds_o = $this->session->userdata('questionsId');
var_debug($qIds_o);
Array
(
[0] => 5
[1] => 9
[2] => 3
[3] => 6
[4] => 11
)
but if I retrieve same session in another function of same controller it shows different result
$qIds = $this->session->userdata('questionsId');
var_debug($qIds);
Array
(
[0] => 2
[1] => 8
[2] => 6
[3] => 3
[4] => 5
)
and if I remove ORDER BY RAND() from mysql query like:
$this->db->query("SELECT DISTINCT * FROM questions WHERE `level` = '1' limit 0,5");
it shows same session array in both functions. Very strange.
Please guide what is going wrong....
Here is my controller script:
public function set_value(){
$query = $this->db->query("SELECT DISTINCT * FROM questions WHERE `level` = '1' ORDER BY RAND() limit 0,5");
$result = $query->result_array();
// saving questions id in session
for($i = 0; $i < count($result); $i++)
{
$session['questionsId'][] = $result[$i]['qId'];
}
$this->session->set_userdata($session);
$qIds_o = $this->session->userdata('questionsId');
var_debug($qIds_o);
}
public function get_value(){
$qIds = $this->session->userdata('questionsId');
var_debug($qIds);
}
I called set_value() on page load while once the page loaded I call get_value() using AJAX post which simply hits my_controller/get_value/ and response back to browser.
Without looking at your controller (let's call it my_controller in detail, I think what might be happening is:
(1) You call the first function, my_controller/set_value where set_value sets the session variable and you echo the result.
(2) You then call the second function, show_value that simply echos out the session variable.
What you might be doing in set_value is:
1) echo out the current session variable
2) call the query and re-set the session variable
If this is the case, then when you go to show_value (2nd function) you are looking at the recently re-set value instead of the prior value that you echoed out in the first function.
I have two questions about this sentence:
but if I retrieve same session in another function of same controller it shows different result
Is this on a new page load?
If so, is the query run again?
I'm going to assume the answer to both of these questions is yes, since you said removing RAND() gives you the same results.
You are using a combination of RAND() and LIMIT in your query, meaning you want only five rows in a random order. That means that each time the query is run (and your session data is set), it is very likely that the results will be different.
I don't know exactly what you're doing with these IDs and what sort of data set you need, so this may not be 100% perfect for your solution, but if you only need to set this session data once, you should check if it exists before running the query.
if ($this->session->userdata('questionsId') === FALSE)
{
// Run your query and set your session data here.
// Note that in CI 3.0, Session::userdata()
// will return NULL if empty, not a boolean.
}
I tried to get a umat_id with this SQL query :
SELECT umat_id FROM msumat WHERE nama = $nama
I converted this SQL query into CI's Active Record :
$this->db->select('umat_id');
$terdaftar = $this->db->get_where('msumat', array('nama' => $nama));
So this query should return a string (example : "John").
But I got an error when I tried to echo it :
Object of class CI_DB_mysql_result could not be converted to string
I have tried something like this : echo (string)$terdaftar;, but it's not working.
All I want is to echo "John"
EDIT
Just said I want to insert "John" into a variable. How to do that?
$john = ????
As some of the users already pointed the solution, I'm only explaining why you did get this error so you can understand better the querying results that codeigniter gives.
This error:
But I got an error when I tried to echo it : Object of class
CI_DB_mysql_result could not be converted to string
Happens because you were trying to echo an object.
This piece of code
$terdaftar = $this->db->get_where('msumat', array('nama' => $nama));
Will return an object, this object will have information about the query you've done.
With this object you can get the result(rows) as objects doing this:
$results = $terdaftar->result();
Or you if you feel more comfortable with arrays you can return the results(rows) as an array doing this:
$results = $terdaftar->result_array();
You can also get the number of results doing this:
$number_results = $terdaftar->num_rows()
And this is just an example you can read more about the results here
http://ellislab.com/codeigniter/user-guide/database/results.html
EDIT
A better explanation: imagine that we use the result_array() function to get the result in a pure array format:
$results = $terdaftar->result_array();
Now your variable $results is an array, to iterate through it and get the data you want you'll do something like this:
foreach ($results as $key => $row) {
//the row variable will have each row of your database returned by your query
//so if you want to access a field from that row,
//let's say for example the name field. You would do something like this
if($row['name']=='John')
echo $row['name'];
}
Try:
$this->db->select('umat_id');
$terdaftar = $this->db->get_where('msumat', array('nama' => $nama));
foreach ($terdaftar->result() as $row)
{
echo $row->umat_id;
}
Read the documentation for more information.
Try this:
$this->db->select('umat_id');
$terdaftar = $this->db->get_where('msumat', array('nama' => $nama));
$row = $terdaftar->row_array();
$your_variable = $row['umat_id']; /*Here comes your john*/